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An ideal cold air-standard Brayton cycle operates at steady state with compressor inlet conditions of \(300 \mathrm{~K}\) and \(100 \mathrm{kPa}\), fixed turbine inlet temperature of \(1700 \mathrm{~K}\), and \(k=1.4\). For the cycle, (a) determine the net work developed per unit mass flowing, in \(\mathrm{kJ} / \mathrm{kg}\), and the thermal efficiency for a compressor pressure ratio of 8 . (b) plot the net work developed per unit mass flowing, in \(\mathrm{kJ} / \mathrm{kg}\), and the thermal efficiency, cach versus compressor pressure ratio ranging from 2 to 50 .

Short Answer

Expert verified
a. W_net 鈮 371.6 kJ/kg, 畏 鈮 0.529b. Plot the net work and efficiency for pressure ratios from 2 to 50.

Step by step solution

01

Understand the Brayton Cycle

The Brayton cycle is a thermodynamic cycle that describes how gas turbine engines and jet engines operate. It consists of four processes: isentropic compression, constant-pressure heat addition, isentropic expansion, and constant-pressure heat rejection.
02

List Known Variables

Inlet conditions: - Temperature, T鈧 = 300 K- Pressure, P鈧 = 100 kPaTurbine inlet temperature: T鈧 = 1700 KConstant for air: k = 1.4Compressor pressure ratio: r_P = 8
03

Determine Compressor Outlet Temperature (T鈧)

Using the isentropic relation for compression:a. T鈧 = T鈧 * (r_P)^((k-1)/k)Plug in the values:a. T鈧 = 300 * (8)^((1.4-1)/1.4)
04

Determine the Turbine Outlet Temperature (T鈧)

Next, determine the temperature after expansion which is also isentropic:T鈧 = T鈧 / (r_P)^((k-1)/k)Plug in the values: T鈧 = 1700 / (8)^((1.4-1)/1.4)
05

Calculate Net Work per Unit Mass (W_net)

The work done by the compressor (W_c) and turbine (W_t) can be calculated using the specific heat capacity of air (Cp), where Cp = (k*R)/(k-1) and R = 0.287 kJ/kg路K:a. W_c = Cp * (T鈧 - T鈧) b. W_t = Cp * (T鈧 - T鈧)Then, net work is a. W_net = W_t - W_c
06

Calculate the Thermal Efficiency (畏)

Thermal efficiency (畏) is determined using the formula:a. 畏 = 1 - (T鈧/T鈧) * (r_P)^((k-1)/k - 1)
07

Plot Work and Efficiency Versus Pressure Ratio

Using a range of pressure ratios from 2 to 50, calculate the net work and thermal efficiency for each point and create a plot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isentropic Processes
In thermodynamics, an isentropic process is one where the entropy of the system remains constant. This is typically idealized as a perfectly reversible, adiabatic process. In the Brayton cycle, both the compression and expansion processes are considered isentropic.

These processes are crucial because they determine the efficiency and work output of the cycle. In other words, the ideal performance of the cycle hinges on these isentropic transformations.

When analyzing the compressor in an isentropic process, the relationship between temperature and pressure can be expressed as: \[ T_2 = T_1 \times (r_P)^{\frac{k-1}{k}} \] This equation helps us find the outlet temperature of the compressor (\(T_2\)) given an initial temperature (\(T_1\)) and the pressure ratio (\(r_P\)).

For the turbine, we use the similar isentropic relation:\[ T_4 = T_3 / (r_P)^{\frac{k-1}{k}} \]This allows us to determine the turbine outlet temperature (\(T_4\)) from the turbine inlet temperature (\(T_3\)) and the pressure ratio.

Isentropic processes help in maximizing efficiency because they assume no energy losses, which simplifies the analysis and enables prediction of upper performance limits.
Thermal Efficiency
Thermal efficiency is a key performance metric for any heat engine, including those operating on the Brayton cycle. It measures the percentage of heat energy converted into useful work, indicating how effectively an engine turns heat from combustion into mechanical energy.

For the Brayton cycle, the thermal efficiency (\(\text{畏}\)) can be calculated using:\[ \text{畏} = 1 - \frac{T_1}{T_3} \times (r_P)^{\frac{k-1}{k} -1} \] This equation highlights that efficiency depends on the temperature ratio between the compressor inlet (\(T_1\)) and the turbine inlet (\(T_3\)), as well as the pressure ratio (\(r_P\)).

Higher efficiency indicates more effective use of input energy, which means less fuel is needed for the same amount of work.

