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A viscous liquid \(\left(\mu=0.012 \mathrm{lb} \cdot \mathrm{s} / \mathrm{ft}^{2}, \rho=1.79 \mathrm{slugs} / \mathrm{ft}^{3}\right)\) flows through the annular space between two horizontal, fixed, concentric cylinders. If the radius of the inner cylinder is 1.5 in. and the radius of the outer cylinder is 2.5 in., what is the pressure drop along the axis of the annulus per foot when the volume flowrate is \(0.14 \mathrm{ft}^{3} / \mathrm{s} ?\)

Short Answer

Expert verified
The pressure drop per foot along the axis of the annulus is approximately 17.57 lb/ft².

Step by step solution

01

Convert Units for Radii

First, we need to convert the given radii from inches to feet to maintain unity in our calculations. The inner cylinder radius, 1.5 in., and outer cylinder radius, 2.5 in., can be converted to 0.125 feet and 0.2083 feet respectively.
02

Determine Flow Characteristics

Given the flow rate \(Q = 0.14 \, \text{ft}^3/\text{s}\), viscosity \(\mu = 0.012 \, \text{lb} \cdot \text{s}/\text{ft}^2\), and density \( \rho = 1.79 \, \text{slugs}/\text{ft}^3\), we consider the flow to be steady and driven by a pressure difference. The annular flow can typically be described using the Hagen-Poiseuille equation for flow through annular spaces.
03

Calculate Hydraulic Diameter

The hydraulic diameter \(D_h\) for annular flow is calculated by the expression: \[D_h = 2 \cdot (R_o - R_i) \] where \(R_o\) is the radius of outer cylinder, and \(R_i\) is the radius of inner cylinder. Plugging in values, \[D_h = 2 \cdot (0.2083 - 0.125) = 0.1666 \, \text{ft}.\]
04

Use Hagen-Poiseuille Equation for Annular Flow

The pressure drop \(\Delta P\) per unit length \(L\) for a Newtonian fluid in annular flow is given by the formula: \[\Delta P/L = \frac{32 \cdot \mu \cdot Q}{\pi \cdot \left( R_o^2 - R_i^2 \right)^2}\]Substituting the known values (and converting radii to ft), we calculate \(\Delta P/L\).
05

Plug in Values and Solve

Substitute the values into the formula:\( R_o = 0.2083 \, \text{ft}\), \( R_i = 0.125 \, \text{ft}\), \(\mu = 0.012 \, \text{lb} \cdot \text{s}/\text{ft}^2\), and \(Q = 0.14 \, \text{ft}^3/\text{s}\).\[\Delta P/L = \frac{32 \cdot 0.012 \cdot 0.14}{\pi \cdot (0.2083^2 - 0.125^2)^2}\]Calculating, we find \(\Delta P/L \approx 17.57 \, \text{lb}/\text{ft}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Viscous Flow
Viscous flow refers to the type of fluid flow where the fluid exhibits a significant amount of internal friction or viscosity. This internal friction arises from the intermolecular forces within the fluid as it moves along a solid surface, such as the annular space between two cylinders. Viscosity, represented by the symbol \(\mu\), quantifies the degree of resistance that a fluid offers against shearing forces. In simpler terms, it measures how 'thick' or 'sticky' a fluid is.

When dealing with viscous flow, it's vital to consider both the viscosity of the liquid and the geometry of the flow path. In the case of concentric cylinders, the fluid's flow characteristics depend on the difference between the speeds at which adjacent fluid layers move. Viscous flow is characteristically laminar when these layers slide smoothly past each other, allowing us to use mathematical expressions like the Hagen-Poiseuille equation to describe the fluid motion effectively. Understanding viscous flow is crucial in applications across chemical, mechanical, and civil engineering.
Hagen-Poiseuille Equation
Named after the scientists Gotthilf Hagen and Jean Léonard Marie Poiseuille, the Hagen-Poiseuille equation is fundamental in fluid mechanics for describing the flow of Newtonian fluids through a cylindrical pipe, or annular spaces, with a constant circular cross-section. The equation links several factors including the fluid's viscosity \(\mu\), the pressure difference along the pipe, the length of the pipe \(L\), and the flow rate \(Q\).

For flow in an annular space, a modified version of this equation is typically used, reflecting the different geometry. This version considers the hydraulic diameter, which, in simple words, acts as an equivalent diameter for the annulus. The equation provides a practical way to predict how much pressure must be applied to achieve a specific flow rate. Hagen-Poiseuille's equation is: \[\Delta P / L = \frac{32 \cdot \mu \cdot Q}{\pi \cdot \left( R_o^2 - R_i^2 \right)^2}\]
where \(R_o\) and \(R_i\) are the radii of the outer and inner cylinders respectively. It is important to note that this model assumes a steady, incompressible, and laminar flow regime.
Pressure Drop
In fluid mechanics, pressure drop refers to the reduction in fluid pressure as it flows through a pipe or confined space, such as an annulus between two cylinders. This drop in pressure is primarily due to the frictional forces within the fluid, which are directly related to viscosity. Pressure drop is a critical factor in designing piping systems and calculations are essential for determining the pumping energy needed to transport fluids over distances.

