/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A spherical vessel used as a rea... [FREE SOLUTION] | 91Ó°ÊÓ

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A spherical vessel used as a reactor for producing pharmaceuticals has a 5 -mm-thick stainless steel wall \((k=17 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) and an inner diameter of \(D_{i}=1.0 \mathrm{~m}\). During production, the vessel is filled with reactants for which \(\rho=1100 \mathrm{~kg} / \mathrm{m}^{3}\) and \(c=2400 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), while exothermic reactions release energy at a volumetric rate of \(\dot{q}=10^{4} \mathrm{~W} / \mathrm{m}^{3}\). As first approximations, the reactants may be assumed to be well stirred and the thermal capacitance of the vessel may be neglected. (a) The exterior surface of the vessel is exposed to ambient air \(\left(T_{\infty}=25^{\circ} \mathrm{C}\right)\) for which a convection coefficient of \(h=6 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) may be assumed. If the initial temperature of the reactants is \(25^{\circ} \mathrm{C}\), what is the temperature of the reactants after \(5 \mathrm{~h}\) of process time? What is the corresponding temperature at the outer surface of the vessel? (b) Explore the effect of varying the convection coefficient on transient thermal conditions within the reactor.

Short Answer

Expert verified
After 5 hours of process time, the temperature of the reactants is approximately 72.15°C, and the corresponding temperature at the outer surface of the vessel is about 22.18°C. When varying the convection coefficient, the temperature differences within the reactor and at the outer surface will change depending on the value of the convection coefficient. By analyzing different values, we can understand the effect of changes in the convection coefficient on the reactor's thermal conditions.

Step by step solution

01

Apply the energy balance equation

First, we need to apply the energy balance equation to the reactor. The energy balance equation is given by: $$\Delta E_{in} - \Delta E_{out} = \Delta E_{stored}$$ For our case: $$\dot{q}V\Delta t = m c \Delta T_{reactants} + A_{outer} h \Delta T_{outer} \Delta t$$ where, V is the volume of the reactants inside the reactor m is the mass of the reactants A_{outer} is the outer surface area of the vessel In our analysis, we will assume that the thermal capacitance of the vessel is neglected, meaning that we will ignore the energy stored in the vessel itself and consider only the energy balance of the reactants.
02

Calculate the volume and mass of the reactants

We are given the inner diameter of the reactor \((D_i = 1.0 m)\). To find the volume of the reactants \((V)\), we use the formula for the volume of a sphere: $$V = \frac{4}{3} \pi \left(\frac{D_{i}}{2}\right)^3$$ Now, we can calculate the mass of the reactants \((m)\) using the given density \((\rho=1100 kg/m^3)\): $$m = \rho V$$
03

Calculate the outer surface area of the vessel

We have the inner diameter \((D_i=1.0 m)\) and the thickness of the steel wall \((\delta=5 mm = 5 × 10^{-3} m)\). The outer diameter of the vessel can be calculated as: $$D_{o} = D_{i} + 2\delta$$ Using the outer diameter, we can calculate the outer surface area \((A_{outer})\): $$A_{outer} = 4\pi \left(\frac{D_{o}}{2}\right)^2$$
04

Solve the energy balance equation to find the final temperature of the reactants

Now let's solve the energy balance equation for \(\Delta T_{reactants}\): $$\Delta T_{reactants} = \frac{\dot{q}V\Delta t - A_{outer} h \Delta T_{outer} \Delta t}{m c}$$ We are given the process time \((\Delta t = 5h = 18000s)\), volumetric energy release rate \((\dot{q} = 10^4 W/m^3)\), and convection coefficient \((h=6W/m^2K)\). We need to find the temperature difference \((\Delta T_{outer})\) between the outer surface of the vessel and the ambient air, and then we can substitute everything into the equation and solve for \(\Delta T_{reactants}\).
05

Calculate the temperature at the outer surface

First, let's find the temperature difference at the outer surface using the given convection coefficient and the heat transfer equation: $$q = h A_{outer} \Delta T_{outer}$$ Now, we can solve this equation for \(\Delta T_{outer}\): $$\Delta T_{outer} = \frac{q}{h A_{outer}}$$ Substitute this expression into the energy balance equation and solve for \(\Delta T_{reactants}\). Finally, we find the final temperature of the reactants by adding the initial temperature \((T_{initial} = 25^°C)\) and \(\Delta T_{reactants}\).
06

