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An array of 10 silicon chips, each of length \(L=10 \mathrm{~mm}\) on a side, is insulated on one surface and cooled on the opposite surface by atmospheric air in parallel flow with \(T_{\infty}=24^{\circ} \mathrm{C}\) and \(u_{\infty}=40 \mathrm{~m} / \mathrm{s}\). When in use, the same electrical power is dissipated in each chip, maintaining a uniform heat flux over the entire cooled surface. If the temperature of each chip may not exceed \(80^{\circ} \mathrm{C}\), what is the maximum allowable power per chip? What is the maximum allowable power if a turbulence promoter is used to trip the boundary layer at the leading edge? Would it be preferable to orient the array normal, instead of parallel, to the airflow?

Short Answer

Expert verified
The maximum allowable power per silicon chip with laminar flow is approximately \(0.301 \mathrm{W}\). If a turbulence promoter is used, the maximum allowable power increases to \(0.819 \mathrm{W}\). As for the orientation, changing it to normal to the airflow may increase the convection rate but also add flow disturbances. Deciding whether this option is preferable requires a more in-depth analysis weighing the trade-offs between convection rates and flow disturbances.

Step by step solution

01

Find properties of air

First, we need to find the properties of air at the mean temperature, which is the average of the chip's surface temperature and the free stream air temperature. For this exercise, we will consider air properties at \(\left(24+80\right)/2 = 52^{\circ}\mathrm{C}\) or \(325\mathrm{K}\). Using air property tables at the given temperature and around atmospheric pressure, we get: - Dynamic Viscosity \(\mu = 2.0 \times 10^{-5} \mathrm{~kg/m.s}\) - Thermal Conductivity, \(k = 0.029 \mathrm{~W/m.K}\) - Specific Heat, \(c_p = 1005 \mathrm{~J/kg.K}\) - Density, \(\rho = 1.10 \mathrm{~kg/m^3}\)
02

Calculate the Reynolds number

The Reynolds number (\(\mathrm{Re}\)) for airflow over the chip is: \(\mathrm{Re} = \frac{\rho u_{\infty} L}{\mu}\) Plugging in the known values, we get: \(\mathrm{Re} = \frac{1.10\times 40 \times 0.01}{2.0\times 10^{-5}} = 2.2 \times 10^5\)
03

Calculate the Nusselt number for laminar flow

Since the Reynolds number is greater than \(5\times 10^4\), the flow is turbulent. However, we will first calculate the Nusselt number for laminar flow as follows: \(Nu = 0.664 \times \mathrm{Re}^{0.5} \times Pr^{1/3}\) In case of air, the Prandtl number (\(Pr\)) is close to \(0.71\). Thus, we get: \(Nu = 0.664 \times \sqrt{2.2 \times 10^5} \times {0.71}^{1/3} \approx 184.6\)
04

Calculate the heat transfer coefficient for laminar flow

The heat transfer coefficient (\(h\)) can be found using the Nusselt number and thermal conductivity: \(h = \frac{k \times Nu}{L}\) Plugging in the values, we get: \(h = \frac{0.029 \times 184.6}{0.01} = 537.34 \mathrm{~W/m^2.K}\)
05

Calculate the maximum allowable power for laminar flow

The maximum allowable power can be found using the following formula: \(P = h \times A \times (T_{s} - T_{\infty})\) Here, \(A = L^2\) is the area of one chip. Rearranging the formula, we get: \(P = \frac{h \times L^2}{1} \times (80 - 24)\) Plugging in the values, we get: \(P = 537.34 \times 0.01^2 \times (56) \approx 0.301 \mathrm{W}\)
06

Check the maximum allowable power with turbulence promoter

If a turbulence promoter is used, the Nusselt number for turbulent flow needs to be considered. The Nusselt number formula for turbulent flow is: \(Nu = 0.037 \times \mathrm{Re}^{0.8} \times Pr^{1/3}\) Replacing the values, we get: \(Nu = 0.037 \times (2.2 \times 10^5)^{0.8} \times 0.71^{1/3} \approx 501.0\) Now calculate the heat transfer coefficient for turbulent flow: \(h = \frac{0.029 \times 501.0}{0.01} = 1452.9 \mathrm{~W/m^2.K}\) Finally, we calculate the maximum allowable power for turbulent flow: \(P = \frac{1452.9 \times 0.01^2}{1} \times (80 - 24) \approx 0.819 \mathrm{W}\) Thus, the maximum power per chip is \(0.819 \mathrm{W}\) if a turbulence promoter is used.
07

