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Hydrogen gas is used in a process to manufacture a sheet material of \(6-\mathrm{mm}\) thickness. At the end of the process, \(\mathrm{H}_{2}\) remains in solution in the material with a uniform concentration of \(320 \mathrm{kmol} / \mathrm{m}^{3}\). To remove \(\mathrm{H}_{2}\) from the material, both surfaces of the sheet are exposed to an airstream at \(500 \mathrm{~K}\) and a total pressure of \(3 \mathrm{~atm}\). Due to contamination, the hydrogen partial pressure is \(0.1 \mathrm{~atm}\) in the airstream, which provides a convection mass transfer coefficient of \(1.5 \mathrm{~m} / \mathrm{h}\). The mass diffusivity and solubility of hydrogen (A) in the sheet material (B) are \(D_{\mathrm{AB}}=2.6 \times 10^{-8} \mathrm{~m}^{2} / \mathrm{s}\) and \(S_{\mathrm{AB}}=160 \mathrm{kmol} / \mathrm{m}^{3} \cdot\) atm, respectively. (a) If the sheet material is left exposed to the airstream for a long time, determine the final content of hydrogen in the material \(\left(\mathrm{kg} / \mathrm{m}^{3}\right)\). (b) Identify and evaluate the parameter that can be used to determine whether the transient mass diffusion process in the sheet can be assumed to be characterized by a uniform concentration at any time during the process. Hint: This situation is analogous to that used to determine the validity of the lumped-capacitance method for a transient heat transfer analysis. (c) Determine the time required to reduce the hydrogen mass density at the center of the sheet to twice the limiting value calculated in part (a).

Short Answer

Expert verified
(a) The final content of hydrogen in the material can be calculated as: \( \rho_{H,f} = C_f \times M = (160\,\frac{\text{kmol}}{\text{m}^3\,\text{atm}} \times 0.1\,\text{atm})\times (2\,\frac{\text{kg}}{\text{kmol}}) = 32\,\frac{\text{kg}}{\text{m}^3} \) (b) The mass Biot number (Bi_m) can be calculated as: \(h_m = 1.5\,\frac{\text{m}}{\text{h}} \times \frac{1 \text{h}}{3600\, \text{s}} = 4.17 \times 10^{-4}\,\frac{\text{m}}{\text{s}}\) \( Bi_m = \frac{h_m \delta}{D_{AB}} = \frac{(4.17 \times 10^{-4}\,\frac{\text{m}}{\text{s}}) (6 \times 10^{-3}\, \text{m})}{2.6 \times 10^{-8}\,\frac{\text{m}^2}{\text{s}}} = 96.3 \) (c) To find the time required, we can use the error function and rearranged Fick's second law equation: \( t = \frac{\left(\frac{1}{2} \times 6 \times 10^{-3}\, \text{m}\right)^2}{4 \times 2.6 \times 10^{-8}\,\frac{\text{m}^2}{\text{s}} \times \left[\text{erf}^{-1} \left(\frac{2C_f - C_f}{C_i - C_f} \right)\right]^2} \approx 3012\,\text{s} \) Thus, the time required to reduce the hydrogen mass density at the center of the sheet to twice the limiting value is approximately 3012 seconds.

Step by step solution

01

(a) Find the final content of hydrogen in the material

To find the final content of hydrogen in the material, we'll need to use the solubility property of hydrogen in the sheet material (B), given as \(S_{AB}=160\,\text{kmol}/\text{m}^3\,\text{atm}\). The hydrogen partial pressure at the air interface is given as 0.1 atm. Calculate the final concentration of hydrogen, \( C_{f} = S_{AB} \times p_H = 160\,\frac{\text{kmol}}{\text{m}^3\,\text{atm}} \times 0.1\,\text{atm} \) Now, convert the final concentration of hydrogen to mass density using the molar mass of hydrogen, M (2 kg/kmol). \( \rho_{H,f} = C_f \times M = (160\,\frac{\text{kmol}}{\text{m}^3\,\text{atm}} \times 0.1\,\text{atm})\times (2\,\frac{\text{kg}}{\text{kmol}}) \)
02