To improve thermal efficiency:
  • Decrease the compressor inlet temperature (\(T_1\)).
  • Increase the turbine inlet temperature (\(T_3\)).
  • Optimize the pressure ratio (\(r_P\)).
This knowledge helps engineers design more efficient gas turbine engines, reducing fuel consumption and operating costs.
Pressure Ratio
The pressure ratio (\(r_P\)) is a vital parameter in Brayton cycle analysis, defining the ratio of the compressor outlet pressure to the inlet pressure. It's a determinant of the cycle's performance, directly affecting the temperatures throughout the cycle and, consequently, the efficiency and net work output.

Mathematically, the pressure ratio is given by:\[ r_P = \frac{P_2}{P_1} \]where \(P_2\) is the compressor outlet pressure and \(P_1\) is the compressor inlet pressure.

Increasing the pressure ratio generally improves the thermal efficiency up to a point. Beyond that, the benefits diminish, and additional mechanical challenges emerge.

The impact of varying the pressure ratio (from 2 to 50) is evident in the Brayton cycle plots. Higher pressure ratios result in higher outlet temperatures after compression and lower outlet temperatures after expansion.

This increases the work done by the turbine relative to the work needed by the compressor, thus increasing the net work output. However, there are practical engineering limits to how high the pressure ratio can be set.

Understanding how the pressure ratio influences performance is crucial for optimizing the Brayton cycle in real-world applications.

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Most popular questions from this chapter

Air enters the compressor of an ideal cold air-standard Brayton cycle at \(100 \mathrm{kPa}, 300 \mathrm{~K}\), with a mass flow rate of \(6 \mathrm{~kg} / \mathrm{s}\). The compressor pressure ratio is 10 , and the turbine inlet temperature is \(1400 \mathrm{~K}\). For \(k=1.4\), calculate (a) the thermal efficiency of the cycle. (b) the back work ratio. (c) the net power developed, in \(\mathrm{kW}\).

Consider an air-standard Otto cycle. Operating data at principal states in the cycle are given in the table below. The states are numbered as in Fig. 9.3. The mass of air is \(0.002 \mathrm{~kg}\). Determine (a) the heat addition and the heat rejection, each in kJ. (b) the net work, in kJ. (c) the thermal efficiency. (d) the mean effective pressure, in \(\mathrm{kPa}\). $$ \begin{array}{cccc} \text { State } & T(\mathrm{~K}) & p(\mathrm{kPa}) & u(\mathrm{k}) / \mathrm{kg}) \\ \hline 1 & 305 & 85 & 217.67 \\ 2 & 367.4 & 767.9 & 486.77 \\ 3 & 960 & 2006 & 725.02 \\ 4 & 458.7 & 127.8 & 329.01 \end{array} $$

A four-cylinder, four-stroke internal combustion engine has a bore of \(3.7\) in. and a stroke of \(3.4 \mathrm{in}\). The clearance volume is \(16 \%\) of the cylinder volume at bottom dead center and the crankshaft rotates at 2400 RPM. The processes within each cylinder are modeled as an air-standard Otto cycle with a pressure of \(14.5 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\) and a temperature of \(60^{\circ} \mathrm{F}\) at the beginning of compression. The maximum temperature in the cycle is \(5200^{\circ} \mathrm{R}\). Based on this model, calculate the net work per cycle, in Btu, and the power developed by the engine, in horsepower.

The displacement volume of an internal combustion engine is 3 liters. The processes within each cylinder of the engine are modeled as an air-standard Diesel cycle with a cutoff ratio of \(2.5\). The state of the air at the beginning of compression is fixed by \(p_{1}=95 \mathrm{kPa}, T_{1}=22^{\circ} \mathrm{C}\), and \(V_{1}=\) \(3.17\) liters. Determine the net work per cycle, in \(\mathrm{kJ}\), the power developed by the engine, in \(\mathrm{kW}\), and the thermal efficiency, if the cycle is executed 1000 times per min.

Air enters the compressor of a regenerative gas turbine at \(14.5 \mathrm{lbf} / \mathrm{in}^{2}, 77^{\circ} \mathrm{F}\), and is compressed to \(60 \mathrm{lbf} / \mathrm{in}^{2}\) The air then passes through the regenerator and exits at \(1120^{\circ} \mathrm{R}\). The temperature at the turbine inlet is \(1700^{\circ} \mathrm{R}\). The compressor and turbine each have an isentropic efficiency of \(84 \%\). The net power developed is \(1000 \mathrm{hp}\). Using an air-standard analysis, calculate (a) the thermal efficiency of the cycle. (b) the back work ratio. (c) the regenerator effectiveness (d) the mass flow rate of the air, in lb/s.

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