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Water is the working fluid in a Rankine cycle modified to include one closed feedwater heater and one open feedwater heater. Superheated vapor enters the turbine at \(16 \mathrm{MPa}, 560^{\circ} \mathrm{C}\), and the condenser pressure is \(8 \mathrm{kPa}\). The mass flow rate of steam entering the first- stage turbine is \(120 \mathrm{~kg} / \mathrm{s}\). The closed feedwater heater uses extracted steam at \(4 \mathrm{MPa}\), and the open feedwater heater uses extracted steam at \(0.3 \mathrm{MPa}\). Saturated liquid condensate drains from the closed feedwater heater at \(4 \mathrm{MPa}\) and is trapped into the open feedwater heater. The feedwater leaves the closed heater at \(16 \mathrm{MPa}\) and a temperature equal to the saturation temperature at \(4 \mathrm{MPa}\). Saturated liquid leaves the open heater at \(0.3 \mathrm{MPa}\). Assume all turbine stages and pumps operate isentropically. Determine (a) the net power developed, in kW. (b) the rate of heat transfer to the steam passing through the steam generator, in \(\mathrm{kW}\). (c) the thermal efficiency- (d) the mass flow rate of condenser cooling water, in \(\mathrm{kg} / \mathrm{s}\), if the cooling water undergoes a temperature increase of \(18^{\circ} \mathrm{C}\) with negligible pressure change in passing through the condenser.

Short Answer

Expert verified
(a) Use enthalpy differences to find net power. (b) Calculate heat added in the steam generator. (c) Efficiency is the ratio of net power to heat added. (d) Find the cooling water flow using energy balance in the condenser.

Step by step solution

01

- Determine State Points Using Steam Tables

Utilize steam tables to find properties at different state points. Identify the enthalpies and entropies for each state: 1, 2, 3, etc. This includes steam at turbine inlet, isentropic expansion levels, feedwater heater exits, and condenser.
02

- Energy Balance for Main Turbine

Compute the work produced by the main turbine using the enthalpy change: turbine work: \(W_T = \text{mass flow rate} \times (h_{in} - h_{out})\).
03

- Energy Balance for Pumps

Determine the work required by each pump in the cycle. Use: pump work: \(W_P = \text{mass flow rate} \times (h_{out} - h_{in})\).
04

- Heat Transfer in the Steam Generator

Calculate the heat added in the boiler (steam generator) as the water is heated from the pump exit to the turbine inlet: heat added: \(Q_{in} = \text{mass flow rate} \times (h_{out} - h_{in})\).
05

- Net Power Developed

The net power is the difference between turbine work and pump work: \(W_{net} = \text{Total turbine work} - \text{Total pump work}\).
06

- Thermal Efficiency

Using the net power developed and the heat added, determine the thermal efficiency: \( \text{Efficiency} = \frac{W_{net}}{Q_{in}} \).
07

