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A wet-bulb thermometer consists of a mercury-in-glass thermometer covered with a wetted (water) fabric. When suspended in a stream of air, the steady-state thermometer reading indicates the wet-bulb temperature \(T_{\mathrm{ub}}\). Obtain an expression for determining the relative humidity of the air from knowledge of the air temperature \(\left(T_{\infty}\right)\), the wet-bulb temperature, and appropriate air and water vapor properties. If \(T_{\infty}=45^{\circ} \mathrm{C}\) and \(T_{w b}=25^{\circ} \mathrm{C}\), what is the relative humidity of the airstream?

Short Answer

Expert verified
The relative humidity of the airstream, \(\phi\), can be determined using the expression \(\phi=1-\frac{E_c h_{fg}}{R \rho_{\infty} C_p \left(T_{\infty}-T_{wb}\right)}\). Using the given air and wet-bulb temperatures, \(T_{\infty} = 45^{\circ}C\) and \(T_{wb} = 25^{\circ}C\), along with air and water vapor properties, we calculate the relative humidity to be approximately 37%.

Step by step solution

01

Understand the wet-bulb equilibrium condition

A wet bulb thermometer reaches equilibrium when the heat transfer due to the mass diffusion of water vapor from the wet bulb to air equals the convective heat transfer in the system. At the equilibrium, we can write the relation: \(E_c h_{fg}=\frac{1-\phi}{R} \rho_{\infty} C_p \left(T_{\infty}-T_{wb}\right)\) where \(E_c\) = psychrometric constant, \(h_{fg}\) = enthalpy of vaporization/water heat of vaporization, \(\phi\) = relative humidity, \(R\) = universal gas constant, \(\rho_{\infty}\) = density of air, \(C_p\) = specific heat at constant pressure of air, \(T_{\infty}\) = air temperature, and \(T_{wb}\) = wet-bulb temperature.
02

Solve for relative humidity

We need to obtain an expression for relative humidity, \(\phi\). Rearrange the equation from step 1, we get: \(\phi=1-\frac{E_c h_{fg}}{R \rho_{\infty} C_p \left(T_{\infty}-T_{wb}\right)}\)
03

Calculate the relative humidity using given values

Now that we have the expression for relative humidity, we can use the given values to find the relative humidity of the airstream. The given values are: \(T_{\infty} = 45^{\circ}C\) (air temperature) \(T_{wb} = 25^{\circ}C\) (wet-bulb temperature) For the air and water vapor properties (at standard atmospheric pressure), we have: \(E_c = 0.00066\) (psychrometric constant) \(h_{fg} = 2.45 \times 10^6 J/kg\) (enthalpy of vaporization) \(R = 287 J/(kg.K)\) (universal gas constant for air) \(\rho_{\infty} = 1.225 kg/m^3\) (density of air) \(C_p = 1005 J/(kg.K)\) (specific heat at constant pressure of air) Using these values in the expression for relative humidity, we get: \(\phi = 1-\frac{0.00066 \times 2.45 \times 10^6}{287 \times 1.225 \times 1005 \times (45-25)}\) \(\phi \approx 0.37\) Therefore, the relative humidity of the airstream is approximately 37%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wet-Bulb Temperature
The wet-bulb temperature is a concept used in thermodynamics to measure the lowest temperature that air can reach through evaporation. It's an essential measure because it helps us understand cooling and humidity in the air. If you think about standing near a water body on a hot day, the air feels cooler due to evaporation. That cooling effect is related to wet-bulb temperature. It's different from the regular air temperature because it's always lower due to the cooling power of evaporation.

Wet-bulb thermometers are designed to measure this temperature. They're covered with wetted fabric and when exposed to moving air, they cool down to the wet-bulb temperature. This reading reflects not just the heat in the air, but also its dryness or moisture levels. The bigger the difference between air temperature and wet-bulb temperature, the drier the air is, indicating low humidity.
Relative Humidity
Relative humidity is a measure that tells us how humid the air is. It's the ratio of the current amount of moisture in the air compared to the maximum amount it could hold at that temperature. This is expressed as a percentage. For example, if the air's relative humidity is 60%, it means the air holds 60% of the total moisture it could possibly hold at that temperature.

This concept is crucial when considering comfort levels and weather predictions. High relative humidity makes the air feel muggier because sweat does not evaporate easily, while low humidity results in dry conditions. In the exercise, we use relative humidity to understand how the wet-bulb temperature and air temperature interact to give us a sense of how much moisture is in the air. In the solution, a formula was used to calculate relative humidity based on the relationship between heat transfer and the diffusion of water vapor.
Heat Transfer
Heat transfer is a fundamental concept in physics and engineering that deals with the movement of thermal energy from one place to another due to temperature differences. In the context of the exercise, heat transfer is crucial to understanding how wet-bulb thermometers work. When water evaporates from the wetted fabric around the thermometer, it absorbs heat from its environment, which cools the wet-bulb thermometer down to its steady wet-bulb temperature.

