/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The basic elements of a hydrauli... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The basic elements of a hydraulic press are shown in Fig. P2.12. The plunger has an area of 1 in. \(^{2}\), and a force, \(F_{i}\) can be applied to the plunger through a lever mechanism having a mechanical advantage of 8 to 1 . If the large piston has an area of 150 in. \(^{2}\), what load, \(F_{2}\), can be raised by a force of \(30 \mathrm{lb}\) applied to the lever? Neglect the hydrostatic pressure variation.

Short Answer

Expert verified
The load that can be raised is 36,000 lb.

Step by step solution

01

Identify the Known Values

First, list all the given information from the problem:- Area of the plunger, \( A_i = 1 \text{ in}^2 \)- Area of the large piston, \( A_o = 150 \text{ in}^2 \)- Mechanical advantage of the lever, 8:1- Force applied to the lever, \( F_{ ext{lever}} = 30 \text{ lb} \)
02

Calculate Effective Input Force

Since the lever has a mechanical advantage of 8:1, the effective force applied to the plunger, \( F_i \), is 8 times the force applied to the lever. Thus, \( F_i = 8 \times 30 = 240 \text{ lb} \).
03

Apply Pascal's Principle

Using Pascal's Principle, the pressure exerted by the plunger, \( P_i \), is equal to the pressure exerted by the large piston, \( P_o \). Therefore, we have:\[ P_i = P_o \] \[ \frac{F_i}{A_i} = \frac{F_o}{A_o} \]
04

Solve for Output Force

Rearrange the formula from Step 3 to solve for \( F_o \):\[ F_o = F_i \times \frac{A_o}{A_i} \]Substitute the known values:\[ F_o = 240 \times \frac{150}{1} = 36,000 \text{ lb} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pascal's Principle
Pascal's Principle is a fundamental concept in fluid mechanics. It states that a change in pressure applied to an enclosed fluid is transmitted undiminished throughout the fluid. This principle is vital for understanding how hydraulic systems work. In the context of our hydraulic press problem, Pascal's Principle explains why the force applied at one point (the small plunger) is transferred to another point (the large piston) without losing any strength.

Let's illustrate this with the relevant calculation. When a force is applied to the plunger, it creates pressure given by the formula:
\( P_i = \frac{F_i}{A_i} \)
Because the fluid is enclosed, this pressure is equally applied at the large piston:
\( P_o = \frac{F_o}{A_o} \)
Since \( P_i = P_o \), we can equate these two expressions. This equality allows us to solve for the unknown force or pressure acting on different parts of the system. This concept is the reason why applying a small force over a small area can result in a large force over a larger area, as seen with hydraulic presses.
Mechanical Advantage
Mechanical Advantage is a term used to describe how much a machine multiplies the force applied to it. In our exercise, the lever attached to the hydraulic press provides a mechanical advantage. Specifically, it offers an 8:1 advantage, meaning that the force exerted on the plunger is eight times greater than the force applied to the lever.

This concept can be represented numerically as:
\( F_i = ext{Mechanical Advantage} \times F_{ ext{lever}} \)
In simple words, if you apply 30 lb to the lever, the plunger feels as though you applied 240 lb. The mechanical advantage makes it easier to achieve significant output force without applying input force. Using such levers in hydraulic presses reduces effort and increases efficiency in practical applications.
Input Force Calculation
Input Force Calculation in this context involves determining the effective force applied to the hydraulic system's plunger. We begin by acknowledging the mechanical advantage of our lever system, which boosts the force applied by the user.

Given:
  • Force applied to the lever, \( F_{\text{lever}} = 30 \text{ lb} \)
  • Mechanical advantage = 8
With these in mind, calculate the input force to the plunger as shown:
\( F_i = ext{Mechanical Advantage} \times F_{\text{lever}} = 8 \times 30 = 240 \text{ lb} \)
In other words, while the physical application is just 30 lb, the effective force transmitted through the lever to act on the plunger is 240 lb. This calculation underscores the role of mechanical systems in amplifying effort, making such hydraulic systems particularly powerful.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 0.3 -m-diameter pipe is connected to a 0.02 -m-diameter pipe and both are rigidly held in place. Both pipes are horizontal with pistons at each end. If the space between the pistons is filled with water, what force will have to be applied to the larger piston to balance a force of \(80 \mathrm{N}\) applied to the smaller piston? Neglect friction.

An open container of oil rests on the flatbed of a truck that is traveling along a horizontal road at \(55 \mathrm{mi} / \mathrm{hr}\). As the truck slows uniformly to a complete stop in \(5 \mathrm{s}\), what will be the slope of the oil surface during the period of constant deceleration?

An area in the form of an isosceles triangle with a base width of \(6 \mathrm{ft}\) and an altitude of \(8 \mathrm{ft}\) lies in the plane forming one wall of a tank which contains a liquid having a specific weight of \(79.8 \mathrm{lb} / \mathrm{ft}^{3}\). The side slopes upward making an angle of \(60^{\circ}\) with the horizontal. The base of the triangle is horizontal and the vertex is above the base. Determine the resultant force the fluid exerts on the area when the fluid depth is \(20 \mathrm{ft}\) above the base of the triangular area. Show, with the aid of a sketch, where the center of pressure is located.

A flowrate measuring device is installed in a horizontal pipe through which water is flowing. A U-tube manometer is connected to the pipe through pressure taps located 3 in. on either side of the device. The gage fluid in the manometer has a specific weight of 112 lb/ft \(^{3}\). Determine the differential reading of the manometer corresponding to a pressure drop between the taps of \(0.5 \mathrm{lb} / \mathrm{in}\).

You partially fill a glass with water, place an index card on top of the glass, and then turn the glass upside down while holding the card in place. You can then remove your hand from the card and the card remains in place, holding the water in the glass. Explain how this works.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.