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Steam enters an insulated turbine operating at steady state at \(120 \mathrm{lbf} / \mathrm{in}^{2}, 600^{\circ} \mathrm{F}\), with a mass flow rate of \(3 \times 10^{5}\) \(\mathrm{lb} / \mathrm{h}\) and expands to a pressure of \(10 \mathrm{lbf} / \mathrm{in}^{2}\). The isentropic turbine efficiency is \(80 \%\). If exergy is valued at 8 cents per \(\mathrm{kW} \cdot \mathrm{h}\), determine (a) the value of the power produced, in \(\$ / \mathrm{h}\). (b) the cost of the exergy destroyed, in \(\$ / h\). (c) Plot the values of the power produced and the exergy destroyed, each in \(\$ / h\), versus isentropic efficiency ranging from 80 to \(100 \%\). Ignore the effects of motion and gravity. Let \(T_{0}=70^{\circ} \mathrm{F}\), \(p_{0}=1 \mathrm{~atm} .\)

Short Answer

Expert verified
Values and plots follow from the detailed steps based on given turbine conditions and efficiency, converted to monetary values.

Step by step solution

01

Define Given Data

Identify and list all given data and known values:\[\begin{align*}P_{\text{in}} &= 120 \, \mathrm{lbf} / \mathrm{in}^2 \T_{\text{in}} &= 600^{\circ} \mathrm{F} \dot{m} &= 3 \times 10^5 \, \mathrm{lb} / \mathrm{h} \P_{\text{out}} &= 10 \, \mathrm{lbf} / \mathrm{in}^2 \eta_{\text{isentropic}} &= 80\% = 0.80 \text{Exergy cost} &= 8 \text{ cents per } \mathrm{kW} \cdot \mathrm{h} \T_0 &= 70^{\circ} \mathrm{F} = 530 \, \mathrm{R} \p_0 &= 1 \, \mathrm{atm} \end{align*}\]
02

Calculate Required Isentropic Values

Use steam tables or Mollier diagrams for the given conditions to find the specific enthalpies and entropies at the inlet and at outlet pressures:\[\begin{align*}h_{\text{in}} ; s_{\text{in}} ; h_{\text{s-out}} = f(p_{\text{out}}, s_{\text{in}}) ; h_{\text{out}} = h_{\text{in}} - \eta \times (h_{\text{in}} - h_{\text{s-out}}) \ \end{align*}\]
03

Calculate Power Produced (W_\text{turbine})

Find the actual turbine work done: \[W_{\text{turbine}} = \dot{m} \times (h_{\text{in}} - h_{\text{out}}) \text{ (Convert units appropriately)} \]
04

Convert Power to Dollar Value

Convert power produced to dollar value: \[\text{Value of Power } = W_{\text{turbine}} \times 8\text{ cents }/ \text{kW} \cdot \text{h} \]
05

Calculate Exergy Destroyed

Determine exergy destroyed using isentropic efficiency: \[X_d = \dot{m} \times T_0 \times (s_{\text{out}} - s_{\text{in}}) \]
06

Calculate Cost of Exergy Destroyed

Convert exergy destruction to dollar value using given rate: \[Cost_{\text{exergy}} = X_d \times 8 \text{ cents }/ \text{kW} \cdot \text{h} \]
07

Plot Values

Plot the values of the power produced and the exergy destroyed versus isentropic efficiency ranging from 80% to 100%. Use the results from Steps 4 and 6 to generate the plot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

isentropic efficiency
Isentropic efficiency is a measure of the actual performance of a turbine compared to an ideal, isentropic process. An isentropic process is both adiabatic (no heat transfer) and reversible, meaning it represents the maximum efficiency the turbine could achieve. To calculate isentropic efficiency ( \( \eta_{isentropic} \) ), you can use the following formula: \[ \eta_{isentropic} = \frac{h_{in} - h_{out}}{h_{in} - h_{s-out}} \] Here, \( h_{in} \) is the specific enthalpy at turbine inlet, \( h_{out} \) is the actual specific enthalpy at the outlet, and \( h_{s-out} \) is the isentropic specific enthalpy at the outlet. Higher isentropic efficiency indicates better turbine performance, as more energy is converted into useful work. We use isentropic efficiency to evaluate how close the turbine operates to the ideal process, which helps in maximizing energy use.
enthalpy
Enthalpy represents the total heat content within a system and is crucial in thermodynamic calculations. It is defined as the sum of the internal energy and the product of pressure and volume, expressed as: \[ h = u + p \cdot v \] where \( h \) represents specific enthalpy, \( u \) is internal energy, \( p \) is pressure, and \( v \) is specific volume. For turbines, enthalpy helps determine the energy changes as the steam expands. The change in enthalpy ( \( \Delta h \) ) between the inlet and outlet states directly correlates with the work produced by the turbine: \[ W_{turbine} = \dot{m} \cdot (h_{in} - h_{out}) \] Here, \( \dot{m} \) is the mass flow rate. By understanding enthalpy, engineers can calculate the energy extracted during the expansion process within the turbine.
exergy destruction
Exergy destruction represents the loss of useful work potential due to irreversibilities within a system. These irreversibilities often arise from friction, heat loss, or non-ideal gas expansions. To quantify the exergy destruction ( \( X_d \) ), we use the entropy change and ambient temperature: \[ X_d = \dot{m} \cdot T_0 \cdot (s_{out} - s_{in}) \] Here, \( T_0 \) is the ambient temperature, \( \dot{m} \) is the mass flow rate, and \( s \) represents specific entropy. Minimizing exergy destruction is essential for improving the overall efficiency of the turbine. The destroyed exergy represents energy that could have been converted into valuable work, thus, reducing exergy destruction leads to both economic and environmental benefits.
mass flow rate
Mass flow rate ( \( \dot{m} \) ) is the amount of mass passing through a section of the turbine per unit time. It is a critical parameter in determining the overall energy conversion within the turbine. The mass flow rate is usually measured in \( \text{lb/h} \) or \( \text{kg/s} \). For calculating the work done by the turbine, we use the mass flow rate along with changes in enthalpy: \[ W_{turbine} = \dot{m} \cdot (h_{in} - h_{out}) \] With a higher mass flow rate, the turbine can generate more power, assuming the same enthalpy change. It is important to control and measure the mass flow rate accurately to ensure the turbine operates optimally and efficiently.

