/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A \(0.15\)-m-diameter pulley tur... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(0.15\)-m-diameter pulley turns a belt rotating the driveshaft of a power plant pump. The torque applied by the belt on the pulley is \(200 \mathrm{~N} \cdot \mathrm{m}\), and the power transmitted is \(7 \mathrm{~kW}\). Determine the net force applied by the belt on the pulley, in \(\mathrm{kN}\), and the rotational speed of the driveshaft, in RPM.

Short Answer

Expert verified
The net force is 2.67 kN, and the rotational speed is approximately 334.76 RPM.

Step by step solution

01

- Convert Units of Power

First, convert the power transmitted from kilowatts to watts:\[ P = 7 \text{ kW} = 7000 \text{ W} \]
02

- Calculate the Rotational Speed

Use the formula for power transmitted by a torque to calculate the rotational speed. The formula is given by:\[ P = \tau \times \text{angular velocity} \]Rearrange to find the angular velocity (\(\text{angular velocity} = \frac{P}{\tau}\)):\[ \text{angular velocity} = \frac{7000 \text{ W}}{200 \text{ N} \times \text{ m}} = 35 \text{ rad/s} \]
03

- Convert Angular Velocity to RPM

Convert the angular velocity from radians per second to revolutions per minute (RPM). Use the conversion factor: \( 1 \text{ revolution} = 2\text{\pi} \text{ radians} \) and \( 1 \text{ minute} = 60 \text{ seconds} \):\[ \text{RPM} = \text{angular velocity} \times \frac{60}{2\text{\pi}} = 35 \times \frac{60}{2\text{\pi}} \approx 334.76 \text{ RPM} \]
04

- Calculate the Net Force Applied by the Belt

Determine the net force using the relationship between torque, force, and radius. The formula for torque is:\[ \tau = F \times r \]Rearrange to find force (\(F = \frac{\tau}{r}\)) where radius (\(r\)) is half the diameter:\[ r = \frac{0.15 \text{ m}}{2} = 0.075 \text{ m} \]\[ F = \frac{200 \text{ N} \times \text{ m}}{0.075 \text{ m}} = 2666.67 \text{ N} \]Convert to kilonewtons (\(\text{kN}\)):\[ F = 2.67 \text{ kN} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Transmission
Power transmission is a fundamental concept in engineering thermodynamics. It deals with the transfer of energy from one place to another or from one form to another. In mechanical systems, power transmission usually involves moving components such as belts, chains, and gears. Power is defined as the rate at which work is done, and it is measured in watts (W) or kilowatts (kW). For example, in our exercise, the power transmitted is given as 7 kW, which is converted to 7000 W for further computations.
Torque and Angular Velocity
Torque and angular velocity are crucial in analyzing the rotational motion of objects. Torque (τ) is a measure of the force that can cause an object to rotate about an axis and is calculated as the product of force (F) and radius (r). The unit for torque is Newton-meter (N·m). In the example, the applied torque by the belt on the pulley is 200 N·m.
Angular velocity (ω) measures how fast an object rotates or revolves relative to another point, measured in radians per second (rad/s). The relationship between power (P), torque (τ), and angular velocity (ω) is given by the formula:
\ P = τ \times ω
Using this equation helps us determine the angular velocity when power and torque are known. As shown in the exercise, rearranging it, we find:
\(\text{angular velocity} = \frac{P}{τ} = \frac{7000 \text{ W}}{200 \text{ N} · \text{ m}} = 35 \text{ rad/s}\).
Unit Conversion
Unit conversion is essential for ensuring that all calculations are consistent and accurate. In engineering problems, it is often necessary to convert quantities from one unit to another. In the exercise, the power was initially given in kilowatts (kW) but had to be converted to watts (W) for proper calculations. This is done by multiplying by 1000: \(\text{7 kW} = 7000 \text{ W}\).
Furthermore, converting angular velocity from radians per second (rad/s) to revolutions per minute (RPM) uses the factors \(1 \text{ revolution} = 2\text{Ï€ radians}\text{ and }\text{1 minute} = 60 \text{ seconds}\). The formula:
\(\text{RPM} = \text{angular velocity} \times \frac{60}{2\text{Ï€}} = 35 \times \frac{60}{2\text{Ï€}} \approx 334.76 \text{ RPM}\).Lastly, converting the force from Newtons (N) to kilonewtons (kN) is done by dividing by 1000, as 1 kN = 1000 N. Hence,\(\text{Force} = 2666.67 \text{ N} = 2.67 \text{ kN}\). This step simplifies the interpretation of the results.

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