/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 For each of the following cases,... [FREE SOLUTION] | 91Ó°ÊÓ

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For each of the following cases, determine an appropriate characteristic length \(L_{c}\) and the corresponding Biot number \(B i\) that is associated with the transient thermal response of the solid object. State whether the lumped capacitance approximation is valid. If temperature information is not provided, evaluate properties at \(T=300 \mathrm{~K}\). (a) A toroidal shape of diameter \(D=50 \mathrm{~mm}\) and cross-sectional area \(A_{c}=5 \mathrm{~mm}^{2}\) is of thermal conductivity \(k=2.3 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The surface of the torus is exposed to a coolant corresponding to a convection coefficient of \(h=50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (b) A long, hot AISI 304 stainless steel bar of rectangular cross section has dimensions \(w=3 \mathrm{~mm}\), \(W=5 \mathrm{~mm}\), and \(L=100 \mathrm{~mm}\). The bar is subjected to a coolant that provides a heat transfer coefficient of \(h=15 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) at all exposed surfaces. (c) A long extruded aluminum (Alloy 2024) tube of inner and outer dimensions \(w=20 \mathrm{~mm}\) and \(W=24 \mathrm{~mm}\), respectively, is suddenly submerged in water, resulting in a convection coefficient of \(h=37 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) at the four exterior tube surfaces. The tube is plugged at both ends, trapping stagnant air inside the tube. (d) An \(L=300-m m\)-long solid stainless steel rod of diameter \(D=13 \mathrm{~mm}\) and mass \(M=0.328 \mathrm{~kg}\) is exposed to a convection coefficient of \(h=30 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (e) A solid sphere of diameter \(D=12 \mathrm{~mm}\) and thermal conductivity \(k=120 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is suspended in a large vacuum oven with internal wall temperatures of \(T_{\text {sur }}=20^{\circ} \mathrm{C}\). The initial sphere temperature is \(T_{i}=100^{\circ} \mathrm{C}\), and its emissivity is \(\varepsilon=0.73\). (f) A long cylindrical rod of diameter \(D=20 \mathrm{~mm}\), density \(\rho=2300 \mathrm{~kg} / \mathrm{m}^{3}\), specific heat \(c_{p}=1750 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and thermal conductivity \(k=16 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is suddenly exposed to convective conditions with \(T_{\infty}=20^{\circ} \mathrm{C}\). The rod is initially at a uniform temperature of \(T_{i}=200^{\circ} \mathrm{C}\) and reaches a spatially averaged temperature of \(T=100^{\circ} \mathrm{C}\) at \(t=225 \mathrm{~s}\). (g) Repeat part (f) but now consider a rod diameter of \(D=200 \mathrm{~mm}\).

Short Answer

Expert verified
For each case, the characteristic lengths, the Biot numbers, and the validity of the lumped capacitance approximation are: (a) \( L_{c} = 2.94 \mathrm{~mm} \), \( Bi = 0.064 \), valid. (b) \( L_{c} = 4 \mathrm{~mm} \), \( Bi = 0.026 \), valid. (c) \( L_{c} = 4 \mathrm{~mm} \), \( Bi = 0.123 \), not valid. (d) \( L_{c} = 6.5 \mathrm{~mm} \), \( Bi = 0.034 \), valid. (e) \( L_{c} = 6 \mathrm{~mm} \), \( Bi_{r} = 0.00615 \), valid. (f) \( L_{c} = 10 \mathrm{~mm} \), \( Bi = 0.0468 \), valid. (g) \( L_{c} = 100 \mathrm{~mm} \), \( Bi = 0.468 \), not valid.

Step by step solution

01

Calculate the characteristic length Lc

Since the torus is cylindrical in nature, calculate the characteristic dimension as the volume/(surface area): \[ L_{c} = \frac{\pi r_{d}^{2} - \pi r_{i}^{2}}{2\pi r_{d} + 2\pi r_{i}} = \frac{A_{c}}{\pi (r_{d} + r_{i})} \] Where \( r_{d} \) and \( r_{i} \) are the outer and inner radii of the torus. Given that \( D = 50 \mathrm{~mm} \) and \( A_{c} = 5 \mathrm{~mm}^{2} \), we can find the inner and outer radii and determine Lc.
02

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can input the known values of h and k and the value of Lc calculated in the previous step to find the Biot number.
03