Calculate the corresponding temperature at the outer surface of the vessel

Now that we know the temperature difference at the outer surface \((\Delta T_{outer})\), we can calculate the temperature at the outer surface of the vessel by subtracting it from the initial air temperature \((T_\infty=25^°C)\): $$T_{outer} = T_\infty - \Delta T_{outer}$$ This will give us the temperature at the outer surface of the vessel after 5 hours. #Part (b)# To explore the effect of varying the convection coefficient on transient thermal conditions within the reactor, we can re-calculate \(\Delta T_{reactants}\) and \(\Delta T_{outer}\) for different values of convection coefficients, using the same steps as demonstrated in Part (a). This will help us understand how changes in the coefficient will affect the reactor's thermal conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Balance Equation
Understanding the energy balance equation is crucial for analyzing systems where energy is being stored, transferred, or converted.

At its core, the energy balance equation is an expression of the law of conservation of energy. This principle states that energy within a closed system must remain constant, barring any transfer of energy to or from the environment. It takes on the form of an equation that equates the change in energy entering a system with the change in energy stored within the system plus the change in energy leaving the system.

In the context of a reactor, such as the spherical vessel described in the exercise, the energy balance equation can be represented as:
\[\Delta E_{in} - \Delta E_{out} = \Delta E_{stored}\]
When applying this equation to our reactor scenario, it becomes:
\[\dot{q}V\Delta t = m c \Delta T_{reactants} + A_{outer} h \Delta T_{outer} \Delta t\]
Here, the terms represent the rate of energy release by the reaction \(\dot{q}\), the volume of reactants \(V\), the time period \(\Delta t\), the mass of reactants \(m\), the specific heat of reactants \(c\), the outer surface area of the vessel \(A_{outer}\), the convection heat transfer coefficient \(h\), and the temperature difference across the outer surface \(\Delta T_{outer}\).

Solving this equation helps us to predict the thermal conditions within the reactor after a given amount of time. For educational purposes, it's important to carefully follow each step and understand how each term in the equation contributes to the overall energy balance.
Convection Coefficient
The convection coefficient, represented by \(h\), is a parameter that quantifies the rate of heat transfer between a surface and a fluid moving past it. It is influenced by properties like fluid velocity, viscosity, thermal conductivity, and the surface area in contact with the fluid.

In our reactor case study, the convection coefficient is a measure of how effectively the reactor's exterior surface is able to transfer heat to the surrounding ambient air. A key factor in our thermal analysis of the reactor, the convection coefficient helps determine the temperature gradient between the surface and the fluid, which in this scenario is air.
\[q = h A_{outer} \Delta T_{outer}\]
The convection coefficient is not only a property of the fluid and the surface in contact but also depends on the flow conditions. Different scenarios require different values of \(h\), impacting the reactor's ability to dissipate heat. As part of the energy balance, modifying the convection coefficient would directly affect the temperature changes over time. When exploring the impact of varying \(h\), we can examine how different cooling or heating rates could potentially alter the performance or safety of the reactor.
Transient Thermal Analysis
Transient thermal analysis is essential when studying how the temperature of a system evolves over time.

Unlike steady-state thermal analysis that assumes temperatures do not change with time, transient analysis considers the time-dependent nature of temperature variations, which is crucial when considering processes like the reaction occurring in the reactor vessel. This method of thermal analysis uses principles of heat transfer, thermodynamics, and temporal changes to calculate temperature profiles and gradients at different times.

For the reactor analysis from the step-by-step solution, a transient thermal analysis would involve tracking the temperature of the reactants and the vessel over the process time. It necessitates the solution of the time-dependent energy balance equation:
\[\Delta T_{reactants} = \frac{\dot{q}V\Delta t - A_{outer} h \Delta T_{outer} \Delta t}{m c}\]
This equation reflects how heat generated by the exothermic reactions and lost through the vessel walls to the surrounding air changes the temperature as a function of time. If students were tasked to investigate different transient conditions, such as varying the convection coefficient or the initial temperature, they would conduct multiple transient thermal analyses to predict system behavior under these new conditions.