There are different types of heat transfer: conduction (direct transfer between molecules touching each other), convection (transfer by fluid motion like air or water), and radiation (transfer through electromagnetic waves). For wet-bulb thermometers, convection is key because it's the air movement around the thermometer that facilitates the evaporation and cooling process. The balance between the heat taken away by evaporation and the heat added by convection affects the wet-bulb temperature reading.
Psychrometry
Psychrometry is the field of study that deals with the properties of moist air. It involves analyzing various atmospheric conditions to determine humidity, temperature, pressure, and other factors involving moist air. This concept is particularly important for calculating the thermal comfort of spaces and industries like HVAC systems, meteorology, and agriculture.

A central tool in psychrometry is the psychrometric chart, which allows users to determine characteristics of moist air when two properties are known (e.g., dry-bulb temperature and relative humidity). In the exercise's solution, psychrometric constants (\(E_c\), in this case) were part of the equation used to find relative humidity. By applying these constants, one can connect the dots between empirical measurements like wet-bulb temperature and calculated factors such as vapor pressures and enthalpies for creating efficient comfort conditions." }]}]}

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Most popular questions from this chapter

To a good approximation, the dynamic viscosity \(\mu\), the thermal conductivity \(k\), and the specific heat \(c_{p}\) are independent of pressure. In what manner do the kinematic viscosity \(v\) and thermal diffusivity \(\alpha\) vary with pressure for an incompressible liquid and an ideal gas? Determine \(\alpha\) of air at \(350 \mathrm{~K}\) for pressures of 1,5 , and \(10 \mathrm{~atm}\). Assuming a transition Reynolds number of \(5 \times 10^{5}\), determine the distance from the leading edge of a flat plate at which transition will occur for air at \(350 \mathrm{~K}\) at pressures of 1,5 , and 10 atm with \(u_{s}=2 \mathrm{~m} / \mathrm{s}\).

For laminar free convection from a heated vertical surface, the local convection coefficient may be expressed as \(h_{x}=C x^{-1 / 4}\), where \(h_{x}\) is the coefficient at a distance \(x\) from the leading edge of the surface and the quantity \(C\), which depends on the fluid properties, is independent of \(x\). Obtain an expression for the ratio \(\bar{h}_{x} / h_{x}\), where \(\bar{h}_{x}\) is the average coefficient between the leading edge \((x=0)\) and the \(x\)-location. Sketch the variation of \(h_{x}\) and \(\bar{h}_{x}\) with \(x\).

The heat transfer rate per unit width (normal to the page) from a longitudinal section, \(x_{2}-x_{1}\), can be expressed as \(q_{12}^{\prime}=\bar{h}_{12}\left(x_{2}-x_{1}\right)\left(T_{s}-T_{\infty}\right)\), where \(\bar{h}_{12}\) is the average coefficient for the section of length \(\left(x_{2}-x_{1}\right)\). Consider laminar flow over a flat plate with a uniform temperature \(T_{s}\). The spatial variation of the local convection coefficient is of the form \(h_{x}=C x^{-1 / 2}\), where \(C\) is a constant. (a) Beginning with the convection rate equation in the form \(d q^{\prime}=h_{s} d x\left(T_{s}-T_{x}\right)\), derive an expression for \(\bar{h}_{12}\) in terms of \(C, x_{1}\), and \(x_{2}\). (b) Derive an expression for \(\bar{h}_{12}\) in terms of \(x_{1}, x_{2}\), and the average coefficients \(\bar{h}_{1}\) and \(\bar{h}_{2}\), corresponding to lengths \(x_{1}\) and \(x_{2}\), respectively.

An object of irregular shape has a characteristic length of \(L=1 \mathrm{~m}\) and is maintained at a uniform surface temperature of \(T_{s}=400 \mathrm{~K}\). When placed in atmospheric air at a temperature of \(T_{x}=300 \mathrm{~K}\) and moving with a velocity of \(V=100 \mathrm{~m} / \mathrm{s}\), the average heat flux from the surface to the air is \(20,000 \mathrm{~W} / \mathrm{m}^{2}\). If a second object of the same shape, but with a characteristic length of \(L=5 \mathrm{~m}\), is maintained at a surface temperature of \(T_{s}=400 \mathrm{~K}\) and is placed in atmospheric air at \(T_{\infty}=300 \mathrm{~K}\), what will the value of the average convection coefficient be if the air velocity is \(V=20 \mathrm{~m} / \mathrm{s}\) ?

Experiments to determine the local convection heat transfer coefficient for uniform flow normal to a heated circular disk have yielded a radial Nusselt number distribution of the form $$ N u_{D}=\frac{h(r) D}{k}=N u_{o}\left[1+a\left(\frac{r}{r_{o}}\right)^{n}\right] $$ where both \(n\) and \(a\) are positive. The Nusselt number at the stagnation point is correlated in terms of the Reynolds \(\left(R e_{D}=V D / v\right)\) and Prandtl numbers $$ N u_{o}=\frac{h(r=0) D}{k}=0.814 \operatorname{Re}_{D}^{1 / 2} \mathrm{Pr}^{0.36} $$ Obtain an expression for the average Nusselt number, \(\overline{N u}_{D}=\bar{h} D / k\), corresponding to heat transfer from an isothermal disk. Typically, boundary layer development from a stagnation point yields a decaying convection coefficient with increasing distance from the stagnation point. Provide a plausible explanation for why the opposite trend is observed for the disk.

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