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If the variation of the acceleration of gravity, in \(\mathrm{m} / \mathrm{s}^{2}\), with elevation \(z\), in \(\mathrm{m}\), above sea level is \(g=9.81-\left(3.3 \times 10^{-6}\right) z\), determine the percent change in weight of an airliner landing from a cruising altitude of \(10 \mathrm{~km}\) on a runway at sea level.

Short Answer

Expert verified
The percent change in weight is 0.336%.

Step by step solution

01

Identify the given variables

Given: Gravitational acceleration at sea level, g at sea level, \( g_0 = 9.81 \frac{m}{s^2} \) Elevation, z = 10,000 m Formula for gravitational acceleration: \(g = 9.81 - (3.3 \times 10^{-6})z \)
02

Calculate the gravitational acceleration at cruising altitude

Substitute the value of z into the formula: \( g(10,000) = 9.81 - (3.3 \times 10^{-6}) \times 10,000 \) g(10,000) = 9.81 - 0.033 = 9.777 \frac{m}{s^2}
03

Determine the change in gravitational acceleration

Calculate the change in gravitational acceleration from z = 10,000 m to z = 0 m. \(\text{Change in } g = 9.81 - 9.777 = 0.033 \frac{m}{s^2}\).
04

Calculate the percent change in weight

Percent change can be calculated as follows: \((\frac{\text{Change in } g}{g_0}) \times 100 = (\frac{0.033}{9.81}) \times 100 \text{Percent change in weight} = 0.336\text{%}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

percent change in weight
When calculating the percent change in weight due to the change in altitude, it's essential to understand the concept of percent change itself. Percent change is a way to express how much a quantity has changed, as a percentage of its original value. Given the formula:
  • Original value (weight related to gravitational acceleration at sea level) is denoted as \( g_0 = 9.81 \frac{m}{s^{2}} \)
  • Change in the value of gravity at 10 km altitude \( g_{\text{alt}} = 9.777 \frac{m}{s^2} \)

To determine the percent change in weight, we first calculate the difference in gravitational acceleration between the two altitudes. Then, we compare this change to the original value and convert it into a percentage. So we have:\( \text{Percent change} = \frac{ \text{Change in value} }{ \text{Original value} } \times 100 \)This results in:\( \text{Percent change in weight} = \frac{0.033}{9.81} \times 100 = 0.336\text{%} \)Thus, by descending from 10 km altitude to sea level, the weight change due to gravity is approximately 0.336%.
elevation effect on gravity
Gravitational acceleration varies with elevation. At higher elevations, the effect of Earth's gravity diminishes slightly. This reduction is because gravity decreases with the square of the distance between the two masses.

For engineering purposes, we use a simplified linear formula to approximate this change:\( g = 9.81 - (3.3 \times 10^{-6})z \)

Where:
  • \( g \) is the gravitational acceleration at elevation \( z \).
  • \( z \) is the elevation in meters.

In our exercise, we analyzed how gravity changes with a 10,000-meter (10 km) change in elevation. By substituting \( z = 10,000 \text{m} \) into the formula, we calculated the gravitational acceleration at this altitude as:\( g(10,000) = 9.81 - (3.3 \times 10^{-6}) \times 10,000 \)

This gives us \( 9.777 \frac{m}{s^2} \), showing that gravity decreases as we ascend.

Understanding this concept is crucial for fields such as aerospace engineering, where knowing the exact behavior of gravity at various altitudes can impact flight dynamics and the design of aircraft and spacecraft.
engineering problem solving
Solving engineering problems often involves breaking down complex real-world phenomena into manageable calculations. Let's summarize an effective approach:

  1. Identify Given Variables: Begin by extracting all the known data from the problem statement. In our case, this includes the gravitational constant at sea level and the cruising altitude.
  2. Implement Formulas: Use relevant equations to determine the unknowns. Here, we substituted the elevation value into the gravity formula.
  3. Calculate Changes: After finding the new value (gravitational acceleration at 10 km), calculate the change compared to the original value.
  4. Determine Percent Change: Finally, translate this change into a percentage to understand its impact on the system, which in our example pertains to the airliner's weight change.


Approaching problems with clear, structured thinking helps avoid errors and ensures accurate solutions. Always double-check units and calculations, and ensure each step logically leads to the next. Properly documenting and understanding each stage builds a robust foundation for tackling more complex problems in engineering.

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Most popular questions from this chapter

The variation of pressure within the biosphere affects not only living things but also systems such as aircraft and undersea exploration vehicles. (a) Plot the variation of atmospheric pressure, in atm, versus elevation \(z\) above sea level, in \(\mathrm{km}\), ranging from 0 to \(10 \mathrm{~km}\). Assume that the specific volume of the atmosphere, in \(\mathrm{m}^{3} / \mathrm{kg}\), varies with the local pressure \(p\), in \(\mathrm{kPa}\), according to \(v=72.435 / p\). (b) Plot the variation of pressure, in atm, versus depth \(z\) below sea level, in \(\mathrm{km}\), ranging from 0 to \(2 \mathrm{~km}\). Assume that the specific volume of seawater is constant, \(v=0.956 \times\) \(10^{-3} \mathrm{~m}^{3} / \mathrm{kg}\) In each case, \(g=9.81 \mathrm{~m} / \mathrm{s}^{2}\) and the pressure at sea level is \(1 \mathrm{~atm}\)

The weight of an object on an orbiting space vehicle is measured to be \(42 \mathrm{~N}\) based on an artificial gravitational acceleration of \(6 \mathrm{~m} / \mathrm{s}^{2}\). What is the weight of the object, in \(\mathrm{N}\), on earth, where \(g=9.81 \mathrm{~m} / \mathrm{s}^{2}\) ?

You are asked to address a city council hearing concerning the decision to purchase a commercially available \(10-\mathrm{kW}\) wind turbine-generator having an expected life of 12 or more years. As an engineer, what considerations will you point out to the council members to help them with their decision?

A dish of liquid water is placed on a table in a room. After a while, all of the water evaporates. Taking the water and the air in the room to be a closed system, can the system be regarded as a pure substance during the process? After the process is completed? Discuss.

A system consists of liquid water in equilibrium with a gaseous mixture of air and water vapor. How many phases are present? Does the system consist of a pure substance? Explain. Repeat for a system consisting of ice and liquid water in equilibrium with a gaseous mixture of air and water vapor.

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