/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 A thermocouple inserted in a 4-m... [FREE SOLUTION] | 91Ó°ÊÓ

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A thermocouple inserted in a 4-mm-diameter stainless steel tube having a diffuse, gray surface with an emissivity of \(0.4\) is positioned horizontally in a large airconditioned room whose walls and air temperature are 30 and \(20^{\circ} \mathrm{C}\), respectively. (a) What temperature will the thermocouple indicate if the air is quiescent? (b) Compute and plot the thermocouple measurement error as a function of the surface emissivity for \(0.1 \leq \varepsilon \leq 1.0\).

Short Answer

Expert verified
In this problem, we first find the steady-state temperature for the stainless steel tube by applying energy balance. For (a), assuming negligible convective heat transfer as the air is quiescent, we calculate the thermocouple indicated temperature \(T_{th}^\circ C \approx T_{tube}\). To calculate thermocouple measurement error in (b), we find the difference between the actual temperature of the tube and the thermocouple indicated temperature (∆T = \(T_{tube} - T_{th}\)), and plot the errors as a function of surface emissivity values ranging from 0.1 to 1.0.

Step by step solution

01

Calculate the net radiative heat transfer to the tube

We will first calculate the net radiative heat transfer to the tube. The net radiative heat transfer can be found using the following formula: \[q_{rad} = A_{tube} \sigma \epsilon (T_{walls}^4 - T_{tube}^4)\] where \(q_{rad}\) is the net radiative heat transfer, \(A_{tube}\) is the surface area of the tube, \(\sigma\) is the Stefan-Boltzmann constant \(= 5.67 \times 10^{-8} W/m^2K^4\), \(\epsilon\) is the emissivity of the tube, \(T_{walls}\) is the temperature of the walls in Kelvin, and \(T_{tube}\) is the temperature of the tube in Kelvin.
02

Calculate the convective heat transfer from the air to the tube

Next, we will calculate the convective heat transfer from the air to the tube. The convective heat transfer can be found using the following formula: \[q_{conv} = h A_{tube} (T_{air} - T_{tube})\] where \(q_{conv}\) is the convective heat transfer, \(h\) is the heat transfer coefficient, \(A_{tube}\) is the surface area of the tube, \(T_{air}\) is the temperature of the air in Kelvin, and \(T_{tube}\) is the temperature of the tube in Kelvin.
03

Apply energy balance on the stainless steel tube

At steady-state, the energy balance can be written as: \[q_{rad} = q_{conv}\] By substituting the expressions for \(q_{rad}\) and \(q_{conv}\) from steps 1 and 2, we can solve for the temperature of the tube, \(T_{tube}\), in Kelvin: \[A_{tube} \sigma \epsilon (T_{walls}^4 - T_{tube}^4) = h A_{tube} (T_{air} - T_{tube})\] Solve for \(T_{tube}\) to find its temperature.
04

Calculate the thermocouple indicated temperature (Part a)

Given that the air is quiescent (still), the convective heat transfer coefficient, \(h\), is assumed to be relatively lower. Therefore, the heat transfer due to convection is negligible, and the temperature of the thermocouple, \(T_{th}\), can be assumed to be close to the temperature of the tube: \[T_{th} \approx T_{tube}\] To find the temperature in degrees Celsius, we subtract 273.15 from the Kelvin temperature: \[T_{th}^{\circ C} = T_{th} - 273.15\]
05

Calculate the thermocouple measurement error (Part b)

The thermocouple measurement error can be defined as the difference between the actual temperature of the tube and the thermocouple indicated temperature: \(Error = T_{tube} - T_{th}\) For a range of surface emissivities from \(0.1 \leq \varepsilon \leq 1.0\), calculate the thermocouple measurement error.
06

