/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 A boiler used to generate satura... [FREE SOLUTION] | 91Ó°ÊÓ

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A boiler used to generate saturated steam is in the form of an unfinned, cross-flow heat exchanger, with water flowing through the tubes and a high- temperature gas in cross flow over the tubes. The gas, which has a specific heat of \(1120 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) and a mass flow rate of \(10 \mathrm{~kg} / \mathrm{s}\), enters the heat exchanger at \(1400 \mathrm{~K}\). The water, which has a flow rate of \(3 \mathrm{~kg} / \mathrm{s}\), enters as saturated liquid at \(450 \mathrm{~K}\) and leaves as saturated vapor at the same temperature. If the overall heat transfer coefficient is \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and there are 500 tubes, each of \(0.025-\mathrm{m}\) diameter, what is the required tube length?

Short Answer

Expert verified
The required tube length for the boiler is approximately 7.48 meters.

Step by step solution

01

Calculate the heat transfer from the gas side

Using the information provided, we can find the heat transfer from the gas side. Gas specific heat: \(C_{p,g} = 1120 \, \mathrm{J / kg \cdot K}\) Gas mass flow rate: \(\dot{m}_{g} = 10 \, \mathrm{kg / s}\) Gas temperature difference: \(ΔT_{g} = T_{g,in} - T_{g,out}\) We are given that: Gas enters the heat exchanger at \(T_{g,in} = 1400 \, \mathrm{K}\). The water enters at 450 K, leaves at the same temperature, and undergoes a phase change. Since the overall heat transfer coefficient remains constant, we can assume that the temperature difference between the gas and water remains constant. Therefore, we can say that: Gas exits the heat exchanger at \(T_{g,out} = 450 \, \mathrm{K}\). Now, let's find the temperature difference and heat transfer of the gas: Temperature difference: \(ΔT_{g} = T_{g,in} - T_{g,out} = 1400 - 450 = 950 \, \mathrm{K}\) Heat transfer from the gas side: \(Q_{g} = \dot{m}_{g} * C_{p,g} * ΔT_{g} = 10 * 1120 * 950 = 10,640,000 \, \mathrm{W}\)
02

Calculate the heat transfer from the water side

We are given that water leaves the heat exchanger as saturated vapor at 450 K. We can use steam tables to find the enthalpy change of the water. Water mass flow rate: \(\dot{m}_{w} = 3 \, \mathrm{kg / s}\) Water enthalpy change: \(Δh_{w} = h_{fg} = 2200 \, \mathrm{kJ / kg}\) (approximate value from steam tables at 450 K) Now, let's find the heat transfer of the water side: Heat transfer from the water side: \(Q_{w} = \dot{m}_{w} * Δh_{w} = 3 * 2200 * 10^3 = 6,600,000 \, \mathrm{W}\)
03

Equate heat transfer from both sides and calculate the required area

In a heat exchanger, the heat transfer from the gas side must be equal to the heat transfer from the water side: \(Q_{g} = Q_{w}\) \(10,640,000 = 6,600,000\) Overall heat transfer coefficient: \(U = 50\,\mathrm{W/m^2.K}\) Now, let's find the required heat transfer area (A): \(A = \frac{Q_{w}}{U * ΔT_{w}} = \frac{6,600,000}{50 * 450} = 293.3 \, \mathrm{m^2}\)
04

Calculate the required tube length

We are given that there are 500 tubes of 0.025-m diameter in the heat exchanger. We can calculate the tube length (L) using the formula for the surface area of a cylinder: Surface area of a single tube: \(A = πDL\) Total surface area: \(A_{total} = N * A = 500 * π(0.025)L\) Now, let's calculate the tube length: \(293.3 = 500 * π(0.025)L\) \(L = \frac{293.3}{500 * π(0.025)} = 7.481\,\mathrm{m}\) The required tube length is approximately 7.48 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boiler Heat Transfer
Understanding boiler heat transfer is crucial for many industrial applications, particularly in generating saturated steam. In our scenario, we have an unfinned cross-flow heat exchanger in a boiler system. To maximize efficiency, the design aims to transfer heat from a high-temperature gas to water, converting it into steam.

To optimize this process, we first look at the specific heat of the gas—which is a measure of the heat energy required to raise the temperature of a unit mass of a substance by one degree. In this case, the gas has a specific heat of 1120 J/kg.K. With the gas entering at 1400 K and exiting at a much lower temperature, it's clear that a considerable temperature differential exists, which drives the heat transfer process.

It's important to note that the efficiency of heat transfer in a boiler doesn't rely only on temperature differences and mass flow rates but also on the characteristics of the exchanger surface. The textures, materials, and dimensions of the tubes all affect how well heat is transferred from the gas to the water. In our example, heat is effectively transferred because the high temperature and flow rate of the gas maximize the energy available to convert the liquid water into saturated steam.
Saturated Steam Generation
The generation of saturated steam is central to many industrial processes, including power generation and heating applications. In our exercise, water enters the heat exchanger as a saturated liquid at 450 K and leaves as saturated vapor at the same temperature. This change of phase from liquid to vapor at a constant temperature is a significant aspect of saturated steam generation.

To achieve efficient steam generation, it's crucial that the water receives enough heat to undergo this phase change. This is where the enthalpy change comes into play. Enthalpy is a thermodynamic quantity equivalent to the total heat content of a system. The enthalpy change of water, often found in steam tables, provides a measurement of the energy needed for water at a given pressure to become steam.

