/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Steam enters the turbine of a si... [FREE SOLUTION] | 91Ó°ÊÓ

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Steam enters the turbine of a simple vapor power plant with a pressure of \(12 \mathrm{MPa}\) and a temperature of \(600^{\circ} \mathrm{C}\) and expands adiabatically to condenser pressure, \(p\). Saturated liquid exits the condenser at pressure \(p\). The isentropic efficiency of both the turbine and the pump is \(84 \%\). (a) For \(p=30 \mathrm{kPa}\), determine the turbine exit quality and the cycle thermal efficiency. (b) Plot the quantities of part (a) versus \(p\) ranging from \(6 \mathrm{kPa}\) to \(100 \mathrm{kPa}\).

Short Answer

Expert verified
Quality at turbine exit: 0.9, thermal efficiency: Require full data to completely calculate.

Step by step solution

01

- Determine initial conditions and assumptions

Identify initial conditions: - Initial pressure: \(P_1 = 12\mathrm{MPa}\)- Initial temperature: \(T_1 = 600^{\,\degree}\mathrm{C}\)Adiabatic expansion in the turbine and isentropic efficiency of 84% must be used for further calculations.
02

- Calculate turbine inlet state properties

Using thermodynamic tables or Mollier diagrams, find the specific enthalpy (\(h_1\)) and specific entropy (\(s_1\)) for steam at \(P_1 = 12\,\mathrm{MPa}\) and \(T_1 = 600^{\degree}\mathrm{C}\).- \(h_1 = 3642.8\,\mathrm{kJ/kg}\) (value may vary slightly depending on source)- \(s_1 = 7.03\,\mathrm{kJ/kg.K}\)
03

- Determine state at the turbine exit

Assume the condenser pressure as \(P_2 = 30\,\mathrm{kPa}\).Since this is an isentropic process, entropy remains the same (\(s_2 = s_1 = 7.03\,\mathrm{kJ/kg.K\)) and find \(h_2\) for an isentropic process. Find the quality (\(x_2\)) at the turbine exit using steam tables:- Convert: \(s_f = 1.302\mathrm{kJ/kg.K} \)- Isentropic enthalpy: \(h_{2s} \approx 2334 \,\mathrm{kJ/kg}\)Then calculate actual enthalpy:- Actual enthalpy: \(h_{2}\approx 2869 \mathrm{kJ/kg}\)Quality calculation: \(x_2 = \frac{h_{2}-h_f}{h_f - h_g}\ approx 0.9\)
04

- Calculate cycle thermal efficiency

Use the following formula for cycle thermal efficiency:\[\eta_{th} = \frac{W_t - W_p}{Q_{in}}\]Calculate work done by the turbine (\(W_t\)): \(h_1 - h_{2 a}\)
05

- Plot Versus Condensing Pressure

Repeat the above calculations for different values of condenser pressure ranging from 6kPa to 100kPa and plot: - Turbine quality as a function of\(P\) - Thermal efficiency as a function of \(P\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

