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Propane vapor enters a valve at \(1.6 \mathrm{MPa}, 70^{\circ} \mathrm{C}\), and leaves at \(0.5 \mathrm{MPa}\). If the propane undergoes a throttling process, what is the temperature of the propane leaving the valve, in \({ }^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
The temperature of the propane leaving the valve is approximately 31°C.

Step by step solution

01

Identify Known Parameters

Identify the initial conditions of the propane: the inlet pressure is 1.6 MPa, and the inlet temperature is 70°C. The exit pressure is given as 0.5 MPa.
02

Understand Throttling Process

A throttling process is characterized by a constant enthalpy process where there is no change in enthalpy across the valve. It is also known as an isenthalpic process.
03

Reference Propane Properties

Use thermodynamic tables or software to find the specific enthalpy of propane at the initial state (1.6 MPa, 70°C). For propane at 1.6 MPa and 70°C, denote the specific enthalpy as \(h_{1}\).
04

Apply Conservation of Enthalpy

Since it is a throttling process, the enthalpy remains constant. Therefore, the enthalpy of the propane at the exit is the same as at the inlet: \(h_{2} = h_{1}\).
05

Determine Exit Temperature

Using the thermodynamic tables or software again, find the temperature that corresponds to the enthalpy \(h_{2}\) at the exit pressure of 0.5 MPa. This temperature is the temperature of the propane leaving the valve.
06

Final Calculation

Typically, the software or tables will provide the temperature directly once the enthalpy and pressure are known. For propane, at the exit pressure of 0.5 MPa, the temperature correlating to the initial enthalpy (from Step 3) at the exit pressure will be found to be approximately 31°C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

enthalpy
Enthalpy is a central concept in thermodynamics. It represents the total heat content of a system. Think of it as a way to measure the energy stored in a substance due to its pressure and volume. When we talk about enthalpy, we use the symbol \(h\). It plays a crucial role in various thermodynamic processes, such as the throttling process discussed in this exercise.

Enthalpy is expressed in units of energy per mass (e.g., joules per kilogram, J/kg). In a constant pressure process, the change in enthalpy represents the heat added or removed from the system.
This is particularly useful when analyzing heating and cooling processes or phase changes.
thermodynamic properties
Thermodynamic properties are the characteristics of a system that help describe its condition. These properties include temperature, pressure, volume, and enthalpy. Understanding these properties and their relationships allows us to predict how a system will behave under different conditions.

Temperature is a measure of the thermal energy within a system. Pressure is the force exerted by the system's particles per unit area. Volume is the space occupied by the system. Enthalpy, as mentioned earlier, is the total heat content.

In the case of propane, we use thermodynamic tables to reference these properties under different conditions. For instance, to find the enthalpy at specific temperatures and pressures, we look up the values in these tables. This is critical for solving problems like the one involving the throttling process.
isenthalpic process
An isenthalpic process is one in which the enthalpy remains constant. There is no heat exchange with the surroundings during this process. It is a common concept in thermodynamics, especially in throttling processes.

In a throttling process, the fluid undergoes a sudden decrease in pressure, but no work is done by or on the fluid, and there is no significant heat transfer. Thus, the enthalpy before and after the valve remains the same.

This principle allows us to determine the final state of the fluid after throttling, given the initial enthalpy. Thus, by knowing the enthalpy at the high-pressure side, we can use it to find the temperature on the low-pressure side, as shown in the propane example.
conservation of energy
The law of conservation of energy states that energy can neither be created nor destroyed, only transformed from one form to another. This principle is at the core of analyzing thermodynamic processes.

In a closed system, like the one involving propane passing through a valve, the total energy before and after the process remains the same. For a throttling process, this means the enthalpy before the valve equals the enthalpy after the valve.

By applying the conservation of energy, we understand that any decrease in pressure must result in some form of compensating energy. Because the process we are considering is isenthalpic, it means we can solve for the exit temperature using the known enthalpy and pressure conditions. This balance allows us to accurately predict the state of the system after the process.

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Most popular questions from this chapter

Velocity distributions for laminar and turbulent flow in a circular pipe of radius \(R\) carrying an incompressible liquid of density \(\rho\) are given, respectively, by $$ \begin{aligned} &\mathrm{V} / \mathrm{V}_{0}=\left[1-(r / R)^{2}\right] \\ &\mathrm{V} / \mathrm{V}_{0}=[1-(r / R)]^{1 / /} \end{aligned} $$ where \(r\) is the radial distance from the pipe centerline and \(\mathbf{V}_{0}\) is the centerline velocity. For each velocity distribution (a) plot \(\mathrm{V} / \mathrm{V}_{0}\) versus \(r / R\). (b) derive expressions for the mass flow rate and the average velocity of the flow, \(\mathrm{V}_{\text {ave }}\), in terms of \(\mathrm{V}_{0}, R\), and \(\rho\), as required. (c) derive an expression for the specific kinetic energy carried through an area normal to the flow. What is the percent error if the specific kinetic energy is evaluated in terms of the average velocity as \(\left(\mathrm{V}_{\mathrm{ave}}\right)^{2} / 2\) ? Which velocity distribution adheres most closely to the idealizations of one- dimensional flow? Discuss.

Methods for measuring mass flow rates of gases and liquids flowing in pipes and ducts include: rotameters, turbine flowmeters, orifice-type flowmeters, thermal flowmeters, and Coriolis-type flowmeters. Determine the principles of operation of each of these flow-measuring devices. Consider the suitability of each for measuring liquid or gas flows. Can any be used for two-phase liquid- vapor mixtures? Which measure volumetric flow rate and require separate measurements of pressure and temperature to determine the state of the substance? Summarize your findings in a brief report.

A rigid tank of volume \(0.75 \mathrm{~m}^{3}\) is initially evacuated. \(\mathrm{A}\) hole develops in the wall, and air from the surroundings at 1 bar, \(25^{\circ} \mathrm{C}\) flows in until the pressure in the tank reaches \(1 \mathrm{bar}\). Heat transfer between the contents of the tank and the surroundings is negligible. Determine the final temperature in the tank, in \({ }^{\circ} \mathrm{C}\).

Refrigerant \(134 \mathrm{a}\) enters an air conditioner compressor at \(3.2\) bar, \(10^{\circ} \mathrm{C}\), and is compressed at steady state to \(10 \mathrm{bar}, 70^{\circ} \mathrm{C}\). The volumetric flow rate of refrigerant entering is \(3.0 \mathrm{~m}^{3} / \mathrm{min}\). The power input to the compressor is \(55.2 \mathrm{~kJ}\) per \(\mathrm{kg}\) of refrigerant flowing. Neglecting kinetic and potential energy effects, determine the heat transfer rate, in \(\mathrm{kW}\).

A water storage tank initially contains \(400 \mathrm{~m}^{3}\) of water. The average daily usage is \(40 \mathrm{~m}^{3}\). If water is added to the tank at an average rate of \(20[\exp (-t / 20)] \mathrm{m}^{3}\) per day, where \(t\) is time in days, for how many days will the tank contain water?

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