(b) Identify and evaluate the parameter for uniform concentration

The hint suggests that there is an analogy between mass transfer and heat transfer problems. In transient heat transfer analysis, the Biot number (Bi) is used to determine the validity of the lumped-capacitance method. Similarly, for mass transfer, we can define a mass Biot number (Bi_m) as follows: \( Bi_m = \frac{h_m \delta}{D_{AB}}\) where \(h_m\) is the mass transfer coefficient (1.5 m/h), \(\delta\) is the sheet thickness (6 mm), and \(D_{AB}\) is the mass diffusivity (2.6 脳 10鈦烩伕 m虏/s). First, convert the mass transfer coefficient to the same unit as mass diffusivity (m/s), \( h_m = 1.5\,\frac{\text{m}}{\text{h}} \times \frac{1 \text{h}}{3600\, \text{s}}\) Now, calculate the mass Biot number, \( Bi_m = \frac{h_m \delta}{D_{AB}}\)
03

(c) Time required to reduce hydrogen mass density to twice the limiting value

We have to determine the time required to reduce the hydrogen mass density at the center of the sheet to twice the final content of hydrogen. We can use Fick's second law of diffusion, which involves the error function (erf): \( \frac{C - C_f}{C_i - C_f} = \text{erf}\left(\frac{x}{2\sqrt{D_{AB}t}}\right) \) Rearranging the equation to solve for time, we get \( t = \frac{x^2}{4D_{AB}\left[\text{erf}^{-1} \left(\frac{C - C_f}{C_i - C_f} \right)\right]^2} \) To find the time required for the hydrogen mass density to be twice the limiting value, we need to plug in x as half the sheet thickness, Ci as the initial concentration (320 kmol/m鲁), and C as twice the final concentration: \( t = \frac{\left(\frac{1}{2} \times 6 \times 10^{-3}\, \text{m}\right)^2}{4 \times 2.6 \times 10^{-8}\,\frac{\text{m}^2}{\text{s}} \times \left[\text{erf}^{-1} \left(\frac{2C_f - C_f}{C_i - C_f} \right)\right]^2} \) Calculate the time t.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Diffusion
Hydrogen diffusion is a fundamental concept in mass transfer processes. It involves the movement of hydrogen molecules through a material due to a concentration gradient. Diffusion is driven by the random motion of molecules, moving from an area of higher concentration to one of lower concentration.

There are several factors affecting hydrogen diffusion:
  • Concentration gradient: A higher difference in concentration increases the rate of diffusion.
  • Temperature: Higher temperatures increase molecular motion, enhancing diffusion.
  • Material properties: The nature of the sheet material affects diffusion. Porous or less dense materials may allow faster diffusion.
  • Diffusivity: Defined as the extent to which a molecule spreads out over time within a given medium, diffusivity (\( D_{AB} \) in this case) is crucial. For hydrogen, the molar mass is small, meaning it can diffuse quickly.
The diffusion of hydrogen can be described using Fick's laws, particularly when we're interested in situations where concentration varies with both time and position.
Solubility
Solubility is the measure of how much of a particular solute can dissolve in a solvent at a given temperature and pressure. In the context of hydrogen diffusion into a material, solubility indicates the maximum amount of hydrogen that can be dissolved in the sheet material.

The solubility of hydrogen in the sheet material is characterized by the parameter \( S_{AB} \), which represents the amount of hydrogen (\( \text{kmol/m}^3 \)) that can be dissolved under a unit partial pressure of hydrogen (\( \text{atm} \)).
  • It is essential for predicting how much hydrogen will remain in the material when subjected to certain conditions.
  • In the problem, solubility helps us calculate the final concentration of hydrogen by multiplying it with the hydrogen partial pressure in the air.
Therefore, understanding solubility helps determine equilibrium conditions where the rate of hydrogen entering the material equals the rate leaving it.
Biot Number
The Biot number is a dimensionless parameter that describes the ratio of internal resistance to diffusive transport (within a material) compared to external convective forces. It is commonly used in heat and mass transfer to assess the effectiveness of a process.

Defined as \( Bi_m = \frac{h_m \delta}{D_{AB}} \), where:
  • \( h_m \) is the convective mass transfer coefficient indicating the ease of mass transfer over the surface.
  • \( \delta \) is the characteristic length, usually the thickness of the material.
  • \( D_{AB} \) is the diffusivity, showing how well the substance moves within the medium.
A small Biot number suggests that internal transport within the material occurs faster than external transfer, implying a uniform concentration within the material. Conversely, a high Biot number indicates dominating external mass transfer resistance, meaning possible concentration gradients within the material.
Fick's Second Law
Fick's Second Law of Diffusion describes how diffusion causes the concentration of a substance to change over time. While Fick's First Law relates to steady-state diffusion, Fick's Second Law considers dynamic situations where concentration varies with time.This law is represented by the equation:\[\frac{\partial C}{\partial t} = D_{AB} abla^2 C\]where:
  • \( C \) represents concentration.
  • \( t \) denotes time.
  • \( D_{AB} \) is the mass diffusivity.
  • \( abla^2 \) is the Laplacian operator, which can include second derivatives of \( x, y, z \) coordinates.
This law is powerful for predicting how the concentration of hydrogen within the material will decay over time due to diffusion. It is applied specifically when calculating the time required to achieve a particular concentration within the material, as seen in transient mass transfer problems. Mathematical tools, such as the error function, are often used to solve these equations efficiently.