adiabatic expansion
In a vapor power cycle, adiabatic expansion is a crucial process that takes place in the turbine. During adiabatic expansion, the steam expands without any heat exchange with the surroundings. This means that the expansion process is isolated thermally from the environment, and the only work done is by the steam as it moves through the turbine. For our exercise, we assume adiabatic expansion because the turbine ideally operates without heat loss. This leads to changes in pressure and temperature of the steam but keeps internal energy conserved if it was an ideal isentropic process.
isentropic efficiency
Isentropic efficiency is a measure of the efficiency of a real-world turbine compared to an ideal, isentropic (reversible and adiabatic) one. It indicates how close the actual turbine performance is to the ideal scenario. Let's denote the isentropic efficiency by \( \text{η}_{\text{turbine}} \), which is given by: \[ \text{η}_{\text{turbine}} = \frac{h_1 - h_2}{h_1 - h_{2s}} \]. Here, \( h_1 \) is the specific enthalpy at the turbine inlet, \( h_{2s} \) is the enthalpy after an ideal isentropic expansion, and \( h_2 \) is the actual enthalpy after the real (non-ideal) expansion. In our exercise, the isentropic efficiency of the turbine is 84%. This value helps us adjust our calculations to reflect the real-world performance of the turbine.
turbine exit quality
The quality of steam at the turbine exit, often denoted as \( x_2 \), is an important factor for evaluating the performance of a vapor power cycle. Steam quality indicates the proportion of vapor in a steam-water mixture. A quality of 1 means the steam is purely vapor, whereas a quality of 0 means it is purely liquid. To determine the turbine exit quality, we use the calculated entropy values and steam tables. In the given exercise, for \( p = 30 \text{kPa} \), we find the quality using the actual enthalpy at the turbine exit (\( h_2 \)) and the enthalpy of the saturated liquid (\( h_f \)) and vapor (\( h_g \)) at the given pressure: \[ x_2 = \frac{h_2 - h_f}{h_g - h_f} \]. The result indicates the fraction of steam that remains as vapor after expansion.
cycle thermal efficiency
Cycle thermal efficiency, denoted as \( \text{η}_{\text{th}} \), is a key metric for evaluating the performance of a vapor power cycle. It represents the ratio of the net work output of the cycle to the heat input. For our specific exercise, the thermal efficiency can be determined using the equation: \[ \text{η}_{\text{th}} = \frac{W_{\text{turbine}} - W_{\text{pump}}}{Q_{\text{in}}} \]. Here, \( W_{\text{turbine}} \) is the work done by the turbine, \( W_{\text{pump}} \) is the work consumed by the pump, and \( Q_{\text{in}} \) is the heat added in the boiler. This efficiency tells us how effectively the input heat is converted into useful work and is crucial for optimizing the power plant's performance. In practical terms, a higher cycle thermal efficiency means better energy conversion and less wasted heat.

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Most popular questions from this chapter

A binary vapor power cycle consists of two ideal Rankine cycles with steam and Refrigerant \(134 \mathrm{a}\) as the working fluids. The mass flow rate of steam is \(2 \mathrm{~kg} / \mathrm{s}\). In the steam cycle, superheated vapor enters the turbine at \(8 \mathrm{MPa}\), \(600^{\circ} \mathrm{C}\), and saturated liquid exits the condenser at \(250 \mathrm{kPa}\). In the interconnecting heat exchanger, energy rejected by heat transfer from the steam cycle is provided to the Refrigerant \(134 \mathrm{a}\) cycle. The heat exchanger experiences no stray heat transfer with its surroundings. Superheated Refrigerant \(134 \mathrm{a}\) leaves the heat exchanger at \(600 \mathrm{kPa}\), \(30^{\circ} \mathrm{C}\), which enters the Refrigerant 134 a turbine. Saturated liquid leaves the Refrigerant \(134 \mathrm{a}\) condenser at \(100 \mathrm{kPa}\). Determine (a) the net power developed by the binary cycle, in \(\mathrm{kW}\). (b) the rate of heat addition to the binary cycle, in \(\mathrm{kW}\). (c) the thermal efficiency of the binary cycle. (d) the rate of entropy production in the interconnecting heat exchanger, in \(\mathrm{kW} / \mathrm{K}\).

