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A normal shock occurs in a stream of oxygen. The oxygen flows at \(\mathrm{Ma}=1.8\) and the upstream pressure and temperature are 15 psia and \(85^{\circ} \mathrm{F}\) (a) Calculate the following on the downstream side of the shock: static pressure, stagnation pressure, static temperature, stagnation temperature, static density, and velocity. (b) If the Mach number is doubled to \(3.6,\) what will be the resulting values of the parameters listed in part (b)?

Short Answer

Expert verified
The solution to this problem involves converting the given parameters into SI units, using the normal shock equations for a perfect gas to calculate the downstream temperature, pressure, density and Mach number, determining the stagnation conditions and calculating the downstream velocity. The calculations would then be repeated with the Mach number doubled. The exact values of the downstream properties depend on the specific characteristics of oxygen and the values provided in the normal shock tables.

Step by step solution

01

Convert input values to SI units

Take the given values and convert them into SI units for easier calculation and interpretation. For example, pressure in psia can be converted to Pascals and temperature in Fahrenheit can be converted to Kelvin.
02

Apply the normal shock equations for a perfect gas

Use the already known conditions (upstream Mach number, temperature and pressure) and apply the normal shock equations to derive the downstream pressure (\(P_2\)), temperature (\(T_2\)), density (\(蟻_2\)), and the downstream Mach number (\(Ma_2\)). The equations relate the upstream and downstream variables.
03

Calculate the stagnation properties

Calculate the stagnation pressure (\(P_{02}\)) and temperature (\(T_{02}\)) by using the definition of these quantities. The stagnation pressure and temperature for an adiabatic process are related to the static pressure and temperature by a factor that depends on the specific heats ratio and Mach number.
04

Calculate the downstream velocity

The downstream velocity can be found by using the definition of Mach number and the downstream Mach number obtained in step 2. Velocity of flow is the Mach number times the speed of sound, \(V = Ma \sqrt{纬RT_2}\), where \(纬\) is the ratio of specific heats, \(R\) is the gas constant, and \(T_2\) is the downstream temperature.
05

Repeat the calculations for doubled Mach number

Repeat Steps 2, 3, and 4 with the Mach number now doubled to 3.6

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Mach Number
The Mach number is a fundamental concept in gas dynamics and plays a crucial role in understanding shock waves. It is the ratio of the speed of an object moving through a fluid to the speed of sound in that fluid. Mathematically, it is expressed as \(Ma = \frac{V}{a}\), where \(V\) is the velocity of the object and \(a\) is the speed of sound in the fluid.

In the context of normal shock waves, Mach number helps determine whether the flow is subsonic or supersonic. When the Mach number is greater than 1, as in our exercise example, the flow is supersonic. Normal shock waves typically occur in supersonic flows where they act to abruptly decelerate the flow to subsonic speeds. This deceleration affects various properties of the flow such as temperature, pressure, and density.

When the Mach number doubles, the effect on these flow properties is also significant, especially after the shock wave. Therefore, understanding and calculating Mach numbers are vital for analyzing and predicting the changes brought about by shock waves in gas dynamics.
Significance of Stagnation Properties
Stagnation properties, namely stagnation pressure and temperature, are essential tools for understanding flow dynamics, especially in compressible flows like those involving shock waves.

Stagnation pressure \(P_0\) is the pressure a fluid achieves if it is brought to rest isentropically (without any loss of energy due to friction or turbulence). Similarly, stagnation temperature \(T_0\) is the temperature the fluid would reach under the same conditions.
  • Stagnation pressure can be found using the equation:\[ P_0 = P \left(1 + \frac{\gamma - 1}{2} Ma^2\right)^{\frac{\gamma}{\gamma - 1}} \]where \( \gamma \) is the ratio of specific heats, and \( Ma \) is the Mach number.

These properties help in determining the total energy and the maximum possible velocity of the gas flow at different stages of the flow process.

In scenarios involving normal shock waves, stagnation properties differ before and after the shock. By understanding these differences, engineers can predict how energy changes in a system, which is crucial for designing efficient propulsion systems and aircraft.
Understanding Static Pressure After a Shock
Static pressure is another key player in gas dynamics, notably when analyzing shock waves. It refers to the pressure exerted by the fluid particles in a static or moving fluid. Unlike stagnation pressure, static pressure is sometimes impacted significantly in high-speed flows.

