/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Consider a coupled shell-in-tube... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider a coupled shell-in-tube heat exchange device consisting of two identical heat exchangers \(A\) and \(B\). Air flows on the shell side of heat exchanger A, entering at \(T_{h, i, \mathrm{~A}}=520 \mathrm{~K}\) and \(\dot{m}_{h, \mathrm{~A}}=10 \mathrm{~kg} / \mathrm{s}\). Ammonia flows in the shell of heat exchanger \(B\), entering at \(T_{c, i \mathrm{~B}}=280 \mathrm{~K}, m_{c, \mathrm{~B}}=5 \mathrm{~kg} / \mathrm{s}\). The tube-side flow is common to both heat exchangers and consists of water at a flow rate \(\dot{m}_{c, \mathrm{~A}}=\dot{m}_{\hat{h, B}}\) with two tube passes. The UA product increases with water flow rate for heat exchanger A as expressed by the relation \(U A_{\mathrm{A}}=a+\) \(b \dot{m}_{c, \mathrm{~A}}\) where \(a=6000 \mathrm{~W} / \mathrm{K}\) and \(b=100 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). For heat exchanger \(\mathrm{B}, U A_{\mathrm{B}}=1.2 U A_{\mathrm{A}}\). (a) For \(\dot{m}_{c, \mathrm{~A}}=\dot{m}_{k, \mathrm{~B}}=1 \mathrm{~kg} / \mathrm{s}\), determine the outlet air and ammonia temperatures, as well as the heat transfer rate. (b) The plant engineer wishes to fine-tune the heat exchanger performance by installing a variablespeed pump to allow adjustment of the water flow rate. Plot the outlet air and outlet ammonia temperatures versus the water flow rate over the range \(0 \mathrm{~kg} / \mathrm{s} \leq \dot{m}_{c \mathrm{~A}}=m_{\mathrm{h}, \mathrm{B}} \leq 2 \mathrm{~kg} / \mathrm{s}\).

Short Answer

Expert verified
In summary, to analyze the coupled shell-in-tube heat exchangers A and B, we calculate the \(UA_{A}\) and \(UA_{B}\) products for the given mass flow rates and use the \(\epsilon-NTU\) method to find the outlet air and ammonia temperatures. For a water flow rate of \(1 kg/s\), we find the corresponding \(UA_{A} = 6100 W/K\) and \(UA_{B} = 7320 W/K\) values. We use these to determine the outlet temperatures \(T_{h,o,~A}\) and \(T_{c,o,~B}\). To analyze the performance in the given range of water flow rates, we plot the outlet temperatures for various \(\dot{m}_{c, ~A}\) values in the range \(0 \leq \dot{m}_{c,~A} = \dot{m}_{h,~B} \leq 2 kg/s\). This plot helps the plant engineer optimize the heat exchanger performance by selecting the appropriate water flow rate.

Step by step solution

01

Calculation of UA products for A and B

We need to calculate \(UA_{A}\) and \(UA_{B}\) for the given mass flow rates. Using the given relation for \(UA_{A}\) and knowing that \(UA_{B} = 1.2UA_{A}\), we have: \(UA_{A} = a + b \dot{m}_{c, ~A}\) \(UA_{B} = 1.2 UA_{A}\) For \(\dot{m}_{c, ~A} = \dot{m}_{k,\mathrm{~B}} = 1 kg/s\), \(UA_{A} = 6000 + 100 (1) = 6100 W/K\) \(UA_{B} = 1.2 (6100) = 7320 W/K\)
02

Energy Balance Equations

To find the outlet air and ammonia temperatures, we need to establish the energy balance equations for both heat exchangers. We know that the heat gained by the cold fluid (water) equals the heat lost by the hot fluid (air or ammonia). Therefore, For heat exchanger A, \(Q_{A} = m_{h,~A} C_{p,h} (T_{h,i,~A} - T_{h,o,~A}) = m_{c,~A} C_{p,c} (T_{co,~A} - T_{ci,~A})\) For heat exchanger B, \(Q_{B} = m_{c,~B} C_{p,c} (T_{c,o,~B} - T_{c,i,~B}) = m_{h,~B} C_{p,h} (T_{ho,~A} - T_{ho,~B})\)
03

