Chapter 5: Problem 2
An incompressible fluid flows horizontally in the \(x-y\) plane with a velocity given by \\[ u=30(y / h)^{1 / 2} \mathrm{m} / \mathrm{s}, \mathrm{v}=0 \\] where \(y\) and \(h\) are in meters and \(h\) is a constant. Determine the average velocity for the portion of the flow between \(y=0\) and \(y=h\)
Short Answer
Step by step solution
Understand the Average Velocity Formula
Setup the Integral
Simplify the Integral Expression
Compute the Integral
Substitute the Integral Back Into the Expression
Simplify the Expression
Answer the Problem
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Average velocity calculation
For our specific problem, this concept is represented by the formula: \[ \overline{u} = \frac{1}{h} \int_0^h u(y) \, dy \] Here, \( h \) is the upper bound of the region of interest, which is the maximum height in the y-direction of our flow region, and \( u(y) \) is the velocity profile that varies with \( y \).
The key steps in the average velocity calculation involve setting up the integral using the given velocity equation, calculating the integral, and then simplifying the result to find \( \overline{u} \). This approach ensures we accurately depict how the velocity changes across the fluid's flow path. Understanding this process is essential for various engineering applications, such as designing pipes or predicting fluid movement.
Velocity profile integration
In our scenario, the velocity profile is provided as a function of y, \( u(y) = 30(y/h)^{1/2} \), where \( h \) is a constant. Setting up the integral involves placing this profile into the integral equation: \[ \overline{u} = \frac{1}{h} \int_0^h 30 \left( \frac{y}{h} \right)^{1/2} \, dy \]. Here, the function \( 30(y/h)^{1/2} \) needs to be integrated from \( 0 \) to \( h \). Remember, understanding this setup is crucial because the whole purpose is to assess the mean effect of the velocity across the span.
Notice how constants such as \( 30 \) and \( h^{-1/2} \) are factored out to simplify the integral. This simplification is integral (pun intended!) to solving the problem efficiently and getting a clear picture of the fluid's average velocity.
Power rule integration
Applying this rule to our expression, \( \int y^{1/2} \, dy \), transforms this into: \[ \left[ \frac{y^{3/2}}{3/2} \right]_0^h = \left[ \frac{2}{3} y^{3/2} \right]_0^h = \frac{2}{3} h^{3/2} \]. This result comes from substituting the upper and lower limits \( h \) and \( 0 \) into the integrated expression, resulting in \( \frac{2}{3} h^{3/2} \) because the zero term drops off.
The elegance of the power rule lies in its ability to handle fractional exponents easily and commonly appears in fluid dynamics scenarios. By mastering it, you're well-equipped to tackle complex velocity profiles and optimize fluid dynamic systems more effectively.