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Fully developed conditions are known to exist for water flowing through a \(25-\mathrm{mm}\)-diameter tube at \(0.01 \mathrm{~kg} / \mathrm{s}\) and \(27^{\circ} \mathrm{C}\). What is the maximum velocity of the water in the tube? What is the pressure gradient associated with the flow?

Short Answer

Expert verified
The maximum velocity of the water in the tube is \(0.0205 \text{ m/s}\) and the pressure gradient associated with the flow is \(-4700.41 \text{ Pa/m}\).

Step by step solution

01

Determine flow rate and cross-sectional area

Given: - Diameter of the tube (D) = 25 mm = 0.025 m - Mass flow rate of water (m_dot) = 0.01 kg/s - Temperature of water (T) = 27掳C First, we will find the volume flow rate (Q) by dividing the mass flow rate (m_dot) by the density of the water (蟻). At 27掳C, the density of water is approximately 996 kg/m鲁. $$Q = \frac{m_dot}{蟻} = \frac{0.01 \text{ kg/s}}{996 \text{ kg/m鲁}} = 1.004 \times 10^{-5} \text{ m鲁/s}$$ Next, we will calculate the cross-sectional area (A) of the tube by using the formula for the area of a circle: $$A = \pi \left(\frac{D}{2}\right)^2 = \pi \left(\frac{0.025 \text{ m}}{2}\right)^2 = 4.9087 \times 10^{-4} \text{ m虏}$$
02

Calculate maximum velocity (V_max)

Now we can find the maximum velocity (V_max) by dividing the flow rate (Q) by the cross-sectional area (A): $$V_{max} = \frac{Q}{A} = \frac{1.004 \times 10^{-5} \text{ m鲁/s}}{4.9087 \times 10^{-4} \text{ m虏}} = 0.0205 \text{ m/s}$$ The maximum velocity of the water in the tube is 0.0205 m/s.
03

Determine pressure gradient

To calculate the pressure gradient, we will use the Hagen-Poiseuille equation, which relates the pressure drop to the flow rate in a pipe: $$\Delta P = \frac{128 \mu Q L}{\pi D^4}$$ where: - 螖P is the pressure drop - 渭 is the dynamic viscosity of the fluid (can be approximated as 0.000797 kg/m路s for water at 27掳C) - L is the length of the pipe (unknown) We are interested in finding the pressure gradient, which is the pressure drop per unit length (鈭侾/鈭侺). To do this, we will divide both sides of the Hagen-Poiseuille equation by the length L: $$\frac{\Delta P}{L} = \frac{128 \mu Q}{\pi D^4}$$ Now plug in the values we have calculated and the dynamic viscosity of water: $$\frac{\partial P}{\partial L} = \frac{128 \times 0.000797 \text{ kg/m路s} \times 1.004 \times 10^{-5} \text{ m鲁/s}}{\pi \times (0.025 \text{ m})^4} = -4700.41 \text{ Pa/m}$$ The pressure gradient associated with the flow of water through the tube is -4700.41 Pa/m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fully Developed Flow
Understanding fluid flow within pipes is crucial for various engineering applications. One essential concept in this field is 'fully developed flow.' A fully developed flow refers to a condition in fluid dynamics where the velocity profile of the fluid does not change in the direction of flow. This phenomenon occurs after fluid has entered a pipe and traveled some distance, allowing it to settle into a steady state of motion.

Characteristics of fully developed flow include a constant velocity across any cross-section of the pipe and zero acceleration of fluid particles in the streamwise direction. It's important to note that, for a fully developed flow, the effect of the pipe entrance has diminished, and the effects of viscosity are fully realized, resulting in a predictable and steady velocity profile. In practical terms, the fully developed flow assumption simplifies calculations and provides more accurate modeling for engineers and physicists when designing pipe systems.
Hagen-Poiseuille Equation
The Hagen-Poiseuille equation plays a pivotal role in fluid dynamics, particularly in the analysis of laminar flow through circular pipes. Expressing the volumetric flow rate as a function of pipe characteristics and fluid properties, it provides insights into the relationship between the pressure difference across the length of the pipe and the ensuing flow.

The equation is mathematically given by: \[ Q = \frac{\pi \Delta P R^4}{8 \mu L} \]where \( Q \) is the volumetric flow rate, \( \Delta P \) is the pressure difference between the two ends of the pipe, \( R \) is the radius of the pipe, \( \mu \) is the dynamic viscosity of the fluid, and \( L \) is the length of the pipe over which the pressure difference is measured. This equation assumes a laminar, incompressible, and steady flow with no slip at the pipe wall. It is critical for predicting flow rates and understanding the effects of changing conditions within the pipes.
Pressure Gradient
In fluid dynamics, the pressure gradient is a significant factor, referring to the rate at which the pressure changes with respect to distance in a particular direction, often indicated by \( \frac{\partial P}{\partial x} \). It's a vector quantity, providing both the magnitude and the direction of the pressure change.

The importance of the pressure gradient cannot be understated as it plays a crucial role in driving the flow of fluids in pipes, ducts, or open channels. Fluids tend to flow from regions of high pressure to low pressure, and it's this gradient that facilitates the movement. For laminar flow in pipes, the pressure gradient can be both negative and positive, indicating flow in different directions. Calculation of the pressure gradient is essential for determining the energy required for fluid transport and the design of efficient fluid delivery systems.
Maximum Velocity
In the context of fluid flow inside a pipe, 'maximum velocity' is a term that refers to the highest speed attained by the fluid along the axis of the pipe. This is typically found at the centerline of a pipe in laminar flow conditions, where due to the no-slip condition at the walls, the velocity of the fluid gradually decreases from the maximum at the center to zero at the pipe boundary.