Calculate the outlet air and ammonia temperatures

To calculate the outlet air and ammonia temperatures, we need to use the \(\epsilon-NTU\) method. The effectiveness (\(\epsilon\)) can be calculated as: \(\epsilon = \frac{Q}{Q_{max}} = \frac{Q}{\dot{m} C_{p,min} (T_{h,i} - T_{c,i})}\) For heat exchangers A and B: \(\epsilon_A = \frac{1-e^{-NTU_{A}(1-CR_{A})}}{1+CR_{A}(1-e^{-NTU_{A}(1-CR_{A})})}\) \(\epsilon_B = \frac{1-e^{-NTU_{B}(1-CR_{B})}}{1+CR_{B}(1-e^{-NTU_{B}(1-CR_{B})})}\) where \(NTU_A = \cfrac{UA_{A}}{\dot{m}_{c,A} C_{p,c}},\) \(NTU_B = \cfrac{UA_{B}}{\dot{m}_{h,B} C_{p,h}},\) \(CR_A = \cfrac{\dot{m}_{h,A} C_{p,h}}{\dot{m}_{c,A} C_{p,c}},\) \(CR_B = \cfrac{\dot{m}_{c,B} C_{p,c}}{\dot{m}_{h,B} C_{p,h}}.\) Using the given quantities, temperatures, and specific heat capacities, we can calculate the outlet air and ammonia temperatures using the energy balance equations stated in Step 2.
04

Plot outlet air and ammonia temperatures as a function of water flow rate

To analyze the performance of both heat exchangers in the given range of water flow rates, we will plot \(T_{h,o,~A}\), and \(T_{c,o,~B}\) as a function of \(\dot{m}_{c, ~A}\) in the range \(0 \leq \dot{m}_{c,~A} = \dot{m}_{h,~B} \leq 2 kg/s\). This can be done by repeating Steps 1-3 for each data point in the specified range and plotting the results. The resulting plot will allow the plant engineer to visualize the relationship between the water flow rate and the outlet air and ammonia temperatures, which can in turn be used to optimize the heat exchanger performance by installing a variable-speed pump.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Shell-and-Tube Heat Exchanger
Shell-and-tube heat exchangers are widely used in industries due to their effectiveness and versatility. They consist of a series of tubes, one set inside another larger shell, allowing different fluids to flow through either the tubes or the shell. This configuration facilitates the transfer of heat between the hot fluid, which flows on one side, and the cold fluid on the other side.

In the exercise, we discuss a heat exchanger where air and ammonia serve as the hot and cold fluids. The water flows through the tubes, while air or ammonia flows on the shell side in respective heat exchangers A and B. This setup is efficient for applications that require a significant transfer of heat due to the large surface area provided by the tubes.

Several key components enhance the performance of a shell-and-tube heat exchanger, such as baffling to direct fluid flow and promote turbulent mixing, which improves heat transfer rates. The design may also allow for simple maintenance and cleaning, all vital in maintaining optimal operation.
Thermal Energy Balance
A critical aspect of any heat exchanger system is the thermal energy balance. It involves ensuring that the energy lost by the hot fluid is equal to the energy gained by the cold fluid. This principle is vital for calculating outlet temperatures and the heat transfer rate.

In heat exchanger A, where air is the hot fluid, you apply the balance by calculating: \[ Q_A = \dot{m}_{h,A} C_{p,h} (T_{h,i,A} - T_{h,o,A}) = \dot{m}_{c,A} C_{p,c} (T_{c,o,A} - T_{c,i,A}) \] Similarly, for heat exchanger B with ammonia, the equation looks like: \[ Q_B = \dot{m}_{c,B} C_{p,c} (T_{c,o,B} - T_{c,i,B}) = \dot{m}_{h,B} C_{p,h} (T_{h,i,B} - T_{h,o,B}) \]

These equations are grounded on the conservation of energy, ensuring none is lost or unaccounted for in the exchanger. They serve as fundamental tools in determining how effectively the system operates.
NTU Method
The NTU (Number of Transfer Units) method is a cornerstone in the analysis of heat exchangers. It provides a way to calculate the heat exchanger's effectiveness without needing to know the exact outlet temperatures initially.

The effectiveness \( \epsilon \) describes how well the heat exchanger performs compared to an ideal version with infinite heat transfer area. The NTU is calculated using the product of the overall heat transfer coefficient and the heat transfer area relative to the heat capacities of the fluids:

For exchanger A: \[ NTU_A = \frac{UA_{A}}{\dot{m}_{c,A} C_{p,c}} \]

And for exchanger B:\[ NTU_B = \frac{UA_{B}}{\dot{m}_{h,B} C_{p,h}} \]

The NTU method allows the determination of \( \epsilon \), which can then be used to find outlet temperatures. Understanding NTU is vital for designing and optimizing heat exchangers, as it connects heat exchanger size, flow rates, and thermodynamic properties.
Effectiveness of Heat Exchangers
Effectiveness, symbolized as \( \epsilon \), quantifies how well a heat exchanger transfers heat compared to an ideal exchanger. The ideal one would have infinity large area, achieving maximum possible heat transfer. The use of \( \epsilon \) in practical calculations assists in understanding real-world performance.The effectiveness can be expressed as:\[ \epsilon = \frac{Q}{Q_{max}} = \frac{Q}{\dot{m} C_{p,min} (T_{h,i} - T_{c,i})} \]Here, \(Q\) is the actual heat transfer, and \(Q_{max}\) represents the theoretical maximum heat transfer rate. A higher effectiveness indicates a more efficient exchanger.In our heat exchanger setup, the effectiveness equations for A and B are as follows:\[ \epsilon_{A} = \frac{1-e^{-NTU_{A}(1-CR_{A})}}{1+CR_{A}(1-e^{-NTU_{A}(1-CR_{A})})} \]\[ CR_{A} = \frac{\dot{m}_{h,A} C_{p,h}}{\dot{m}_{c,A} C_{p,c}} \]And similarly for B minus the key parameters. Understanding effectiveness helps engineers fine-tune systems like the one proposed with a variable-speed pump to maximize efficiency under different conditions.

