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In the preliminary design of a power plant, water is chosen as the working fluid and it is determined that the turbine inlet temperature may not exceed \(520^{\circ} \mathrm{C}\). Based on expected cooling water temperatures, the condenser is to operate at a pressure of \(0.06\) bar. Determine the steam generator pressure required if the isentropic turbine efficiency is \(80 \%\) and the quality of steam at the turbine exit must be at least \(90 \%\).

Short Answer

Expert verified
Determine the steam generator pressure by iterating the inlet pressure until the exit quality constraint is satisfied for a turbine exit with a quality of at least 90% and an isentropic efficiency of 80%.

Step by step solution

01

Identify State Points and Property Values

At the turbine inlet, the temperature is given as \(520^{\circ}C\) and the pressure needs to be determined. At the turbine exit, the pressure is given as \(0.06\) bar and the quality must be at least \(90\%\) (\(x_2 = 0.9\)). Let's denote the turbine inlet state as point 1 (\(h_1\)) and the exit state as point 2 (\(h_2\)).
02

Use Steam Tables for State Points

Using steam tables to find the properties at the turbine inlet (state 1) and the condenser (state 2). For exit pressure, \(P_2 = 0.06\) bar, find \(h_{f2}\) and \(h_{fg2}\), and the specific volumes. At inlet temperature \(T_1 = 520^{\circ}C\), determine \(h_1\) based on chosen pressure.
03

Isoentropic Efficiency Relation

The isentropic efficiency \(\eta_{is}\) is given as \(80\%\). The actual turbine work and enthalpy drop can be related as:\[ \eta_{is} = \frac{h_1 - h_2}{h_1 - h_{2,s}} \]Where \(h_{2,s}\) is the enthalpy at state 2 assuming an isentropic process.
04

Determine \(h_{2,s}\)

Assume an isentropic process (entropy remains constant), find \(s_2 = s_1\). Use steam tables to determine \(h_{2,s}\) at \(P_2 = 0.06\) bar.
05

Compute the Actual Exit Enthalpy

Using the isentropic efficiency and \(h_{2,s}\):\[ h_2 = h_1 - \eta_{is} (h_1 - h_{2,s}) \], verify that the quality \(x_2\) at this \(h_2\) is at least \(90\%\).
06

Adjust Inlet Pressure

Iterate the inlet pressure until the exit quality constraint (at least \(90\%\)) is satisfied. Adjust \(h_1\) with new pressure and re-calculate.
07

Final Calculations and Verification

Verify all calculations and ensure that the inlet pressure provides the necessary conditions for the outlet quality and the isentropic efficiency requirements.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isentropic Efficiency
Isentropic efficiency is a measure of the effectiveness of a thermodynamic device, such as a turbine or compressor, in converting energy. It compares the actual performance of the device with an ideal process, where no energy loss due to friction or other inefficiencies occurs.
The formula for isentropic efficiency (\text{\textbackslash eta_{\textnormal{is}}}) is:\( \text{\textbackslash eta_{\textnormal{is}} = \frac{h_1 - h_2}{h_1 - h_{2,s}}} \)
Here:
  • \text{\textbackslash h_1} is the enthalpy at the inlet,
  • \text{\textbackslash h_2} is the actual enthalpy at the exit,
  • and \text{\textbackslash h_{2,s}} is the enthalpy at the exit assuming it is an isentropic process.

Because real processes are not perfectly efficient, the actual enthalpy change (\text{\textbackslash h_1 - h_2}) will always be less than the ideal enthalpy change (\text{\textbackslash h_1 - h_{2,s}}), leading to efficiency values less than 100%. This efficiency impacts the power plant’s overall performance, hence optimizing it is essential for better energy conversion and cost-effectiveness.
Steam Quality
Steam quality refers to the proportion of vapor in a mixture of vapor and liquid at a specific pressure and temperature. It is usually expressed as a percentage. High-quality steam, close to 100%, is primarily vapor, which is ideal for turbine performance and reduces erosion and mechanical wear.
The quality of the steam (\text{\textbackslash x}) can be found using the following relationship:\( \text{\textbackslash x = \frac{m_{\textnormal{vapor}}}{m_{\textnormal{total}}}} \)
For the turbine exit condition in this exercise, the quality (\text{\textbackslash x_2}) needs to be at least 90% to ensure that most of the steam is vapor:
  • \text{\textbackslash x \rightarrow \frac{M_{\textnormal{vapor}}}{M_{\textnormal{total}}}} = 0.9

Ensuring this high steam quality minimizes the risk of turbine blade damage and enhances overall efficiency. Low-quality steam can cause problems such as corrosion and inefficiencies in the cycle.
Thermodynamic Cycles
Thermodynamic cycles are processes that involve a series of thermodynamic steps returning a system to its initial state, creating a loop. These cycles are fundamental in the operation of power plants, refrigerators, and engines.
The most common cycle used in power plant design is the Rankine cycle, which involves four main processes:
  • 1. **Isentropic Compression** in a pump,
  • 2. **Constant Pressure Heat Addition** in a boiler,
  • 3. **Isentropic Expansion** in a turbine,
  • 4. **Constant Pressure Heat Rejection** in a condenser.

