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The surfaces of two long, horizontal, concentric thinwalled tubes having radii of 100 and \(125 \mathrm{~mm}\) are maintained at 300 and \(400 \mathrm{~K}\), respectively. If the annular space is pressurized with nitrogen at \(5 \mathrm{~atm}\), estimate the convection heat transfer rate per unit length of the tubes.

Short Answer

Expert verified
To estimate the convection heat transfer rate per unit length of the tubes, first find the average gas temperature as \( T_m = \frac{T_1 + T_2}{2} \). Then determine the properties of nitrogen at this temperature, including thermal conductivity (k), dynamic viscosity (渭), density (蟻), and specific heat (Cp). Calculate Reynolds (Re) and Prandtl (Pr) numbers using the formulas \( Re = \frac{D_h 蟻V}{渭} \) and \( Pr = \frac{C_p渭}{k} \). Next, find the Nusselt number using the correlation \( Nu = C Re^m Pr^n \) and calculate the heat transfer coefficient (h) with \( h = \frac{Nu \times k}{D_h} \). Finally, determine the convection heat transfer rate per unit length using the equation \( q = h \pi D_i L (T_2 - T_1) \).

Step by step solution

01

Find the Average Temperature

Take the average of the two tube surface temperatures to find the average gas temperature: \( T_m = \frac{T_1 + T_2}{2} \) where \(T_1 = 300 \mathrm{~K}\) and \(T_2 = 400 \mathrm{~K}\).
02

Determine the Properties of Nitrogen at the Average Temperature

Refer to tables or thermodynamic property databases (such as NIST) to find the properties of nitrogen at the average temperature found in Step 1. We need the following nitrogen properties: - Thermal conductivity (k) - Dynamic viscosity (渭) - Density (蟻) - Specific heat (Cp)
03

Calculate Reynolds (Re) and Prandtl (Pr) Numbers

With the properties from Step 2, calculate the Reynolds number (Re) and Prandtl number (Pr) as follows: \( Re = \frac{D_h 蟻V}{渭} \) \( Pr = \frac{C_p渭}{k} \) where \(D_h\) is the hydraulic diameter of the annulus and V is the flow velocity of the nitrogen gas.
04

Calculate the Nusselt Number

Use the Nusselt number correlation for a concentric annulus: \( Nu = C Re^m Pr^n \) where C, m, and n are constants for the specific geometry of the annulus.
05

Calculate the Heat Transfer Coefficient, h

Use the Nusselt number to calculate the heat transfer coefficient (h): \( h = \frac{Nu \times k}{D_h} \)
06

Calculate the Convection Heat Transfer Rate per Unit Length

With the heat transfer coefficient, we can now calculate the convection heat transfer rate per unit length using the following equation: \( q = h \pi D_i L (T_2 - T_1) \) where \(D_i\) is the inner tube diameter, \(L\) is the length of the tubes (per unit length, L=1), and \(T_1\) and \(T_2\) are the surface temperatures of the inner and outer tubes, respectively. With all these steps, we can calculate the convection heat transfer rate per unit length between the two concentric tubes filled with nitrogen gas at 5 atm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds number
The Reynolds number is a dimensionless value that estimates the flow regime within a fluid. It helps determine whether the flow is laminar (smooth and orderly) or turbulent (chaotic and irregular). In our context, it is particularly relevant when calculating the heat transfer in gases like nitrogen during convection processes.

To calculate the Reynolds number, use the formula:
  • \( Re = \frac{D_h \rho V}{\mu} \)
Here, \(D_h\) is the hydraulic diameter, \(\rho\) is the density of the nitrogen, \(V\) is the flow velocity, and \(\mu\) is the dynamic viscosity.

The flow characteristics, identified by this number, heavily influence how heat is transferred between surfaces. Typically, values of \( Re \) less than 2300 indicate laminar flow, while values above 4000 indicate turbulent flow. Knowing whether your flow is laminar or turbulent helps in predicting heat transfer efficiency better.
Prandtl number
The Prandtl number is another dimensionless number that provides insight into the nature of thermal convection within a fluid. It compares the rate of momentum diffusion (viscous force) to the rate of thermal diffusion (heat conduction).

