/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Often young children drink milk ... [FREE SOLUTION] | 91Ó°ÊÓ

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Often young children drink milk \(\left(\rho=1030 \mathrm{kg} / \mathrm{m}^{3}\right)\) through a straw. Determine the maximun length of a vertical straw that a child can use to empty a milk container, assuming that the child can develop \(75 \mathrm{mm}\) Hg of suction, and use this answer to determine if you think this is a reasonable estimate of the suction that a child can develop.

Short Answer

Expert verified
The maximum length of a vertical straw a child can use to empty a milk container, assuming that the child can develop \(75 \) mm Hg of suction power, is approximately \( 99 \) cm which is a reasonable estimate of the suction that a child can develop.

Step by step solution

01

Understand the Problem

The child creates a vacuum in their mouth, lowering the pressure at the top of the straw. The outside air pressure is then higher than pressure in the straw, and pushes the milk up the straw. To know the highest milk can be sucked up the straw, it's necessary to calculate the maximum height the milk can be pushed by atmospheric pressure.
02

Convert Units

Given suction power of child is \(75 \) mm Hg. Convert this suction power to Pascal - \(75 \) mm Hg = \(75 \times 133.32 \) Pa. Calculating this, it gives us a suction power of \(10,000 \) Pa. Here we have used the equivalence \(1 \) mm Hg = \(133.32 \) Pa.
03

Using Fluid Pressure Formula

Pressure at a depth in a fluid column is given by \( P = \rho g h \), where \( \rho \) = fluid density, \( g \) = acceleration due to gravity and \( h \) = height of the fluid column. Solving for \( h \), we get \( h = P/(\rho g) \).
04

Calculation

Inserting the values into the formula, for \( P = 10,000 \) Pa, \( \rho = 1030 \) kg/m³ (milk's density), and \( g = 9.8 \) m/s² (approx value of gravity), the \( h = 10,000 / (1030 \times 9.8) \). Calculating this, we get \( h \approx 0.99 \) m. This is the maximum height the milk can be pushed up.
05

Validating the Answer

Since 0.99 m (or 99 cm) is relatively taller than the usual length of a milk straw which is about 20-25 cm, this largely exhibits a child's suction ability. Hence, this seems a reasonable estimate of the suction that a child can develop.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Pressure
Fluid pressure is a central concept in fluid mechanics. It describes the force that a fluid exerts per unit area. In the context of our problem, the pressure is determined by the difference in pressure between the child's mouth and the atmospheric pressure outside the straw. The greater this difference, the stronger the pressure that pushes the fluid upward through the straw.

Fluid pressure can be calculated using the equation:
  • \( P = \rho g h \)
where:
  • \( P \) is the fluid pressure,
  • \( \rho \) is the fluid density,
  • \( g \) is the gravitational acceleration, and
  • \( h \) is the height of the fluid column.
Understanding fluid pressure helps explain how atmospheric forces can move liquids through a straw.
Suction Power
Suction power refers to the ability to create a pressure difference that causes a fluid to be pushed or lifted. In our exercise, the child's mouth acts like a small vacuum, where they decrease the internal pressure, allowing atmospheric pressure to push the milk up the straw.

The measure of this suction power can be demonstrated in different units like mm Hg or Pascal. It's important to convert these units appropriately to calculate the height a liquid can be lifted. In our case, a suction power of 75 mm Hg is equivalent to 10,000 Pa, a crucial conversion in understanding the exercise.
Suction enables the effective movement of fluids against gravity by entirely relying on pressure differences.
Atmospheric Pressure
Atmospheric pressure is the pressure exerted by the weight of the atmosphere above us. It's a fundamental force that helps in the upward movement of fluids in open systems like the straw.
  • Outside the straw, atmospheric pressure pushes against whatever is inside, trying to equalize the pressure.
Thus, when the pressure inside the straw is reduced (by suction, for example), the atmospheric pressure pushes the liquid upwards. This is why understanding atmospheric pressure is fundamental in our problem.
Without atmospheric pressure, the movement of milk through the straw would not be possible. It is this force that drives the milk upwards once a child reduces the pressure in the straw by sucking.
Fluid Density
Fluid density is a measure of how much mass is contained in a unit volume of a fluid. The density of a fluid directly impacts how it behaves under pressure, and thus it's essential in calculating how high a fluid will rise under given pressure conditions.
  • In the exercise, the density of milk is given as 1030 kg/m³, which affects the fluid pressure calculation.
The greater the density, the greater the pressure required to lift the fluid because more mass is being moved for the same amount of upward force.
When considering suction and atmospheric pressure, fluid density is a critical factor in determining the maximum achievable height for the liquid in a straw.

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