- Cooling Water Requirement for Condenser

Determine the mass flow rate of cooling water needed in the condenser by setting up an energy balance for the condenser: \( Q_{out} = \text{mass flow rate of steam} \times \text{enthalpy change of steam} = \text{mass flow rate of water} \times \text{specific heat of water} \times \text{temperature change of water} \). Solve for \( \text{mass flow rate of water} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Efficiency
Thermal efficiency is a measure of a Rankine cycle's performance. It tells us how well the cycle converts heat energy into useful work. You can determine the thermal efficiency using the formula: \[ \eta = \frac{W_{net}}{Q_{in}} \]. Here, \(W_{net}\) is the net work output, and \(Q_{in}\) is the heat input. Start by calculating \(W_{net}\), the difference between the total turbine work and the total pump work. This value represents the useful work. Then, calculate \(Q_{in}\), the heat input to the cycle. Typically, this is the heat added in the steam generator. The ratio of these two values gives the thermal efficiency. It's essential to have accurate data for enthalpies and mass flow rates to calculate these values correctly.
Isentropic Process
An isentropic process is a reversible adiabatic process, meaning there is no heat transfer and entropy remains constant. Rankine cycles often assume isentropic conditions for turbines and pumps, simplifying calculations and closely approximating real-world performance. For example, if you need to determine the work done by a turbine, you use the initial and final enthalpies, assuming no entropy change. This allows you to apply the formula: \[ W_T = \dot{m} \times (h_{in} - h_{out}) \], where \( \dot{m} \) is the mass flow rate, \( h_{in} \) is the inlet enthalpy, and \( h_{out} \) is the outlet enthalpy. Similarly, for pumps, the work required can be determined using a similar approach. Maintaining isentropic conditions ensures the most efficient energy transfer.
Energy Balance
Understanding energy balance is crucial in the Rankine cycle. It ensures all energy inputs and outputs are accounted for. In the context of this problem, consider several key components: turbines, pumps, and the steam generator. For the turbine: \[ W_T = \dot{m} \times (h_{in} - h_{out}) \]. For the pump: \[ W_P = \dot{m} \times (h_{out} - h_{in}) \]. And for the steam generator: \[ Q_{in} = \dot{m} \times (h_{out} - h_{in}) \]. Ensure that the energy leaving each system matches the energy entering minus any work done by or on the system. This principle helps check the accuracy of your calculations and ensures all components perform correctly.
Steam Tables
Steam tables are essential tools for solving Rankine cycle problems. They provide thermal properties of water and steam at various temperatures and pressures—crucial for determining enthalpies, entropies, and other properties. For this exercise, you would use steam tables to find properties at specific state points, like the superheated vapor entering the turbine at 16 MPa and 560°C. Here, you'll look up corresponding enthalpies and entropies. These values are critical for calculating work and heat transfer. For example, use these properties to find enthalpy differences in the turbine: \[ W_T = \dot{m} \times (h_{in} - h_{out}) \]. Accurate use of steam tables ensures precise calculations and is fundamental in thermodynamic analysis.
Heat Transfer
Heat transfer is a key concept in the Rankine cycle, representing the energy exchanged between the system and its surroundings. In this cycle, heat is added in the steam generator and removed in the condenser. Calculating the heat added involves determining the enthalpy increase from the pump exit to the turbine inlet: \[ Q_{in} = \dot{m} \times (h_{out} - h_{in}) \]. Similarly, the heat removed in the condenser can be calculated using the enthalpy drop of the steam as it condenses. This is important for determining cooling water requirements: \[ Q_{out} = \dot{m_s} \times (h_{in} - h_{out}) = \dot{m_w} \times c_w \times \Delta T \]. Here, \( \dot{m_s} \) is the steam mass flow rate, \(\dot{m_w} \) is the mass flow rate of cooling water, \(c_w\) is the specific heat of water, and \(\Delta T\) is the temperature change of the cooling water. Understanding heat transfer is vital for designing efficient cooling systems and optimizing cycle performance.

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Most popular questions from this chapter

Data for a regenerative vapor power cycle using an open and a closed feedwater heater similar in design to that shown in Fig P8.60 are provided in the table below. Steam enters the turbine at \(14 \mathrm{MPa}, 560^{\circ} \mathrm{C}\), state 1 , and expands isentropically in three stages to a condenser pressure of \(80 \mathrm{kPa}\), state 4 . Saturated liquid exiting the condenser at state 5 is pumped isentropically to state 6 and enters the open feedwater heater. Between the first and second turbine stages, some steam is extracted at \(1 \mathrm{MPa}\), state 2 , and diverted to the closed feedwater heater. The diverted steam leaves the closed feedwater heater as saturated liquid at \(1 \mathrm{MPa}\), state 10 , undergoes a throttling process to \(0.2 \mathrm{MPa}\), state 11, and enters the open feedwater heater. Steam is also extracted between the second and third turbine stages at \(0.2 \mathrm{MPa}\), state 3, and diverted to the open feedwater heater. Saturated liquid at \(0.2 \mathrm{MPa}\) exiting the open feedwater heater at state 7 is pumped isentropically to state 8 and enters the closed feedwater heater. Feedwater exits the closed feedwater heater at \(14 \mathrm{MPa}, 170^{\circ} \mathrm{C}\), state 9, and then enters the steam generator. If the net power developed by the cycle is \(300 \mathrm{MW}\), determine (a) the cycle thermal efficiency. (b) the mass flow rate into the first turbine stage, in \(\mathrm{kg} / \mathrm{s}\). (c) the rate of heat transfer from the working fluid as it passes through the condenser, in MW.

