/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 The velocity potential for a spi... [FREE SOLUTION] | 91Ó°ÊÓ

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The velocity potential for a spiral vortex flow is given by \(\phi=(\Gamma / 2 \pi) \theta-(m / 2 \pi) \operatorname{tn} r,\) where \(\Gamma\) and \(m\) are constants. Show that the angle, \(\alpha\), between the velocity vector and the radial direction is constant throughout the flow field (see Fig. P6.49)

Short Answer

Expert verified
The angle \(\alpha\) is constant because \(\tan \alpha = -\frac{\Gamma}{m}\), which is independent of \(r\) and \(\theta\).

Step by step solution

01

Understand the velocity potential

The velocity potential is a scalar function whose gradient gives the velocity field of a fluid flow. In this problem, the potential is given as \( \phi = \frac{\Gamma}{2\pi} \theta - \frac{m}{2\pi} \ln r \).
02

Derive the velocity components

To find the velocity components in a polar coordinate system \((r, \theta)\), find the derivatives of the potential function \(\phi\). The radial component \(v_r\) is given by \(v_r = \frac{\partial \phi}{\partial r}\), and the tangential component \(v_\theta\) is given by \(v_\theta = \frac{1}{r}\frac{\partial \phi}{\partial \theta}\).
03

Calculating \(v_r\)

Calculate \(v_r\) by differentiating \(\phi\) with respect to \(r\): \[ v_r = \frac{\partial}{\partial r} \left( \frac{\Gamma}{2\pi} \theta - \frac{m}{2\pi} \ln r \right) = -\frac{m}{2\pi r} \].
04

Calculating \(v_\theta\)

Calculate \(v_\theta\) by differentiating \(\phi\) with respect to \(\theta\) and then dividing by \(r\): \[ v_\theta = \frac{1}{r} \cdot \frac{\partial}{\partial \theta} \left( \frac{\Gamma}{2\pi} \theta - \frac{m}{2\pi} \ln r \right) = \frac{\Gamma}{2\pi r} \].
05

Calculate the angle \(\alpha\)

The angle \(\alpha\) is the angle between the velocity vector and the radial direction, calculated using the components: \[ \tan \alpha = \frac{v_\theta}{v_r} = \frac{\frac{\Gamma}{2\pi r}}{-\frac{m}{2\pi r}} = -\frac{\Gamma}{m} \].
06

Conclude \(\alpha\) is constant

Since \(\tan \alpha = -\frac{\Gamma}{m}\), \(\alpha\) is constant throughout the flow field because it depends only on the constants \(\Gamma\) and \(m\), not on the variables \(r\) or \(\theta\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spiral Vortex Flow
Spiral vortex flow is a fascinating concept in fluid mechanics that describes a unique pattern of circulation within a fluid. In such a flow, the fluid moves in spiral paths around a central point. This can often be observed in natural phenomena, such as whirlpools or tornado spirals. Understanding this flow involves visualizing how the fluid spirals around a center while often moving outward or inward in a radial direction.

In mathematical terms, a spiral vortex is characterized by specific functions like the velocity potential. These functions help describe how the fluid particles are moving in the flow field. By examining these functions and the derived velocity components, we can unravel the forces directing the fluid into its spiral shape.

For students working with spiral vortex problems, it is important to understand that the key variables often involve radial distance and angular position. By analyzing these variables, you can grasp how the velocity and direction of the fluid change, or in the case of this exercise, remain constant throughout the flow field.
Velocity Potential
The velocity potential in fluid mechanics is a scalar function that helps to simplify the analysis of flow patterns. Its gradient yields the actual velocity field of the fluid flow. In simpler terms, it is like a map that tells you how the fluid is moving without showing individual detailed velocity vectors directly.

In this particular exercise, the velocity potential \( \phi = \frac{\Gamma}{2\pi} \theta - \frac{m}{2\pi} \ln r \) involves two essential elements: the angular component, \( \theta \), and the radial logarithmic component, \( \ln r \). These components respectively control how the flow circulates in angular and radial directions. The constants \( \Gamma \) and \( m \) are specific parameters that represent strength and influence of the spiral nature of the flow.

