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Three kg of Refrigerant 22 undergoes a process for which the pressure-specific volume relation is \(p v^{-0.8}=\) constant. The initial state of the refrigerant is 12 bar and \(60^{\circ} \mathrm{C}\), and the final pressure is 8 bar. Kinetic and potential energy effects are negligible. Determine the work, in kJ, for the process.

Short Answer

Expert verified
Calculate initial and final specific volumes, use the polytropic work formula: \( W = \frac{p_2 v_2 - p_1 v_1}{1 - n} \).

Step by step solution

01

Identify Given Information

Given: - Mass of Refrigerant 22, \( m = 3 \text{ kg} \)- Initial pressure, \( p_1 = 12 \text{ bar} \)- Initial temperature, \( T_1 = 60^{\text{\circ}} \text{C} \)- Final pressure, \( p_2 = 8 \text{ bar} \)- The process follows the relation \( p v^{-0.8} = \text{constant} \) The goal is to determine the work done during the process.
02

Determine Initial Specific Volume

Using a Refrigerant 22 property table or software, find the specific volume \( v_1 \) corresponding to the initial state (12 bar and 60°C). For instance, \( v_1 = 0.0200 \text{ m}^3/\text{kg} \).
03

Apply Process Relation

The process follows the relation \( p v^{-0.8} = C \), meaning:\[ 12 \text{ bar} \cdot (0.0200 \text{ m}^3 / \text{kg})^{-0.8} = C \]
04

Determine Final Specific Volume

Using the constant \( C \) found in the previous step with the final pressure, find the final specific volume:\[ C = p_2 v_2^{-0.8} \]\[ v_2 = \left( \frac{C}{p_2} \right)^{-1/0.8} \]Substitute \( p_2 = 8 \text{ bar} \) and solve for \( v_2 \).
05

Calculate the Work Done

For a polytropic process, work \( W \) is given by:\[ W = \frac{p_2 v_2 - p_1 v_1}{1 - n} \]Substitute \( n = -0.8 \), \( p_1 = 12 \text{ bar} \), \( v_1 = 0.0200 \text{ m}^3 / \text{kg} \), \( p_2 = 8 \text{ bar} \), and the calculated \( v_2 \) value to find \( W \) in \( \text{kJ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polytropic Process
In thermodynamics, a polytropic process is a type of process that follows the relation \( p v^n = \text{constant} \), where \( p \) stands for pressure, \( v \) stands for specific volume, and \( n \) is the polytropic index. In our case, the process follows the relation \( p v^{-0.8} = \text{constant} \). This means the polytropic index, \( n \), is \( -0.8 \).
For polytropic processes:
  • \( n = 0 \) corresponds to an isobaric process (constant pressure).
  • \( n = 1 \) corresponds to an isothermal process (constant temperature).
  • \( n = \text{specific value} \) like our case indicates a unique polytropic behavior.
Understanding the polytropic index is crucial because it dictates how pressure and specific volume vary with respect to each other during the process.
Specific Volume
Specific volume is defined as the volume occupied by a unit mass of a substance. It is the inverse of density and is expressed in \( \text{m}^3/\text{kg} \).
In the context of Refrigerant 22, specific volume is determined from refrigerant property tables at given conditions of pressure and temperature. For example, in the given exercise, the initial specific volume \( v_1 \) is found to be \( 0.0200 \text{ m}^3/\text{kg} \) at 12 bar and 60°C.
Typical steps involve:
  • Referring to refrigerant property tables or software.
  • Identifying properties at specific states.
Accurate determination of specific volume is essential for calculating other thermodynamic properties and for conducting further analysis of the process.
Thermodynamic Work
Thermodynamic work refers to the work done by or on a system during a thermodynamic process. For a polytropic process, the work done \( W \) can be calculated using the formula:
\[ W = \frac{p_2 v_2 - p_1 v_1}{1 - n} \]
Here:
  • \( p_1 \) and \( p_2 \) are the initial and final pressures respectively.
  • \( v_1 \) and \( v_2 \) are the initial and final specific volumes respectively.
  • \( n \) is the polytropic index.
This formula requires finding the final specific volume \( v_2 \) using the given polytropic relation. Once \( v_2 \) is determined, the work done can be calculated directly. The work is normally expressed in kilojoules \( \text{kJ} \).
Pressure-Volume Relationship
The pressure-volume relationship in a thermodynamic process describes how pressure and volume vary during the process. For a polytropic process, this takes the form:
\[ p v^n = \text{constant} \]
In this exercise, we know:
\[ 12 \text{ bar} \times (0.0200 \text{ m}^3/\text{kg})^{-0.8} = \text{constant} \]
From this constant, we can find the final specific volume with:
\[ v_2 = \bigg( \frac{\text{constant}}{p_2} \bigg)^{-\frac{1}{0.8}} \]
Knowing how pressure and specific volume relate helps us understand the behavior of the refrigerant during this polytropic process. This relationship allows us to calculate any other state properties required, such as work done or change in internal energy.

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Most popular questions from this chapter

Using the tables for water, determine the specified property data at the indicated states. In each case, locate the state on sketches of the \(p-v\) and \(T-v\) diagrams. (a) At \(p=2 \mathrm{MPa}, T=300^{\circ} \mathrm{C}\). Find \(u\), in kJ/kg. (b) At \(p=2.5 \mathrm{MPa}, T=200^{\circ} \mathrm{C}\). Find \(u\), in \(\mathrm{kJ} / \mathrm{kg}\). (c) At \(T=170^{\circ} \mathrm{F}, x=50 \%\). Find \(u\), in Btu/lb. (d) At \(p=100 \mathrm{lbf} / \mathrm{in}^{2}, T=300^{\circ} \mathrm{F}\). Find \(h\), in Btu/lb. (e) At \(p=1.5 \mathrm{MPa}, v=0.2095 \mathrm{~m}^{3} / \mathrm{kg}\). Find \(h\), in \(\mathrm{kJ} / \mathrm{kg}\).

One kg of air in a piston-cylinder assembly undergoes two processes in series from an initial state where \(p_{1}=\) \(0.5 \mathrm{MPa}, T_{1}=227^{\circ} \mathrm{C}\) : Process 1-2: Constant-temperature expansion until the volume is twice the initial volume. Process 2-3: Constant-volume heating until the pressure is again \(0.5 \mathrm{MPa}\). Sketch the two processes in series on a \(p-v\) diagram. Assuming ideal gas behavior, determine (a) the pressure at state 2 , in MPa, (b) the temperature at state 3 , in \({ }^{\circ} \mathrm{C}\), and for each of the processes (c) the work and heat transfer, each in kJ.

Water contained in a piston-cylinder assembly, initially at \(300^{\circ} \mathrm{F}\), a quality of \(90 \%\), and a volume of \(6 \mathrm{ft}^{3}\), is heated at constant temperature to saturated vapor. If the rate of heat transfer is \(0.3 \mathrm{Btu} / \mathrm{s}\), determine the time, in min, for this process of the water to occur. Kinetic and potential energy effects are negligible.

Check the applicability of the ideal gas model for (a) water at \(600^{\circ} \mathrm{F}\) and pressures of \(900 \mathrm{lbf} / \mathrm{in} .{ }^{2}\) and 100 lbf/in. (b) nitrogen at \(-20^{\circ} \mathrm{C}\) and pressures of 75 bar and 1 bar.

A system consists of liquid nitrogen in equilibrium with nitrogen vapor. How many phases are present? The system undergoes a process during which all of the liquid is vaporized. Can the system be viewed as being a pure substance during the process? Explain.

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