/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 The average free convection coef... [FREE SOLUTION] | 91Ó°ÊÓ

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The average free convection coefficient for the exterior surfaces of a long, horizontal rectangular duct exposed to a quiescent fluid can be estimated from the Hahn-Didion (H-D) correlation [ASHRAE Proceedings, Part 1, pp. 262-67, 1972] $$ \overline{N u}_{P}=0.55 R a_{P}^{1 / 4}\left(\frac{H}{P}\right)^{1 / 8} \quad R a_{P} \leq 10^{7} $$] where the characteristic length is the half-perimeter, \(P=(w+H)\), and \(w\) and \(H\) are the horizontal width and vertical height, respectively, of the duct. The thermophysical properties are evaluated at the film temperature. (a) Consider a horizontal \(0.15-\mathrm{m}\)-square duct with a surface temperature of \(35^{\circ} \mathrm{C}\) in ambient air at \(15^{\circ} \mathrm{C}\). Calculate the average convection coefficient and the heat rate per unit length using the H-D correlation. (b) Calculate the average convection coefficient and the heat rate per unit length considering the duct as formed by vertical plates (sides) and horizontal plates (top and bottom). Do you expect this estimate to be lower or higher than that obtained with the H-D correlation? Explain the difference, if any. (c) Using an appropriate correlation, calculate the average convection coefficient and the heat rate per unit length for a duct of circular cross section having a perimeter equal to the wetted perimeter of the rectangular duct of part (a). Do you expect this estimate to be lower or higher than that obtained with the H-D correlation? Explain the difference, if any.

Short Answer

Expert verified
In summary, after calculating the Grashof, Prandtl, and Rayleigh numbers at the film temperature, we apply the H-D correlation to find the average Nusselt number for a square duct. Using this, we calculate the average convection coefficient (\(h\)) and heat rate per unit length (\(q'\)) for the given problem. We perform similar calculations for vertical and horizontal plates and a circular duct and compare these results with the H-D correlation to determine which scenario has higher or lower estimates.

Step by step solution

01

Calculate the Grashof and Prandtl numbers

First, we need to evaluate the Grashof (\(Gr\)) and Prandtl (\(Pr\)) numbers using the given temperature values and thermophysical properties of air. We will calculate these numbers at the film temperature, which is the average between the surface temperature and the ambient temperature. The formulas for these numbers are: $$ Gr = \frac{g \beta (T_s - T_\infty) L^3}{\nu^2} \quad, \quad Pr = \frac{\mu C_p}{k} $$ where \(g\) is the acceleration due to gravity, \(\beta\) is the coefficient of thermal expansion, \(T_s\) is the surface temperature, \(T_\infty\) is the ambient temperature, \(L\) is the characteristic length, \(\nu\) is the kinematic viscosity, \(\mu\) is the dynamic viscosity, \(C_p\) is the specific heat at constant pressure, and \(k\) is the thermal conductivity.
02

Calculate the Rayleigh number

Next, we can calculate the Rayleigh number (\(Ra\)) from Grashof and Prandtl numbers using the following formula: $$ Ra = Gr \cdot Pr $$
03

Apply the H-D correlation

Now we can apply the H-D correlation for the average Nusselt number. The equation for the H-D correlation is given by: $$ \overline{N u}_{P}=0.55 R a_{P}^{1 / 4}\left(\frac{H}{P}\right)^{1 / 8} \quad $$ Since the H-D correlation is related to the half-perimeter, we need to calculate it as \(P = w + H\). In the given problem, the duct has a square shape, so \(w = H = 0.15\,\textnormal{m}\) and \(P = 0.30\,\textnormal{m}\).
04

Calculate the average convection coefficient

Once we have the average Nusselt number, we can calculate the average convection coefficient \(h\) using the following formula: $$ h = \frac{\overline{N u}_{P} k}{P} $$
05

Calculate the heat rate per unit length

Finally, we can calculate the heat rate per unit length \(q'\) using its relationship with the average convection coefficient \(h\): $$ q' = h (T_s - T_\infty) A $$ where \(A\) is the area of the duct's external surface. (b) Calculate the average convection coefficient and the heat rate per unit length considering the duct as formed by vertical plates (sides) and horizontal plates (top and bottom).
06

Apply convection correlations for vertical and horizontal plates

In this case, we consider the duct as being formed by vertical and horizontal plates. We will apply convection correlations for natural convection from vertical and horizontal plates and calculate the heat transfer rates per unit length for each. Then, we will compare our results with the results obtained using the H-D correlation. (c) Calculate the average convection coefficient and the heat rate per unit length for a duct of circular cross-section having a perimeter equal to the wetted perimeter of the rectangular duct of part (a).
07

Apply an appropriate correlation for circular ducts

In this part, we will use a suitable convection correlation for a circular duct and calculate the average convection coefficient and the heat rate per unit length. Then, we will compare our results with the results obtained using the H-D correlation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nusselt Number Correlation
The Nusselt number is a dimensionless parameter that represents the ratio of convective to conductive heat transfer across a boundary. In engineering applications, determining the Nusselt number is crucial for predicting the heat transfer rate in systems where convection plays a role. Nusselt number correlations, like the Hahn-Didion (H-D) correlation, provide a way to estimate the convective heat transfer coefficient given certain conditions and geometries.

