/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 A furnace for processing semicon... [FREE SOLUTION] | 91影视

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A furnace for processing semiconductor materials is formed by a silicon carbide chamber that is zone heated on the top section and cooled on the lower section. With the elevator in the lowest position, a robot arm inserts the silicon wafer on the mounting pins. In a production operation, the wafer is rapidly moved toward the hot zone to achieve the temperature-time history required for the process recipe. In this position the top and boltom surfaces of the wafer exchange radiation with the hot and cool rones, respectively, of the chamber. The zone temperatures are \(T_{\mathrm{a}}=1500 \mathrm{~K}\) and \(T_{c}=\) \(330 \mathrm{~K}\), and the emissivity and thickness of the wafer are \(e=0.65\) and \(d=0.78 \mathrm{~mm}\), respectively. With the ambient gas at \(T_{w}=700 \mathrm{~K}\), convection coefficients at the upper and lower surfaces of the wafer are 8 and \(4 \mathrm{~W} / \mathrm{m}^{2}-\mathrm{K}\). respectively. The silicon wafer has a den. sity of \(2700 \mathrm{~kg} / \mathrm{m}^{3}\) and a specific heat of \(875 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). (a) For an initial condition corresponding fo a wafer tempersture of \(T_{w i}=300 \mathrm{~K}\) and the position of the wafer shawn schematically. determine the corresponding time rate of change of the wafer tempereture, \(\left(d T_{w} / d r\right)_{0}\). (b) Determine the steady state temperature reached by the wafer if it remains in this position. How significant is convection heat transfer for this situation? Sketch how you would expect the wafer temperature to vary as a function of vertical distance.

Short Answer

Expert verified
Calculate initial temperature change rate using energy balance. For steady state, radiation balances convection, showing radiation as the dominant heat transfer mode.

Step by step solution

01

Understand the Heat Transfer Mechanisms

We have radiation exchange between the wafer and the hot and cool zones, as well as convection heat transfer from the ambient gas to the wafer. The objective is to determine the time rate of change of temperature initially and the steady-state temperature.
02

Scenario Analysis for Initial Rate of Temperature Change

Consider the wafer's initial temperature, initial rate of temperature change, heat transfer through convection, and radiation. The net heat transfer will be calculated by considering the energy gained through radiation and convection from the ambient gas.
03

Apply the Law of Energy Conservation

The rate of energy change in the wafer equals the difference in energy absorbed due to radiation minus the energy lost due to convection.Use:\[\dot{Q}_{net} = \rho c V \frac{dT_w}{dt}\]where \(\rho = 2700\, \text{kg/m}^3\), \(c = 875\, \text{J/kg.K}\), and \(V\) is the volume of the wafer.
04

Calculate Radiation Heat Transfer

For radiation:\[\dot{Q}_{rad} = \varepsilon \sigma A \left( T_a^4 - T_w^4 \right) - \varepsilon \sigma A \left( T_c^4 - T_w^4 \right)\]Set emissivity \(\varepsilon = 0.65\), Stefan-Boltzmann constant \(\sigma = 5.67 \times 10^{-8} \text{W/m}^2\text{.K}^4\), area \(A\), and substitute given temperatures.
05

Calculate Convection Heat Transfer

For convection, we have:\[\dot{Q}_{conv} = h_u A (T_a - T_w) + h_l A (T_c - T_w)\]where the upper and lower convection coefficients are \(h_u = 8\, \text{W/m}^2\text{-K}\) and \(h_l = 4\, \text{W/m}^2\text{-K}\) respectively.
06

Solve the Energy Balance Equation

Substitute \(\dot{Q}_{rad}\) and \(\dot{Q}_{conv}\) into our energy conservation equation and solve for \(\frac{dT_w}{dt}\). Use the wafer's initial conditions to calculate the rate of temperature change.
07

Determine Steady State Temperature

For steady state, the net heat exchange is zero:\[\dot{Q}_{net} = \dot{Q}_{rad} + \dot{Q}_{conv} = 0\]Solve the resulting equation to find the steady-state temperature of the wafer.
08

Analyze the Role of Convection

Evaluate the heat transfer contributions from both convection and radiation to determine the significance of convection compared to radiation. Discuss its effect on reaching the steady-state temperature.
09

Sketch Temperature Variation with Distance

With dominant radiation heat transfer at the wafer's surfaces, temperature distribution may not be uniform. Sketch a curve indicating higher temperatures near the hot zone and lower near the cool zone.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiation Heat Transfer
In the semiconductor processing scenario, radiation heat transfer plays a significant role. Radiation is the method by which energy transfers as electromagnetic waves. When the silicon wafer is positioned between the hot and cool zones, it exchanges heat primarily through radiation with these zones.

