/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Air at \(40^{\circ} \mathrm{C}\)... [FREE SOLUTION] | 91Ó°ÊÓ

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Air at \(40^{\circ} \mathrm{C}\) flows over a long, 25-mm-diameter cylinder with an embedded electrical heater. In a series of tests, measurements were made of the power per unit length, \(P^{t}\), required to maintain the cylinder surface temperature at \(300^{\circ} \mathrm{C}\) for different freestream velocities \(V\) of the air. The results are as follows: \begin{tabular}{lccccc} \hline Air velocity, \(V(\mathrm{~m} / \mathrm{s})\) & 1 & 2 & 4 & 8 & 12 \\ Power, \(P^{\prime}(\mathrm{W} / \mathrm{m})\) & 450 & 658 & 983 & 1507 & 1963 \\\ \hline \end{tabular} (a) Determine the convection coefficient for cach velocity, and display your results graphically. (b) Assuming the dependence of the convection coeffcient on the velucity to be of the form \(h=C V^{\prime \prime}\), determine the parameters \(C\) and \(n\) from the results of part (a).

Short Answer

Expert verified
Calculate \(h\) using \(P', V\). Use \(h = C V^n\) to find \(C, n\).

Step by step solution

01

Understanding the problem

We are given measurements of power per unit length, \(P'\), needed to keep a cylinder at a constant temperature in air with varying speeds \(V\). We need to calculate the convection heat transfer coefficient \(h\) for each velocity and then express \(h\) as a function of \(V\).
02

Use Fourier's Law for Convection

The power per unit length due to convection can be expressed using Newton's Law of Cooling: \(P' = h \cdot A \cdot \Delta T\). Here, \(A = \pi D\) (where \(D = 0.025\, \mathrm{m}\) is the diameter) and \(\Delta T = 300^{\circ}C - 40^{\circ}C = 260^{\circ}C\).
03

Calculate the convection coefficient \(h\)

For each velocity \(V\), calculate \(h\) using the equation \(h = \frac{P'}{A \cdot \Delta T}\). For example, for \(V = 1\, \mathrm{m/s}\), \(A = \pi \cdot 0.025\, \mathrm{m}\). Calculate for all given velocities.
04

Organize your calculated data

Once you have calculated the values for \(h\) for each velocity, arrange them in a table corresponding to the respective velocities.
05

Plot \(h\) as a function of \(V\)

Create a plot with velocity \(V\) on the x-axis and convection coefficient \(h\) on the y-axis. This will show how \(h\) varies with \(V\).
06

Assume form and find \(C\) and \(n\)

Assume \(h = CV^n\). Using the data points, convert this expression to \(\log(h) = \log(C) + n\log(V)\). Use linear regression to find \(\log(C)\) and \(n\). Transform back to find \(C\).
07