The H-D correlation mentioned in the exercise is specifically designed for natural convection situations and relates the Nusselt number, Rayleigh number, and the physical dimensions of the surface. It is expressed as: \[\overline{Nu}_{P}=0.55 Ra_{P}^{1 / 4}\left(\frac{H}{P}\right)^{1 / 8}\] where \(\overline{Nu}_{P}\) is the average Nusselt number for the perimeter, \(Ra_{P}\) is the Rayleigh number, \(H\) is the height, and \(P\) is the half-perimeter of the duct. This correlation is particularly useful for cases with Rayleigh numbers less than \(10^{7}\). It simplifies calculations when dealing with free convection along the exterior surfaces of a duct.

However, students should keep in mind that Nusselt number correlations vary widely depending on the specific case and geometry. Each correlation has its range of validity; hence, it's essential to use the appropriate correlation for accurate results. In scenarios where the H-D correlation is not suitable, alternative correlations based on the geometry of the objects should be considered.
Natural Convection
Natural convection occurs when fluid motion and heat transfer are driven by buoyancy forces, which arise due to density differences in the fluid caused by temperature variations. Unlike forced convection where an external source, like a pump or fan, moves the fluid, natural convection relies solely on this natural process. It's a phenomenon that significantly influences the heat transfer rate without any mechanical assistance.

In the context of the exercise, the ambient air's temperature variation around the duct creates a density difference that induces natural convection. The warmer surface of the duct heats the adjacent air, making it less dense and causing it to rise, while cooler, denser air takes its place, thus forming a convective current. This current facilitates the transfer of heat from the duct to the surrounding air.

When calculating convection coefficients for scenarios involving natural convection, it's essential to consider factors such as the orientation of the surface (horizontal or vertical), the physical properties of the fluid at the film temperature, and the geometrical dimensions. This consideration will affect the convection correlations used, the Nusselt number, and ultimately the heat transfer rate per unit length, as demonstrated in the exercise.
Heat Transfer Coefficient
The heat transfer coefficient, denoted by \(h\), is a measure of the convective heat transfer capability between a solid surface and a fluid in contact with it. It's a crucial value in thermodynamics and heat transfer as it directly affects the rate at which heat is transferred by convection. The coefficient quantifies the amount of heat transferred per unit area per degree of temperature difference between the surface and the fluid.

In mathematical terms, the relationship between the Nusselt number, thermal conductivity of the fluid \(k\), and the heat transfer coefficient is given by: \[h = \frac{\overline{Nu} \times k}{L}\]where \(L\) is the characteristic length, and \(\overline{Nu}\) is the average Nusselt number. In the context of the exercise, once you have determined the Nusselt number using the H-D correlation, you can find the heat transfer coefficient for the duct. This value is not only critical for determining the heat rate per unit length but is also a telling indicator of how efficiently the duct surface can transfer heat to the surrounding air.

The heat transfer coefficient also depends on the nature of the fluid flow and the properties of the fluid at a given temperature. As the exercise shows, different geometries can lead to varying heat transfer coefficients, and thus, affect the overall heat rate per unit length, underscoring the importance of correctly evaluating this coefficient based on established correlations.

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Most popular questions from this chapter

A horizontal 100-mm-diameter pipe passing hot oil is to be used in the design of an industrial water heater. Based on a typical water draw rate, the velocity over the pipe is \(0.5 \mathrm{~m} / \mathrm{s}\). The hot oil maintains the outer surface temperature at \(85^{\circ} \mathrm{C}\) and the water temperature is \(37^{\circ} \mathrm{C}\). Investigate the effect of flow direction on the heat rate (W/m) for (a) horizontal, (b) downward, and (c) upward flow.

During a winter day, the window of a patio door with a height of \(1.8 \mathrm{~m}\) and width of \(1.0 \mathrm{~m}\) shows a frost line near its base. The room wall and air temperatures are \(15^{\circ} \mathrm{C}\). (a) Explain why the window would show a frost layer at the base rather than at the top. (b) Estimate the heat loss through the window due to free convection and radiation. Assume the window has a uniform temperature of \(0^{\circ} \mathrm{C}\) and the emissivity of the glass surface is \(0.94\). If the room has electric baseboard heating, estimate the corresponding daily cost of the window heat loss for a utility rate of \(0.18 \mathrm{\$} / \mathrm{kW} \cdot \mathrm{h}\).

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