The hot zone at a temperature of 1500 K radiates energy to the wafer, while the wafer itself emits radiation towards the cooler zone and its surroundings. The net radiation heat transfer \( \dot{Q}_{rad} \) can be calculated using the formula:
  • \( \dot{Q}_{rad} = \varepsilon \sigma A \left( T_a^4 - T_w^4 \right) - \varepsilon \sigma A \left( T_c^4 - T_w^4 \right) \)
Here, \( \varepsilon \) represents emissivity (0.65 for silicon), \( \sigma \) is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m虏路K鈦), and \( A \) is the area of the wafer. This formula incorporates both the radiation received from the hot zone and emitted to the cool zone.

Radiation is especially impactful due to the high temperature differences ( between 1500 K and 330 K) and the nature of electromagnetic wave transfer, which does not require a medium. This makes it essential to consider radiation when analyzing the heat exchange in wafer processing.
Convection Heat Transfer
Convection heat transfer also contributes to the temperature change of the wafer, though its significance may vary. Convection involves the transfer of heat through a fluid, in this case, the ambient gas around the silicon wafer.

The upper surface of the wafer faces the hot zone and is subject to a convection coefficient of 8 W/m虏-K, while the lower surface, facing the cool zone, has a convection coefficient of 4 W/m虏-K. The heat transfer through convection can be represented by:
  • \( \dot{Q}_{conv} = h_u A (T_a - T_w) + h_l A (T_c - T_w) \)
where \( h_u \) and \( h_l \) are the convection coefficients for the upper and lower surfaces, respectively.

Convection is generally a weaker form of heat transfer compared to radiation, given the larger scale of energy exchanged through electromagnetic waves in radiation. However, it still plays a role in reaching equilibrium, particularly influencing the wafer's temperature towards the ambient air's influence.

Understanding the balance between radiation and convection is crucial for effectively controlling the temperature of the wafer during semiconductor manufacturing.
Energy Conservation
Energy conservation is a fundamental principle in determining the rate of temperature change and the steady-state condition of the wafer. The concept revolves around the energy balance in which the net energy into the wafer is equal to the rate of change of its internal energy.

By applying energy conservation, one can determine the initial temperature change rate using:
  • \( \dot{Q}_{net} = \rho c V \frac{dT_w}{dt} \)
where \( \rho \) is the density, \( c \) the specific heat, and \( V \) the volume of the wafer. \( \dot{Q}_{net} \) is the net heat transfer, comprising both radiation and convection contributions.

For steady-state, the principle implies that the total heat gained and lost by the wafer equals to zero. This balance allows us to solve for the wafer's constant temperature in the steady state:
  • \( \dot{Q}_{rad} + \dot{Q}_{conv} = 0 \)
This equation helps us find the final steady-state temperature, ensuring that all absorbed and lost energy equilibrates.

Through energy conservation, we quantify how efficiently a semiconductor wafer reaches its desired temperature profile during processing. Proper adherence to these principles is key to effective semiconductor manufacturing.

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Most popular questions from this chapter

A small sphere of reference-grade iron with a specific heat of \(447 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) and a mass of \(0.515 \mathrm{~kg}\) is suddenly immersed in a water-ice mixfure. Fine thermoceuple wires suspend the sphere, and the temperature is observed to change from 15 to \(14^{\circ} \mathrm{C}\) in \(6.35 \mathrm{~s}\). The experiment is repeated with a metallic sphere of the same diameter, but of unknown compoxition with a mass of \(1.263 \mathrm{~kg}\). If the same observed temperature change occurs in \(4.59 \mathrm{~s}\), what is the specific heat of the unknown material?

