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A hydrometer is used to measure the specific gravity of liquids. (See Video \(\vee 2.6 .\) ) For a certain liquid a hydrometer reading indicates a specific gravity of \(1.15 .\) What is the liquid's density and specific weight? Express your answer in SI units.

Short Answer

Expert verified
The density is 1150 kg/m³ and the specific weight is approximately 11281.5 N/m³.

Step by step solution

01

Understanding Specific Gravity

Specific gravity is the ratio of the density of a substance to the density of a reference substance; for liquids, water is usually the reference. Therefore, specific gravity has no units. If a liquid has a specific gravity of 1.15, it means the liquid is 1.15 times as dense as water.
02

Density of Water in SI Units

In the International System of Units (SI), the density of water at 4°C is approximately 1000 kg/m³. This value will be our reference for calculating the density of the liquid.
03

Calculating the Density of the Liquid

To find the density of the liquid, multiply its specific gravity by the density of water. Thus, the density \( \rho \) of the liquid is \( \rho = 1.15 \times 1000 \, \text{kg/m}^3 = 1150 \, \text{kg/m}^3 \).
04

Understanding specific weight

The specific weight of a fluid is the weight per unit volume and can be calculated using the formula \( \gamma = \rho \times g \), where \( g \) is the acceleration due to gravity, approximately 9.81 m/s² in SI units.
05

Calculating the Specific Weight of the Liquid

Using the formula \( \gamma = \rho \times g \), where \( \rho = 1150 \, \text{kg/m}^3 \) and \( g = 9.81 \, \text{m/s}^2\), we have \( \gamma = 1150 \times 9.81 \, \text{N/m}^3 \). Therefore, the specific weight of the liquid is approximately \( 11281.5 \, \text{N/m}^3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Gravity
Specific gravity is a term used to describe how dense a substance is compared to a reference, usually water, especially in fluid mechanics. It is a dimensionless quantity because it is the ratio of two densities. This means it doesn't have units like meters or kilograms, just a pure number that tells you the relative density compared to water.

A specific gravity greater than 1 indicates that the liquid is denser than water. In the case of our example, the specific gravity is 1.15. This means the liquid is 1.15 times as dense as water, which is why measuring specific gravity is crucial for understanding the properties of various liquids in applications ranging from industrial processes to quality control in laboratories.

Specific gravity can be measured using a hydrometer, which floats at different levels in liquids with different densities. Understanding this concept is essential for fields like engineering and natural sciences.
Density Calculation
Density is a fundamental concept, often linked to specific gravity. It is the amount of mass per unit volume a substance possesses. In fluid mechanics, density helps to predict how substances will behave when they are subject to different forces.

To calculate the density of a liquid from its specific gravity, use the formula:
  • Density of liquid = Specific gravity × Density of water
Since the specific gravity in our example is 1.15, and the density of water is 1000 kg/m³ at 4°C, you can calculate the liquid's density as:
\[\rho = 1.15 \times 1000 \, \text{kg/m}^3 = 1150 \, \text{kg/m}^3 \]
This calculation tells you how much mass, in kilograms, is present within each cubic meter of the liquid. Knowing the density is important for determining buoyancy and pressure processes in engineering applications.
Specific Weight
Specific weight, sometimes called weight density, refers to how much a substance weighs per unit volume. It's important in fields like civil engineering for understanding how forces apply to structures and fluids.

The specific weight \( \gamma \) of a fluid can be calculated by multiplying the density \( \rho \) by the acceleration due to gravity \( g \), which is approximately 9.81 m/s² in SI units. The specific weight formula is:
  • Specific weight \( \gamma = \rho \times g \)
For our liquid with a specified density of 1150 kg/m³:\[\gamma = 1150 \, \text{kg/m}^3 \times 9.81 \, \text{m/s}^2 = 11281.5 \, \text{N/m}^3 \]
This result tells us the force exerted by the liquid per unit volume, which is crucial for designing containers and systems that will hold the liquid. It makes sure they can withstand the forces exerted by the liquid's weight.

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