/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 A spherical shell of inner and o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A spherical shell of inner and outer radii \(r_{i}\) and \(r_{o}\), respectively, contains heat-dissipating components, and at a particular instant the temperature distribution in the shell is known to be of the form $$ T(r)=\frac{C_{1}}{r}+C_{2} $$ Are conditions steady-state or transient? How do the heat flux and heat rate vary with radius?

Short Answer

Expert verified
The given temperature distribution T(r) represents steady-state conditions. The heat flux, q(r), varies with radius and is inversely proportional to the square of the radius: \(q(r) = \frac{kC_{1}}{r^2}\). The heat rate, Q(r), is constant and does not depend on the radius: \(Q(r) = 4\pi{kC_{1}}\).

Step by step solution

01

Identify steady-state or transient conditions

Steady-state conditions occur when the temperature distribution in the system does not change with time. In our case, the temperature function T(r) is given solely as a function of radius r. Since there is no dependence on time (t), we conclude that the conditions are steady-state.
02

Apply Fourier's Law in radial direction

Fourier's Law of heat conduction for a spherical coordinate system in radial direction states the heat flux (q) as: \[q(r) = -k\frac{dT}{dr}\] where k is the thermal conductivity of the material and dT/dr is the temperature gradient with respect to r. Now, let's find dT/dr for given T(r) function: \[T(r) = \frac{C_{1}}{r} + C_{2}\] \[ \frac{dT}{dr} = -\frac{C_1}{r^2}\]
03

Calculate heat flux q(r)

Insert the found derivative of the temperature function (dT/dr) into the Fourier's Law: \[q(r) = -k\left(-\frac{C_{1}}{r^2}\right)\] \[q(r) = \frac{kC_{1}}{r^2}\] The heat flux, q(r), varies with radius and is inversely proportional to the square of the radius.
04

Calculate heat rate Q(r)

The heat rate, Q(r), is the total heat transfer across a spherical surface of radius r. To calculate it, we will multiply the heat flux q(r) by the surface area of the sphere: \[Q(r) = q(r) \cdot A\] where A is the surface area of a sphere with radius r, \[A = 4\pi{r^2}\] Substituting the calculated heat flux q(r) and the surface area A into the formula for heat rate: \[Q(r) = \frac{kC_{1}}{r^2} \cdot 4\pi{r^2}\] \[Q(r) = 4\pi{kC_{1}}\] We observe that heat rate Q(r) is constant and does not depend on the radius. In conclusion, the given temperature distribution T(r) represents steady-state conditions. The heat flux, q(r), varies with radius and is inversely proportional to the square of the radius. The heat rate, Q(r), is constant and does not depend on the radius.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fourier's Law of Heat Conduction
Fourier's Law of heat conduction is a fundamental principle that describes how heat is transferred through materials. When a temperature gradient exists within a material, heat will flow from the warmer to the cooler region at a rate proportional to the gradient. In a mathematical form, Fourier's law is expressed as:
\[q = -k abla T\]
Here, \(q\) represents the heat flux density, which is the rate of heat transfer per unit area, \(k\) is the thermal conductivity of the material, and \(abla T\) is the temperature gradient indicating the rate at which the temperature changes in space. The negative sign indicates that heat flows in the direction of decreasing temperature. In the context of spherical coordinates, this law is particularly relevant for analyzing heat conduction through objects like spherical shells.
Temperature Distribution in Spherical Coordinates
Understanding temperature distribution in spherical coordinates is key to solving heat transfer problems involving spheres. In spherical systems, heat conduction can be radially symmetric, and thus the temperature often depends only on the radial distance from the center, denoted by \(r\). The temperature distribution describes how temperature changes with respect to this radial distance.
For a spherical shell, the temperature distribution can take various forms, but a common form is expressed as:
\[T(r) = \frac{C_1}{r} + C_2\]
where \(C_1\) and \(C_2\) are constants that can be determined based on boundary conditions or known temperatures at certain points. This equation showcases that temperature within the sphere can vary inversely with radius or might have a constant component, offering insight into the thermal behavior within the shell.
Heat Flux Variation with Radius
Heat flux is a critical concept in thermal analysis, representing the rate at which heat energy passes through a surface per unit area. According to Fourier's Law, in a spherical coordinate system, heat flux changes with the radius. Mathematically, for a temperature distribution \(T(r)\), the heat flux \(q(r)\) is expressed as:
\[q(r) = -k\frac{dT}{dr}\]
When dealing with a temperature distribution given by \(T(r) = \frac{C_{1}}{r} + C_{2}\), the differential change in temperature with respect to radius \(r\) can be found, leading to:
\[q(r) = \frac{kC_{1}}{r^2}\]
Here, we observe that the heat flux is inversely proportional to the square of the radius, which implies that heat flux intensity decreases as one moves away from the center of the sphere. This variation is particularly important when designing objects with spherical geometries such as pressure vessels, to ensure efficient thermal management.
Heat Transfer in Spherical Shells
In the study of heat transfer, spherical shells are a common geometrical shape to analyze due to their relevance in many practical applications. The rate of heat being transferred across a spherical shell of radius \(r\) is quantified by the heat rate, \(Q(r)\). This heat rate is calculated by multiplying the heat flux by the area through which heat is flowing:
\[Q(r) = q(r) \cdot A\]
For a sphere, the area \(A\) is given by the surface area formula \(A = 4\pi r^2\). By plugging in the expression for heat flux found using Fourier's Law, we get a heat rate that is independent of the radius:
\[Q(r) = 4\pi kC_{1}\]
The constancy of the heat rate, regardless of the radius, indicates that the same amount of heat is being transferred across any spherical surface within the shell. This implies a uniform heat transfer across spherical shells, making the spherical geometry a remarkable case in the study of steady-state heat conduction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider steady-state conditions for one-dimensional conduction in a plane wall having a thermal conductivity \(k=50 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and a thickness \(L=0.25 \mathrm{~m}\), with no internal heat generation. Determine the heat flux and the unknown quantity for each case and sketch the temperature distribution, indicating the direction of the heat flux. \begin{tabular}{crcc} \hline Case & \(T_{1}\left({ }^{\circ} \mathrm{C}\right)\) & \(T_{2}\left({ }^{\circ} \mathrm{C}\right)\) & \(d T / d x(\mathbf{K} / \mathbf{m})\) \\ \hline 1 & 50 & \(-20\) & \\ 2 & \(-30\) & \(-10\) & 160 \\ 3 & 70 & & \(-80\) \\ 4 & & 40 & 200 \\ 5 & & 30 & \\ \hline \end{tabular}

