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Fully developed conditions are known to exist for water flowing through a \(25-\mathrm{mm}\)-diameter tube at \(0.01 \mathrm{~kg} / \mathrm{s}\) and \(27^{\circ} \mathrm{C}\). What is the maximum velocity of the water in the tube? What is the pressure gradient associated with the flow?

Short Answer

Expert verified
The maximum velocity of the water in the tube is \(0.0205 \text{ m/s}\) and the pressure gradient associated with the flow is \(-4700.41 \text{ Pa/m}\).

Step by step solution

01

Determine flow rate and cross-sectional area

Given: - Diameter of the tube (D) = 25 mm = 0.025 m - Mass flow rate of water (m_dot) = 0.01 kg/s - Temperature of water (T) = 27掳C First, we will find the volume flow rate (Q) by dividing the mass flow rate (m_dot) by the density of the water (蟻). At 27掳C, the density of water is approximately 996 kg/m鲁. $$Q = \frac{m_dot}{蟻} = \frac{0.01 \text{ kg/s}}{996 \text{ kg/m鲁}} = 1.004 \times 10^{-5} \text{ m鲁/s}$$ Next, we will calculate the cross-sectional area (A) of the tube by using the formula for the area of a circle: $$A = \pi \left(\frac{D}{2}\right)^2 = \pi \left(\frac{0.025 \text{ m}}{2}\right)^2 = 4.9087 \times 10^{-4} \text{ m虏}$$
02

Calculate maximum velocity (V_max)

Now we can find the maximum velocity (V_max) by dividing the flow rate (Q) by the cross-sectional area (A): $$V_{max} = \frac{Q}{A} = \frac{1.004 \times 10^{-5} \text{ m鲁/s}}{4.9087 \times 10^{-4} \text{ m虏}} = 0.0205 \text{ m/s}$$ The maximum velocity of the water in the tube is 0.0205 m/s.
03

Determine pressure gradient

To calculate the pressure gradient, we will use the Hagen-Poiseuille equation, which relates the pressure drop to the flow rate in a pipe: $$\Delta P = \frac{128 \mu Q L}{\pi D^4}$$ where: - 螖P is the pressure drop - 渭 is the dynamic viscosity of the fluid (can be approximated as 0.000797 kg/m路s for water at 27掳C) - L is the length of the pipe (unknown) We are interested in finding the pressure gradient, which is the pressure drop per unit length (鈭侾/鈭侺). To do this, we will divide both sides of the Hagen-Poiseuille equation by the length L: $$\frac{\Delta P}{L} = \frac{128 \mu Q}{\pi D^4}$$ Now plug in the values we have calculated and the dynamic viscosity of water: $$\frac{\partial P}{\partial L} = \frac{128 \times 0.000797 \text{ kg/m路s} \times 1.004 \times 10^{-5} \text{ m鲁/s}}{\pi \times (0.025 \text{ m})^4} = -4700.41 \text{ Pa/m}$$ The pressure gradient associated with the flow of water through the tube is -4700.41 Pa/m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fully Developed Flow
Understanding fluid flow within pipes is crucial for various engineering applications. One essential concept in this field is 'fully developed flow.' A fully developed flow refers to a condition in fluid dynamics where the velocity profile of the fluid does not change in the direction of flow. This phenomenon occurs after fluid has entered a pipe and traveled some distance, allowing it to settle into a steady state of motion.

Characteristics of fully developed flow include a constant velocity across any cross-section of the pipe and zero acceleration of fluid particles in the streamwise direction. It's important to note that, for a fully developed flow, the effect of the pipe entrance has diminished, and the effects of viscosity are fully realized, resulting in a predictable and steady velocity profile. In practical terms, the fully developed flow assumption simplifies calculations and provides more accurate modeling for engineers and physicists when designing pipe systems.
Hagen-Poiseuille Equation
The Hagen-Poiseuille equation plays a pivotal role in fluid dynamics, particularly in the analysis of laminar flow through circular pipes. Expressing the volumetric flow rate as a function of pipe characteristics and fluid properties, it provides insights into the relationship between the pressure difference across the length of the pipe and the ensuing flow.

