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Consider atmospheric air at \(25^{\circ} \mathrm{C}\) and a velocity of \(25 \mathrm{~m} / \mathrm{s}\) flowing over both surfaces of a 1 - \(\mathrm{m}\)-long flat plate that is maintained at \(125^{\circ} \mathrm{C}\). Determine the rate of heat transfer per unit width from the plate for values of the critical Reynolds number corresponding to \(10^{5}\), \(5 \times 10^{5}\), and \(10^{6}\).

Short Answer

Expert verified
The rate of heat transfer per unit width for each of the critical Reynolds numbers is: Case 1 (Re_c = \( 10^{5} \)): q'1 = 680.4 W/m Case 2 (Re_c = \( 5 \times 10^{5} \)): q'2 = 1364.5 W/m Case 3 (Re_c = \( 10^{6} \)): q'3 = 1922.0 W/m

Step by step solution

01

Calculate the Reynolds number

To calculate the Reynolds number, we need the following formula: Re_L = \( \frac{\rho V L}{\mu} \) where Re_L is the Reynolds number, 蟻 is the density of the fluid (air), V is the velocity, L is the length of the plate, and 渭 is the dynamic viscosity of the fluid. We are given the values of V and L. We need to find the values of 蟻 and 渭 for the air at given temperature (25掳C). These values can be found in a thermodynamic properties table or an online calculator. For air at 25掳C: 蟻 = 1.184 kg/m鲁 渭 = 1.85 脳 10鈦烩伒 kg/m路s Now we can calculate the Reynolds number: Re_L = \( \frac{(1.184 kg/m鲁)(25 m/s)(1 m)}{1.85 脳 10鈦烩伒 kg/m路s} \) Re_L = 1.6 脳 10鈦
02

Determine the flow regime and Nusselt number relation

The critical Reynolds number values are given as 10鈦, 5 脳 10鈦, and 10鈦. Since the calculated Reynolds number (1.6 脳 10鈦) is higher than all three critical Reynolds numbers, the flow is turbulent for all cases. In turbulent flow over a flat plate, the Nusselt number is related to the Reynolds number and the Prandtl number (Pr) by the following correlation: Nu_L = 0.0296 脳 Re_L^(4/5) 脳 Pr^(1/3) We will need the Prandtl number for air at 25掳C, which can also be found in a thermodynamic properties table or an online calculator: Pr = 0.707.
03

Calculate the heat transfer coefficients for each critical Reynolds number

We will now calculate the heat transfer coefficient (h) for each of the critical Reynolds numbers using the Nusselt number correlation. First, we calculate the Nusselt numbers for each case: Case 1: Re_c = 10鈦 Nu_L1 = 0.0296 脳 (10鈦)^(4/5) 脳 (0.707)^(1/3) Nu_L1 = 259.4 Case 2: Re_c = 5 脳 10鈦 Nu_L2 = 0.0296 脳 (5 脳 10鈦)^(4/5) 脳 (0.707)^(1/3) Nu_L2 = 520.0 Case 3: Re_c = 10鈦 Nu_L3 = 0.0296 脳 (10鈦)^(4/5) 脳 (0.707)^(1/3) Nu_L3 = 732.8 Next, we calculate the heat transfer coefficients (h) using the formula: h = \( \frac{k}{L} \) 脳 Nu_L where k is the thermal conductivity of the fluid (air). For air at 25掳C, k = 0.02624 W/m路K. h1 = \( \frac{0.02624 W/m路K}{1 m} \) 脳 259.4 = 6.804 W/m虏路K h2 = \( \frac{0.02624 W/m路K}{1 m} \) 脳 520.0 = 13.645 W/m虏路K h3 = \( \frac{0.02624 W/m路K}{1 m} \) 脳 732.8 = 19.220 W/m虏路K
04

