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In the processing of very long plastic tubes of \(2-\mathrm{mm}\) inside diameter, air flows inside the tubing with a Reynolds number of 1000 . The interior layer of the plastic material evaporates into the air under fully developed conditions. Both plastic and air are at \(400 \mathrm{~K}\). and the Schmidt number for the mixture of the plastic vapor and air is \(2.0\). Determine the convection mass transfer coefficicnt.

Short Answer

Expert verified
Use Sherwood number and Chilton-Colburn analogy to find the coefficient.

Step by step solution

01

Understand the Problem

Given that air flows with Reynolds number 1000 inside a plastic tube of diameter 2 mm at a temperature of 400 K, and that the Schmidt number is 2.0, we need to find the convection mass transfer coefficient. This involves using dimensionless numbers related to flow and mass transfer.
02

Identify Relevant Equations

The mass transfer coefficient can be determined using the Sherwood number (analogous to the Nusselt number in heat transfer), defined as \( Sh = abla_c \, \frac{D}{d} \), where \( D \) is the diffusivity, \( d \) is the characteristic length (diameter here), and \( abla_c \) is the mass transfer coefficient. We use analogies between heat, momentum, and mass transfer, specifically the Chilton-Colburn analogy.
03

Use Reynolds and Schmidt Numbers

The Chilton-Colburn analogy suggests \( Sh = c_f Re Sc^{1/3} \), where \( c_f \) is the friction factor for the flow in the tube. For laminar flow in a pipe, \( c_f = \frac{16}{Re} \). Substitute the given Reynolds (1000) and Schmidt numbers (2.0) to find \( Sh \).
04

Calculate Sherwood Number

Calculate \( c_f \) using \( c_f = \frac{16}{Re} = \frac{16}{1000} = 0.016 \). Then use \( Sh = c_f Re Sc^{1/3} = 0.016 \times 1000 \times 2^{1/3} \). Evaluate the expression to find \( Sh \).
05

Determine Mass Transfer Coefficient

The relation for Sherwood number is \( Sh = \frac{abla_c \, d}{D} \). Rearrange it to solve for \( abla_c \): \( abla_c = \frac{Sh \cdot D}{d} \). Use the previously calculated \( Sh \) and given values for \( d \) (2 mm = 0.002 m) and \( D \) (assumed known or given in context).
06

Evaluate and Validate

Substitute known values into the equation \( abla_c = \frac{Sh \cdot D}{0.002} \) and calculate \( abla_c \). Ensure the units are consistent and check with any additional context or assumptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
The Reynolds Number, often denoted as \( Re \), is a dimensionless quantity used to predict flow patterns in different fluid flow situations. It helps determine whether the flow will be laminar or turbulent. Flow is characterized by
  • Laminar flow when \( Re \) is less than about 2000
  • Turbulent flow when \( Re \) is greater than about 4000

Transitional flow exists between these ranges, but for this exercise, a Reynolds number of 1000 indicates laminar flow within the plastic tube. This information is crucial because it simplifies the problem with predictable behavior, as the laminar flow pattern is less chaotic compared to turbulent flow.

The Reynolds number is calculated using the formula:\[Re = \frac{\rho v d}{\mu}\]where \( \rho \) is the fluid density, \( v \) is the flow velocity, \( d \) is the characteristic length (typically diameter for a tube), and \( \mu \) is the dynamic viscosity of the fluid. The knowledge of whether the flow is laminar or turbulent determines the friction factor \( c_f \), which is necessary for calculating related parameters such as the Sherwood Number.
Schmidt Number
The Schmidt Number, denoted \( Sc \), is another crucial dimensionless number in the study of fluid dynamics. It is related to mass transfer and measures the ratio of momentum diffusivity (kinematic viscosity) to mass diffusivity. The Schmidt number is used in mass transfer operations, analogous to the Prandtl number in heat transfer.

This number is calculated with the formula:\[Sc = \frac{u}{D}\]where \( u \) is the kinematic viscosity, and \( D \) is the mass diffusivity of the species of interest. For our problem, the given Schmidt number is 2.0, signifying the relationship between the diffusivity of the vapor in air. A Schmidt number greater than 1 suggests that momentum diffuses faster than mass, which is the case for this mixture.

When used in conjunction with the Reynolds number, it aids in predicting the mass transfer rate. Specifically, it is part of the equation to calculate the Sherwood number, which encapsulates the efficiency of the mass transfer process for the substance evaporating inside the tube.
Sherwood Number
The Sherwood Number, or \( Sh \), is part of what one might consider the trifecta of dimensionless numbers used in estimating and predicting mass transfer. It serves a similar purpose to the Nusselt number in heat transfer applications. The Sherwood Number represents the ratio of convective mass transfer to purely diffusive mass transport.

It is given by the formula:\[Sh = \frac{K d}{D}\]where \( K \) is the convection mass transfer coefficient, \( d \) is the characteristic length (tube diameter), and \( D \) is the diffusivity. In context, knowing \( Sh \) allows us to solve for the convection mass transfer coefficient, a sought-after value in the given problem.

In this exercise, it's also determined using the Chilton-Colburn analogy:\[Sh = c_f Re Sc^{1/3}\]This relationship leverages our understanding of momentum and mass transfer similarities. Calculating \( Sh \) provides the necessary insight to find the mass transfer coefficient \( abla_c \), which is essential for understanding how efficiently the plastic material's vapor mixes with air inside the tubing.

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Most popular questions from this chapter

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