The steady-state temperature distribution in a semitransparent material of thermal conductivity \(k\) and thickness \(L\) exposed to laser irradiation is of the form $$ T(x)=-\frac{A}{k a^{2}} e^{-a x}+B x+C $$ (a) Obtain expressions for the conduction heat fluxes at the front and rear surfaces. (b) Derive an expression for \(\dot{q}(x)\). (c) Derive an expression for the rate at which radiation is absorbed in the entire material, per unit surface area. Express your result in terms of the known constants for the temperature distribution, the thermal conductivity of the material, and its thickness. where \(A, a, B\), and \(C\) are known constants. For this situation, radiation absorption in the material is manifested by a distributed heat generation term, \(\dot{q}(x)\).

A spherical particle of radius \(r_{1}\) experiences uniform thermal generation at a rate of \(\dot{q}\). The particle is encapsulated by a spherical shell of outside radius \(r_{2}\) that is cooled by ambient air. The thermal conductivities of the particle and shell are \(k_{1}\) and \(k_{2}\), respectively, where \(k_{1}=2 k_{2}\). (a) By applying the conservation of energy principle to spherical control volume \(A\), which is placed at an arbitrary location within the sphere, determine a relationship between the temperature gradient \(d T / d r\) and the local radius \(r\), for \(0 \leq r \leq r_{1}\). (b) By applying the conservation of energy principle to spherical control volume \(\mathrm{B}\), which is placed at an arbitrary location within the spherical shell, determine a relationship between the temperature gradient \(d T / d r\) and the local radius \(r\), for \(r_{1} \leq r \leq r_{2}\). (c) On \(T-r\) coordinates, sketch the temperature distribution over the range \(0 \leq r \leq r_{2}\).

The one-dimensional system of mass \(M\) with constant properties and no internal heat generation shown in the figure is initially at a uniform temperature \(T_{i^{*}}\). The electrical heater is suddenly energized, providing a uniform heat flux \(q_{o}^{\prime \prime}\) at the surface \(x=0\). The boundaries at \(x=L\) and elsewhere are perfectly insulated. (a) Write the differential equation, and identify the boundary and initial conditions that could be used to determine the temperature as a function of position and time in the system. (b) On \(T-x\) coordinates, sketch the temperature distributions for the initial condition \((t \leq 0)\) and for several times after the heater is energized. Will a steady-state temperature distribution ever be reached? (c) On \(q_{x}^{\prime \prime}-t\) coordinates, sketch the heat flux \(q_{x}^{\prime \prime}(x, t)\) at the planes \(x=0, x=L / 2\), and \(x=L\) as a function of time. (d) After a period of time \(t_{e}\) has elapsed, the heater power is switched off. Assuming that the insulation is perfect, the system will eventually reach a final uniform temperature \(T_{f}\) Derive an expression that can be used to determine \(T_{f}\) as a function of the parameters \(q_{o}^{\prime \prime}, t_{e}, T_{i}\), and the system characteristics \(M, c_{p}\), and \(A_{s}\) (the heater surface area).

A steam pipe is wrapped with insulation of inner and outer radii \(r_{i}\) and \(r_{o}\), respectively. At a particular instant the temperature distribution in the insulation is known to be of the form $$ T(r)=C_{1} \ln \left(\frac{r}{r_{o}}\right)+C_{2} $$ Are conditions steady-state or transient? How do the heat flux and heat rate vary with radius?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.