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At cruise conditions, air flows into a jet engine at a steady rate of 65 lbm/s. Fuel enters the engine at a sieady rate of \(0.60 \mathrm{Ism} / \mathrm{s}\). The average velocity of the exhaust gases is 1500 ft/s relative to the engine. If the engine exhaust effective cross-sectional area is \(3.5 \mathrm{ft}^{2}\), estimate the density of the exhaust gases in \(\mathrm{lbm} / \mathrm{ft}^{3}\).

Short Answer

Expert verified
The estimated density of the exhaust gases is \(0.0125 lbm/ft^3\)

Step by step solution

01

Calculate the Total Mass Flow Rate Out of the Engine

Firstly, calculate the total mass flow rate out of the jet engine by using the conservation of mass principle, which states that the total mass flow rate of air and fuel entering the engine must be equal to the mass flow rate of the exhaust gases exiting the engine. Given that air flows into the engine at a rate of 65 lbm/s and fuel at a rate of 0.60 lbm/s, the total incoming mass flow rate is \(65 lbm/s + 0.60 lbm/s = 65.60 lbm/s\)
02

Calculate the Volume Flow Rate of the Exhaust Gases

The volume flow rate of the exhaust gases can be obtained from the product of the cross-sectional area of the exhaust and the velocity of the gases. So, \(Volume Flow Rate = Area*Velocity = 3.5ft^2 * 1500 ft/s = 5250 ft^3/s\).
03

Find the Density of the Exhaust Gases

The density of the exhaust gases can be found by dividing the mass flow rate by the volume flow rate. Therefore, the density of the exhaust gases is \(Density = Mass Flow rate / Volume Flow Rate = 65.60 lbm/s / 5250ft^3/s = 0.0125 lbm/ft^3\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Flow Rate
In fluid mechanics, understanding the concept of the mass flow rate is crucial for solving problems related to fluid movement through systems such as jet engines. The mass flow rate is a measure of the amount of mass moving through a cross-sectional area per unit time. It's generally expressed in units like lbm/s or kg/s. This metric is essential in ensuring systems like engines operate efficiently and safely.

To calculate the mass flow rate, one needs to sum the contributions of all substances entering a system. In our jet engine exercise, the air enters the engine at 65 lbm/s, and the fuel at 0.60 lbm/s. Combined, they give an incoming total mass flow rate of 65.60 lbm/s. This is used to determine the outgoing exhaust flow, maintaining a balance as described by the principle of the conservation of mass. By keeping this balance, engineers can predict the engine's performance and required fuel consumption.
Conservation of Mass
The conservation of mass is a fundamental principle in physics, asserting that the mass of an isolated system must remain constant over time, regardless of the processes occurring within the system. This principle is critical when analyzing fluid dynamics in systems like jet engines.

In the context of our exercise, it means that the mass of air and fuel entering the engine must equal the mass of the exhaust gases exiting the engine. Therefore, despite the conversion of energy forms and the complexities of combustion, the mass flow rate into the engine (65.60 lbm/s) is precisely the mass flow rate out. This conservation ensures that calculations such as the exhaust density can be done accurately without "mysterious" losses or gains of mass.
Density Calculation
Density is a measure of mass per unit volume and is a crucial parameter for understanding fluid dynamics in engines. In this exercise, density helps us understand how tightly packed the exhaust gases are as they exit the engine. Understanding this density is vital for further calculations, such as those involving thrust or environmental emissions.

To calculate density, we use the formula \[ \text{Density} = \frac{\text{Mass Flow Rate}}{\text{Volume Flow Rate}} \]Plugging in our values from the exercise, the mass flow rate through the engine was found to be 65.60 lbm/s and the exhaust volume flow rate 5250 ft³/s. Therefore, the density is \[ 0.0125 \text{ lbm/ft}^3 \]This result shows that the exhaust gases are relatively light, which is typical for high-speed jet exhaust.
Volume Flow Rate
Volume Flow Rate is the volume of fluid that passes through a given surface per unit time. In our exercise, it’s specifically the volume of exhaust gases exiting the jet engine. The volume flow rate helps us understand how much space the fluid occupies as it moves.

To calculate this rate, we multiply the cross-sectional area of the exhaust by the speed of the exhaust gases:\[ \text{Volume Flow Rate} = \text{Area} \times \text{Velocity} \]Given the exercise provides an area of 3.5 ft² and a velocity of 1500 ft/s, the calculation is:\[ 3.5 \text{ ft}^2 \times 1500 \text{ ft/s} = 5250 \text{ ft}^3/\text{s} \]This high volume flow rate reflects the speed and capacity of the exhaust gases being expelled from the engine, crucial for maintaining thrust and efficiency.

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Most popular questions from this chapter

Storm sewer backup causes your basement to flood at the steady tate of 1 in. of depth per hour. The basement floor area is \(1500 \mathrm{ft}^{2}\) What capacity (gal/min) pump would you rent to (a) kecp the water eccumulated in your basement at a constant level urtil the storm sewer is blocked off. and (b) reduce the water accumulation in ycur basement at a rate of 3 in fhr even while the backup problem exiss?

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