/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 How might you explain the entrop... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

How might you explain the entropy production concept in terms a child would understand?

Short Answer

Expert verified
Entropy production is like the mess created when you continuously play with toys, making things more disorderly over time.

Step by step solution

01

Understand Entropy

Imagine you have a room full of toys, all neatly organized on shelves. Entropy is a way to measure how messy or disorganized things are in the room.
02

Natural Tendency

Over time, as you play with the toys, they get scattered all over the floor. This tendency of things to move from order to disorder is what entropy is all about.
03

Energy and Entropy

Think about how much energy it takes to clean up the toys and put them back on the shelves. This effort is like reducing entropy, but when you leave them and play, the toys get disorganized again, making the entropy increase.
04

Explaining Entropy Production

When you continuously play and scatter the toys, you're producing more mess, or in scientific terms, producing more entropy. The process of increasing disorder over time is called entropy production.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics
Thermodynamics is a branch of physics that studies how energy moves and changes in a system. One of the key ideas in thermodynamics is that energy cannot be created or destroyed, only transformed from one form to another.

Imagine cooking your favorite dish. You use the stove (heat energy) to cook the food (chemical energy). The energy changes form but doesn't disappear.
  • Energy Conservation: The total amount of energy always stays the same.
  • Systems: Everything interacting in a defined space, like ingredients in a pot.
  • Processes: How energy changes in the system, like cooking.


Physics uses thermodynamics to describe how heat and work affect matter and how systems become more or less ordered.
Understanding Entropy
Entropy is a measure of disorder or randomness in a system. It helps scientists understand how systems evolve over time.

Imagine you just finished organizing your room—everything is in its place. That's low entropy because it's orderly. But, as you play, things get messy, which means higher entropy.

Here's a simple way to understand entropy with key points:
  • Low Entropy: When things are neat and organized.
  • High Entropy: When things are scattered and chaotic.
  • Natural Tendency: Over time, systems naturally become more disordered (higher entropy).


For instance, a melting ice cube in a glass of water increases entropy because the structured ice (low entropy) turns into liquid water, which is more disordered (high entropy).
Energy and Entropy Relationship
Energy and entropy are closely related in thermodynamics. Controlling energy input and output affects the entropy of a system.

Think about cleaning your room. It requires energy to move from disorder (high entropy) to order (low entropy). But leaving your toys out increases the room’s disorder over time (entropy production).

Important points to remember:
  • Energy Input: Adding energy, like cleaning up, can decrease entropy locally.
  • Energy Output: Without energy, systems tend to become more random and disordered (higher entropy).
  • Entropy Production: Whenever you use energy, some of it always increases the total disorder of the universe.


Energy and entropy help us understand why certain processes happen and why others don’t. Like why ice melts in a warm room but doesn’t refreeze unless energy is removed.

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Most popular questions from this chapter

A compressor operating at steady state takes in atmospheric air at \(20^{\circ} \mathrm{C}, 1\) bar at a rate of \(1 \mathrm{~kg} / \mathrm{s}\) and discharges air at 5 bar. Plot the power required, in \(\mathrm{kW}\), and the exit temperature, in \({ }^{\circ} \mathrm{C}\), versus the isentropic compressor efficiency ranging from 70 to \(100 \%\). Assume the ideal gas model for the air and neglect heat transfer with the surroundings and changes in kinetic and potential energy.

Hydrogen gas \(\left(\mathrm{H}_{2}\right)\) at \(35^{\circ} \mathrm{C}\) and pressure \(p\) enters an insulated control volume operating at steady state for which \(\dot{W}_{\mathrm{cv}}=0\). Half of the hydrogen exits the device at 2 bar and \(90^{\circ} \mathrm{C}\) and the other half exits at 2 bar and \(-20^{\circ} \mathrm{C}\). The effects of kinetic and potential energy are negligible. Employing the ideal gas model with constant \(c_{p}=14.3 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\), determine the minimum possible value for the inlet pressure \(p\), in bar.

Air as an ideal gas is compressed from a state where the pressure is \(0.1 \mathrm{MPa}\) and the temperature is \(27^{\circ} \mathrm{C}\) to a state where the pressure is \(0.5 \mathrm{MPa}\) and the temperature is \(207^{\circ} \mathrm{C}\). Can this process occur adiabatically? If yes, determine the work per unit mass of air, in \(\mathrm{kJ} / \mathrm{kg}\), for an adiabatic process between these states. If no, determine the direction of the heat transfer.

Steam at \(0.7 \mathrm{MPa}, 355^{\circ} \mathrm{C}\) enters an open feedwater heater operating at steady state. A separate stream of liquid water enters at \(0.7 \mathrm{MPa}, 35^{\circ} \mathrm{C}\). A single mixed stream exits as saturated liquid at pressure \(p\). Heat transfer with the surroundings and kinetic and potential energy effects can be ignored. (a) If \(p=0.7 \mathrm{MPa}\), determine the ratio of the mass flow rates of the incoming streams and the rate at which entropy is produced within the feedwater heater, in \(\mathrm{kJ} / \mathrm{K}\) per \(\mathrm{kg}\) of liquid exiting. (b) Plot the quantities of part (a), each versus pressure \(p\) ranging from \(0.6\) to \(0.7 \mathrm{MPa}\).

Steam is contained in a large vessel at \(100 \mathrm{lbf} / \mathrm{in} .^{2}, 450^{\circ} \mathrm{F}\). Connected to the vessel by a valve is an initially evacuated tank having a volume of \(1 \mathrm{ft}^{3}\). The valve is opened until the tank is filled with steam at pressure \(p\). The filling is adiabatic, kinetic and potential energy effects are negligible, and the state of the large vessel remains constant. (a) If \(p=100 \mathrm{lbf} / \mathrm{in} .^{2}\), determine the final temperature of the steam within the tank, in \({ }^{\circ} \mathrm{F}\), and the amount of entropy produced within the tank, in \(\mathrm{Btu} /{ }^{\circ} \mathrm{R}\). (b) Plot the quantities of part (a) versus presssure \(p\) ranging from 10 to \(100 \mathrm{lbf} / \mathrm{in}\).

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