The Prandtl number formula is:
  • \( Pr = \frac{C_p \mu}{k} \)
where \(C_p\) is the specific heat at constant pressure, \(\mu\) is the dynamic viscosity, and \(k\) is the thermal conductivity.

A higher Prandtl number implies that the fluid's thermal diffusivity is low compared to its momentum diffusivity. Fluids like oils, for example, have a high Prandtl number, suggesting that thermal conduction is slower relative to momentum diffusion. Each type of fluid can have a different value, which has a profound impact on calculating the Nusselt number, especially in convective heat transfer scenarios like those observed in concentric tube setups.
Nusselt number
The Nusselt number signifies the enhancement of heat transfer in a fluid compared to conduction alone. Think of it as the measure of convective heat transfer versus pure conductive heat transfer.

The generalized correlation for the Nusselt number is:
  • \( Nu = C Re^m Pr^n \)
where \(C\), \(m\), and \(n\) are empirical constants dependent on the system geometry and flow conditions.

In this exercise involving concentric tubes, it gives us a way to determine the heat transfer coefficient, which is a vital parameter for assessing how effective the nitrogen gas is at transferring heat from one tube surface to the other. Practically, a higher Nusselt number suggests better heat transfer efficiency, which can be desirable depending on the application.
Thermal conductivity
Thermal conductivity is a fundamental property that expresses a material's ability to conduct heat. In our scenario, it determines how effectively nitrogen can transport heat via conduction alongside convection.

The symbol for thermal conductivity is \(k\), and its units are typically expressed in W/m路K. Higher values of \(k\) indicate better conductivity, meaning the material will transfer heat more efficiently at any temperature gradient.

Thermal conductivity ties into the calculations for both the Prandtl and Nusselt numbers. It ultimately helps us understand how well the nitrogen will perform in the setup, filling the space between concentric tubes and helping answer questions regarding heat transfer rates.
Specific heat
Specific heat, usually symbolized as \(C_p\), refers to the amount of heat per unit mass required to raise the temperature by one degree Celsius. It fundamentally defines how much energy a fluid can store for each degree of temperature rise.

In the context of our exercise, nitrogen's specific heat influences its capacity to absorb and release heat. It is a vital variable in the Prandtl number formula and helps us determine how much thermal energy the nitrogen can carry away during the convection process.

Specific heat values can vary widely across different substances, so having accurate data for nitrogen at the average operating temperatures in the concentric tube setup is crucial to get precise heat transfer predictions.

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Most popular questions from this chapter

An aluminum alloy (2024) plate, heated to a uniform temperature of \(227^{\circ} \mathrm{C}\), is allowed to cool while vertically suspended in a room where the ambient air and surroundings are at \(27^{\circ} \mathrm{C}\). The plate is \(0.3 \mathrm{~m}\) square with a thickness of \(15 \mathrm{~mm}\) and an emissivity of \(0.25\). (a) Develop an expression for the time rate of change of the plate temperature, assuming the temperature to be uniform at any time. (b) Determine the initial rate of cooling (K/s) when the plate temperature is \(227^{\circ} \mathrm{C}\). (c) Justify the uniform plate temperature assumption. (d) Compute and plot the temperature history of the plate from \(t=0\) to the time required to reach a temperature of \(30^{\circ} \mathrm{C}\). Compute and plot the corresponding variations in the convection and radiation heat transfer rates.