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (b)
04

Calculate the characteristic length Lc

For an object with a rectangular cross section, we can take the average of the two smallest dimensions (w and W) as the characteristic length: \[ L_{c} = \frac{w + W}{2} \]
05

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can substitute the known values of h, k, and Lc to obtain the Biot number.
06

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (c)
07

Calculate the characteristic length Lc

For a hollow cylinder, we can calculate the characteristic length by taking the volume/(surface area) of the hollow region: \[ L_{c} = \frac{\pi R_{o}^{2} - \pi R_{i}^{2}}{2\pi R_{o} + 2\pi R_{i}} \]
08

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can substitute the known values of h, k, and Lc to obtain the Biot number.
09

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (d)
10

Calculate the characteristic length Lc

Since the rod is cylindrical, we can take half the diameter as the characteristic length: \[ L_{c} = \frac{D}{2} \]
11

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can substitute the known values of h, k, and Lc to obtain the Biot number.
12

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (e)
13

Calculate the characteristic length Lc

For a sphere, the characteristic length is equal to the radius: \[ L_{c} = \frac{D}{2} \]
14

Calculate the Biot number Bi

Since this problem involves radiation instead of convection, we will use the radiation analog of the Biot number, which is \[ Bi_{r} = \frac{2hrL_{c}}{k} \] where hr is the radiation heat transfer coefficient.
15

Assess the validity of the lumped capacitance approximation

If the radiation Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (f)
16

Calculate the characteristic length Lc

Since the rod is cylindrical, we can take half the diameter as the characteristic length: \[ L_{c} = \frac{D}{2} \]
17

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can substitute the known values of h, k, and Lc to obtain the Biot number.
18

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid. (g)
19

Calculate the characteristic length Lc

Since the rod is cylindrical, we can take half the diameter as the characteristic length: \[ L_{c} = \frac{D}{2} \]
20

Determine the Biot number Bi

Using the formula Bi = \( \frac{h L_{c}}{k} \), we can substitute the known values of h, k, and Lc to obtain the Biot number.
21

Assess the validity of the lumped capacitance approximation

If the Biot number is less than or equal to 0.1, the lumped capacitance approximation is valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot number
The Biot number is an important figure in the study of heat transfer, especially when using the lumped capacitance method. It is a dimensionless parameter defined as the ratio of conductive resistance within a body to the convective resistance across the surface of the body. Mathematically, it can be expressed as: \[Bi = \frac{hL_{c}}{k}\] where:
  • \(h\) is the heat transfer coefficient (in \(W/m^2 \cdot K\)),
  • \(L_{c}\) is the characteristic length (in meters),
  • \(k\) is the thermal conductivity of the material (in \(W/m \cdot K\)).
A Biot number less than or equal to 0.1 indicates that the lumped capacitance approximation is valid. This suggests that the temperature within an object can be assumed uniform, simplifying thermal analysis. If the Biot number is greater than 0.1, temperature gradients within the object become significant, meaning more complex models are needed to accurately describe the heat transfer process.
characteristic length
The characteristic length \(L_{c}\) is a measure used to describe the "size" of the object relevant to the heat transfer process. It helps in evaluating the object's thermal behavior during heat transfer:For different shapes, the characteristic length can be calculated differently, as follows:
  • **Cylindrical objects** such as rods have a characteristic length calculated as half the diameter: \[ L_{c} = \frac{D}{2} \]
  • **Rectangular objects** use the average of the two smallest dimensions: \[ L_{c} = \frac{w + W}{2} \]
  • **Hollow cylinders** or toroidal shapes might require a more detailed formula taking both inner and outer surfaces into account: \[ L_{c} = \frac{A_{c}}{2\pi(r_{d} + r_{i})} \]
By calculating this length, it becomes easier to predict how the object will behave under heat transfer conditions. This helps determine whether a simpler model, like the lumped capacitance method, is appropriate.
heat transfer coefficient
The heat transfer coefficient, denoted as \(h\), is crucial in analyzing heat exchange between a solid object and a fluid in contact with it. This coefficient is significant as it reflects how effectively heat is being transferred through the surface of the object.In heat transfer analysis, the value of \(h\) can be influenced by:
  • The type of fluid (such as air, water, oil),
  • The state of the fluid flow (laminar or turbulent),
  • Surface properties of the solid,
  • The temperature difference between the solid and the fluid.
It is measured in \(W/m^2 \cdot K\) and can vary widely depending on the condition of the experiment or practical situation. For example, a solid object immersed in water might have a higher \(h\) compared to the same object exposed to air. Understanding the heat transfer coefficient helps in assessing whether simple methods like using the lumped capacitance model are applicable or more complex computational approaches are necessary.

