/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 128 A radiator on a proposed satelli... [FREE SOLUTION] | 91影视

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A radiator on a proposed satellite solar power station must dissipate beat being generated within the satellite by madiating it into space. The radiator surface has a solar absorptivity of \(0.5\) and an emissivity of \(0.95\). What is the equilibrium surface temperature when the solar irradiation is \(1000 \mathrm{~W} / \mathrm{m}^{2}\) and the required heat dissipation is 1500 W/m \({ }^{2}\) ?

Short Answer

Expert verified
The equilibrium surface temperature is approximately 364 K.

Step by step solution

01

Understand the Problem

We need to find the equilibrium surface temperature of a radiator on a satellite that is absorbing solar energy and emitting thermal radiation. Given: the solar absorptivity \( \alpha = 0.5 \), the emissivity \( \varepsilon = 0.95 \), solar irradiation \( G = 1000 \text{ W/m}^2 \), and the required heat dissipation \( Q = 1500 \text{ W/m}^2 \).
02

Apply Energy Balance Equation

The energy absorbed by the radiator due to solar radiation is \( \alpha G \). The energy emitted is given by the Stefan-Boltzmann Law: \( \varepsilon \sigma T^4 \), where \( \sigma = 5.67 \times 10^{-8} \text{ W/m}^2 \text{K}^4 \) is the Stefan-Boltzmann constant.
03

Set Up the Equation

For equilibrium, the absorbed power must equal the emitted power plus the required heat dissipation. Thus: \[ \alpha G + Q = \varepsilon \sigma T^4 \]. Substitute the given values into the equation: \[ 0.5 \times 1000 + 1500 = 0.95 \times 5.67 \times 10^{-8} \times T^4 \].
04

Solve for Temperature \( T \)

Substitute the values and solve for \( T \) numerically. First rewrite: \[ 500 + 1500 = 0.95 \times 5.67 \times 10^{-8} \times T^4 \] \[ 2000 = 0.95 \times 5.67 \times 10^{-8} \times T^4 \]. Now, solve for \( T^4 \) by dividing: \[ T^4 = \frac{2000}{0.95 \times 5.67 \times 10^{-8}} \]. The approximate computation results in \[ T^4 \approx 36903423.97 \]. Taking the fourth root gives \( T \approx 364 \text{ K} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiative Heat Transfer
Radiative heat transfer is the process of heat energy transferring from one body to another through electromagnetic waves. Unlike conduction or convection, it doesn't require a medium to transfer heat. This form of heat transfer is significant in space where conduction or convection are not feasible. In simpler terms, radiative heat transfer is how objects emit and absorb thermal radiation. Every object emits radiation depending on its temperature, and when this energy reaches another object, it can be absorbed, increasing the latter's thermal energy.
In the context of satellite systems, radiative heat transfer is used to dissipate excess heat generated by internal systems into the vast emptiness of space. The efficiency with which a satellite radiates heat affects the temperature regulation onboard. This is crucial for maintaining the operational integrity of the satellite.
*Key features of radiative heat transfer include:*
  • It depends on the surface properties of the object, such as emissivity and absorptivity.
  • Emissivity, \( \varepsilon \), is a measure of how well a surface emits radiation compared to a perfect blackbody.
  • Absorptivity, \( \alpha \), measures how much radiation is absorbed compared to the total incoming radiation.
Stefan-Boltzmann Law
The Stefan-Boltzmann Law is a fundamental principle in physics that describes the power radiated from a blackbody in terms of its temperature. The law states that the total energy radiated per unit surface area of a blackbody across all wavelengths each second (also known as the blackbody's radiant emittance, \( E \)) is directly proportional to the fourth power of the blackbody's thermodynamic temperature, \( T \. \).Mathematically, the Stefan-Boltzmann law is given by:\[ E = \varepsilon \sigma T^4 \] where \( \sigma \) is the Stefan-Boltzmann constant, approximately \( 5.67 \times 10^{-8} \) W/m虏K鈦.This equation highlights that even a small increase in temperature significantly increases the emitted radiation. For satellites, understanding this law is key to designing components that can effectively balance absorbed solar energy and radiated heat. Using the Stefan-Boltzmann law to ensure equilibrium between absorbed energy and emitted energy, designers can prevent satellites from overheating or becoming too cold.
*Remember:*
  • The law assumes a perfect black body, making \( \varepsilon \) equal to \( 1 \, \) but for real surfaces, emissivity is less than 1.
  • This law helps calculate equilibrium temperatures when setting up systems like the satellite radiator.
Satellite Thermal Management
Satellite thermal management is essential for maintaining optimal operating temperatures of its components. Unlike Earth-based systems, satellites cannot rely on surrounding air or convection for cooling. Instead, they depend heavily on radiative cooling and thermal insulation to regulate temperature. Using materials with specific absorptive and emissive properties is crucial.
The equilibrium surface temperature, like in the exercise solution provided, plays a critical role. If the satellite system absorbs more energy than it radiates, it may overheat. Conversely, if more heat is lost than absorbed, freezing occurs.
Key considerations for satellite thermal management systems include:
  • Material selection: Using materials with high emissivity can help maximize heat dissipation through radiation.
  • Design configurations: Efficient radiative surfaces like panels or fins help spread and emit heat efficiently into space.
  • Active thermal control: Some systems may use heaters or heat pipes to redistribute heat evenly among components.
Understanding and applying these principles ensures satellites endure the harsh environmental conditions of space while maintaining their intended functionalities.