Convection heat transfer coefficients for a hot horizontal surface facing upward may be determined by a gage whose specific features depend on whether the temperature of the surroundings is known. For configuration A, a copper disk, which is electrically heated from below, is encased in an insulating material such that all of the heat is transferred by convection and radiation from the top surface. If the surface emissivity and the temperatures of the air and surroundings are known, the convection coefficient may be determined from measurement of the electrical power and the surface temperature of the disk. Configuration B is used in situations for which the temperature of the surroundings is not known. A thin, insulating strip separates semicircular disks with independent electrical heaters and different emissivities. If the emissivities and temperature of the air are known, the convection coefficient may be determined from measurement of the electrical power supplied to each of the disks in order to maintain them at a common temperature. (a) In an application of configuration A to a disk of diameter \(D=160 \mathrm{~mm}\) and emissivity \(\varepsilon=0.8\), values of \(P_{\text {elec }}=10.8 \mathrm{~W}\) and \(T=67^{\circ} \mathrm{C}\) are measured for \(T_{\infty}=T_{\text {sur }}=27^{\circ} \mathrm{C}\). What is the corresponding value of the average convection coefficient? How does it compare with predictions based on a standard correlation? (b) Now consider an application of configuration \(B\) for which \(T_{\infty}=17^{\circ} \mathrm{C}\) and \(T_{\text {sur }}\) is unknown. With \(D=160 \mathrm{~mm}, \varepsilon_{1}=0.8\), and \(\varepsilon_{2}=0.1\), values of \(P_{\text {elect, } 1}=9.70 \mathrm{~W}\) and \(P_{\text {elec, } 2}=5.67 \mathrm{~W}\) are measured when \(T_{1}=T_{2}=77^{\circ} \mathrm{C}\). Determine the corresponding values of the convection coefficient and the temperature of the surroundings. How does the convection coefficient compare with predictions by an appropriate correlation?

At the end of its manufacturing process, a silicon wafer of diameter \(D=150 \mathrm{~mm}\), thickness \(\delta=1 \mathrm{~mm}\), and emissivity \(\varepsilon=0.65\) is at an initial temperature of \(T_{i}=325^{\circ} \mathrm{C}\) and is allowed to cool in quiescent, ambient air and large surroundings for which \(T_{\infty}=T_{\text {sur }}=25^{\circ} \mathrm{C}\). (a) What is the initial rate of cooling? (b) How long does it take for the wafer to reach a temperature of \(50^{\circ} \mathrm{C}\) ? Comment on how the relative effects of convection and radiation vary with time during the cooling process.

The human eye contains aqueous humor, which separates the external cornea and the internal iris-lens structure. It is hypothesized that, in some individuals, small flakes of pigment are intermittently liberated from the iris and migrate to, and subsequently damage, the cornea. Approximating the geometry of the enclosure formed by the cornea and iris-lens structure as a pair of concentric hemispheres of outer radius \(r_{o}=10 \mathrm{~mm}\) and inner radius \(r_{i}=7 \mathrm{~mm}\), respectively, investigate whether free convection can occur in the aqueous humor by evaluating the effective thermal conductivity ratio, \(k_{\mathrm{efI}} / k\). If free convection can occur, it is possible that the damaging particles are advected from the iris to the cornea. The iris-lens structure is at the core temperature, \(T_{i}=37^{\circ} \mathrm{C}\), while the cornea temperature is measured to be \(T_{o}=34^{\circ} \mathrm{C}\). The properties of the aqueous humor are \(\rho=990 \mathrm{~kg} / \mathrm{m}^{3}, k=0.58 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(c_{p}=4.2 \times 10^{3} \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=7.1 \times 10^{-4} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\), and \(\beta=3.2 \times 10^{-4} \mathrm{~K}^{-1}\)

Many laptop computers are equipped with thermal management systems that involve liquid cooling of the central processing unit (CPU), transfer of the heated liquid to the back of the laptop screen assembly, and dissipation of heat from the back of the screen assembly by way of a flat, isothermal heat spreader. The cooled liquid is recirculated to the CPU and the process continues. Consider an aluminum heat spreader that is of width \(w=275 \mathrm{~mm}\) and height \(L=175 \mathrm{~mm}\). The screen assembly is oriented at an angle \(\theta=30^{\circ}\) from the vertical direction, and the heat spreader is attached to the \(t=3\)-mm-thick plastic housing with a thermally conducting adhesive. The plastic housing has a thermal conductivity of \(k=0.21 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and emissivity of \(\varepsilon=0.85\). The contact resistance associated with the heat spreaderhousing interface is \(R_{t, c}^{\prime \prime}=2.0 \times 10^{-4} \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\). If the CPU generates, on average, \(15 \mathrm{~W}\) of thermal energy, what is the temperature of the heat spreader when \(T_{\infty}=T_{\text {sur }}=23^{\circ} \mathrm{C}\) ? Which thermal resistance (contact, conduction, radiation, or free convection) is the largest?

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