Calculate the rate of heat transfer per unit width for each case

Now, we can calculate the rate of heat transfer per unit width (q') for each case using the formula: q' = h 脳 螖T 脳 W where 螖T is the temperature difference between the plate and the air, and W is the width of the plate (in our case, per unit width, so W = 1m). For all cases, 螖T = 125掳C - 25掳C = 100掳C or 100 K. q'1 = (6.804 W/m虏路K)(100 K)(1 m) = 680.4 W/m q'2 = (13.645 W/m虏路K)(100 K)(1 m) = 1364.5 W/m q'3 = (19.220 W/m虏路K)(100 K)(1 m) = 1922.0 W/m The rate of heat transfer per unit width for each of the critical Reynolds numbers is: Case 1 (Re_c = 10鈦): q'1 = 680.4 W/m Case 2 (Re_c = 5 脳 10鈦): q'2 = 1364.5 W/m Case 3 (Re_c = 10鈦): q'3 = 1922.0 W/m

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number Calculation
Understanding the concept of the Reynolds number is essential when studying heat transfer over a flat plate. It's a dimensionless quantity used in fluid mechanics to predict the flow regime 鈥 whether it will be laminar or turbulent. When flowing over objects such as a flat plate, the Reynolds number helps in characterizing the nature of the flow.

To calculate the Reynolds number, \( Re_L \), the formula \( Re_L = \frac{\rho V L}{\mu} \) is used, where \( \rho \) is the fluid density, \( V \) is the fluid velocity, \( L \) is the characteristic length (in this case, the length of the plate), and \( \mu \) is the fluid's dynamic viscosity. For atmospheric air at \(25^\circ \mathrm{C}\), the density and dynamic viscosity can be found from standard thermodynamic tables. Applying these values to the formula gives the Reynolds number, which then determines the flow regime. If the value of \( Re_L \) is higher than a critical value, typically ranging around \(10^5\) to \(10^6\), the flow is considered turbulent.
Nusselt Number Relation
The Nusselt number, \( Nu \), is another dimensionless number used in heat transfer to describe the ratio of convective to conductive heat transfer across a boundary. In the context of a flat plate, it provides a measure of the thermal conductivity of the boundary layer that forms as air flows over the plate. The Nusselt number is particularly helpful as it relates to the heat transfer coefficient, \( h \).

For turbulent flow over a flat plate, the Nusselt number can be calculated using the empirical correlation: \( Nu_L = 0.0296 \times Re_L^{4/5} \times Pr^{1/3} \), where \( Pr \) is the Prandtl number, which depends on the fluid properties at the given temperature. The Prandtl number is the ratio of momentum diffusivity to thermal diffusivity and for air at \(25^\circ \mathrm{C}\) is typically around 0.707. With the Reynolds number already calculated, the Nusselt number can be determined, which will then be used to find the heat transfer coefficient.
Heat Transfer Coefficient
The heat transfer coefficient, \( h \), is a crucial parameter in the study of convective heat transfer. It quantifies the heat transfer rate per unit area and per degree temperature difference between the surface and the fluid. Once the Nusselt number is known, \( h \) can be found by the relation \( h = \frac{k}{L} \times Nu_L \), where \( k \) is the thermal conductivity of the air and \( L \) is the length of the plate, mentioned in the Nusselt number relation.

For each critical Reynolds number, the heat transfer coefficient is calculated individually as it determines how efficiently heat is transferred for various flow conditions. Understanding \( h \) allows designers to predict how quickly a plate will cool or heat in a specific fluid flow scenario, directly impacting thermal management and system performance.
Rate of Heat Transfer
The rate of heat transfer, commonly denoted as \( q' \) when referring to per unit width, signifies the amount of heat energy transferred per unit time. It is critical in applications ranging from aerospace to industrial processes where temperature control is vital. In our exercise, \( q' \) can be found using the formula \( q' = h \times \Delta T \times W \), where \( \Delta T \) is the difference in temperature between the hot plate and the cooler air, and \( W \) is the width of the plate.

This calculation is significant for engineers to ensure that the plate dissipates heat at the right rate, avoiding overheating or insufficient cooling. Knowing the rate of heat transfer aids in the design and analysis of cooling systems, heating units, and can even influence the choice of materials used based on their thermal properties.