By taking the gradient of this potential, the velocity components can be derived, allowing us to make deeper insights into both the speed and direction of flow at any given point.
Polar Coordinates
Polar coordinates offer a unique and efficient way to analyze flow, especially in cases like spiral vortex flows. In contrast to Cartesian coordinates, which locate a point in space using \(x\) and \(y\) axes, polar coordinates make use of \(r\) and \(\theta\).

- \(r\): Represents the radial distance from the origin (a measure of how far you are from the center of the flow).
- \(\theta\): Measures the angular position around the origin, typically in radians.

This coordinate system is particularly beneficial for problems involving circles or spirals, where geometries are oriented around a center point. In our spiral vortex flow example, it simplifies the mathematics by aligning the analysis with the natural path of the flow, following the curves dictated by \(r\) and \(\theta\).

Utilizing polar coordinates allows engineers and students to effectively map the swirling movement of the fluid, helping to solve complex flow problems by breaking them into more manageable components.
Velocity Components
The velocity components in fluid flow give insight into the actual motion of the fluid in the spiral vortex. These components are derived from the velocity potential by taking partial derivatives in polar coordinates:

- **Radial Velocity (\( v_r \))**: This indicates the speed at which fluid particles are moving directly away from or towards the center. For our scenario, it can be expressed as:\[ v_r = \frac{\partial \phi}{\partial r} = -\frac{m}{2\pi r} \]

- **Tangential Velocity (\( v_\theta \))**: This signifies the speed at which fluid is flowing in a circular path around the center point, and is calculated as:\[ v_\theta = \frac{1}{r} \cdot \frac{\partial \phi}{\partial \theta} = \frac{\Gamma}{2\pi r} \]

Understanding these components is vital as they describe not just how fast, but which direction the fluid moves at any point. The constancy of the angle \(\alpha\) between these components implies that while the motion paths may curve, the overall flow pattern remains steady under the conditions outlined by the potential and the constants \(\Gamma\) and \(m\).

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Most popular questions from this chapter

Determine an expression for the vorticity of the flow field described by $$\mathbf{V}=-x y^{3} \hat{\mathbf{i}}+y^{4} \hat{\mathbf{j}}$$ Is the flow irrotational?

The three components of velocity in a flow field are given by $$\begin{array}{l} u=x^{2}+y^{2}+z^{2} \\ v=x y+y z+z^{2} \\ w=-3 x z-z^{2} / 2+4 \end{array}$$ (a) Determine the volumetric dilatation rate and interpret the results. (b) Determine an expression for the rotation vector. Is this an irrotational flow field?

In a certain two-dimensional flow field, the velocity is constant with components \(u=-4 \mathrm{ft} / \mathrm{s}\) and \(v=-2 \mathrm{ft} / \mathrm{s}\). Deter mine the corresponding stream function and velocity potential for this flow field. Sketch the equipotential line \(\phi=0\) which passes through the origin of the coordinate system.

The stream function for a two-dimensional, nonviscous, incompressible flow field is given by the expression $$\psi=-2(x-y)$$ where the stream function has the units of \(\mathrm{ft}^{2} / \mathrm{s}\) with \(x\) and \(y\) in feet. (a) Is the continuity equation satisfied? (b) Is the flow field irrotational? If so, determine the corresponding velocity potential. (c) Determine the pressure gradient in the horizontal \(x\) direction at the point \(x=2 \mathrm{ft}, y=2 \mathrm{ft}\)

A highly viscous Newtonian liquid \(\left(\rho=1300 \mathrm{kg} / \mathrm{m}^{3}\right.\) \(\mu=6.0 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}^{2}\) ) is contained in a long, vertical, \(150-\mathrm{mm}\) diameter tube. Initially the liquid is at rest but when a valve at the bottom of the tube is opened flow commences. Although the flow is slowly changing with time, at any instant the velocity distribution is parabolic, that is, the flow is quasi-steady. (See Video \(Y(6.6 .)\) Some measurements show that the average velocity, \(V\), is changing in accordance with the equation \(V=0.1 t,\) with \(V\) in \(\mathrm{m} / \mathrm{s}\) when \(t\) is in seconds. (a) Show on a plot the velocity distribution \(\left(v_{i} \text { vs. } r\right)\) at \(t=2 \mathrm{s}\), where \(v_{\mathrm{e}}\) is the velocity and \(r\) is the radius from the center of the tube. (b) Verify that the flow is laminar at this instant.

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