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An annular aluminum fin of rectangular profile is attached to a circular tube having an outside diameter of \(25 \mathrm{~mm}\) and a surface temperature of \(250^{\circ} \mathrm{C}\). The fin is \(1 \mathrm{~mm}\) thick and \(10 \mathrm{~mm}\) long, and the temperature and the convection coefficient associated with the adjoining fluid are \(25^{\circ} \mathrm{C}\) and \(25 \mathrm{~W} / \mathrm{m}^{2}\) + \(\mathrm{K}\), respectively. (a) What is the heat loss per fin? (b) If 200 such fins are spaced at 5-mm increments along the tube length, what is the heat loss per meter of tube length?

Short Answer

Expert verified
(a) Calculate heat loss per fin using the formula for fin heat transfer rate. (b) Multiply by 200 for the heat loss per meter with 200 fins.

Step by step solution

01

Fin Parameters Identification

Identify the given parameters of the fin and the surrounding environment. The tube diameter is given as \( D = 25 \text{ mm} \) or \( 0.025 \text{ m} \), the fin thickness is \( T = 1 \text{ mm} \) or \( 0.001 \text{ m} \), and the fin length is \( L = 10 \text{ mm} \) or \( 0.01 \text{ m} \). The base temperature \( T_b = 250^{\circ} \text{C} \), fluid temperature \( T_\infty = 25^{\circ} \text{C} \), and convection coefficient \( h = 25 \text{ W/m}^2/\text{K} \).
02

Calculate Fin Area

Calculate the area of the fin. The fin is a rectangular profile extending around the cylinder, thus the perimeter \( P = \pi \times D = \pi \times 0.025 \), and the area \( A_c = P \times T = (\pi \times 0.025) \times 0.001 \).
03

Determine Heat Transfer Rate

Use the fin heat transfer rate equation for a rectangular fin:\[q_f = P \sqrt{h k A_c (T_b - T_\infty)} \tanh\left(\frac{L}{\sqrt{\frac{k}{h}}}\right)\]where \( k \) is the thermal conductivity of aluminum (typically \( k = 237 \text{ W/m} \cdot \text{K} \)). Substitute the values to find \( q_f \).
04

Heat Loss from Single Fin

After computing the value of heat transfer rate \( q_f \) using the parameters in the equation, you will find the heat loss for a single fin. Use the calculated \( P \), \( A_c \), ,and constants \( h \), \( k \), \( T_b \), \( T_\infty \) with appropriate calculations to conclude the value of \( q_f \).
05

Heat Loss for Multiple Fins

To find the heat loss per meter of tube length, multiply the heat loss from a single fin \( q_f \) by the number of fins over a meter. Calculate the number of fins: A 5-mm increment spacing with a 1-mm thick fin gives us 200 fins per meter. Thus, the total heat loss \( Q \) is \( 200 \times q_f \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Annular Fins
Annular fins are an effective solution for improving heat dissipation from cylindrical surfaces, such as pipes or tubes. They are essentially flat plates that encircle the tube, extending from the surface to increase the overall area exposed to the surrounding medium. By increasing the surface area, annular fins facilitate a greater rate of heat loss from the tube to the surroundings. This is particularly beneficial for enhancing the thermal performance of systems like radiators or heat exchangers.

The construction of annular fins is typically characterized by critical dimensions: thickness, outer radius, and the length or depth from the base to the fin tip. Their geometry allows them to encircle the tube, and when heat is conducted from the base towards the tip, it is simultaneously being convected from all sides. Thus, the sensitivity of these fins to environmental factors, such as convection heat transfer coefficients, is paramount in their effectiveness.

When applying annular fins, it's essential to consider the material since thermal conductivity plays a significant role in determining their efficiency.
Convection Heat Transfer
Convection heat transfer is a critical mechanism by which heat is exchanged between a solid surface and a fluid (like air or water) in motion. This process is vital in many engineering applications, including cooling and heating systems.

In the context of the problem, convection heat transfer occurs between the fin and the surrounding fluid. The convection heat transfer coefficient, denoted by \( h \), is a measure of the convection intensity and depends on several factors like the flow type (laminar or turbulent) and fluid properties. Here, \( h \) is given as 25 W/m²·K.
  • An increase in \( h \) implies more effective heat dissipation.
  • Convection can be enhanced by increasing fluid flow or improving fin design.
To determine heat loss, we must consider both conduction within the fin and convection to the surrounding fluid.
Thermal Conductivity
Thermal conductivity is a property of a material that indicates its ability to conduct heat. Represented by the letter \( k \), it is expressed in units of W/m·K. High thermal conductivity in a material means it can transfer heat effectively across its length.

In this scenario, the material in question is aluminum, widely regarded for its excellent thermal conductivity, with a typical value of \( k = 237 \text{ W/m} \cdot \text{K} \). This property plays a pivotal role in how efficiently the fin conducts heat from the tube surface to its extended surface area.
  • Metals like aluminum are preferred for their superior thermal conductive properties.
  • A higher \( k \) ensures that heat is evenly spread across the fin, enhancing its effectiveness.
Understanding the thermal conductivity allows for the effective design of fins to maximize heat dissipation.
Heat Loss Calculation
Calculating heat loss in a fin system involves understanding both the conductive and convective components of heat transfer. The goal is to determine the amount of heat dissipation from the fin into the surrounding environment.

For a single fin, this is achieved by using established equations, such as the fin heat transfer rate formula. The calculation considers:
  • The perimeter of the fin \( P \).
  • Cross-sectional area \( A_c \).
  • The temperature difference \( T_b - T_\infty \).
  • Material thermal conductivity \( k \).
After determining the heat loss for one fin, we can extend this to find the total heat loss per meter of tube length by multiplying the individual fin heat loss by the total number of fins, given by the spacing and fin dimensions.

This approach enables thermal system designers to predict and optimize the thermal performance of finned surfaces effectively.

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Most popular questions from this chapter

A plane wall of thickness \(0.1 \mathrm{~m}\) and thermal conductiv ity \(25 \mathrm{~W} / \mathrm{m}\), K having uniform volumetric heat generation of \(0.3 \mathrm{MW} / \mathrm{m}^{3}\) is insulated on one side, while the other side is exposed to a fluid at \(92^{\circ} \mathrm{C}\). The convection heat transfer coefficient between the wall and the fluid is \(500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Determine the maximum temperature in the wall.

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