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By inspection, arrange the following dimensional parameters into dimensionless parameters: (a) kinematic viscosity, \(v,\) length, \(\ell,\) and time, \(t ;\) and (b) volume flow rate, \(Q,\) pump diameter, \(D,\) and pump impeller rotation speed, \(N\)

Short Answer

Expert verified
The dimensionless parameters for problem (a) is \(\frac{v}{\ell t}\), and for problem (b) is \(\frac{Q}{D^3 N}\)

Step by step solution

01

Understand the variables for problem (a)

For problem (a), the given parameters are the kinematic viscosity (\(v\)), which has units of m²/sec, length (\(l\)), which is expressed in metres (m), and time (\(t\)), which is measured in seconds (sec).
02

Creating dimensionless parameters for problem (a)

To create a dimensionless parameter, the goal is to balance the units from the different parameters given. The variables could be multiplied or divided among each other to cancel the units out. So, dividing kinematic viscosity (\(v\)) by the product of length (\(l\)) and time (\(t\)) will result in a dimensionless parameter, because the units cancel each other out: \(\frac{v}{\ell t}\). This ratio doesn't have any units and is therefore dimensionless.
03

Understanding variables for problem (b)

For problem (b), the given parameters are the volume flow rate (\(Q\)), which has units of m³/sec, the pump diameter (\(D\)), which is expressed in metres (m), and pump impeller rotation speed (\(N\)), which is measured in revolution per second (rps).
04

Creating dimensionless parameters for problem (b)

For problem (b), dividing volume flow rate (\(Q\)) by the product of pump's diameter cubed (\(D^3\)) and impeller rotation speed (\(N\)) gives a dimensionless parameter because all of dimensions get cancelled out. So, the dimensionless parameter for problem (b) is \(\frac{Q}{D^3 N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematic Viscosity
Kinematic viscosity is a fundamental property of fluid mechanics, which plays a crucial role in describing the flow behavior of fluids. It is defined as the ratio of dynamic viscosity to fluid density and is represented by the symbol \( v \).
In the SI system, its units are expressed as square meters per second \( m^2/s \). It essentially gives us an idea of how easily a fluid can flow under its own weight.
High kinematic viscosity means the fluid flows slowly, making it thick and sticky, whereas low kinematic viscosity means the fluid is thinner and flows more easily. Understanding kinematic viscosity is essential in many engineering applications, such as designing pipes and pumps, to ensure efficient flow and minimize energy loss. It also appears frequently in dimensionless parameters such as the
  • Reynolds number, which is a key factor in determining fluid flow regimes like laminar or turbulent.
Dimensionless Parameters
Dimensionless parameters are combinations of variables that have no units. They allow us to make sense of complex systems by simplifying and scaling them to understand their relative magnitudes. Dimensionless numbers are crucial in fluid dynamics because they help to generalize the results of experiments and observations without the need for scaling calculations.Creating a dimensionless number involves selecting appropriate parameters such that their units cancel out. For example, with kinematic viscosity \( v \), length \( \ell \), and time \( t \), a dimensionless number is formed by \( \frac{v}{\ell t} \). This is important in comparing different systems or processes.
In practical scenarios, these parameters help to
  • identify similar behavioral patterns among different systems,
  • predict performance and outcomes,
  • simplify mathematical models used in simulations,
  • analyze scaling laws and correlate related attributes.
Understanding dimensionless numbers can significantly aid in making important engineering decisions and innovating new technologies.
Volume Flow Rate
Volume flow rate is a measure of the quantity of fluid that passes through a point or a section per unit time, denoted as \( Q \), and is measured in cubic meters per second (\( m^3/s \)). It is a critical parameter in many engineering and fluid mechanics applications, as it quantifies the efficiency and capacity of fluid transport systems.In real-world applications, knowing the volume flow rate helps in
  • designing efficient piping systems,
  • selecting suitable pumps and valves,
  • ensuring sufficient fluid delivery in processes,
  • regulating flow in hydraulic systems,
  • and assessing engine performance.
To create dimensionless parameters, \( Q \) is often used in conjunction with other parameters such as the pump diameter \( D \) and impeller rotation speed \( N \). By appropriately combining these variables, a ratio such as \( \frac{Q}{D^3 N} \) can be derived, which is unitless.
This is quintessential in comparing the flow capacity across different systems and optimizing their performance.

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Most popular questions from this chapter

Develop the Froude number by starting with estimates of the fluid kinetic energy and fluid potential energy.

A stream of atmospheric air is used to keep a ping-pong ball aloft by blowing the air upward over the ball. The ping-pong ball has a mass of \(2.5 \mathrm{g}\) and a diameter \(D_{1}=3.8 \mathrm{cm},\) and the air stream has an upward velocity of \(V_{1}=0.942 \mathrm{m} / \mathrm{s}\). This system is to be modeled by pumping water upward with a velocity \(V_{2}\) over a solid ball of diameter \(D_{2}\) and density \(\rho_{b_{2}}=2710 \mathrm{kg} / \mathrm{m}^{3} .\) In both cases, the net weight of the ball \(W_{b}\) is equal to the air drag, $$\mathrm{W}_{b}=\frac{\mathrm{C}_{\mathrm{D}} \rho A V^{2}}{2}$$where \(\mathrm{C}_{\mathrm{D}}=0.60, \rho\) is the fluid density, \(A\) the ball's projected area, and \(V\) the velocity of the fluid upstream from the ball. Determine all possible combinations of \(V_{2}\) and \(D_{2}\). [Hint: A force balance involving the drag on the ball, the buoyant force on the ball, and the weight of the ball is needed.]

The speed of deep ocean waves depends on the wave length and gravitational acceleration. What are the appropriate dimensionless parameters?

An incompressible fluid oscillates harmonically \(\left(V=V_{0}\right.\) \(\sin \omega t, \text { where } V \text { is the velocity })\) with a frequency of 10 rad/s in a 4-in.- -diameter pipe. A \(\frac{1}{4}\) scale model is to be used to determine the pressure difference per unit length, \(\Delta p_{\ell}\) (at any instant) along the pipe. Assume that $$\Delta p_{\ell}=f\left(D, V_{0}, \omega, t, \mu, \rho\right)$$ where \(D\) is the pipe diameter, \(\omega\) the frequency, \(t\) the time, \(\mu\) the fluid viscosity, and \(p\) the fluid density. (a) Determine the similarity requirements for the model and the prediction equation for \(\Delta p_{\ell}\) (b) If the same fluid is used in the model and the prototype at what frequency should the model operate?

At a sudden contraction in a pipe the diameter changes from \(D_{1}\) to \(D_{2} .\) The pressure drop, \(\Delta p,\) which develops across the contraction is a function of \(D_{1}\) and \(D_{2},\) as well as the velocity, \(V\), in the larger pipe, and the fluid density, \(\rho,\) and viscosity, \(\mu .\) Use \(D_{1}, V,\) and \(\mu\) as repeating variables to determine a suitable set of dimensionless parameters. Why would it be incorrect to include the velocity in the smaller pipe as an additional variable?

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