For a normal shock wave, static pressure sees a jump as the flow passes through the shock barrier. This is because the flow velocity decreases abruptly, leading to a compressive effect that increases the pressure.

The relationship between upstream and downstream static pressures in a normal shock can be given by:\[ \frac{P_2}{P_1} = 1 + \frac{2\gamma}{\gamma + 1}(Ma_1^2 - 1) \] where \(P_2\) is the downstream pressure, and \(P_1\) is the upstream pressure.

Knowing static pressure is vital for applications involving fluid dynamics as it directly affects force canopies, structural analysis, and the design of aerodynamic surfaces. In scenarios where the Mach number is increased, such as in our exercise, we anticipate a greater increase in static pressure, necessitating reinforced structures to handle these changes.
Exploring Gas Dynamics with Normal Shock Waves
Gas dynamics is a branch of fluid mechanics that deals with flows having significant density variations, which are common in supersonic speeds. Normal shock waves are a crucial phenomenon within this domain, as they dramatically impact flow characteristics.

When a supersonic flow encounters a normal shock wave, it converts into a subsonic flow. This exchange entails changes in the static and stagnation properties of the fluid, such as pressure, temperature, and density. These changes can be predicted and calculated using specific equations known as the normal shock relations.
  • Post-shock, the density and pressure increase while the Mach number and velocity decrease.
  • Temperature experiences an increase due to the conversion of kinetic energy into thermal energy.


Gas dynamics principles are also applicable to greater Mach numbers, as shown in the exercise where the Mach number is doubled. Studying these changes helps engineers in practical applications such as designing jet engines, calculating aerodynamic forces, and ensuring the stability and performance of high-speed vehicles.

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Most popular questions from this chapter

An ideal gas is to flow isentropically from a large tank where the air is maintained at a temperature and pressure of \(59^{\circ} \mathrm{F}\) and 80 psia to standard atmospheric discharge conditions. Describe in general terms the kind of duct involved and determine the duct exit Mach number and velocity in \(\mathrm{ft} / \mathrm{s}\) if the gas is air.

Air flows in a constant-area, insulated duct. The air enters the duct at \(520^{\circ} \mathrm{R}, 50\) psia, and \(\mathrm{Ma}=0.45 .\) At a downstream location, the Mach number is one. Find: (a) The pressure and temperature at the downstream location (b) The change in specific entropy (c) The frictional force if the duct is circular and \(1 \mathrm{ft}\) in diameter.

Air is supplied to a convergent-divergent nozzle from a reservoir where the pressure is \(100 \mathrm{kPa}\). The air is then discharged through a short pipe into another reservoir where the pressure can be varied. The cross- sectional area of the pipe is twice the area of the throat of the nozzle. Friction and heat transfer may be neglected throughout the flow. If the discharge pipe anstant cross-sectional area, determine the range of static pressure in the pipe for which a normal shock will stand in the divergent section of the nozzle. If the discharge pipe tapers so that its cross- sectional area is reduced by \(25 \%\), show that a normal shock cannot be drawn to the end of the divergent section of the nozzle. Find the maximum strength of shock (as expressed by the upstream Mach number) that can be formed.

A nozzle for a supersonic wind tunnel is designed to achieve a Mach number of \(3.0,\) with a velocity of \(2000 \mathrm{m} / \mathrm{s},\) and a density of \(1.0 \mathrm{kg} / \mathrm{m}^{3}\) in the test section. Find the temperature and pressure in the test section and the upstream stagnation conditions. The fluid is helium.

The gas entering a rocket nozzle has a stagnation pressure of \(1500 \mathrm{kPa}\) and a stagnation temperature of \(3000^{\circ} \mathrm{C}\). The rocket is traveling in the still Standard Atmosphere at \(30,000 \mathrm{m}\). Find the throat and exit area for a flow rate of \(10 \mathrm{kg} / \mathrm{s}\). Assume \(k=1.35, R=\) \(287.0 \mathrm{N} \cdot \mathrm{m} / \mathrm{kg} \cdot \mathrm{K} .\) The gas is perfectly, expanded to the ambient pressure.

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