/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Consider the problem of oxygen t... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the problem of oxygen transfer from the interior lung cavity, across the lung tissue, to the network of blood vessels on the opposite side. The lung tissue (species B) may be approximated as a plane wall of thickness \(L\). The inhalation process may be assumed to maintain a constant molar concentration \(C_{\mathrm{A}}(0)\) of oxygen (species A) in the tissue at its inner surface \((x=0)\), and assimilation of oxygen by the blood may be assumed to maintain a constant molar concentration \(C_{\mathrm{A}}(L)\) of oxygen in the tissue at its outer surface \((x=L)\). There is oxygen consumption in the tissue due to metabolic processes, and the reaction is zero order, with \(\dot{N}_{\mathrm{A}}=-k_{0}\). Obtain expressions for the distribution of the oxygen concentration in the tissue and for the rate of assimilation of oxygen by the blood per unit tissue surface area.

Short Answer

Expert verified
The distribution of the oxygen concentration in the lung tissue is given by: \(C_A(x) = -\frac{k_0}{2D_{AB}}x^2 + \frac{-k_0L + 2D_{AB}(C_A^{ext} - C_A^{int})}{2D_{AB}L}x + C_A^{int}\) The rate of assimilation of oxygen by the blood per unit tissue surface area is given by: \(N_A(L) = \frac{k_0L}{2}- (C_A^{ext} - C_A^{int})\)

Step by step solution

01

Set up a mass balance equation for the oxygen concentration

: To set up a mass balance equation, we can consider a differential volume of lung tissue, with thickness dx, located at a distance x from the inner surface. The mass balance equation for species A (oxygen) on this differential volume will be: Accumulation = Influx - Efflux + Generation In this case, the accumulation of oxygen in the control volume is negligible, as the mass balance represents a steady-state situation. The influx and efflux will occur due to mass diffusion and generation is due to the zero-order reaction with a rate constant k0. Therefore, by applying Fick's law of mass diffusion, the mass balance equation will be: \(-D_{AB}\frac{d^{2}C_A}{dx^2} = -k_0\)
02

Solve the mass balance equation for the oxygen concentration distribution

: To solve this second-order ordinary differential equation, we need to integrate it twice: Integrating once, we get: \(-D_{AB}\frac{dC_A}{dx} = -k_0x + C_1\) And integrating a second time, we get: \(C_A(x) = -\frac{k_0}{2D_{AB}}x^2 + C_1x + C_2\) To find the constants C1 and C2, we can use the boundary conditions given: \(C_A(0) = C_A^{int} \Rightarrow C_2 = C_A^{int}\) \(C_A(L) = C_A^{ext} \Rightarrow -\frac{k_0}{2D_{AB}}L^2 + C_1L + C_A^{int} = C_A^{ext}\) From this last equation, we can solve for C1: \(C_1 = \frac{-k_0L + 2D_{AB}(C_A^{ext} - C_A^{int})}{2D_{AB}L}\) Thus, the distribution of the oxygen concentration in the lung tissue is given by: \(C_A(x) = -\frac{k_0}{2D_{AB}}x^2 + \frac{-k_0L + 2D_{AB}(C_A^{ext} - C_A^{int})}{2D_{AB}L}x + C_A^{int}\)
03

Determine the rate of assimilation of oxygen by the blood per unit tissue surface area

: The rate of assimilation of oxygen is defined as the flux of oxygen at the outer surface of the lung tissue (x = L). We can find the flux using Fick's law: \(N_A = -D_{AB}\frac{dC_A}{dx}\) To find the flux at x = L, we must differentiate the expression for the concentration distribution of oxygen with respect to x and substitute x = L: \(\frac{dC_A}{dx} = -\frac{k_0}{D_{AB}}x + \frac{-k_0L + 2D_{AB}(C_A^{ext} - C_A^{int})}{2D_{AB}L}\) \(N_A(L) = -D_{AB}\left(-\frac{k_0}{D_{AB}}L + \frac{-k_0L + 2D_{AB}(C_A^{ext} - C_A^{int})}{2D_{AB}L}\right)\) After simplifying, we get: \(N_A(L) = \frac{k_0L}{2}- (C_A^{ext} - C_A^{int})\) This expression gives the rate of assimilation of oxygen by the blood per unit tissue surface area.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fick's Law
Fick's Law is a fundamental principle describing how gases like oxygen diffuse through a medium. In the context of lung tissue, it helps us understand how oxygen moves from the air into the bloodstream. According to Fick's Law, the rate of diffusion is proportional to the concentration gradient. This means that oxygen will naturally move from an area of higher concentration (inside the lungs) to an area of lower concentration (blood vessels). The equation for Fick’s Law is given by:
\[ J = -D_{AB} \frac{dC}{dx} \]
where:
  • \(J\) is the diffusion flux (amount of substance per unit area per unit time)
  • \(D_{AB}\) is the diffusion coefficient of oxygen in lung tissue
  • \(\frac{dC}{dx}\) is the concentration gradient
Understanding this law is crucial for analyzing oxygen transfer in the lungs. By using this law, we can find out how much oxygen reaches the blood per unit time.
Mass Diffusion
Mass diffusion is the process through which molecules spread from areas of high concentration to areas of low concentration. In lung tissue, diffusion is the primary method by which oxygen enters blood vessels. The movement follows the concentration gradient created between the interior lung cavity and the blood vessels. This gradient is maintained by inhalation and the metabolic consumption of oxygen by the body. Factors affecting mass diffusion include:
  • Concentration difference: A higher difference results in a greater diffusion rate.
  • Diffusion coefficient: This value indicates how easily a molecule like oxygen can move through the lung tissue.
  • Tissue thickness: Thicker tissues may reduce the rate of diffusion.
By understanding these factors, we can predict how efficiently oxygen will transfer into the bloodstream.
Zero Order Reaction
In a zero-order reaction, the rate of reaction is constant and independent of the concentration of reactants. For oxygen transfer in lung tissue, metabolic processes consume oxygen at a constant rate, represented by the term \(-k_0\). This means that regardless of how much oxygen is available, it will be consumed at a steady pace.
This concept is simplified as:
  • The rate of oxygen consumption: \(-k_0\). This constant rate affects the overall oxygen distribution within the lung tissue.
By applying this concept, we can derive expressions for how oxygen concentration changes across lung tissue.
Steady-State Mass Balance
Steady-state mass balance considers the equilibrium where the rate of oxygen entering the tissue equals the rate leaving it, plus any consumption due to reactions. In the context of the lungs, this balance determines the distribution and assimilation of oxygen. Under steady-state:
  • Accumulation of oxygen within the tissue is negligible.
  • Oxygen influx equals the sum of efflux and consumption by zero-order reactions.
The equation representing this balance is:
\[ -D_{AB}\frac{d^2C_A}{dx^2} = -k_0 \]
This setup helps find the concentration profile across lung tissue by integrating and applying boundary conditions. It’s a key step in understanding how much oxygen can be transferred into the blood, vital for physiological functions.