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Most popular questions from this chapter

A rigid, well-insulated tank consists of two compartments, each having the same volume, separated by a valve. Initially, one of the compartments is evacuated and the other contains \(0.25 \mathrm{lbmol}\) of a gas at \(50 \mathrm{lbf} / \mathrm{in} .^{2}\) and \(100^{\circ} \mathrm{F}\). The valve is opened and the gas expands to fill the total volume, eventually achieving an equilibrium state. Using the ideal gas model (a) determine the final temperature, in \({ }^{\circ} \mathrm{F}\), and final pressure, in lbf/in. \({ }^{2}\) (b) evaluate the exergy destruction, in Btu. (c) What is the cause of exergy destruction in this case? Let \(T_{0}=70^{\circ} \mathrm{F}, p_{0}=1 \mathrm{~atm}\).

Water vapor at \(4.0 \mathrm{MPa}\) and \(400^{\circ} \mathrm{C}\) enters an insulated turbine operating at steady state and expands to saturated vapor at \(0.1 \mathrm{MPa}\). The effects of motion and gravity can be neglected. Determine the work developed and the exergy destruction, each in \(\mathrm{kJ}\) per \(\mathrm{kg}\) of water vapor passing through the turbine. Let \(T_{0}=27^{\circ} \mathrm{C}, p_{0}=0.1 \mathrm{MPa}\).

Steam enters a turbine operating at steady state at \(4 \mathrm{MPa}\), \(500^{\circ} \mathrm{C}\) with a mass flow rate of \(50 \mathrm{~kg} / \mathrm{s}\). Saturated vapor exits at \(10 \mathrm{kPa}\) and the corresponding power developed is \(42 \mathrm{MW}\). The effects of motion and gravity are negligible. (a) For a control volume enclosing the turbine, determine the rate of heat transfer, in MW, from the turbine to its surroundings Assuming an average turbine outer surface temperature of \(50^{\circ} \mathrm{C}\), determine the rate of exergy destruction, in MW. (b) If the turbine is located in a facility where the ambient temperature is \(27^{\circ} \mathrm{C}\), determine the rate of exergy destruction for an enlarged control volume including the turbine and its immediate surroundings so heat transfer takes place at the ambient temperature. Explain why the exergy destruction values of parts (a) and (b) differ. Let \(T_{0}=300 \mathrm{~K}, p_{0}=100 \mathrm{kPa}\).

Air enters a turbine operating at steady state with a pressure of \(75 \mathrm{lbf} / \mathrm{in}^{2}\), a temperature of \(800^{\circ} \mathrm{R}\), and a velocity of 400 ft/s. At the turbine exit, the conditions are \(15 \mathrm{lbf} / \mathrm{in}^{2}\), \(600^{\circ} \mathrm{R}\), and \(100 \mathrm{ft} / \mathrm{s}\). Heat transfer from the turbine to its surroundings takes place at an average surface temperature of \(620^{\circ} \mathrm{R}\). The rate of heat transfer is 2 Btu per lb of air passing through the turbine. For the turbine, determine the work developed and the exergy destruction, each in Btu per lb of air flowing. Let \(T_{0}=40^{\circ} \mathrm{F}, p_{0}=15 \mathrm{lbf} / \mathrm{in}^{2}{ }^{2}\)

Air enters a compressor operating at steady state at \(T_{1}=\) \(320 \mathrm{~K}, p_{1}=2\) bar with a velocity of \(80 \mathrm{~m} / \mathrm{s}\). At the exit, \(T_{2}=550 \mathrm{~K}, p_{2}=6\) bar and the velocity is \(180 \mathrm{~m} / \mathrm{s}\). The air can be modeled as an ideal gas with \(c_{p}=1.01 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}\). Stray heat transfer can be ignored. Determine, in kJ per \(\mathrm{kg}\) of air flowing, (a) the power required by the compressor and (b) the rate of exergy destruction within the compressor. Let \(T_{0}=\) \(300 \mathrm{~K}, p_{0}=1\) bar. Ignore the effects of motion and gravity.

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