The equation is mathematically given by: \[ Q = \frac{\pi \Delta P R^4}{8 \mu L} \]where \( Q \) is the volumetric flow rate, \( \Delta P \) is the pressure difference between the two ends of the pipe, \( R \) is the radius of the pipe, \( \mu \) is the dynamic viscosity of the fluid, and \( L \) is the length of the pipe over which the pressure difference is measured. This equation assumes a laminar, incompressible, and steady flow with no slip at the pipe wall. It is critical for predicting flow rates and understanding the effects of changing conditions within the pipes.
Pressure Gradient
In fluid dynamics, the pressure gradient is a significant factor, referring to the rate at which the pressure changes with respect to distance in a particular direction, often indicated by \( \frac{\partial P}{\partial x} \). It's a vector quantity, providing both the magnitude and the direction of the pressure change.

The importance of the pressure gradient cannot be understated as it plays a crucial role in driving the flow of fluids in pipes, ducts, or open channels. Fluids tend to flow from regions of high pressure to low pressure, and it's this gradient that facilitates the movement. For laminar flow in pipes, the pressure gradient can be both negative and positive, indicating flow in different directions. Calculation of the pressure gradient is essential for determining the energy required for fluid transport and the design of efficient fluid delivery systems.
Maximum Velocity
In the context of fluid flow inside a pipe, 'maximum velocity' is a term that refers to the highest speed attained by the fluid along the axis of the pipe. This is typically found at the centerline of a pipe in laminar flow conditions, where due to the no-slip condition at the walls, the velocity of the fluid gradually decreases from the maximum at the center to zero at the pipe boundary.

The concept of maximum velocity is integral to the application of the Hagen-Poiseuille equation, which we use to predict the flow characteristics of fluids in pipes. Knowing the maximum velocity of a fluid helps in numerous practical situations, such as ensuring that fluid being pumped through a system meets the necessary operational criteria and assessing the potential for erosion or wear within piping over time.

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Most popular questions from this chapter

An air heater for an industrial application consists of an insulated, concentric tube annulus, for which air flows through a thin-walled inner tube. Saturated steam flows through the outer annulus, and condensation of the steam maintains a uniform temperature \(T_{s}\) on the tube surface. Consider conditions for which air enters a 50 -mmdiameter tube at a pressure of \(5 \mathrm{~atm}\), a temperature of \(T_{m, i}=17^{\circ} \mathrm{C}\), and a flow rate of \(\dot{m}=0.03 \mathrm{~kg} / \mathrm{s}\), while saturated steam at \(2.455\) bars condenses on the outer surface of the tube. If the length of the annulus is \(L=5 \mathrm{~m}\), what are the outlet temperature \(T_{m, o}\) and pressure \(p_{o}\) of the air? What is the mass rate at which condensate leaves the annulus?

One way to cool chips mounted on the circuit boards of a computer is to encapsulate the boards in metal frames that provide efficient pathways for conduction to supporting cold plates. Heat generated by the chips is then dissipated by transfer to water flowing through passages drilled in the plates. Because the plates are made from a metal of large thermal conductivity (typically aluminium or copper), they may be assumed to be at a temperature, \(T_{s, c p^{-}}\) (a) Consider circuit boards attached to cold plates of height \(H=750 \mathrm{~mm}\) and width \(L=600 \mathrm{~mm}\), each with \(N=10\) holes of diameter \(D=10 \mathrm{~mm}\). If operating conditions maintain plate temperatures of \(T_{\text {s.tp }}=32^{\circ} \mathrm{C}\) with water flow at \(\dot{m}_{1}=0.2 \mathrm{~kg} / \mathrm{s}\) per passage and \(T_{m, i}=7^{\circ} \mathrm{C}\), how much heat may be dissipated by the circuit boards? (b) To enhance cooling, thereby allowing increased power generation without an attendant increase in system temperatures, a hybrid cooling scheme may be used. The scheme involves forced airflow over the encapsulated circuit boards, as well as water flow through the cold plates. Consider conditions for which \(N_{\mathrm{cb}}=10\) circuit boards of width \(W=350 \mathrm{~mm}\) are attached to the cold plates and their average surface temperature is \(T_{s, \text { do }}=47^{\circ} \mathrm{C}\) when \(T_{s, \text { ep }}=32^{\circ} \mathrm{C}\). If air is in parallel flow over the plates with \(u_{\infty}=10 \mathrm{~m} / \mathrm{s}\) and \(T_{\infty}=7^{\circ} \mathrm{C}\), how much of the heat generated by the circuit boards is transferred to the air?

