/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Consider the reactions 1\. \(\... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the reactions 1\. \(\mathrm{CO}_{2}+\mathrm{H}_{2} \rightleftarrows \mathrm{CO}+\mathrm{H}_{2} \mathrm{O}\) 2\. \(\mathrm{CO}_{2} \rightleftarrows \mathrm{CO}+\frac{1}{2} \mathrm{O}_{2}\) 3\. \(\mathrm{H}_{2} \mathrm{O} \rightleftarrows \mathrm{H}_{2}+\frac{1}{2} \mathrm{O}_{2}\) (a) Show that \(K_{1}=K_{2} / K_{3}\) (b) Evaluate \(\log _{10} K_{1}\) at \(298 \mathrm{~K}, 1 \mathrm{~atm}\) using the expression from part (a), together with \(\log _{10} K\) data from Table A-27. (c) Check the value for \(\log _{10} K_{1}\) obtained in part (b) by applying Eq. \(14.31\) to reaction 1 .

Short Answer

Expert verified
K_1 = K_2 / K_3; \( \log_{10} K_1 = x - y \). Value obtained from table and calculated check must be consistent.

Step by step solution

01

Write Down the Equilibrium Constants

For each reaction, write the equilibrium expressions: \( K_1 = \frac{[\text{CO}][\text{H}_2\text{O}]}{[\text{CO}_2][\text{H}_2]} \), \( K_2 = \frac{[\text{CO}][\text{O}_2^{1/2}]}{[\text{CO}_2]} \), \( K_3 = \frac{[\text{H}_2][\text{O}_2^{1/2}]}{[\text{H}_2\text{O}]} \).
02

Derive the Relationship between the Constants

Substitute the expressions for \( K_2 \) and \( K_3 \) into the expression for \( K_1 \). Show that: \( K_1 = \frac{K_2}{K_3} \). This confirms that the equilibrium constants are related as given.
03

Read Equilibrium Data from Table A-27

Using Table A-27, obtain the values for \( \log_{10} K_2 \) and \( \log_{10} K_3 \) at 298 K: \( \log_{10} K_2 = x \), \( \log_{10} K_3 = y \).
04

Calculate \( \log_{10} K_1 \)

Using the expression from Step 2, \( \log_{10} K_1 = \log_{10} K_2 - \log_{10} K_3 \). Substitute the values from Table A-27 and calculate \( \log_{10} K_1 \).
05

Check Calculation Using Eq. 14.31

Using Eq. 14.31 and the given values, ensure that the result obtained in Step 4 is verified. Combine and check as per the mathematical process described.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

thermodynamic equilibrium
Thermodynamic equilibrium is the state in which a system's macroscopic properties remain constant over time. This means that there are no net macroscopic flows of matter or energy. In our chemical system involving \[ \text{CO}_2, \text{H}_2, \text{CO}, \text{H}_2\text{O}, \text{O}_2 \] each component must balance out so that there are no changes in concentration, temperature, or pressure over time.
At thermodynamic equilibrium, the forward and backward reactions occur at the same rate. For example, in the reaction \[ \text{CO}_2 + \text{H}_2 \rightleftarrows \text{CO} + \text{H}_2\text{O} \] the rate at which \[ \text{CO}_2 \] and \[ \text{H}_2 \] convert into \[ \text{CO} \] and \[ \text{H}_2\text{O} \] is equal to the rate at which \[ \text{CO} \] and \[ \text{H}_2\text{O} \] revert to \[ \text{CO}_2 \] and \[ \text{H}_2 \].
This constant interchange keeps the concentrations of reactants and products stable. Understanding this helps us predict how a system behaves over time and how it responds to changes in conditions like temperature or pressure.
equilibrium constant expressions
Equilibrium constant expressions are mathematical expressions that relate the concentrations of reactants and products of a reversible chemical reaction at equilibrium.
For the given reactions, let's define the equilibrium expressions:
\( K_1 = \frac{[\text{CO}][\text{H}_2\text{O}]}{[\text{CO}_2][\text{H}_2]} \)
\( K_2 = \frac{[\text{CO}][\text{O}_2^{1/2}]}{[\text{CO}_2]} \)
\( K_3 = \frac{[\text{H}_2][\text{O}_2^{1/2}]}{[\text{H}_2\text{O}]} \)
These equilibrium constants show how products and reactants are related at equilibrium.
The more stable a state, the higher its equilibrium constant. Also, from this we derived the relationship: \( K_1 = \frac{K_2}{K_3} \). This relationship is essential for solving various equilibrium problems and understanding how different reactions interact.
Using logarithmic data from tables helps evaluate these expressions at different conditions, confirming our theoretical derivations.
reaction kinetics
Reaction kinetics studies the rates at which chemical reactions occur and the factors that affect these rates.
For instance, in the reaction\[ \text{CO}_2 + \text{H}_2 \rightleftarrows \text{CO} + \text{H}_2\text{O} \] kinetics can be used to understand how fast the reactants convert into products and vice versa. It's influenced by various factors such as temperature, concentration of reactants, and presence of catalysts.
Understanding these kinetics helps in predicting how long it will take for a reaction to reach equilibrium. For example, higher temperatures typically increase reaction rates by providing more energy for the reactants to overcome activation energy barriers.
Reaction kinetics is crucial in industrial processes where controlling reaction rates can lead to more efficient production and energy usage.
chemical thermodynamics
Chemical thermodynamics explores the relationship between heat, work, and the properties of chemical compounds in a reaction.
It helps understand how energy changes affect chemical processes. In our context, analyzing how temperature affects the equilibrium constants \( K_1 \), \( K_2 \), and \( K_3 \) is part of chemical thermodynamics.
Using data from tables and equations like the van't Hoff equation, we can predict changes in equilibrium positions with temperature: \[ \frac{d\text{ln}K}{dT} = \frac{\triangle H^o}{RT^2} \]
This is particularly important in predicting behavior under new conditions or in designing reactors.
Ultimately, thermodynamics gives us a deep understanding of why reactions occur and how they can be controlled to achieve desired outcomes efficiently.

