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Under certain conditions, wind blowing past a rectangular speed limit sign can cause the sign to oscillate with a frequency \(\omega\). (See Fig. P7.11 and Video Y9.6.) Assume that \(\omega\) is a function of the sign width, \(b\), sign height, \(h\), wind velocity, \(V\), air density, \(\rho\), and an elastic constant, \(k\), for the supporting pole. The constant, \(k\), has dimensions of \(F L\). Develop a suitable set of pi terms for this problem.

Short Answer

Expert verified
The dimensionless pi terms are \( \pi_1 = \frac{\omega b}{V}\), \( \pi_2 = \frac{h}{b}\), \( \pi_3 = \frac{k}{\rho V^2 b^2}\).

Step by step solution

01

Identify relevant variables and their dimensions

The problem gives us the following variables: frequency \( \omega \), sign width \( b \), sign height \( h \), wind velocity \( V \), air density \( \rho \), and elastic constant \( k \). The dimensions are: \( \omega \) has dimensions of frequency \( [T^{-1}] \), \( b \) and \( h \) (length) are \( [L] \), \( V \) (velocity) is \( [LT^{-1}] \), \( \rho \) (density) is \( [ML^{-3}] \), and \( k \) (force times length) is \( [F][L] \), which is \( [ML^2T^{-2}] \).
02

Determine the base dimensions

To create the dimensionless pi terms, we consider a base set of dimensions: length \( [L] \), mass \( [M] \), and time \( [T] \). The variables involved are expressed in these fundamental dimensions.
03

Apply Buckingham Pi Theorem

The Buckingham Pi Theorem suggests finding a set of dimensionless pi terms (\( \pi \) terms) from these variables. Consider choosing, for instance, \( b \), \( \rho \), and \( V \) as the repeating variables. The constraint is that these variables must be dimensionally independent.
04

Formulate the dimensionless pi terms

Using the repeating variables \( b \), \( \rho \), and \( V \), express each remaining variable \( \omega \), \( h \), \( k \) in terms of these base variables to find dimensionless groups. For example, with dimensions \([T^{-1}]=\omega = b^a \rho^b V^c\), solve for \( a \, , b \, , c\) such that the result is dimensionless.
05

Calculate specific pi groups

Using the dimension equations, we find: \[\pi_1 = \frac{\omega b}{V}, \quad \pi_2 = \frac{h}{b}, \quad \pi_3 = \frac{k}{\rho V^2 b^2}.\] Verify that these groups are dimensionless by replacing with their respective dimensions and ensuring they have no units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buckingham Pi Theorem
The Buckingham Pi Theorem is a key concept in dimensional analysis that simplifies complex physical situations by reducing physical quantities into dimensionless numbers, called pi terms. To do this effectively, you must first identify all the variables involved and express their respective dimensions in terms of the basic dimensional units: length (L), mass (M), and time (T).

Here's how it works:
  • Identify all relevant variables and their dimensions. For the problem at hand, we have frequency \( \omega \), sign width \( b \), sign height \( h \), wind velocity \( V \), air density \( \rho \), and the elastic constant \( k \).
  • Choose a subset of these variables that are dimensionally independent to serve as repeating variables. In this case, \( b \), \( \rho \), and \( V \) are often chosen because they cover the dimensions of length, mass, and time effectively.
  • Construct dimensionless pi terms with these repeating variables to uncover fundamental relationships between them without the bias of units.
When using the Buckingham Pi Theorem, the goal is to transform the problem into a simpler, more understandable form.

This theorem offers a systematic method for breaking down complex problems and establishing their core relationships.
Oscillation Frequency
Oscillation frequency (\( \omega \)) refers to the number of vibrations that occur in a given time period, often measured in cycles per second or Hertz (Hz). In problems involving physical structures, understanding the oscillation frequency is crucial because it indicates how the structure behaves under specific forces such as wind.

The frequency of oscillation of an object can be influenced by several external factors:
  • The geometric properties of the object, such as height \( h \) and width \( b \).
  • External influences like wind velocity \( V \) and air density \( \rho \).
  • The material properties, captured here by the elastic constant \( k \).
For wind-induced vibrations, calculating how often a pattern of oscillation repeats itself based on these parameters helps ensure the stability and safety of structures. Determining the dimensionless term \( \pi_1 = \frac{\omega b}{V} \) illustrates how the frequency is normalized across different conditions and scales.
Wind-Induced Vibration
Any structure exposed to wind can experience wind-induced vibrations. These occur due to uneven pressure distribution caused by the wind flow around the structure, leading to oscillations. Such vibrations can be harmful if not properly understood or mitigated.

