Chapter 8: Problem 81
Water is pumped between two large open reservoirs through \(1.5 \mathrm{km}\) of smooth pipe. The water surfaces in the two reservoirs are at the same efevation. When the pump adds \(20 \mathrm{kW}\) to the water the flowrate is \(1 \mathrm{m}^{3} / \mathrm{s}\). If minor losses are negligible, determine the pipe diameter.
Short Answer
Step by step solution
Understanding the Problem
Use Energy Equation
Solve for Head Loss
Use Darcy-Weisbach Equation
Calculate Flow Velocity
Guess Friction Factor for Turbulent Flow
Solve for Diameter
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Darcy-Weisbach equation
- The flow velocity
- The pipe's length and diameter
- The fluid's density
- The friction factor
- \( H_f \) is the head loss due to friction.
- \( f \) is the friction factor, which depends on the surface roughness of the pipe and flow conditions.
- \( L \) is the pipe length.
- \( D \) is the pipe diameter.
- \( V \) is the flow velocity.
- \( g \) is the acceleration due to gravity.
Flow rate calculation
Pipe diameter determination
- Start with the Darcy-Weisbach equation for head loss and plug in known values for head loss and friction factor.
- Express flow velocity in terms of diameter using the flow rate equation.
- Combine these expressions and simplify to isolate \( D \).
- Numerically solve the resulting equation which may look like: \( D^5 \approx 0.055 \).
Incompressible flow
- Volume flow rate remains consistent across different sections of the pipe.
- Density is constant, simplifying the application of energy equations.
- Changes in pressure and velocity can still impact flow velocity and head loss calculations.