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Most popular questions from this chapter

A large sheet of material \(40 \mathrm{~mm}\) thick contains dissolved hydrogen \(\left(\mathrm{H}_{2}\right)\) having a uniform concentration of \(3 \mathrm{kmol} / \mathrm{m}^{3}\). The sheet is exposed to a fluid stream that causes the concentration of the dissolved hydrogen to be reduced suddenly to zero at both surfaces. This surface condition is maintained constant thereafter. If the mass diffusivity of hydrogen is \(9 \times 10^{-7} \mathrm{~m}^{2} / \mathrm{s}\), how much time is required to bring the density of dissolved hydrogen to a value of \(1.2 \mathrm{~kg} / \mathrm{m}^{3}\) at the center of the sheet?

A He-Xe mixture containing \(0.75\) mole fraction of helium is used for cooling of electronics in an avionics application. At a temperature of \(300 \mathrm{~K}\) and atmospheric pressure, calculate the mass fraction of helium and the mass density, molar concentration, and molecular weight of the mixture. If the cooling system capacity is \(10 \mathrm{~L}\), what is the mass of the coolant?

Consider an ideal gas mixture of \(n\) species. (a) Derive an equation for determining the mass fraction of species \(i\) from knowledge of the mole fraction and the molecular weight of each of the \(n\) species. Derive an equation for determining the mole fraction of species \(i\) from knowledge of the mass fraction and the molecular weight of each of the \(n\) species. (b) In a mixture containing equal mole fractions of \(\mathrm{O}_{2}\), \(\mathrm{N}_{2}\), and \(\mathrm{CO}_{2}\), what is the mass fraction of each species? In a mixture containing equal mass fractions of \(\mathrm{O}_{2}, \mathrm{~N}_{2}\), and \(\mathrm{CO}_{2}\), what is the mole fraction of each species?

To enhance the effective surface, and hence the chemical reaction rate, catalytic surfaces often take the form of porous solids. One such solid may be visualized as consisting of a large number of cylindrical pores, each of diameter \(D\) and length \(L\). To enhance the effective surface, and hence the chemical reaction rate, catalytic surfaces often take the form of porous solids. One such solid may be visualized as consisting of a large number of cylindrical pores, each of diameter \(D\) and length \(L\). Consider conditions involving a gaseous mixture of \(\mathrm{A}\) and B for which species A is chemically consumed at the catalytic surface. The reaction is known to be first order, and the rate at which it occurs per unit area of the surface may be expressed as \(k_{1}^{\prime \prime} C_{\mathrm{A}}\), where \(k_{1}^{\prime \prime}(\mathrm{m} / \mathrm{s})\) is the reaction rate constant and \(C_{\mathrm{A}}\left(\mathrm{kmol} / \mathrm{m}^{3}\right)\) is the local molar concentration of species A. Under steadystate conditions, flow over the porous solid is known to maintain a fixed value of the molar concentration \(C_{\mathrm{A}, 0}\) at the pore mouth. Beginning from fundamentals, obtain the differential equation that governs the variation of \(C_{\mathrm{A}}\) with distance \(x\) along the pore. Applying appropriate boundary conditions, solve the equation to obtain an expression for \(C_{\mathrm{A}}(x)\).

Consider a spherical organism of radius \(r_{o}\) within which respiration occurs at a uniform volumetric rate of \(\dot{N}_{\mathrm{A}}=-k_{0}\). That is, oxygen (species A) consumption is governed by a zero-order, homogeneous chemical reaction. (a) If a molar concentration of \(C_{\mathrm{A}}\left(r_{o}\right)=C_{\mathrm{A}, o}\) is maintained at the surface of the organism, obtain an expression for the radial distribution of oxygen, \(C_{\mathrm{A}}(r)\), within the organism. From your solution, can you discern any limits on applicability of the result? (b) Obtain an expression for the rate of oxygen consumption within the organism. (c) Consider an organism of radius \(r_{o}=0.10 \mathrm{~mm}\) and a diffusion coefficient for oxygen transfer of \(D_{\mathrm{AB}}=10^{-8} \mathrm{~m}^{2} / \mathrm{s}\). If \(C_{\mathrm{A}, o}=5 \times 10^{-5} \mathrm{kmol} / \mathrm{m}^{3}\)and \(k_{0}=1.2 \times 10^{-4} \mathrm{kmol} / \mathrm{s}^{*} \mathrm{~m}^{3}\), what is the molar concentration of \(\mathrm{O}_{2}\) at the center of the organism?

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