Verify the linearization and solution

Ensure the calculated \(h\) values are consistent across different velocities and the equation \( h = CV^n \) describes the relationship correctly. Double-check the values of \( C \) and \( n \) using the plot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Coefficient
In the world of thermodynamics, the convection coefficient is a pivotal concept. It represents the rate of heat transfer between a surface and a fluid moving across it. Let's understand how it is used in this particular exercise. When air flows over a heated cylinder, like in the given problem, the convection coefficient, denoted as \(h\), can be evaluated using the formula from Newton's Law of Cooling.To compute \(h\), the power per unit length \(P'\) required for maintaining the cylinder's temperature, the surface area \(A\) of the cylinder, and the temperature difference \(\Delta T\) between the cylinder's surface and the air can be used. In this exercise:
  • The surface area \(A\) is calculated as \(\pi D\), where \(D = 0.025\, \text{m}\) is the diameter of the cylinder.
  • The temperature difference \(\Delta T\) is \(300^{\circ}C - 40^{\circ}C = 260^{\circ}C\).
These values allow us to calculate \(h\) for each air velocity, helping to visualize how the heat transfer behaves under different conditions.
Newton's Law of Cooling
This fundamental principle describes the heat transfer between a solid surface and a fluid, such as air, flowing over it. Newton’s Law of Cooling is pivotal in determining the rate at which an object cools—or is heated—by its surroundings. The formula governing this principle is: \[P' = h \cdot A \cdot \Delta T\]Here, \(P'\) is the power per unit length needed to keep the cylinder at a constant temperature, \(h\) is the convection coefficient, \(A\) is the area of the surface in contact with the fluid, and \(\Delta T\) is the temperature difference between the surface and the fluid.By using this equation in the given exercise, we connect the energy required to maintain the cylinder's temperature to the convection coefficient. Understanding this relationship is crucial for calculating \(h\) and predicting how the cylinder's surface will behave under various air velocities. This law helps engineers and scientists design systems that efficiently manage heat transfer.
Cylinder Surface Temperature
Maintaining a high surface temperature on the cylinder requires understanding how heat is conducted away by the air passing over it. In the problem, the cylinder's surface is maintained at a constant \(300^{\circ}C\) despite varying air velocities, due to the electrical heater embedded within it. This temperature difference \(\Delta T\) of \(260^{\circ}C\) between the cylinder and the air is paramount for calculating the power needed.This exercise shows how heat transfer is managed at different velocities by adjusting the required power \(P'\). Since \(h\) is directly influenced by \(\Delta T\), maintaining a stable cylinder surface temperature is essential to determining accurate values of the convection coefficient \(h\). By carefully monitoring and calculating this temperature, engineers can ensure efficient thermal management in various practical applications.
Velocity Dependence
Velocity significantly affects how heat is transferred from the cylinder to the air. In the exercise, the freestream velocities range from \(1\, \text{m/s}\) to \(12\, \text{m/s}\). As velocity increases, so does the convection coefficient \(h\), illustrating an essential dependency that occurs in fluid flows.To quantify this relationship, we assume a model: \(h = C V^n\), where \(C\) and \(n\) are constants we determine through data analysis. Converting it to a linear form using logarithms simplifies finding \(C\) and \(n\) through regression techniques. This process reveals how changes in air velocity can enhance or dampen heat transfer, which is important when designing cooling systems for machinery or regulating temperature in electronic devices. Understanding this dependence is crucial for optimizing thermal performance in various engineering applications.

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Most popular questions from this chapter

A freezer compartment is covered with a \(2-\mathrm{mm}\)-thick layer of frost at the time it malfunctions. If the compartment is in ambient air at \(20^{\circ} \mathrm{C}\) and a coefficient of \(h=2\) \(\mathrm{W} / \mathrm{m}^{2}\) - \(\mathrm{K}\) characterizes heat transfer by natural convection from the exposed surface of the layer, estimate the time required to completely melt the frost. The frost may be assumed to have a mass density of \(700 \mathrm{~kg} / \mathrm{m}^{3}\) and a latent heat of fusion of \(334 \mathrm{k} / / \mathrm{kg}\).

During its manufacture, plate glass at \(600^{\circ} \mathrm{C}\) is cooled by passing air over its surface such that the convection heat transfer coefficient is \(h=5 \mathrm{~W} / \mathrm{ma}^{2}+\mathrm{K}\). To prevent cracking, it is known that the temperature gradient must not exceed \(15^{\circ} \mathrm{C} / \mathrm{mm}\) at any point in the glass during the cooling process. If the thermal conductivity of the glass is \(1.4 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) and its surface emissivity is \(0.8\), what is the lowest temperature of the air that can initially be used for the cooling? Assume that the temperature of the air equals that of the surroundings.