In terms of practical design, this means that the system must be capable of supplying sufficient heat to match this enthalpy change. Otherwise, the water won't fully convert into steam. The careful balance of flow rates, temperatures, and properties of the substances involved is necessary to ensure complete steam generation.
Overall Heat Transfer Coefficient
The overall heat transfer coefficient is a measure that combines all the resistances to heat transfer in a system into a single value. It’s fundamental to heat exchanger design, helping engineers asses how effectively a heat exchanger can move thermal energy from one fluid to another. For our boiler, the stated overall heat transfer coefficient is 50 W/m^2.K. The higher this coefficient, the more efficient the heat transfer.

However, achieving a high overall heat transfer coefficient requires careful consideration of several factors. These include the conductance of the tube material, the convection on both the inside and the outside of the tubes, and any fouling or scaling that may occur, which can significantly decrease efficiency. In this instance, the given coefficient suggests an effective design, allowing for sufficient heat transfer to generate the necessary amount of steam while balancing the energy input and costs.

In the context of the problem, balancing the overall heat transfer coefficient against the amount of surface area available from the 500 tubes must be managed to ensure that enough heat is transferred to vaporize the water. The coefficient influences the required length of the tubes in the exchanger, ensuring optimal design to satisfy the steam generation needs.

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Most popular questions from this chapter

Ethylene glycol and water, at 60 and \(10^{\circ} \mathrm{C}\), respectively, enter a shell-and-tube heat exchanger for which the total heat transfer area is \(15 \mathrm{~m}^{2}\). With ethylene glycol and water flow rates of 2 and \(5 \mathrm{~kg} / \mathrm{s}\), respectively, the overall heat transfer coefficient is \(800 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Determine the rate of heat transfer and the fluid outlet temperatures. (b) Assuming all other conditions to remain the same, plot the effectiveness and fluid outlet temperatures as a function of the flow rate of ethylene glycol for \(0.5 \leq \dot{m}_{h} \leq 5 \mathrm{~kg} / \mathrm{s}\).

Cooling of outdoor electronic equipment such as in telecommunications towers is difficult due to seasonal and diurnal variations of the air temperature, and potential fouling of heat exchange surfaces due to dust accumulation or insect nesting. A concept to provide a nearly constant sink temperature in a hermetically sealed environment is shown below. The cool surface is maintained at nearly constant groundwater temperature \(\left(T_{1}=5^{\circ} \mathrm{C}\right)\) while the hot surface is subjected to a constant heat load from the electronic equipment \(\left(q_{2}=50 \mathrm{~W}, T_{2}\right)\). Connecting the surfaces is a concentric tube of length \(L=10 \mathrm{~m}\) with \(D_{i}=100 \mathrm{~mm}\) and \(D_{o}=150 \mathrm{~mm}\). A fan moves air at a mass flow rate of \(m=0.0325 \mathrm{~kg} / \mathrm{s}\) and dissipates \(P=10 \mathrm{~W}\) of thermal energy. Heat transfer to the cool surface is described by \(q_{1}^{N}=\bar{h}_{1}\left(T_{h_{1} o}-T_{1}\right)\) while heat transfer from the hot surface is described by \(q_{2}^{\prime \prime}=\bar{h}_{2}\left(T_{2}-T_{f_{0}}\right)\) where \(T_{f_{0}}\) is the fan outlet temperature. The values of \(\bar{h}_{1}\) and \(h_{2}\) are 40 and \(60 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. To isolate the electronics from ambient temperature variations, the entire device is insulated at its outer surfaces. The design engineer is concerned that conduction through the wall of the inner tube may adversely affect the device performance. Determine the value of \(T_{2}\) for the limiting cases of (i) no conduction resistance in the inner tube wall and (ii) infinite conduction resistance in the inner tube wall. Does the proposed device maintain maximum temperatures below \(80^{\circ} \mathrm{C}\) ?

Consider Problem 11.36. (a) For \(\dot{m}_{c \mathrm{CA}}=\dot{m}_{\mathrm{h}, \mathrm{B}}=10 \mathrm{~kg} / \mathrm{s}\), determine the outlet air and ammonia temperatures, as well as the heat transfer rate. (b) Plot the outlet air and outlet ammonia temperatures versus the water flow rate over the range \(5 \mathrm{~kg} / \mathrm{s} \leq \dot{m}_{c, \mathrm{~A}}=m_{h, \mathrm{~B}} \leq 50 \mathrm{~kg} / \mathrm{s}\).

A counterflow, concentric tube heat exchanger is designed to heat water from 20 to \(80^{\circ} \mathrm{C}\) using hot oil, which is supplied to the annulus at \(160^{\circ} \mathrm{C}\) and discharged at \(140^{\circ} \mathrm{C}\). The thin-walled inner tube has a diameter of \(D_{i}=20 \mathrm{~mm}\), and the overall heat transfer coefficient is \(500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The design condition calls for a total heat transfer rate of \(3000 \mathrm{~W}\). (a) What is the length of the heat exchanger? (b) After 3 years of operation, performance is degraded by fouling on the water side of the exchanger, and the water outlet temperature is only \(65^{\circ} \mathrm{C}\) for the same fluid flow rates and inlet temperatures. What are the corresponding values of the heat transfer rate, the outlet temperature of the oil, the overall heat transfer coefficient, and the water- side fouling factor, \(R_{f,}^{n}\) ?

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