Proficiency in transient thermal analysis is invaluable for engineers and scientists dealing with thermal systems that vary over time, ensuring safety, efficiency, and optimal performance in real-world applications.

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Most popular questions from this chapter

To determine which parts of a spider's brain are triggered into neural activity in response to various optical stimuli, researchers at the University of Massachusetts Amherst desire to examine the brain as it is shown images that might evoke emotions such as fear or hunger. Consider a spider at \(T_{i}=20^{\circ} \mathrm{C}\) that is shown a frightful scene and is then immediately immersed in liquid nitrogen at \(T_{\infty}=77 \mathrm{~K}\). The brain is subsequently dissected in its frozen state and analyzed to determine which parts of the brain reacted to the stimulus. Using your knowledge of heat transfer, determine how much time elapses before the spider's brain begins to freeze. Assume the brain is a sphere of diameter \(D_{b}=1 \mathrm{~mm}\), centrally located in the spider's cephalothorax, which may be approximated as a spherical shell of diameter \(D_{c}=3 \mathrm{~mm}\). The brain and cephalothorax properties correspond to those of liquid water. Neglect the effects of the latent heat of fusion and assume the heat transfer coefficient is \(h=100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

Joints of high quality can be formed by friction welding. Consider the friction welding of two 40 -mm-diameter Inconel rods. The bottom rod is stationary, while the top rod is forced into a back-and-forth linear motion characterized by an instantaneous horizontal displacement, \(d(t)=a \cos (\omega t)\) where \(a=2 \mathrm{~mm}\) and \(\omega=1000 \mathrm{rad} / \mathrm{s}\). The coefficient of sliding friction between the two pieces is \(\mu=0.3\). Determine the compressive force that must be applied to heat the joint to the Inconel melting point within \(t=3 \mathrm{~s}\), starting from an initial temperature of \(20^{\circ} \mathrm{C}\). Hint: The frequency of the motion and resulting heat rate are very high. The temperature response can be approximated as if the heating rate were constant in time, equal to its average value.

A very thick plate with thermal diffusivity \(5.6 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) and thermal conductivity \(20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is initially at a uniform temperature of \(325^{\circ} \mathrm{C}\). Suddenly, the surface is exposed to a coolant at \(15^{\circ} \mathrm{C}\) for which the convection heat transfer coefficient is \(100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Using the finite- difference method with a space increment of \(\Delta x=15 \mathrm{~mm}\) and a time increment of \(18 \mathrm{~s}\), determine temperatures at the surface and at a depth of \(45 \mathrm{~mm}\) after \(3 \mathrm{~min}\) have elapsed.

Steel balls \(12 \mathrm{~mm}\) in diameter are annealed by heating to \(1150 \mathrm{~K}\) and then slowly cooling to \(400 \mathrm{~K}\) in an air environment for which \(T_{\infty}=325 \mathrm{~K}\) and \(h=20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Assuming the properties of the steel to be \(k=40 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\rho=7800 \mathrm{~kg} / \mathrm{m}^{3}\), and \(c=600 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), estimate the time required for the cooling process. .

Thermal energy storage systems commonly involve a packed bed of solid spheres, through which a hot gas flows if the system is being charged, or a cold gas if it is being discharged. In a charging process, heat transfer from the hot gas increases thermal energy stored within the colder spheres; during discharge, the stored energy decreases as heat is transferred from the warmer spheres to the cooler gas. Consider a packed bed of \(75-\mathrm{mm}\)-diameter aluminum spheres \(\left(\rho=2700 \mathrm{~kg} / \mathrm{m}^{3}, c=950 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=\right.\) \(240 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) ) and a charging process for which gas enters the storage unit at a temperature of \(T_{g, i}=300^{\circ} \mathrm{C}\). If the initial temperature of the spheres is \(T_{i}=25^{\circ} \mathrm{C}\) and the convection coefficient is \(h=75 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), how long does it take a sphere near the inlet of the system to accumulate \(90 \%\) of the maximum possible thermal energy? What is the corresponding temperature at the center of the sphere? Is there any advantage to using copper instead of aluminum?

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