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Most popular questions from this chapter

Water is used for both fluids (unmixed) flowing through a single-pass, cross- flow heat exchanger. The hot water enters at \(90^{\circ} \mathrm{C}\) and \(10,000 \mathrm{~kg} / \mathrm{h}\), while the cold water enters at \(10^{\circ} \mathrm{C}\) and \(20,000 \mathrm{~kg} / \mathrm{h}\). If the effectiveness of the exchanger is \(60 \%\), determine the cold water exit temperature.

Consider a Rankine cycle with saturated steam leaving the boiler at a pressure of \(2 \mathrm{MPa}\) and a condenser pressure of \(10 \mathrm{kPa}\). (a) Calculate the thermal efficiency of the ideal Rankine cycle for these operating conditions. (b) If the net reversible work for the cycle is \(0.5 \mathrm{MW}\), calculate the required flow rate of cooling water supplied to the condenser at \(15^{\circ} \mathrm{C}\) with an allowable temperature rise of \(10^{\circ} \mathrm{C}\). (c) Design a shell-and-tube heat exchanger (one-shell, multiple-tube passes) that will meet the heat rate and temperature conditions required of the condenser. Your design should specify the number of tubes and their diameter and length.

Consider a concentric tube heat exchanger characterized by a uniform overall heat transfer coefficient and operating under the following conditions: \begin{tabular}{lccrc} \hline & \(\dot{m}\) \((\mathbf{k g} / \mathbf{s})\) & \(c_{p}\) \((\mathbf{J} / \mathbf{k g} \cdot \mathbf{K})\) & \(T_{i}\) \((\boldsymbol{C})\) & \(T_{o}\) \((\mathbf{C})\) \\ \hline Cold fluid & \(0.125\) & 4200 & 40 & 95 \\ Hot fluid & \(0.125\) & 2100 & 210 & \(-\) \\ \hline \end{tabular} What is the maximum possible heat transfer rate? What is the heat exchanger effectiveness? Should the heat exchanger be operated in parallel flow or in counterflow? What is the ratio of the required areas for these two flow conditions?

A cross-flow heat exchanger used in a cardiopulmonary bypass procedure cools blood flowing at \(5 \mathrm{~L} / \mathrm{min}\) from a body temperature of \(37^{\circ} \mathrm{C}\) to \(25^{\circ} \mathrm{C}\) in order to induce body hypothermia, which reduces metabolic and oxygen requirements. The coolant is ice water at \(0^{\circ} \mathrm{C}\), and its flow rate is adjusted to provide an outlet temperature of \(15^{\circ} \mathrm{C}\). The heat exchanger operates with both fluids unmixed, and the overall heat transfer coefficient is \(750 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The density and specific heat of the blood are \(1050 \mathrm{~kg} / \mathrm{m}^{3}\) and \(3740 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), respectively. a) Determine the heat transfer rate for the exchanger. b) Calculate the water flow rate. c) What is the surface area of the heat exchanger? d) Calculate and plot the blood and water outlet temperatures as a function of the water flow rate for the range 2 to \(4 \mathrm{~L} / \mathrm{min}\), assuming all other parameters remain unchanged. Comment on how the changes in the outlet temperatures are affected by changes in the water flow rate. Explain this behavior and why it is an advantage for this application.

Thin-walled aluminum tubes of diameter \(D=10 \mathrm{~mm}\) are used in the condenser of an air conditioner. Under normal operating conditions, a convection coefficient of \(h_{i}=5000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) is associated with condensation on the inner surface of the tubes, while a coefficient of \(h_{o}=100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) is maintained by airflow over the tubes. (a) What is the overall heat transfer coefficient if the tubes are unfinned? (b) What is the overall heat transfer coefficient based on the inner surface, \(U_{i}\), if aluminum annular fins of thickness \(t=1.5 \mathrm{~mm}\), outer diameter \(D_{o}=20 \mathrm{~mm}\), and pitch \(S=3.5 \mathrm{~mm}\) are added to the outer surface? Base your calculations on a 1-m-long section of tube. Subject to the requirements that \(t \geq 1 \mathrm{~mm}\) and \((S-t) \geq 1.5 \mathrm{~mm}\), explore the effect of variations in \(t\) and \(S\) on \(U_{i}\). What combination of \(t\) and \(S\) would yield the best heat transfer performance?

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