To analyze wind-induced vibration:
  • Consider the wind velocity \( V \), which determines the speed at which air flows past the structure.
  • Analyze the effect of the air density \( \rho \), which can affect how much force the wind exerts on the structure.
  • Evaluate the dimensions of the structure \( b \) and \( h \), as they affect how the structure reacts to wind forces.
In engineering, knowing how these parameters interact is crucial for designing structures that can withstand natural forces without succumbing to fatigue or structural failure. Protecting against excessive vibrations involves tuning the geometry and material properties to ensure they align well with the expected environmental conditions.
Dimensionless Pi Terms
Dimensionless pi terms are at the heart of analyzing complex systems using the Buckingham Pi Theorem. They distill the essence of a problem by removing any dependency on specific units, allowing for greater insight and comparison across different scenarios.

In our exercise, the dimensionless pi terms are composed as follows:
  • \( \pi_1 = \frac{\omega b}{V} \) represents how the oscillation frequency \( \omega \) is related to the physical dimensions \( b \) and the wind speed \( V \). It is useful in predicting structural behavior under varying wind speeds.
  • \( \pi_2 = \frac{h}{b} \) compares the height and width of the structure, often used for assessing the aspect ratio's effect on vibration.
  • \( \pi_3 = \frac{k}{\rho V^2 b^2} \) encapsulates how material stiffness, air properties, and geometric features contribute to the vibration response.
Each of these terms is carefully derived to ensure they are truly dimensionless, meaning that they are pure numeric ratios derived from various combinations of the original variables. This approach helps in simplifying experimental analysis and in making broad generalizations about similar systems.

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Most popular questions from this chapter

Assume that the drag, \(\mathscr{D},\) on an aircraft flying at supersonic speeds is a function of its velocity, \(V\), fluid density, \(\rho\) speed of sound, \(c,\) and a series of lengths, \(\ell_{1}, \ldots, \ell_{i},\) which describe the geometry of the aircraft. Develop a set of pi terms that could be used to investigate experimentally how the drag is affected by the various factors listed. Form the pi terms by inspection.

The pressure rise, \(\Delta p,\) across a pump can be expressed as \\[ \Delta p=f(D, \rho, \omega, Q) \\] where \(D\) is the impeller diameter, \(\rho\) the fluid density, \(\omega\) the rotational speed, and \(Q\) the flowrate. Determine a suitable set of dimensioniess parameters.

The pressure drop, \(\Delta p\), over a certain length of horizontal pipe is assumed to be a function of the velocity, \(V\), of the fluid in the pipe, the pipe diameter, \(D\), and the fluid density and viscosity, \(\rho\) and \(\mu .\) (a) Show that this flow can be described in dimensionless form as a "pressure coefficient," \(C_{p}=\Delta p /\left(0.5 \rho V^{2}\right)\) that depends on the Reynolds number, Re \(=\rho V D / \mu\). (b) The following data were obtained in an experiment involving a fluid with \(p=2 \operatorname{slug} s / \mathrm{f}^{3}, \mu=2 \times 10^{-3} 1 \mathrm{b} \cdot \mathrm{s} / \mathrm{ft}^{2},\) and \(D=0.1 \mathrm{ft} .\) Plot a dimensionless graph and use a power law equation to determine the functional relationship between the pressure coefficient and the Reynolds number. (c) What are the limitations on the applicability of your equation obtained in part (b)?

At a sudden contraction in a pipe the diameter changes from \(D_{1}\) to \(D_{2}\). The pressure drop, \(\Delta p\), which develops across the contraction is a function of \(D_{1}\) and \(D_{2}\), as well as the velocity, \(V\), in the larger pipe, and the fluid density, \(\rho,\) and viscosity, \(\mu .\) Use \(D_{1}, V,\) and \(\mu\) as repeating variables to determine a suitable set of dimensionless parameters. Why would it be incorrect to include the velocity in the smaller pipe as an additional variable?

A cone and plate viscometer consists of a cone with a very small angle \(\alpha\) which rotates above a flat surface as shown in Fig. \(\mathrm{P} 7.17 .\) The torque, \(\mathscr{T},\) required to rotate the cone at an angular velocity, \(\omega,\) is a function of the radius, \(R,\) the cone angle, \(\alpha,\) and the fluid viscosity, \(\mu,\) in addition to \(\omega .\) With the aid of dimensional analysis, determine how the torque will change if both the viscosity and angular velocity are doubled.

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