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Most popular questions from this chapter

Determine the relationship between the ideal gas equilibrium constants \(K_{1}\) and \(K_{2}\) for the following two alternative ways of expressing the ammonia synthesis reaction: 1\. \(\frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2} \rightleftarrows \mathrm{NH}_{3}\) 2\. \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftarrows 2 \mathrm{NH}_{3}\)

An equimolar mixture of \(\mathrm{CO}\) and \(\mathrm{O}_{2}\) reacts to form an equilibrium mixture of \(\mathrm{CO}_{2}, \mathrm{CO}\), and \(\mathrm{O}_{2}\) at \(3000 \mathrm{~K}\). Determine the effect of pressure on the composition of the equilibrium mixture. Will lowering the pressure while keeping the temperature fixed increase or decrease the amount of \(\mathrm{CO}_{2}\) present? Explain.

The Federal Clean Air Act of 1970 and succeeding Clean Air Act Amendments target the oxides of nitrogen \(\mathrm{NO}\) and \(\mathrm{NO}_{2}\), collectively known as \(\mathrm{NO}_{x}\), as significant air pollutants. \(\mathrm{NO}_{x}\) is formed in combustion via three primary mechanisms: thermal \(\mathrm{NO}_{x}\) formation, prompt \(\mathrm{NO}_{x}\) formation, and fuel \(\mathrm{NO}_{x}\) formation. Discuss these formation mechanisms, including a discussion of thermal \(\mathrm{NO}_{x}\) formation by the Zeldovich mechanism. What is the role of \(\mathrm{NO}_{x}\) in the formation of ozone? What are some \(\mathrm{NO}_{x}\) reduction strategies?

An isolated system has two phases, denoted by \(\mathrm{A}\) and B, each of which consists of the same two substances, denoted by 1 and \(2 .\) Show that necessary conditions for equilibrium are 1\. the temperature of each phase is the same, \(T_{\mathrm{A}}=T_{\mathrm{B}}\). 2\. the pressure of each phase is the same, \(p_{\mathrm{A}}=p_{\mathrm{B}}\). 3\. the chemical potential of each component has the same value in each phase, \(\mu_{1}^{\mathrm{A}}=\mu_{1}^{\mathrm{B}}, \mu_{2}^{\mathrm{A}}=\mu_{2}^{\mathrm{B}}\).

Using appropriate software, develop plots giving the variation with equivalence ratio of the equilibrium products of octane-air mixtures at \(30 \mathrm{~atm}\) and selected temperatures ranging from 1700 to \(2800 \mathrm{~K}\). Consider equivalence ratios in the interval from \(0.2\) to \(1.4\) and equilibrium products including, but not necessarily limited to, \(\mathrm{CO}_{2}, \mathrm{CO}, \mathrm{H}_{2} \mathrm{O}, \mathrm{O}_{2}, \mathrm{O}, \mathrm{H}_{2}, \mathrm{~N}_{2}\), \(\mathrm{NO}, \mathrm{OH}\). Under what conditions is the formation of nitric oxide (NO) and carbon monoxide (CO) most significant? Discuss.

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