A binary vapor power cycle consists of two ideal Rankine cycles with steam and Refrigerant \(134 \mathrm{a}\) as the working fluids. The mass flow rate of steam is \(2 \mathrm{~kg} / \mathrm{s}\). In the steam cycle, superheated vapor enters the turbine at \(8 \mathrm{MPa}\), \(600^{\circ} \mathrm{C}\), and saturated liquid exits the condenser at \(250 \mathrm{kPa}\). In the interconnecting heat exchanger, energy rejected by heat transfer from the steam cycle is provided to the Refrigerant \(134 \mathrm{a}\) cycle. The heat exchanger experiences no stray heat transfer with its surroundings. Superheated Refrigerant \(134 \mathrm{a}\) leaves the heat exchanger at \(600 \mathrm{kPa}\), \(30^{\circ} \mathrm{C}\), which enters the Refrigerant 134 a turbine. Saturated liquid leaves the Refrigerant \(134 \mathrm{a}\) condenser at \(100 \mathrm{kPa}\). Determine (a) the net power developed by the binary cycle, in \(\mathrm{kW}\). (b) the rate of heat addition to the binary cycle, in \(\mathrm{kW}\). (c) the thermal efficiency of the binary cycle. (d) the rate of entropy production in the interconnecting heat exchanger, in \(\mathrm{kW} / \mathrm{K}\).

Superheated steam at \(20 \mathrm{MPa}, 560^{\circ} \mathrm{C}\) enters the turbine of a vapor power plant. The pressure at the exit of the turbine is \(0.5\) bar, and liquid leaves the condenser at \(0.4\) bar at \(75^{\circ} \mathrm{C}\). The pressure is increased to \(20.1\) MPa across the pump. The turbine and pump have isentropic efficiencies of 81 and \(85 \%\), respectively. Cooling water enters the condenser at \(20^{\circ} \mathrm{C}\) with a mass flow rate of \(70.7 \mathrm{~kg} / \mathrm{s}\) and exits the condenser at \(3 \mathrm{~S}^{\circ} \mathrm{C}\). For the cycle, determine (a) the mass flow rate of steam, in \(\mathrm{kg} / \mathrm{s}\) (b) the thermal efficiency.

Water is the working fluid in a regenerative Rankine cycle with one closed feedwater heater. Steam enters the turbine at \(1400 \mathrm{lb} /\) in. \({ }^{2}\) and \(1000^{\circ} \mathrm{F}\) and expands to \(120 \mathrm{lbt} / \mathrm{in}^{2}\), where some of the steam is extracted and diverted to the closed feedwater heater. The remaining steam expands through the second-stage turbine to the condenser pressure of \(2 \mathrm{lbf}\) in. \({ }^{2}\) Each turbine stage and the pump have isentropic efficiencies of \(85 \%\). Flow through the condenser, closed feedwater heater, and steam generator is at constant pressure. Condensate exiting the feedwater heater as saturated liquid at \(120 \mathrm{lbf} / \mathrm{in}^{2}\) undergoes a throttling process as it passes through a trap into the condenser. The feedwater leaves the heater at \(1400 \mathrm{lbf} / \mathrm{in}^{2}\) and a temperature equal to the saturation temperature at \(120 \mathrm{lbf} / \mathrm{in}^{2}\). The net power output of the cycle is \(1 \times 10^{9} \mathrm{Btu} / \mathrm{h}\). Determine for the cycle (a) the mass flow rate of steam entering the first stage of the turbine, in \(\mathrm{lb} / \mathrm{h}\). (b) the rate of heat transfer, in Btu/h, to the working fluid passing through the steam generator. (c) the thermal efficiency.

An ideal Rankine cycle with reheat uses water as the working fluid. The conditions at the inlet to the first-stage turbine are \(p_{1}=2500 \mathrm{lbf} / \mathrm{in}^{2}, T_{1}=1000^{\circ} \mathrm{F}\). The steam is reheated at constant pressure \(p\) between the turbine stages to \(1000^{\circ} \mathrm{F}\). The condenser pressure is \(1 \mathrm{lbf} / \mathrm{in}^{2}\) (a) If \(p / p_{1}=0.2\), determine the cycle thermal efficiency and the steam quality at the exit of the second-stage turbine. (b) Plot the quantities of part (a) versus the pressure ratio \(p / p_{1}\) ranging from \(0.05\) to \(1.0\).

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