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Most popular questions from this chapter

Consider an air-conditioning system composed of a bank of tubes arranged normal to air flowing in a duct at a mass rate of \(\dot{m}_{a}(\mathrm{~kg} / \mathrm{s})\). A coolant flowing through the tubes is able to maintain the surface temperature of the tubes at a constant value of \(T_{s}

Evaporation of liquid fuel droplets is often studied in the laboratory by using a porous sphere technique in which the fuel is supplied at a rate just sufficient to maintain a completely wetted surface on the sphere. Consider the use of kerosene at \(300 \mathrm{~K}\) with a porous sphere of 1 -mm diameter. At this temperature the kerosene has a saturated vapor density of \(0.015 \mathrm{~kg} / \mathrm{m}^{3}\) and a latent heat of vaporization of \(300 \mathrm{~kJ} / \mathrm{kg}\). The mass diffusivity for the vapor-air mixture is \(10^{-5} \mathrm{~m}^{2} / \mathrm{s}\). If dry, atmospheric air at \(V=15 \mathrm{~m} / \mathrm{s}\) and \(T_{\infty}=300 \mathrm{~K}\) flows over the sphere, what is the minimum mass rate at which kerosene must be supplied to maintain a wetted surface? For this condition, by how much must \(T_{\infty}\) actually exceed \(T_{s}\) to maintain the wetted surface at \(300 \mathrm{~K}\) ?

An air-cooled steam condenser is operated with air in cross flow over a square, in-line array of 400 tubes \(\left(N_{L}=N_{T}=20\right.\) ), with an outside tube diameter of \(20 \mathrm{~mm}\) and longitudinal and transverse pitches of \(S_{L}=60 \mathrm{~mm}\) and \(S_{T}=30 \mathrm{~mm}\), respectively. Saturated steam at a pressure of \(2.455\) bars enters the tubes, and a uniform tube outer surface temperature of \(T_{s}=390 \mathrm{~K}\) may be assumed to be maintained as condensation occurs within the tubes. (a) If the temperature and velocity of the air upstream of the array are \(T_{i}=300 \mathrm{~K}\) and \(V=4 \mathrm{~m} / \mathrm{s}\), what is the temperature \(T_{o}\) of the air that leaves the array? As a first approximation, evaluate the properties of air at \(300 \mathrm{~K}\). (b) If the tubes are \(2 \mathrm{~m}\) long, what is the total heat transfer rate for the array? What is the rate at which steam is condensed in \(\mathrm{kg} / \mathrm{s}\) ? (c) Assess the effect of increasing \(N_{L}\) by a factor of 2 , while reducing \(S_{L}\) to \(30 \mathrm{~mm}\). For this configuration, explore the effect of changes in the air velocity.

A flat plate of width \(1 \mathrm{~m}\) is maintained at a uniform surface temperature of \(T_{s}=150^{\circ} \mathrm{C}\) by using independently controlled, heat-generating rectangular modules of thickness \(a=10 \mathrm{~mm}\) and length \(b=50 \mathrm{~mm}\). Each module is insulated from its neighbors, as well as on its back side. Atmospheric air at \(25^{\circ} \mathrm{C}\) flows over the plate at a velocity of \(30 \mathrm{~m} / \mathrm{s}\). The thermophysical properties of the module are \(k=5.2 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, c_{p}=320 \mathrm{~J} / \mathrm{kg}+\mathrm{K}\), and \(\rho=2300 \mathrm{~kg} / \mathrm{m}^{3}\). (a) Find the required power generation, \(\dot{q}\left(\mathrm{~W} / \mathrm{m}^{3}\right)\), in a module positioned at a distance \(700 \mathrm{~mm}\) from the leading edge. (b) Find the maximum temperature \(T_{\max }\) in the heatgenerating module.

Consider steady, parallel flow of atmospheric air over a flat plate. The air has a temperature and free stream velocity of \(300 \mathrm{~K}\) and \(25 \mathrm{~m} / \mathrm{s}\). (a) Evaluate the boundary layer thickness at distances of \(x=1,10\), and \(100 \mathrm{~mm}\) from the leading edge. If a second plate were installed parallel to and at a distance of \(3 \mathrm{~mm}\) from the first plate, what is the distance from the leading edge at which boundary layer merger would occur? (b) Evaluate the surface shear stress and the \(y\)-velocity component at the outer edge of the boundary layer for the single plate at \(x=1,10\), and \(100 \mathrm{~mm}\). (c) Comment on the validity of the boundary layer approximations.

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