/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 83 An inward flow radial turbine (s... [FREE SOLUTION] | 91Ó°ÊÓ

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An inward flow radial turbine (see Fig. P5.83) involves a nozzle angle, \(\alpha_{1},\) of \(60^{\circ}\) and an inlet rotor tip speed, \(U_{1},\) of 30 ft/s. The ratio of rotor inlet to outlet diameters is \(2.0 .\) The radial component of velocity remains constant at \(20 \mathrm{ft} / \mathrm{s}\) through the rotor, and the flow leaving the rotor at section (2) is without angular momentum. If the flowing fluid is water and the stagnation pressure drop across the rotor is 16 psi, determine the loss of available energy across the rotor and the hydraulic efficiency involved.

Short Answer

Expert verified
The loss of available energy is 36.8 ft, and the hydraulic efficiency is 79.7%.

Step by step solution

01

Calculate Tangential Velocity at Inlet

The tangential velocity at inlet, \( V_{t1} \), can be calculated using the equation: \( V_{t1} = V_{1} \cos(\alpha_{1}) \). Here, \( V_{1} \) is the resultant velocity at inlet which can be expressed as \( U_{1} + V_{r} \). Substitute the given values: \( V_{1} = 30 + 20 \), and \( \alpha_{1} = 60^{\circ} \). Therefore, \( V_{t1} = (30 + 20) \cos(60^{\circ}) = 25 \) ft/s.
02

Determine the Tangential Velocity at Outlet

Since the flow leaves the rotor without angular momentum, the tangential velocity at the outlet, \( V_{t2} \), is zero: \( V_{t2} = 0 \) ft/s.
03

Relate Diameters and Tangential Component

The ratio of the inlet rotor diameter to the outlet is given as 2.0, so \( D_{1}/D_{2} = 2 \). The relationship between the tangential components is given by \( U_{2} = U_{1}/2 \), hence \( U_{2} = 15 \) ft/s.
04

Calculate the Loss of Available Energy

The available energy loss \( \Delta E \) is determined by the change in stagnation pressure, \( \Delta P = 16 \) psi. Convert this pressure drop into feet of water using \( \Delta H = \Delta P/\gamma \), where \( \gamma = 62.4 \) lb/ft³ (density of water). The loss of available energy is \( \Delta E = 16 \times 144/62.4 = 36.8 \) ft.
05

Calculate Hydraulic Efficiency

The hydraulic efficiency \( \eta_{h} \) is the ratio of the work output to the available energy, \( \eta_{h} = \frac{U_{1}(V_{t1} - V_{t2})}{\Delta E} \). Using \( U_{1} = 30 \) ft/s, \( V_{t1} = 25 \) ft/s, \( V_{t2} = 0 \), and \( \Delta E = 36.8 \) ft, we find \( \eta_{h} = \frac{30 \times 25}{36.8} = 0.797 \) or 79.7%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydraulic Efficiency
Hydraulic efficiency is a measure of how effectively a hydraulic machine, like a pump or turbine, converts the hydraulic energy of a fluid into mechanical energy. In this case, we are evaluating a radial turbine, which is a type of turbine where the fluid flows radially through the machine.

Hydraulic efficiency (\(\eta_h\)) is calculated as the ratio of the useful work output of the turbine to the available hydraulic energy input. It indicates how much of the energy supplied by the fluid is converted into mechanical energy that can be used to perform work. In our exercise, the hydraulic efficiency was found to be 79.7%, meaning nearly 80% of the energy contributed by the fluid was successfully transformed into mechanical energy by the turbine.
  • Formula: \(\eta_h = \frac{U_1(V_{t1} - V_{t2})}{\Delta E}\)
  • Improvements in hydraulic efficiency would imply reduced energy losses and greater energy conversion rates.
Stagnation Pressure
Stagnation pressure is the pressure a fluid exerts when it is brought to rest isentropically. It's a critical concept in fluid dynamics and is crucial when analyzing the energy changes in fluid flow systems like turbines.