Under conditions for which the same room temperature is maintained by a heating or cooling system, it is not uncommon for a person to feel chilled in the winter but comfortable in the summer. Provide a plausible explanation for this situation (with supporting calculations) by considering a room whose air temperature is maintained at \(20^{\circ} \mathrm{C}\) throughout the year, while the walls of the room are nominally at \(27^{\circ} \mathrm{C}\) and \(14^{\circ} \mathrm{C}\) in the summer and winter, respectively. The exposed surface of a person in the room may be assumed to be at a temperature of \(32^{\circ} \mathrm{C}\) throughout the year and to have an emissivity of \(0.90\). The coefficient associated with heat transfer by natural convection between the person and the room air is approximately \(2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

A rectangular forced air heating duct is suspended from the ceiling of a basement whose air and walls are at a termperiture of \(T_{\mathrm{w}}=T_{\mathrm{er}}=5^{\circ} \mathrm{C}\). The duct is \(15 \mathrm{~m}\) long. and its cross-section is \(350 \mathrm{~mm} \times 200 \mathrm{~mm}\). (a) For an uninsulated duct whose average surfice temperature is \(50^{\circ} \mathrm{C}\), estimate the rate of heat loss from the duct. The surface emissivity and convection coefficient are approximately \(0.5\) and \(4 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). respectively. (b) If heated air enters the duct at \(58^{\circ} \mathrm{C}\) and a velocity of \(4 \mathrm{~m} / \mathrm{s}\) and the heat loss corresponds to the result of part (a), what is the outlet temperature? The density and specific heat of the air may be assumed to be \(\rho=1.10 \mathrm{~kg} / \mathrm{m}^{\prime}\) and \(c_{p}=1008 \mathrm{~J} / \mathrm{kg}\) * \(\mathrm{K}\), respectively.

A glass window of width \(W=1 \mathrm{~m}\) and height \(H=2 \mathrm{~m}\) is \(5 \mathrm{~mm}\) thick and has a thermal conductivity of \(k_{e}=\) \(1.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). If the inner and outer surface temperatures of the glass are \(15^{\circ} \mathrm{C}\) and \(-20^{\circ} \mathrm{C}\), respectively, on a cold winter day, what is the rate of heat loss through the glass? To reduce heat loss through windows, it is customary to use a double pane construction in which adjoining. panes are separated by an air space if the spacing is \(10 \mathrm{~mm}\) and the glass surfaces in contact with the air have temperatures of \(10^{\circ} \mathrm{C}\) and \(-15^{\circ} \mathrm{C}\), what is the rate of heat loss from a \(I \mathrm{~m} \times 2 \mathrm{~m}\) window? The thermal conductivity of air is \(k_{t}=0.024 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\).

An aluminum plate 4 mun thick is moxinted in a horizontal position, and its botlom surface is well insulated. \(\mathrm{A}\) special, thin costing is applied to the top surface such that it atsorts \(80 \%\) of any incident solar radiation, while having an cmissivity of \(0.25\). The density \(\rho\) and specific heat \(c\) of aluminum are known to be \(2700 \mathrm{~kg} / \mathrm{m}^{3}\) and \(900 \mathrm{~J} / \mathrm{kg}+\mathrm{K}_{\mathrm{q}}\) respectively. (a) Consider conditions for which the plate is at a temperature of \(25^{\circ} \mathrm{C}\) and its top surface is suddenly exposed to ambient air at \(T_{=}=20^{\circ} \mathrm{C}\) and to solar radiation that provides an incident flux of \(900 \mathrm{~W} / \mathrm{m}^{2}\). The convection heat transfer cuefficient between the surfixce and the uir is \(h=20 \mathrm{~W} / \mathrm{m}^{2}+\mathrm{K}^{2}\). What is the initial rate of change of the plate temperature? (b) What will be the equitibrium temperature of the plate when sleady-state conditions are reached? (c) The surface radialive properties depend on the specific nature of the appliced couting, Compute and plot the steady-state temperature as at functions of the crissivity for \(0.05 \leq \varepsilon \leq 1\). with all other oondations remaining as prescrited. Repeat your calculations for values of \(\alpha_{3}=0.5\) and \(1.0\), and plot the testalts with those obtained fot \(\sigma_{3}=0.8\). If the intent is to maximize the plate temperature, what is the most desirable combination of the plate emissivity and its absorptivity to molar radiation?

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