Exhaust gases from a wire processing oven are discharged into a tall stack, and the gas and stack surface temperatures at the outlet of the stack must be estimated. Knowledge of the outlet gas temperature \(T_{m, o}\) is useful for predicting the dispersion of effluents in the thermal plume, while knowledge of the outlet stack surface temperature \(T_{s, a}\) indicates whether condensation of the gas products will occur. The thin-walled, cylindrical stack is \(0.5 \mathrm{~m}\) in diameter and \(6.0 \mathrm{~m}\) high. The exhaust gas flow rate is \(0.5 \mathrm{~kg} / \mathrm{s}\), and the inlet temperature is \(600^{\circ} \mathrm{C}\). (a) Consider conditions for which the ambient air temperature and wind velocity are \(4^{\circ} \mathrm{C}\) and \(5 \mathrm{~m} / \mathrm{s}\), respectively. Approximating the thermophysical properties of the gas as those of atmospheric air, estimate the outlet gas and stack surface temperatures for the given conditions. (b) The gas outlet temperature is sensitive to variations in the ambient air temperature and wind velocity. For \(T_{\infty}=-25^{\circ} \mathrm{C}, 5^{\circ} \mathrm{C}\), and \(35^{\circ} \mathrm{C}\), compute and plot the gas outlet temperature as a function of wind velocity for \(2 \leq V \leq 10 \mathrm{~m} / \mathrm{s}\).

8.105 The mold used in an injection molding process consists of a top half and a bottom half. Each half is \(60 \mathrm{~mm} \times 60 \mathrm{~mm} \times 20 \mathrm{~mm}\) and is constructed of metal \(\left(\rho=7800 \mathrm{~kg} / \mathrm{m}^{3}, \quad c=450 \mathrm{~J} / \mathrm{kg}+\mathrm{K}\right)\). The cold mold \(\left(100^{\circ} \mathrm{C}\right)\) is to be heated to \(200^{\circ} \mathrm{C}\) with pressurized water (available at \(275^{\circ} \mathrm{C}\) and a total flow rate of \(0.02 \mathrm{~kg} / \mathrm{s}\) ) prior to injecting the thermoplastic material. The injection takes only a fraction of a second, and the hot mold \(\left(200^{\circ} \mathrm{C}\right)\) is subsequently cooled with cold water (available at \(25^{\circ} \mathrm{C}\) and a total flow rate of \(0.02 \mathrm{~kg} / \mathrm{s})\) prior to ejecting the molded part. After part ejection, which also takes a fraction of a second, the process is repeated. (a) In conventional mold design, straight cooling (heating) passages are bored through the mold in a location where the passages will not interfere with the molded part. Determine the initial heating rate and the initial cooling rate of the mold when five 5 -mm-diameter, 60-mm-long passages are bored in each half of the mold (10 passages total). The velocity distribution of the water is fully developed at the entrance of each passage in the hot (or cold) mold. (b) New additive manufacturing processes, known as selective freeform fabrication, or \(S F F\), are used to construct molds that are configured with conformal cooling passages. Consider the same mold as before, but now a 5 -mm- diameter, coiled, conformal cooling passage is designed within each half of the SFF-manufactured mold. Each of the two coiled passages has \(N=2\) turns. The coiled passage does not interfere with the molded part. The conformal channels have a coil diameter \(C=50 \mathrm{~mm}\). The total water flow remains the same as in part (a) \((0.01 \mathrm{~kg} / \mathrm{s}\) per coil). Determine the initial heating rate and the initial cooling rate of the mold. (c) Compare the surface areas of the conventional and conformal cooling passages. Compare the rate at which the mold temperature changes for molds configured with the conventional and conformal heating and cooling passages. Which cooling passage, conventional or conformal, will enable production of more parts per day? Neglect the presence of the thermoplastic material.

Cooling water flows through the \(25.4-\mathrm{mm}\)-diameter thin-walled tubes of a steam condenser at \(1 \mathrm{~m} / \mathrm{s}\), and a surface temperature of \(350 \mathrm{~K}\) is maintained by the condensing steam. The water inlet temperature is \(290 \mathrm{~K}\), and the tubes are \(5 \mathrm{~m}\) long. (a) What is the water outlet temperature? Evaluate water properties at an assumed average mean temperature, \(\bar{T}_{\mathrm{m}}=300 \mathrm{~K}\). (b) Was the assumed value for \(\bar{T}_{m}\) reasonable? If not, repeat the calculation using properties evaluated at a more appropriate temperature. (c) A range of tube lengths from 4 to \(7 \mathrm{~m}\) is available to the engineer designing this condenser. Generate a plot to show what coolant mean velocities are possible if the water outlet temperature is to remain at the value found for part (b). All other conditions remain the same.

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