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Air undergoes two processes in series: Process 1-2: polytropic compression, with \(n=1.3\), from \(p_{1}=\) \(100 \mathrm{kPa}, v_{1}=0.04 \mathrm{~m}^{3} / \mathrm{kg}\) to \(v_{2}=0.02 \mathrm{~m}^{3} / \mathrm{kg}\) Process 2-3: constant-pressure process to \(v_{3}=v_{1}\) Sketch the processes on a \(p-v\) diagram and determine the work per unit mass of air, in \(\mathrm{kJ} / \mathrm{kg}\).

Short Answer

Expert verified
Calculate \( p_2 \) and use it to find work of both processes; sum them to get total work.

Step by step solution

01

- Understand the Problem

There are two processes: a polytropic compression followed by a constant-pressure process. The initial conditions and the specific volume changes are given. The goal is to sketch the processes on a p-v diagram and determine the work per unit mass.
02

- Applying Polytropic Process Equation for Process 1-2

For the polytropic process, use the relation: \[ p_1 v_1^n = p_2 v_2^n \]. Plug the initial values and solve for p_2: \[ 100\times(0.04)^{1.3} = p_2\times(0.02)^{1.3} \]. Simplify to find \[ p_2 \].
03

- Calculate Work Done in Polytropic Process 1-2

{The work done, \( W_{12} \), in a polytropic process is given by: \[ W_{12} = \frac{p_2 v_2 - p_1 v_1}{1 - n} \]. Use the values of \( p_1 \), \( v_1 \), \( p_2 \), and \( v_2 \) to calculate work for process 1-2.}
04

- Calculate Work Done in the Constant-Pressure Process 2-3

For a constant-pressure process, work is given by: \[ W_{23} = p_2 (v_3 - v_2) \]. Since \( v_3 = v_1 \), it becomes \[ W_{23} = p_2 (v_1 - v_2) \]. Using the value of \( p_2 \) calculated earlier, as well as \( v_1 \) and \( v_2 \) given, compute the work done during process 2-3.
05

- Sum the Work Done in Both Processes

{To find the total work done per unit mass, sum the work done in both steps: \[ W_{total} = W_{12} + W_{23} \].}
06

- Sketch the Processes on a p-v Diagram

Draw a p-v diagram with specific volume on the x-axis and pressure on the y-axis. Plot the points (v1, p1), (v2, p2), and (v3, p2). Connect the points to depict the polytropic compression followed by the constant-pressure process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamic Processes
Thermodynamic processes describe the changes that a working substance, such as air, undergoes due to energy exchanges with its surroundings. In this exercise, air undergoes two distinct processes.

Firstly, it experiences a polytropic compression, where the pressure and volume change in a specific relationship. During this process, the exponent 'n' is given as 1.3. Polytropic processes are generally characterized using the equation \( p \cdot v^n = constant\).

Secondly, the air goes through a constant-pressure process. Here, the volume changes while the pressure remains unchanged. This step moves the air back to its original specific volume. Understanding the nature of these processes helps in analyzing the changes in thermodynamic properties like work and heat transfer.

By studying these processes, we can predict the behavior of systems in engineering applications, such as internal combustion engines or refrigeration cycles.
P-v Diagram
A P-v diagram helps in visualizing the changes that occur during various thermodynamic processes. It plots pressure (p) on the y-axis and specific volume (v) on the x-axis.

For our problem, we need to sketch two processes on the P-v diagram. Start by plotting the initial state (v1, p1) and the endpoint for the compression process (v2, p2). Since the volume decreases during this step, the curve will slope downward. This curve is not a straight line but a specific polytropic curve defined by \(p \cdot v^n = constant\).

Next, plot the constant-pressure process, which will show a horizontal line because the pressure remains the same while the volume changes from v2 back to v1. This step completes the cycle depicted on the P-v diagram.

By sketching these processes, we gain important insights into the system's behavior. This visualization helps to better understand the work and energy interactions associated with each process.
Work Calculation
Calculating the work done in thermodynamic processes is crucial for understanding energy transformations. For polytropic processes, we use the formula: \[ W_{12} = \frac{p_2 \cdot v_2 - p_1 \cdot v_1}{1 - n}\].

First, determine the pressure at the end of process 1-2 (p2), using \(p_1 \cdot v_1^n = p_2 \cdot v_2^n\). Substitute the known values to find p2.

Once you have p2, plug the values into the work equation to find Work (W12) during the polytropic compression.

Next, calculate the work for the constant-pressure process using the formula: \[W_{23} = p_2 \cdot (v_1 - v_2)\]. Since v3 equals v1, replace v3 with v1 in the equation. This yields the work done during the constant-pressure expansion (W23).

Summing these two calculations provides the total work done over the entire cycle: \[W_{total} = W_{12} + W_{23}\]. This total work represents the energy transferred by mechanical means, per unit mass, during the processes.
Engineering Problem-Solving
Solving engineering problems involves a step-by-step approach to ensure accurate results and clear understanding. Let's break this down:
  • First, understand the problem and identify the processes and conditions given.
  • Next, apply the relevant equations to each process. For polytropic processes, use \(p_1 \cdot v_1^n = p_2 \cdot v_2^n\) and for constant-pressure processes, use \(W_{23} = p_2 \cdot (v_1 - v_2)\).
  • Then, perform the necessary calculations step-by-step to determine variables like pressure, volume, and work.
  • Sum the work done in all processes to find the total work per unit mass.
  • Finally, sketch the processes on a P-v diagram to visually represent the changes.
Using this structured approach ensures that all aspects of the problem are addressed, leading to a comprehensive solution. This method not only helps solve thermodynamic problems but also builds a stronger foundation for more complex engineering challenges.

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