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Most popular questions from this chapter

An experiment is designed to measure the partition coefficient, \(K\), associated with the transfer of a pharmaceutical product through a polymer material. The partition coefficient is defined as the ratio of the densities of the species of interest (the pharmaceutical) on either side of an interface. In the experiment, liquid pharmaceutical \(\left(\rho_{p}=1250 \mathrm{~kg} / \mathrm{m}^{3}\right)\) is injected into a hollow polymer sphere of inner and outer diameters \(D_{i}=5 \mathrm{~mm}\) and \(D_{o}=5.1 \mathrm{~mm}\), respectively. The sphere is exposed to convective conditions for which the density of the pharmaceutical at the outer surface is zero. After one week, the sphere's mass is reduced by \(\Delta M=8.2 \mathrm{mg}\). What is the value of the partition coefficient if the mass diffusivity is \(D_{\mathrm{AB}}=0.2 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{s}\) ?

Referring to Problem 14.34, a more representative model of respiration in a spherical organism is one for which oxygen consumption is governed by a firstorder reaction of the form \(\dot{N}_{\mathrm{A}}=-k_{1} C_{\mathrm{A}}\). (a) If a molar concentration of \(C_{\mathrm{A}}\left(r_{o}\right)=C_{\mathrm{A}, o}\) is maintained at the surface of the organism, obtain an expression for the radial distribution of oxygen, \(C_{\mathrm{A}}(r)\), within the organism. Hint: To simplify solution of the species diffusion equation, invoke the transformation \(y \equiv r C_{\mathrm{A}}\). (b) Obtain an expression for the rate of oxygen consumption within the organism. (c) Consider an organism of radius \(r_{o}=0.10 \mathrm{~mm}\) and a diffusion coefficient of \(D_{\mathrm{AB}}=10^{-8} \mathrm{~m}^{2} / \mathrm{s}\). If \(C_{\mathrm{A}, o}=5 \times 10^{-5} \mathrm{kmol} / \mathrm{m}^{3}\) and \(k_{1}=20 \mathrm{~s}^{-1}\), estimate the corresponding value of the molar concentration at the center of the organism. What is the rate of oxygen consumption by the organism?

Consider air in a closed, cylindrical container with its axis vertical and with opposite ends maintained at different temperatures. Assume that the total pressure of the air is uniform throughout the container. (a) If the bottom surface is colder than the top surface, what is the nature of conditions within the container? For example, will there be vertical gradients of the species \(\left(\mathrm{O}_{2}\right.\) and \(\left.\mathrm{N}_{2}\right)\) concentrations? Is there any motion of the air? Does mass transfer occur? (b) What is the nature of conditions within the container if it is inverted (i.e., the warm surface is now at the bottom)?

Consider the DVD of Problem 14.49, except now the reacting polymer is blended uniformly with the polycarbonate to reduce manufacturing costs. Assume that a first-order homogeneous chemical reaction takes place between the polymer and oxygen; the reaction rate is proportional to the oxygen molar concentration. (a) Write the governing equation, boundary conditions, and initial condition for the oxygen molar concentration after the DVD is removed from the oxygen- proof pouch, for a DVD of thickness \(2 L\). Do not solve. (b) The DVD will gradually become more opaque over time as the reaction proceeds. The ability to read the DVD will depend on how well the laser light can penetrate through the thickness of the DVD. Therefore, it is important to know the volume-averaged molar concentration of product, \(\bar{C}_{\text {prod }}\), as a function of time. Write an expression for \(\bar{C}_{\text {prod }}\) in terms of the oxygen molar concentration, assuming that every mole of oxygen that reacts with the polymer results in \(p\) moles of product.

Assuming air to be composed exclusively of \(\mathrm{O}_{2}\) and \(\mathrm{N}_{2}\), with their partial pressures in the ratio \(0.21: 0.79\), what are their mass fractions?

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