Plot the thermocouple measurement error as a function of surface emissivity

Using the thermocouple measurement errors calculated in step 5, plot the errors as a function of surface emissivity values ranging from 0.1 to 1.0. The x-axis represents the surface emissivity values, while the y-axis represents the thermocouple measurement errors. This plot will give an understanding of how the thermocouple measurement error varies with the surface emissivity of the stainless steel tube.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Radiation
Thermal radiation is a process through which energy is emitted by a substance in the form of electromagnetic waves. This energy transfer occurs without the need for a medium, meaning it can happen in a vacuum. When one object is hotter than its surroundings, it emits more radiation than it absorbs, causing it to lose heat.
Understanding thermal radiation is key when dealing with situations like the one with the stainless steel tube described in the exercise. The tube, being in a room where the walls are at a higher temperature, absorbs radiation and can reach a thermal equilibrium based on both its properties and the environment around it.
In problems like these, we often need to calculate net radiative heat transfer using the equation:
  • \[ q_{rad} = A_{tube} \sigma \epsilon (T_{walls}^4 - T_{tube}^4) \]
Understanding this interaction can help us predict temperature changes without direct contact between the tube and other objects.
Convective Heat Transfer
Convective heat transfer is essential in understanding how heat moves through fluids like air or water. It involves the physical movement of a fluid carrying heat along with it. In our thermocouple problem, the air in the room affects the heat transfer to the tube through convection.
When air is still, convective heat transfer is relatively low, which implies less heat is transferred from the air to the tube. However, when air moves due to fans or wind, it significantly increases the heat transfer rate.
The basic formula for convective heat transfer is:
  • \[ q_{conv} = h A_{tube} (T_{air} - T_{tube}) \]
Here, the heat transfer coefficient \( h \) plays a vital role, and its value depends on the air's movement around the tube. The slower the air, the smaller \( h \), and vice versa.
Emissivity
Emissivity is a measure of a body's ability to emit thermal radiation compared to a perfect black body. It ranges from 0 to 1, with 1 being a perfect emitter and 0 indicating no emission. For the stainless steel tube in the exercise, emissivity plays a significant role because it directly influences both the radiative heat transfer and the temperature recorded by the thermocouple.
Materials with higher emissivities absorb and emit more radiation, impacting their heat retention or loss more significantly. This is why in the exercise, varying the emissivity affects the temperature read by the thermocouple and the measurement error.
Adjusting the tube's emissivity can be a crucial factor in precise temperature measurement and can be altered by different surface treatments or coatings.
Temperature Measurement
Accurately measuring temperature is vital for many applications, and understanding the interaction between the measurement device and its environment is equally important. In the exercise, a thermocouple is used, which is a type of sensor for measuring temperature by converting thermal potential difference into electrical potential.
However, the reading from a thermocouple may not always directly represent the environment's temperature due to various factors such as radiation from surrounding surfaces or insufficient thermal equilibrium. This discrepancy becomes evident when the tube's temperature is influenced by both thermal radiation and convection from the air. Thus, the temperature the thermocouple "sees" might slightly differ from the actual air temperature.
To reduce measurement errors, certain compensations or adjustments may need to be applied, such as accounting for emissivity changes or external factors like air movement.
Energy Balance
The concept of energy balance is fundamental in solving thermal problems. It entails analyzing all forms of energy entering and leaving a system, ensuring equilibrium is achieved.
In the case of the stainless steel tube, at steady state, the energy transferred by radiation needs to equal the energy lost through convection. Mathematically, this condition is expressed as:
  • \[ A_{tube} \sigma \epsilon (T_{walls}^4 - T_{tube}^4) = h A_{tube} (T_{air} - T_{tube}) \]
Reaching this balance allows us to calculate how the temperature of the tube stabilizes.
Energy balance is not just critical in determining temperature stability, but also in assessing how alterations in properties like emissivity or air movement might affect thermal interactions.

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Most popular questions from this chapter

A cylinder of \(30-\mathrm{mm}\) diameter and \(150-\mathrm{mm}\) length is heated in a large furnace having walls at \(1000 \mathrm{~K}\), while air at \(400 \mathrm{~K}\) is circulating at \(3 \mathrm{~m} / \mathrm{s}\). Estimate the steady-state cylinder temperature under the following specified conditions. (a) The cylinder is in cross flow, and its surface is diffuse and gray with an emissivity of \(0.5\). (b) The cylinder is in cross flow, but its surface is spectrally selective with \(\alpha_{\lambda}=0.1\) for \(\lambda \leq 3 \mu \mathrm{m}\) and \(\alpha_{\lambda}=0.5\) for \(\lambda>3 \mu \mathrm{m}\). (c) The cylinder surface is positioned such that the airflow is longitudinal and its surface is diffuse and gray. (d) For the conditions of part (a), compute and plot the cylinder temperature as a function of the air velocity for \(1 \leq V \leq 20 \mathrm{~m} / \mathrm{s}\).

One scheme for extending the operation of gas turbine blades to higher temperatures involves applying a ceramic coating to the surfaces of blades fabricated from a superalloy such as inconel. To assess the reliability of such coatings, an apparatus has been developed for testing samples under laboratory conditions. The sample is placed at the bottom of a large vacuum chamber whose walls are cryogenically cooled and which is equipped with a radiation detector at the top surface. The detector has a surface area of \(A_{d}=10^{-5} \mathrm{~m}^{2}\), is located at a distance of \(L_{\text {sl }}=1 \mathrm{~m}\) from the sample, and views radiation originating from a portion of the ceramic surface having an area of \(\Delta A_{c}=10^{-4} \mathrm{~m}^{2}\). An electric heater attached to the bottom of the sample dissipates a uniform heat flux, \(q_{b}^{\prime \prime}\), which is transferred upward through the sample. The bottom of the heater and sides of the sample are well insulated. Consider conditions for which a ceramic coating of thickness \(L_{c}=0.5 \mathrm{~mm}\) and thermal conductivity \(k_{c}=\) \(6 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) has been sprayed on a metal substrate of thickness \(L_{s}=8 \mathrm{~mm}\) and thermal conductivity \(k_{s}=\) \(25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The opaque surface of the ceramic may be approximated as diffuse and gray, with a total, hemispherical emissivity of \(\varepsilon_{c}=0.8\). (a) Consider steady-state conditions for which the bottom surface of the substrate is maintained at \(T_{1}=1500 \mathrm{~K}\), while the chamber walls (including the surface of the radiation detector) are maintained at \(T_{w}=90 \mathrm{~K}\). Assuming negligible thermal contact resistance at the ceramic- substrate interface, determine the ceramic top surface temperature \(T_{2}\) and the heat flux \(q_{b}^{\prime \prime}\). (b) For the prescribed conditions, what is the rate at which radiation emitted by the ceramic is intercepted by the detector?

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