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Most popular questions from this chapter

According to its directicnal distribution, solar radiation incident on the earth's surface may be divided into two components. The direct component consists of parallel rays incident at a fixed renith angle \(\theta\), while the diffuse component consists of radiation that may be approximated as being diffusely distributed with \(\theta\). Consider clear sky conditions for which the direct radiation is incident at \(\theta=30^{\circ}\), with a total flux (based on an area that is normal to the rays) of \(q_{\text {dre }}^{*}=\) \(1000 \mathrm{~W} / \mathrm{m}^{2}\), and the total intensity of the diffuse radiation is \(l_{\text {ar }}=70 \mathrm{~W} / \mathrm{m}^{2}+\mathrm{sr}\). What is the total solar irradiation at the earth's surface?

A diffuse, opoque surface at \(700 \mathrm{~K}\) has spectral emissivities of \(\varepsilon_{\mathrm{i}}=0\) for \(0 \leq \lambda \leq 3 \mu \mathrm{m}\), \(\varepsilon_{\mathrm{a}}=0.5\) for \(3 \mu \mathrm{m}<\lambda \leq 10 \mu \mathrm{m}\), and \(\varepsilon_{\mathrm{x}}=0.9\) for \(10 \mu \mathrm{m}<\lambda<\infty\). A radiant flux of \(1000 \mathrm{~W} / \mathrm{m}^{2}\), which is uniformly distributed between 1 and \(6 \mu \mathrm{m}\), is incident on the surface at an angle of \(30^{\circ}\) relative to the surface normal. Calculate the total radiant power from a \(10^{-4} \mathrm{~m}^{2}\) arca of the surface that reaches a radiation detector pusitioned along the normal to the area. The aperture of the detector is \(10^{-5} \mathrm{~m}^{2}\), and its distance from the surface is \(1 \mathrm{~m}\).

A spherical satellite of diameter \(D\) is in orbit about the carth and is coated with a diffuse material for which the spectral absorptivity is \(\alpha_{\lambda}=0.6\) for \(\lambda \leq 3 \mu \mathrm{m}\) and \(\alpha_{2}=0.3\) for \(\lambda>3 \mu \mathrm{m}\). When it is on the "dark" side of the earth, the satellite sees irradiation from the carth's surface only. The irradiation may be assumed to be incident as parallel rays, and its magnitude is \(G_{E}=340 \mathrm{~W} / \mathrm{m}^{2}\). On the "bright" side of the earth the satellite sees the earth irradiation \(G_{E}\) plus the sola irradiation \(G_{5}=1353 \mathrm{~W} / \mathrm{m}^{2}\). The spectrul distribetion of radiation from the earth may be approximuted as that of a blackbody at \(280 \mathrm{~K}\), and the temperature of the satellite may be ussumed to remain below \(500 \mathrm{~K}\). What is the steady-state temperature of the satellite when it is on the dark side of the earth and when it is on the bright side?

One scheme for extending the operation of gas turbine blades to higher temperatures involves applying a ceramic coating to the surfaces of blades fabricated from a superalloy such as inconel. To assess the reliability of such coatings, an apparatus has been developed for testing samples under laboratory conditions. The sample is placed at the bottom of a large vacuum chamber whose walls are cryogenically cooled and which is equipped with a radiation detector at the top surface. The detector has a surface area of \(A_{d}=\) \(10^{-5} \mathrm{~m}^{2}\), is located at a distance of \(L_{2-d}=1 \mathrm{~m}\) from the sample, and views radiation originating from a portion of the ceramic surface having an area of \(\Delta A_{c}=10^{-4}\) \(m^{2}\). An electric heater attached to the bottom of the sample dissipates a uniform heat flux, \(q_{h}^{n}\), which is transferred upward through the sample. The botiom of the heater and sides of the sample are well insulated. Consider conditions for which a ceramic coating of thickness \(L_{\gamma}=0.5 \mathrm{~mm}\) and thermal conductivity \(k_{\mathrm{c}}=6 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) has been sprayed on a metal substrute of thickness \(L,=8 \mathrm{~mm}\) and thermal conductivity \(k_{3}=25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). The opaque surface of the ceramic may be approximated as diffuse and gray. with a total, hemispherical emissivity of \(\varepsilon_{c}=0.8\). (a) Consider steady-state conditions for which the bottom surface of the substrate is maintained at \(T_{1}=1500 \mathrm{~K}\), while the chamber walls (including the surface of the radistion detector) are maintained at \(T_{\mathrm{w}}=90 \mathrm{~K}\). Assuming negligible thermal contact resistance at the ceramic-substrate interface, determine the ceramic top surface temperature \(T_{2}\) and the hest flux \(q_{\hbar-}^{\prime \prime}\) (b) For the prescribed conditions, what is the rate at which radiation emitted by the ceramic is intercepted by the detector? (c) After repeated experiments, numerous cracks develop at the ceramic- substrate interface, creating an interfacial thermal contact resistance. If \(T_{w}\) and \(q_{h}^{\prime \prime}\) are maintained at the conditions associated with part (a), will \(T_{1}\) increase, decrease, or remain the same? Similarly, will \(T_{2}\) increase, decrease, or remain the same? In cach case, justify your answer.

An enclosure has an inside area of \(100 \mathrm{~m}^{2}\), and its inside surface is black and is maintained at a constant temperature. A small opening in the enclosure has an area of \(0.02 \mathrm{~m}^{2}\). The radiant power emitted from this opening is \(70 \mathrm{~W}\). What is the temperature of the interior enclosure wall? If the interior surfice is maintained at this temperature, but is now polished. what will be the value of the radiant power emitted from the opening?

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