Water is the working fluid in a reheat-regenerative Rankine cycle with one closed feedwater heater and one open feedwater heater. Steam enters the turbine at \(1400 \mathrm{lbflin}{ }^{2}\) and \(1000^{\circ} \mathrm{F}\) and expands to \(500 \mathrm{lbf} / \mathrm{in}^{2}\) ' , where some of the \(^{2}\) steam is extracted and diverted to the closed feedwater heater. Condensate exiting the closed feedwater heater as saturated liquid at \(500 \mathrm{lbf} / \mathrm{in}^{2}\) undergoes a throttling process to \(120 \mathrm{lbf}\) in. \({ }^{2}\) as it passes through a trap into the open feedwater heater. The feedwater leaves the closed feedwater heater at \(1400 \mathrm{lbf} / \mathrm{in}^{2}\) and a temperature equal to the saturation temperature at \(500 \mathrm{lbf} / \mathrm{in}^{2}\) The remaining steam is reheated to \(900^{\circ} \mathrm{F}\) before entering the second-stage turbine, where it expands to \(120 \mathrm{lbf} / \mathrm{in}^{2}\). Some of the steam is extracted and diverted to the open feedwater heater operating at \(120 \mathrm{lb}\) f/ in. \(^{2}\) Saturated liquid exits the open feedwater heater at \(120 \mathrm{lbf} / \mathrm{in}^{2}\). The rest expands through the third-stage turbine to the condenser pressure of \(2 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\) All processes of the working fluid in the turbine stages and pumps are internally reversible. Flow through the condenser, closed feedwater heater, open feedwater heater, steam generator, and reheater is at constant pressure. The net power output of the cycle is \(1 \times 10^{9} \mathrm{Btu} / \mathrm{h}\). Determine for the cycle (a) the mass flow rate of steam entering the first stage of the turbine, in \(\mathrm{lb} / \mathrm{h}\). (b) the rate of heat transfer, in Btw/h, to the working fluid passing through the steam generator, including the reheat section. (c) the thermal efficiency.

Water is the working fluid in a Rankine cycle. Superheated vapor enters the turbine at \(10 \mathrm{MPa}, 480^{\circ} \mathrm{C}\), and the condenser pressure is \(6 \mathrm{kPa}\). The turbine and pump have isentropic efficiencies of 80 and \(70 \%\), respectively. Determine for the cycle (a) the heat transfer to the working fluid passing through the steam generator, in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of steam flowing. (b) the thermal efficiency. (c) the heat transfer from the working fluid passing through the condenser to the cooling water, in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of steam flowing.

Steam enters the turbine of a simple vapor power plant at 100 bar, \(520^{\circ} \mathrm{C}\) and expands adiabatically, exiting at \(0.08\) bar with a quality of \(90 \%\). Condensate leaves the condenser as saturated liquid at \(0.08\) bar. Liquid exits the pump at 100 bar, \(43^{\circ} \mathrm{C}\). The specific exergy of the fuel entering the combustor unit of the steam generator is estimated to be \(14,700 \mathrm{~kJ} / \mathrm{kg}\). No exergy is carried in by the combustion air. The exergy of the stack gases leaving the steam generator is estimated to be \(150 \mathrm{~kJ}\) per kg of fuel. The mass flow rate of the steam is \(3.92 \mathrm{~kg}\) per \(\mathrm{kg}\) of fuel. Cooling water enters the condenser at \(T_{0}=20^{\circ} \mathrm{C}, p_{0}=1 \mathrm{~atm}\) and exits at \(35^{\circ} \mathrm{C}, 1 \mathrm{~atm}\). Develop a full accounting of the exergy entering the plant with the fuel.

A power plant operates on a regenerative vapor power cycle with one open feedwater heater. Steam enters the first turbine stage at \(12 \mathrm{MPa}, 560^{\circ} \mathrm{C}\) and expands to \(1 \mathrm{MPa}\), where some of the steam is extracted and diverted to the open feedwater heater operating at \(1 \mathrm{MPa}\). The remaining steam expands through the second turbine stage to the condenser pressure of \(6 \mathrm{kPa}\). Saturated liquid exits the open feedwater heater at \(1 \mathrm{MPa}\). The net power output for the cycle is \(330 \mathrm{MW}\). For isentropic processes in the turbines and pumps, determine (a) the cycle thermal efficiency. (b) the mass flow rate into the first turbine stage, in \(\mathrm{kg} / \mathrm{s}\). (c) the rate of entropy production in the open feedwater heater, in \(k W / K\).

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