Discussion on the array orientation

Changing the orientation of the chips so that they are normal to the airflow would increase the exposed surface area and potentially lowering the temperature since a higher convection rate occurs. However, placing the chips normal to the airflow would create flow disturbance and increase the resistance to the flow, reducing the efficiency of the case. Determining if this arrangement is preferable would require a more in-depth analysis considering the trade-offs between higher convection rates and flow disturbances.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds number
The Reynolds number (\( \mathrm{Re} \)) is key in determining the flow characteristics of a fluid. It is defined as the ratio between the inertial forces and the viscous forces within a fluid flow. It's important because it helps predict whether the flow will be laminar or turbulent.
  • A higher Reynolds number indicates that inertial forces dominate, which is usually associated with turbulent flow.
  • A lower Reynolds number suggests that viscous forces dominate, indicating a laminar flow.
The formula to calculate the Reynolds number in a flow situation, such as airflow over a chip, is given by:\[\mathrm{Re} = \frac{\rho u_{\infty} L}{\mu}\]Where:
  • \( \rho \) is the fluid density.
  • \( u_{\infty} \) is the velocity of the fluid.
  • \( L \) is the characteristic length, often the length of the object the fluid flows over.
  • \( \mu \) is the dynamic viscosity of the fluid.
For our exercise, the calculation confirmed a Reynolds number of \( 2.2 \times 10^5 \), indicating a turbulent flow. Understanding the Reynolds number is crucial for assessing flow behaviors such as the transition from laminar to turbulent flow.
Nusselt number
The Nusselt number (\( Nu \)) is an essential dimensionless number in heat transfer. It correlates the convective heat transfer to the conductive heat transfer across a boundary. Essentially, it helps determine the efficiency of heat transfer in a fluid flow over a surface.
  • A higher Nusselt number suggests more efficient convective heat transfer, which is desirable in cooling applications.
  • For laminar flow, the Nusselt number is typically calculated with empirical correlations like \( Nu = 0.664 \times \mathrm{Re}^{0.5} \times Pr^{1/3} \)
  • For turbulent flow, a different correlation is used, such as \( Nu = 0.037 \times \mathrm{Re}^{0.8} \times Pr^{1/3} \)
The Nusselt number allows the determination of the heat transfer coefficient (\( h \)) using the formula:\[h = \frac{k \times Nu}{L}\]where \( k \)is the thermal conductivity of the fluid. In our example, the Nusselt number for laminar flow was found to be approximately 184.6, but with turbulent flow, it increased to approximately 501.0, indicating a substantial improvement in heat transfer.
Turbulent flow
Turbulent flow refers to a type of fluid flow characterized by chaotic and irregular fluctuations. Unlike laminar flow, turbulent flow does not follow a streamlined path and is more complex and less predictable.
  • This flow type occurs when the Reynolds number exceeds a critical threshold, typically around \( 5 \times 10^4 \).
  • In turbulent flow, eddies, vortices, and rapid changes in pressure and flow velocity dominate.
In the context of the problem, when the inflow surpassed \( \mathrm{Re} = 2.2 \times 10^5 \), turbulent flow was determined. This increased the heat transfer coefficient significantly. Using a turbulence promoter can trigger turbulent flow at lower Reynolds numbers or earlier in the flow over a surface. This property was leveraged to achieve a more substantial cooling effect on the chips by raising the Nusselt number, hence enhancing the power dissipation capability of each chip.
Laminar flow
Laminar flow is often described as smooth, streamlined, or regular flow. In laminar flow, fluid particles move in parallel layers and there is minimal mixing between them. It occurs at lower Reynolds numbers, typically less than \( 2 \times 10^3 \).
  • Laminar flow is more stable and predictable than turbulent flow.
  • It has lower momentum transfer across layers compared to turbulent flow, which results in lower heat transfer efficiency.
In our specific setting, we initially calculated parameters as if the flow might be laminar, even though the problem context indicated turbulent flow. Despite the smooth nature of laminar flow, in many engineering applications, especially cooling or heating, turbulent flow is preferred due to its higher heat transfer capabilities. However, laminar flow can be advantageous in situations where low friction and high accuracy are necessary.

