/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 The stream function for an incom... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The stream function for an incompressible, two-dimensional flow field is $$\psi=a y-b y^{3}$$ where \(a\) and \(b\) are constants. Is this an irrotational flow? Explain.

Short Answer

Expert verified
The flow is not irrotational because its curl is not equal to zero. However, at y=0, the flow can be considered irrotational since the curl equals zero at this point.

Step by step solution

01

Formulate the necessary equations

Use the given stream function \( \psi = ay - by^3 \). Since this is a two-dimensional problem, we know that there is no variation in the \( z \) direction, thus the stream function in Cartesian coordinates can be written as \( u = \frac{\partial{\psi}}{\partial{y}} \) and \( v = -\frac{\partial{\psi}}{\partial{x}} \). Here \( u \) and \( v \) are the velocity components in the \(x\) and \(y\) directions, respectively.
02

Calculate the derivatives

Calculate the partial derivatives of the stream function w.r.t \( x \) and \( y \). Here \( \frac{\partial{\psi}}{\partial{y}} = a - 3by^2 \) and since there are no \( x \) terms in the stream function, \( \frac{\partial{\psi}}{\partial{x}} = 0 \). Therefore, \( u = a - 3by^2 \) and \( v = 0 \).
03

Calculate the curl

The curl of the velocity field in 2D Cartesian coordinates is given by \( \nabla \times \textbf{v} = \frac{\partial{v}}{\partial{x}} - \frac{\partial{u}}{\partial{y}} \). Substituting \( u \) and \( v \) gives \( \nabla \times \textbf{v} = 0 - \frac{\partial}{\partial{y}}(a - 3by^2) = -6by \).
04

Determine if flow is irrotational

We observe that the curl of the velocity field, \( \nabla \times \textbf{v} \), is not equal to zero, which implies that this is not an irrotational flow. This being said, if the fluid is evaluated at \( y = 0 \), the flow can be considered irrotational at this specific point.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stream Function
A stream function is a useful tool in fluid dynamics for representing two-dimensional, incompressible flow fields. It helps in visualizing the flow without directly solving the complex equations of motion. In regions where the stream function is defined, its contour lines represent the flow lines, also known as streamlines. This means that the fluid flows tangent to these lines.

The stream function, denoted usually by \( \psi \), is mathematically related to the velocity components of the flow. For a 2D flow field, the velocity components \( u \) and \( v \) in the \( x \) and \( y \) directions, respectively, can be expressed as partial derivatives of the stream function:
  • \( u = \frac{\partial \psi}{\partial y} \)
  • \( v = -\frac{\partial \psi}{\partial x} \)
With these expressions, we can glean the flow's pattern by examining \( \psi \). This makes the stream function especially valuable for simplifying analysis in fluid mechanics problems.
Incompressible Flow
In fluid dynamics, incompressible flow refers to a flow where the fluid's density remains constant throughout. This simplifies the governing equations since we don't have to consider density changes due to pressure or temperature. Almost all liquids are treated as incompressible under normal conditions. Hence, this assumption is quite applicable and reduces complexity.

For incompressible flow, especially in a two-dimensional context, the concept of continuity simplifies to ensuring that the velocity field maintains this invariance in density. The divergence of the velocity field is zero:
  • \( abla \cdot \textbf{v} = 0 \)
In practice, this means the fluid's volume is conserved as it flows, which can be considered a reasonable approximation for many liquids such as water and oils in engineering applications.
Two-Dimensional Flow
Two-dimensional flow is an idealized representation of fluid flow where all changes occur within a plane, and there is no variation in the third dimension. The flow velocity components only change along two directions, typically identified as \( x \) and \( y \). This is often a good representation for real-world scenarios where the effects along the third dimension, like thickness or depth, are negligible.

In the context of the exercise, we saw that the stream function \( \psi = ay - by^3 \) represents a 2D flow where the flow properties vary only in the \( x \) and \( y \) directions, and there is no dependence on the \( z \) direction. With two-dimensional flow, the use of stream functions becomes especially powerful, enabling a complete description of the flow field without the need for a third dimension.
Curl of Velocity Field
The curl of a velocity field is a vector operation that describes the rotation or circulation of the flow. In fluid dynamics, it represents the tendency of objects within the flow to rotate. For a two-dimensional flow, the curl is simple since it reduces to a scalar quantity.

Calculated via the expression \( abla \times \textbf{v} \), where \( \textbf{v} \) is the velocity vector, this tells us how much the fluid is swirling at a point. Specifically, for the given problem, \( abla \times \textbf{v} = -6by \). This indicates rotation dependent on the \( y \) position.
  • When this value is zero, the flow is termed irrotational, implying no net rotation.
  • If non-zero, it suggests rotation or vorticity in the flow field.
In the context of the exercise, the fact that \( abla \times \textbf{v} \) is not zero except at \( y = 0 \) indicates a rotational flow in the region, thus not entirely irrotational.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The two-dimensional velocity field for an incompressible Newtonian fluid is described by the relationship $$\mathbf{V}=\left(12 x y^{2}-6 x^{3}\right) \hat{\mathbf{i}}+\left(18 x^{2} y-4 y^{3} \hat{\mathbf{j}}\right.$$ where the velocity has units of \(\mathrm{m} / \mathrm{s}\) when \(x\) and \(y\) are in meters. Determine the stresses \(\sigma_{x x}, \sigma_{y y},\) and \(\tau_{x y}\) at the point \(x=0.5 \mathrm{m}\) \(y=1.0 \mathrm{m}\) if pressure at this point is \(6 \mathrm{kPa}\) and the fluid is glycerin at \(20^{\circ} \mathrm{C}\). Shew these stresses on a sketch.

In Section \(6.3,\) we derived the differential equation(s) of linear momentum by considering the motion of a fluid element. Derive the linear momentum equation(s) by considering a small control volume, like we did for the continuity equation in Section 6.2.

Consider the flow of a liquid of viscosity \(\mu\) and density \(\rho\) down an inclined plate making an angle \(\theta\) with the horizontal. The film thickness is \(t\) and is constant. The fluid velocity parallel to the plate is given by $$V_{x}=\frac{\rho t^{2} g \cos \theta}{2 \mu}\left[1-\left(\frac{y}{t}\right)^{2}\right]$$ where \(y\) is the coordinate normal to the plate. Calculate \(\Phi\) and \(\Psi\) for this flow and show that neither satisfies Laplace's equation. Why not?

The velocity in a certain two-dimensional flow field is given by the equation $$\mathbf{v}=2 x t \hat{\mathbf{i}}-2 y t \hat{\mathbf{j}}$$ where the velocity is in ft's when \(x, y,\) and \(t\) are in feet and seconds, respectively. Determine expressions for the local and convective components of acceleration in the \(x\) and \(y\) directions. What is the magnitude and direction of the velocity and the acceleration at the point \(x=y=2 \mathrm{ft}\) at the time \(t=0 ?\)

A viscous fluid is contained between two infinitely long, vertical, concentric cylinders. The outer cylinder has a radius \(r_{o}\) and rotates with an angular velocity \(\omega\). The inner cylinder is fixed and has a radius \(r_{i} .\) Make use of the Navier-Stokes equations to obtain an exact solution for the velocity distribution in the gap. Assume that the flow in the gap is axisymmetric (neither velocity nor pressure are functions of angular position \(\theta\) within the gap) and that there are no velocity components other than the tangential component. The only body force is the weight.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.