In this exercise, water flows through these stages, undergoing various thermodynamic transformations. The working fluid is compressed in a pump, heated in a boiler, expanded in a turbine, and finally condensed in a condenser, thus completing the cycle. Adjusting the parameters (like inlet pressure or condenser pressure) can optimize the cycle for better efficiency, as seen in the problem's iterative process for determining the ideal pressure to maintain high steam quality and efficient energy conversion.

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Most popular questions from this chapter

Early commercial vapor power plants operated with turbine inlet conditions of about 12 bar and \(200^{\circ} \mathrm{C}\). Plants are under development today that can operate at over \(34 \mathrm{MPa}\), with turbine inlet temperatures of \(650^{\circ} \mathrm{C}\) or higher. How have steam generator and turbine designs changed over the years to allow for such increases in pressure and temperature? Discuss.

A binary vapor power cycle consists of two ideal Rankine cycles with steam and ammonia as the working fluids. In the steam cycle, superheated vapor enters the turbine at \(6 \mathrm{MPa}\), \(640^{\circ} \mathrm{C}\), and saturated liquid exits the condenser at \(60^{\circ} \mathrm{C}\). The heat rejected from the steam cycle is provided to the ammonia cycle, producing saturated vapor at \(50^{\circ} \mathrm{C}\), which enters the ammonia turbine. Saturated liquid leaves the ammonia condenser at \(1 \mathrm{MPa}\). For a net power output of \(20 \mathrm{MW}\) from the binary cycle, determine (a) the power output of the steam and ammonia turbines, respectively, in MW. (b) the rate of heat addition to the binary cycle, in MW. (c) the thermal efficiency.

Water is the working fluid in a cogeneration cycle that generates electricity and provides heat for campus buildings. Steam at \(2 \mathrm{MPa}, 320^{\circ} \mathrm{C}\), enters a two-stage turbine with a mass flow rate of \(0.82 \mathrm{~kg} / \mathrm{s}\). A fraction of the total flow, 0.141, is extracted between the two stages at \(0.15 \mathrm{MPa}\) to provide for building heating, and the remainder expands through the second stage to the condenser pressure of \(0.06\) bar. Condensate returns from the campus buildings at \(0.1 \mathrm{MPa}, 60^{\circ} \mathrm{C}\) and passes through a trap into the condenser, where it is reunited with the main feedwater flow. Saturated liquid leaves the condenser at \(0.06\) bar. Each turbine stage has an isentropic efficiency of \(80 \%\), and the pumping process can be considered isentropic. Determine (a) the rate of heat transfer to the working fluid passing through the steam generator, in \(\mathrm{kJ} / \mathrm{h}\). (b) the net power developed, in \(\mathrm{kJ} / \mathrm{h}\). (c) the rate of heat transfer for building heating, in \(\mathrm{kJ} / \mathrm{h}\). (d) the rate of heat transfer to the cooling water passing through the condenser, in \(\mathrm{kJ} / \mathrm{h}\).

Refrigerant \(134 \mathrm{a}\) is the working fluid in a solar power plant operating on a Rankine cycle. Saturated vapor at \(60^{\circ} \mathrm{C}\) enters the turbine, and the condenser operates at a pressure of 6 bar. The rate of energy input to the collectors from solar radiation is \(0.4 \mathrm{~kW}\) per \(\mathrm{m}^{2}\) of collector surface area. Determine the \(\mathrm{min}\) imum possible solar collector surface area, in \(\mathrm{m}^{2}\), per \(\mathrm{kW}\) of power developed by the plant.

A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage at \(12 \mathrm{MPa}, 520^{\circ} \mathrm{C}\) and expands to \(1 \mathrm{MPa}\), where some of the steam is extracted and diverted to the open feedwater heater operating at \(1 \mathrm{MPa}\). The remaining steam expands through the second turbine stage to the condenser pressure of \(6 \mathrm{kPa}\). Saturated liquid exits the open feedwater heater at \(1 \mathrm{MPa}\). For isentropic processes in the turbines and pumps, determine for the cycle (a) the thermal efficiency and (b) the mass flow rate into the first turbine stage, in \(\mathrm{kg} / \mathrm{h}\), for a net power output of \(330 \mathrm{MW}\).

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