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Most popular questions from this chapter

A one-dimensional slab of thickness \(2 L\) is initially at a uniform temperature \(T_{i}\). Suddenly, electric current is passed through the slab causing uniform volumetric heating \(\dot{q}\left(\mathrm{~W} / \mathrm{m}^{3}\right)\). At the same time, both outer surfaces \((x=\pm L)\) are subjected to a convection process at \(T_{\infty}\) with a heat transfer coefficient \(h\). Write the finite-difference equation expressing conservation of energy for node 0 located on the outer surface at \(x=-L\). Rearrange your equation and identify any important dimensionless coefficients.

A solid steel sphere (AISI 1010 ), \(300 \mathrm{~mm}\) in diameter, is coated with a dielectric material layer of thickness \(2 \mathrm{~mm}\) and thermal conductivity \(0.04 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The coated sphere is initially at a uniform temperature of \(500^{\circ} \mathrm{C}\) and is suddenly quenched in a large oil bath for which \(T_{\infty}=100^{\circ} \mathrm{C}\) and \(h=3300 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Estimate the time required for the coated sphere temperature to reach \(140^{\circ} \mathrm{C}\). Hint: Neglect the effect of energy storage in the dielectric material, since its thermal capacitance \((\rho c V)\) is small compared to that of the steel sphere

The heat transfer coefficient for air flowing over a sphere is to be determined by observing the temperature-time history of a sphere fabricated from pure copper. The sphere, which is \(12.7 \mathrm{~mm}\) in diameter, is at \(66^{\circ} \mathrm{C}\) before it is inserted into an airstream having a temperature of \(27^{\circ} \mathrm{C}\). A thermocouple on the outer surface of the sphere indicates \(55^{\circ} \mathrm{C} 69 \mathrm{~s}\) after the sphere is inserted into the airstream. Assume and then justify that the sphere behaves as a spacewise isothermal object and calculate the heat transfer coefficient.

Annealing is a process by which steel is reheated and then cooled to make it less brittle. Consider the reheat stage for a \(100-\mathrm{mm}\)-thick steel plate \(\left(\rho=7830 \mathrm{~kg} / \mathrm{m}^{3}\right.\), \(c=550 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=48 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\), which is initially at a uniform temperature of \(T_{i}=200^{\circ} \mathrm{C}\) and is to be heated to a minimum temperature of \(550^{\circ} \mathrm{C}\). Heating is effected in a gas-fired furnace, where products of combustion at \(T_{\infty}=800^{\circ} \mathrm{C}\) maintain a convection coefficient of \(h=250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) on both surfaces of the plate. How long should the plate be left in the furnace?

In a material processing experiment conducted aboard the space shuttle, a coated niobium sphere of \(10-\mathrm{mm}\) diameter is removed from a furnace at \(900^{\circ} \mathrm{C}\) and cooled to a temperature of \(300^{\circ} \mathrm{C}\). Although properties of the niobium vary over this temperature range, constant values may be assumed to a reasonable approximation, with \(\rho=8600 \mathrm{~kg} / \mathrm{m}^{3}, c=290 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(k=\) \(63 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). (a) If cooling is implemented in a large evacuated chamber whose walls are at \(25^{\circ} \mathrm{C}\), determine the time required to reach the final temperature if the coating is polished and has an emissivity of \(\varepsilon=0.1\). How long would it take if the coating is oxidized and \(\varepsilon=0.6\) ? (b) To reduce the time required for cooling, consideration is given to immersion of the sphere in an inert gas stream for which \(T_{\infty}=25^{\circ} \mathrm{C}\) and \(h=\) \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Neglecting radiation, what is the time required for cooling? (c) Considering the effect of both radiation and convection, what is the time required for cooling if \(h=200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(\varepsilon=0.6\) ? Explore the effect on the cooling time of independently varying \(h\) and \(\varepsilon\).

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