The concept of maximum velocity is integral to the application of the Hagen-Poiseuille equation, which we use to predict the flow characteristics of fluids in pipes. Knowing the maximum velocity of a fluid helps in numerous practical situations, such as ensuring that fluid being pumped through a system meets the necessary operational criteria and assessing the potential for erosion or wear within piping over time.

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Most popular questions from this chapter

At a particular axial station, velocity and temperature profiles for laminar flow in a parallel plate channel have the form $$ \begin{aligned} &u(y)=0.75\left[1-\left(y / y_{o}\right)^{2}\right] \\ &T(y)=5.0+95.66\left(y / y_{o}\right)^{2}-47.83\left(y / y_{o}\right)^{4} \end{aligned} $$ with units of \(\mathrm{m} / \mathrm{s}\) and \({ }^{\circ} \mathrm{C}\), respectively. Determine corresponding values of the mean velocity, \(u_{m}\), and mean (or bulk) temperature, \(T_{m}\). Plot the velocity and temperature distributions. Do your values of \(u_{m}\) and \(T_{m}\) appear reasonable?

A hot fluid passes through a thin-walled tube of \(10-\mathrm{mm}\) diameter and 1-m length, and a coolant at \(T_{\infty}=25^{\circ} \mathrm{C}\) is in cross flow over the tube. When the flow rate is \(\dot{m}=18 \mathrm{~kg} / \mathrm{h}\) and the inlet temperature is \(T_{m, i}=85^{\circ} \mathrm{C}\), the outlet temperature is \(T_{m \rho}=78^{\circ} \mathrm{C}\). Assuming fully developed flow and thermal conditions in the tube, determine the outlet temperature, \(T_{m, a}\) if the flow rate is increased by a factor of 2 . That is, \(\dot{m}=36 \mathrm{~kg} / \mathrm{h}\), with all other conditions the same. The thermophysical properties of the hot fluid are \(\rho=\) \(1079 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=2637 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=0.0034 \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}\), and \(k=0.261 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\).

A thin-walled tube with a diameter of \(6 \mathrm{~mm}\) and length of \(20 \mathrm{~m}\) is used to carry exhaust gas from a smoke stack to the laboratory in a nearby building for analysis. The gas enters the tube at \(200^{\circ} \mathrm{C}\) and with a mass flow rate of \(0.003 \mathrm{~kg} / \mathrm{s}\). Autumn winds at a temperature of \(15^{\circ} \mathrm{C}\) blow directly across the tube at a velocity of \(5 \mathrm{~m} / \mathrm{s}\). Assume the thermophysical properties of the exhaust gas are those of air. (a) Estimate the average heat transfer coefficient for the exhaust gas flowing inside the tube. (b) Estimate the heat transfer coefficient for the air flowing across the outside of the tube. (c) Estimate the overall heat transfer coefficient \(U\) and the temperature of the exhaust gas when it reaches the laboratory.

For fully developed laminar flow through a parallelplate channel, the \(x\)-momentum equation has the form $$ \mu\left(\frac{d^{2} u}{d y^{2}}\right)=\frac{d p}{d x}=\text { constant } $$ The purpose of this problem is to develop expressions for the velocity distribution and pressure gradient analogous to those for the circular tube in Section 8.1. (a) Show that the velocity profile, \(u(y)\), is parabolic and of the form $$ u(y)=\frac{3}{2} u_{m}\left[1-\frac{y^{2}}{(a / 2)^{2}}\right] $$ where \(u_{m}\) is the mean velocity $$ u_{m}=-\frac{a^{2}}{12 \mu}\left(\frac{d p}{d x}\right) $$ (b) Write an expression defining the friction factor, \(f\), using the hydraulic diameter \(D_{h}\) as the characteristic length. What is the hydraulic diameter for the parallel-plate channel? (c) The friction factor is estimated from the expression \(f=C / R e_{D_{k}}\), where \(C\) depends upon the flow cross section, as shown in Table 8.1. What is the coefficient \(C\) for the parallel-plate channel? (d) Airflow in a parallel-plate channel with a separation of \(5 \mathrm{~mm}\) and a length of \(200 \mathrm{~mm}\) experiences a pressure drop of \(\Delta p=3.75 \mathrm{~N} / \mathrm{m}^{2}\). Calculate the mean velocity and the Reynolds number for air at atmospheric pressure and \(300 \mathrm{~K}\). Is the assumption of fully developed flow reasonable for this application? If not, what is the effect on the estimate for \(u_{m}\) ?

8.106 Consider the pharmaceutical product of Problem 8.27. Prior to finalizing the manufacturing process, test trials are performed to experimentally determine the dependence of the shelf life of the drug as a function of the sterilization temperature. Hence, the sterilization temperature must be carefully controlled in the trials. To promote good mixing of the pharmaceutical and, in turn, relatively uniform outlet temperatures across the exit tube area, experiments are performed using a device that is constructed of two interwoven coiled tubes, each of 10 -mm diameter. The thin-walled tubing is welded to a solid high thermal conductivity rod of diameter \(D_{r}=40 \mathrm{~mm}\). One tube carries the pharmaceutical product at a mean velocity of \(u_{p}=0.1 \mathrm{~m} / \mathrm{s}\) and inlet temperature of \(25^{\circ} \mathrm{C}\), while the second tube carries pressurized liquid water at \(u_{w}=0.12 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(127^{\circ} \mathrm{C}\). The tubes do not contact each other but are each welded to the solid metal rod, with each tube making 20 turns around the rod. The exterior of the apparatus is well insulated. (a) Determine the outlet temperature of the pharmaceutical product. Evaluate the liquid water properties at \(380 \mathrm{~K}\). (b) Investigate the sensitivity of the pharmaceutical's outlet temperature to the velocity of the pressurized water over the range \(0.10

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