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Most popular questions from this chapter

A long, cylindrical, electrical heating element of diameter \(D=10 \mathrm{~mm}\), thermal conductivity \(k=240 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), density \(\rho=2700 \mathrm{~kg} / \mathrm{m}^{3}\), and specific heat \(c_{p}=900 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) is installed in a duct for which air moves in cross flow over the heater at a temperature and velocity of \(27^{\circ} \mathrm{C}\) and \(10 \mathrm{~m} / \mathrm{s}\), respectively. (a) Neglecting radiation, estimate the steady-state surface temperature when, per unit length of the heater, electrical energy is being dissipated at a rate of \(1000 \mathrm{~W} / \mathrm{m}\). (b) If the heater is activated from an initial temperature of \(27^{\circ} \mathrm{C}\), estimate the time required for the surface temperature to come within \(10^{\circ} \mathrm{C}\) of its steady-state value.

An uninsulated steam pipe is used to transport hightemperature steam from one building to another. The pipe is of \(0.5-\mathrm{m}\) diameter, has a surface temperature of \(150^{\circ} \mathrm{C}\), and is exposed to ambient air at \(-10^{\circ} \mathrm{C}\). The air moves in cross flow over the pipe with a velocity of \(5 \mathrm{~m} / \mathrm{s}\). (a) What is the heat loss per unit length of pipe? (b) Consider the effect of insulating the pipe with a rigid urethane foam \((k=0.026 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\). Evaluate and plot the heat loss as a function of the thickness \(\delta\) of the insulation layer for \(0 \leq \delta \leq 50 \mathrm{~mm}\).

Consider laminar, parallel flow past an isothermal flat plate of length \(L\), providing an average heat transfer coefficient of \(\bar{h}_{L^{-}}\)If the plate is divided into \(N\) smaller plates, each of length \(L_{N}=L / N\), determine an expression for the ratio of the heat transfer coefficient averaged over the \(N\) plates to the heat transfer coefficient averaged over the single plate, \(\bar{h}_{L, N} / \bar{h}_{L, 1}\).

Consider the following fluids, each with a velocity of \(V=5 \mathrm{~m} / \mathrm{s}\) and a temperature of \(T_{\infty}=20^{\circ} \mathrm{C}\), in cross flow over a 10-mm-diameter cylinder maintained at \(50^{\circ} \mathrm{C}\) : atmospheric air, saturated water, and engine oil. (a) Calculate the rate of heat transfer per unit length, \(q^{\prime}\), using the Churchill-Bernstein correlation. (b) Generate a plot of \(q^{\prime}\) as a function of fluid velocity for \(0.5 \leq V \leq 10 \mathrm{~m} / \mathrm{s}\).

Air at \(27^{\circ} \mathrm{C}\) with a free stream velocity of \(10 \mathrm{~m} / \mathrm{s}\) is used to cool electronic devices mounted on a printed circuit board. Each device, \(4 \mathrm{~mm} \times 4 \mathrm{~mm}\), dissipates \(40 \mathrm{~mW}\), which is removed from the top surface. A turbulator is located at the leading edge of the board, causing the boundary layer to be turbulent. (a) Estimate the surface temperature of the fourth device located \(15 \mathrm{~mm}\) from the leading edge of the board. (b) Generate a plot of the surface temperature of the first four devices as a function of the free stream velocity for \(5 \leq u_{s} \leq 15 \mathrm{~m} / \mathrm{s}\). (c) What is the minimum free stream velocity if the surface temperature of the hottest device is not to exceed \(80^{\circ} \mathrm{C}\) ?

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