A square isothermal chip is of width \(w=5 \mathrm{~mm}\) on a side and is mounted in a substrate such that its side and bock surfaces are well insulated, while the front surface is exposed to the flow of a coolant at \(T_{w}=15^{\circ} \mathrm{C}\). From reliatility considerations, the chip temperature must not cxceed \(T=85^{\circ} \mathrm{C}\). Coclart \(\longrightarrow T_{m} h\) If the coolant is air and the corresponding convection coefficient is \(h=200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), what is the maximum allowable chip power? If the coolant is a dielectric liequid for which \(h=3000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}^{\mathrm{K}}\), what is the maximam allowable power?

Consider a surface-mount type transistor on a circuit board whose temperature is muintained at \(35^{\circ} \mathrm{C}\). Air at \(207 \mathrm{C}\) flows over the upper surface of dimensions \(4 \mathrm{~mm}\) by \(8 \mathrm{~mm}\) with a convection coefficient of \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Three wire leads, each of cross section \(1 \mathrm{~mm}\) by \(0.25 \mathrm{~mm}\) and length 4 nim, conduct heat from the case to the circuit board. The gap between the case and the board is \(0.2 \mathrm{~mm}\). (a) Assuming the case is isothermal and neglecting rudiation, eximate the case temperature uhen \(150 \mathrm{~mW}\) is dissipoted by the thansistor and (i) stagnant air or (ii) a conductive paste fills the gap. The thermal condoctivitios of the wire leadk, air, and cunductive paste are 25, \(0.0263\), and \(0.12\) W/m - \(\mathrm{K}\), respectively. (b) Using the conductive paste to fill the gap, we wish to determine the extent to which increased heat dissipation may be accommodated, subject to the constraint that the case lemperature not exceed \(40^{\circ} \mathrm{C}\). Options include increasing the air speed to achieve a lager convection coefficient \(h\) and/or changing the lead wire material to one of larger thermal conductivity. Independently considering leads fabricated from materials with thermal conductivities of 200 and \(400 \mathrm{~W} / \mathrm{m}+\mathrm{K}\), compute and plot the maximum allowable hean dissipation for variations in \(h\) over the range \(50 \leq h \leq 250 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

In considcring the following jroblems involving heat transfer in the natural environment (outdoors), recog. nize that solar radiation is comprised of long and shon wavelength components. If this radiation is incident on a semitrarsporent medium, such as water or glass, two things will happen to the noneflecied porticn of the radiation. The long wavelength component will be aboubed at the surface of the medium, whereas the short wavelength component will be transmitted by the surface. (a) The number of panes in a window can strongly inftuence the heat loss from a heated room to the outside ambient air, Compare the single- and doublepaned units shown by identifying relevant healt transfer processes for each case. (b) In a typical fat-plate solar collector, energy is collected by a working fluid thut is circulated through fubes that are in good contact with the hack face of an absorber plate. The back. face is insulated frum the surroundings, and the absuber plate receives solar radiation on its front face, which is typically covered by one or more transparent plates. Idensify the relevant heat transfer processes, first for the absorber plate with no cover plate and then for the absorber plate with a single cover plate. (c) The solar energy collector design stoun below has been used for agricultural applications. Air is blown through a long duct whone cross section is in the form of an equilateral triangle. One side of the triangle is comprised of a double-paned, semitransparent cover, while the ceher two sides are constructed from aluminum sheets painted flat black on the inside and covered on the outside with a Layer of styroform insulation. During sunny periods, air entering the system is heated for delivery to cither a greenhouse, grain drying unit, or a storage system. Identify all heat transfer processes associated with the cover plates, the absorter plate(s), and the air. (d) Evacuated-tube solar collectors are capable of improved performance relative to flat-plate collectors. The design consists of an inner tube enclosed in an outer tube that is transparent to solar radiation. The annular space between the tubes is evacuated. The ouler, opaque surface of the inner tube absorbs solar raciation, and a working fluid is passed through the tube to collect the solar energy. The collector design generally consists of a row of such tubes arranged in frunt of a reflecting panel. Identify all heat transfer processes relevant to the performance of this device.

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