When calculating pressure drop, several factors must be considered:
  • Viscosity of the fluid: Higher viscosity leads to a larger pressure drop.
  • Flow geometry: The shape and size of the flow path, such as the annulus between concentric cylinders, significantly affect the pressure drop.
  • Flow rate: An increased flow rate requires a higher pressure to maintain constant flow.
In our specific scenario, the pressure drop per unit length \(\Delta P / L\) is computed using a formula derived from the Hagen-Poiseuille law, tailored for annular flow. Here, pressure drop calculations help ensure that systems are efficient and cost-effective, preventing excessive energy consumption and wear on system components.
Hydraulic Diameter
The hydraulic diameter is a concept in fluid dynamics used to characterize the flow in non-circular conduits. This is particularly useful in annular geometries like the space between two concentric cylinders. While typical circular pipes use their physical diameter to describe flow characteristics, annular flow uses an equivalent 'hydraulic diameter', which simplifies the application of fluid mechanics equations designed for circular pipes.

The hydraulic diameter \(D_h\) for an annulus is given by:\[D_h = 2 \cdot (R_o - R_i)\]where \(R_o\) and \(R_i\) are the outer and inner radii respectively. This equation calculates a diameter that reflects the effective cross-section area available for flow. In our example, this yielded a hydraulic diameter of 0.1666 ft. Hydraulic diameter assists engineers in analyzing and designing systems where fluid flows through complex geometries, ensuring that the conditions for laminar or turbulent flow are accurately assessed.

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Most popular questions from this chapter

A certain flow field is described by the stream function \\[\psi=A \theta+B r \sin \theta\\] where \(A\) and \(B\) are positive constants. Determine the corresponding velocity potential and locate any stagnation points in this flow field.

Determine an expression for the vorticity of the flow field described by \\[\mathbf{V}=-x y^{3} \hat{\mathbf{i}}+y^{4} \hat{\mathbf{j}}\\] Is the flow irrotational?

In a certain steady, two-dimensional flow field the fluid may be assumed to be ideal and the weight of the fluid (specific weight \(\left.=50 \mathrm{lb} / \mathrm{ft}^{3}\right)\) is the only body force. The \(x\) component of velocity is known to be \(u=6 x,\) which gives the velocity in \(\mathrm{ft} / \mathrm{s}\) when \(x\) is measured in feet, and the \(y\) component of velocity is known to be a function of only \(y .\) The \(y\) axis is vertical, and at the origin the velocity is zero. (a) Determine the \(y\) component of velocity so that the continuity equation is satisfied. (b) Can the difference in pressures between the points \(x=1 \mathrm{ft}, y=1 \mathrm{ft}\) and \(x=1 \mathrm{ft}, y=4 \mathrm{ft}\) be determined from the Bernoulli equation? If so, determine the value in \(\mathrm{lb} / \mathrm{ft}^{2}\). If not, explain why not.

For each of the following stream functions, with units of \(\mathrm{m}^{2} / \mathrm{s},\) determine the magnitude and the angle the velocity vector makes with the \(x\) axis at \(x=1 \mathrm{m}, y=2 \mathrm{m} .\) Locate any stagnation points in the flow field. (a) \(\psi=x y\) (b) \(\psi=-2 x^{2}+y\)

As is shown by Eq. \(6.150,\) the pressure gradient for laminar flow through a tube of constant radius is given by the expression \\[\frac{\partial p}{\partial z}=-\frac{8 \mu Q}{\pi R^{4}}\\] For a tube whose radius is changing very gradually, such as the one illustrated in Fig. \(\mathrm{P} 6.106,\) it is expected that this equation can be used to approximate the pressure change along the tube if the actual radius, \(R(z),\) is used at each cross section. The following measurements were obtained along a particular tube. $$\begin{array}{l|l|l|l|l|l|l|l|l|l|l|l} z / \ell & 0 & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 & 0.6 & 0.7 & 0.8 & 0.9 & 1.0 \\ \hline R(z) / R_{o} & 1.00 & 0.73 & 0.67 & 0.65 & 0.67 & 0.80 & 0.80 & 0.71 & 0.73 & 0.77 & 1.00 \end{array}$$ Compare the pressure drop over the length \(\ell\) for this nonuniform tube with one having the constant radius \(R_{o} .\) Hint: To solve this problem you will need to numerically integrate the equation for the pressure gradient given previously.

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