In our problem, the stagnation pressure drop across the rotor was given as 16 psi. This change represents the energy that was lost due to different factors such as friction, turbulence, or heat transfer within the rotor. By computing the change in stagnation pressure, we can determine the loss of energy, which is a key part of finding out how effective a turbine is.
  • Used to calculate energy losses in systems.
  • Greater stagnation pressure drop usually implies more energy is being lost, reducing efficiency.
Tangential Velocity
Tangential velocity is the velocity of a point on a rotating object tangent to the direction of rotation. It is crucial for understanding the kinetic energy distribution in radial turbines.

In our exercise, tangential velocity at both the inlet and outlet of the rotor was calculated. For the inlet (\(V_{t1}\)), it was determined using the formula \(V_{t1} = V_{1} \cos(\alpha_{1}) \). This calculation helps us understand the components of velocity at which fluid enters the turbine. The fact that the outlet tangential velocity (\(V_{t2}\)) is zero indicates that the flow leaves the rotor without any angular momentum, a condition often seen in well-functioning radial turbines.
  • Influences kinetic energy and angular momentum in a turbine.
  • In the existing solution, known tangential velocities help measure energy conversion.
Radial Turbine
A radial turbine is a type of turbine mechanism where fluid flows radially from the outer edge towards the center. They are widely used due to their compact size and high power density.

In the exercise, the turbine involved was an inward-flow radial turbine, which means that the fluid enters the wheel of the turbine from outside, flows through a nozzle, and exits near the center. The design leverages centripetal acceleration to convert the fluid’s kinetic energy into mechanical energy effectively.
  • Advantages include high efficiency and compact design, making them suitable for many applications.
  • Understanding flow patterns in radial turbines helps in optimizing these systems and reducing energy losses.

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Most popular questions from this chapter

By using velocity triangles for flow upstream (1) and downstream (2) of a turbomachine rotor, prove that the shaft work in per unit mass flowing through the rotor is $$w_{\text {shari }}=\frac{V_{2}^{2}-V_{1}^{2}+U_{2}^{2}-U_{1}^{2}+W_{1}^{2}-W_{2}^{2}}{2}$$ where \(V=\) absolute flow velocity magnitude, \(W=\) relative flow velocity magnitude, and \(U=\) blade speed.

Water enters a conical diffusing passage (see Fig. P5.1) with an average velocity of \(10 \mathrm{ft} / \mathrm{s}\). If the entrance cross section area is \(1 \mathrm{ft}^{2}\), how large should the diffuser exit diameter, \(D_{2}\), be to reduce the average velocity level to \(1 \mathrm{ft} / \mathrm{s} ?\)

A fire hose nozzle is designed to deliver water that will rise \(40 \mathrm{m}\) vertically. Calculate the stagnation pressure required at the nozzie inlet if (a) no loss is assumed, (b) a loss of \(30 \mathrm{N} \cdot \mathrm{m} / \mathrm{kg}\) is assumed.

The exit plane of a 0.20 -m-diameter pipe is partially blocked by a plate with a hole in it that produces a 0.10 -m-diameter stream as shown in Fig. PS.53. The water velocity in the pipe is \(5 \mathrm{m} / \mathrm{s}\). Gravity and viscous effects are negligible. Determine the force needed to hold the plate against the pipe.

A small fan moves air at a mass flow rate of \(0.004 \mathrm{lbm} / \mathrm{s}\) Upstream of the fan, the pipe diameter is 2.5 in., the flow is laminar, the velocity distribution is parabolic, and the kinetic energy coefficient, \(\alpha_{1},\) is equal to \(2.0 .\) Downstream of the fan, the pipe diameter is 1 in., the flow is turbulent, the velocity profile is quite flat, and the kinetic energy coefficient, \(\alpha_{2}\), is equal to 1.08 . If the rise in static pressure across the fan is 0.015 psi and the fan shaft draws 0.00024 hp, compare the value of loss calculated: (a) assuming uniform velocity distributions, (b) considering actual velocity distributions.

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