/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 93 A closed, rigid, insulated vesse... [FREE SOLUTION] | 91影视

91影视

A closed, rigid, insulated vessel having a volume of \(0.142 \mathrm{~m}^{3}\) contains oxygen \(\left(\mathrm{O}_{2}\right)\) initially at 100 bar, \(7^{\circ} \mathrm{C}\). The oxygen is stirred by a paddle wheel until the pressure becomes 150 bar. Determine the (a) final temperature, in \({ }^{\circ} \mathrm{C}\). (b) work, in kJ. (c) amount of exergy destroyed in the process, in kJ. Let \(T_{0}=7^{\circ} \mathrm{C}\).

Short Answer

Expert verified
(a) Temperature = 147.075 掳C, (b) Work = 12793.54 kJ, (c) Exergy destroyed 鈮 46

Step by step solution

01

Initial Conditions and Assumptions

Given the initial conditions: Volume (V) = 0.142 m鲁, initial pressure (P鈧) = 100 bar, and initial temperature (T鈧) = 7掳C = 280.15 K. Assume the vessel is closed, rigid (constant volume), and insulated (no heat transfer).
02

Relate Final and Initial Conditions

Since the vessel is rigid and insulated, the volume and internal energy change only due to work done by the paddle wheel. Use the ideal gas law to find the relationship between initial and final states. Using the ideal gas law: PV = nRT where R is the specific gas constant for oxygen, R = 259.84 J/(kg路K). Relate initial and final states using P鈧乂/T鈧 = P鈧俈/T鈧. Since the volume is constant, this reduces to: P鈧/T鈧 = P鈧/T鈧.
03

Solve for Final Temperature (T鈧)

Using P鈧/T鈧 = P鈧/T鈧, solve for T鈧. T鈧 = T鈧 * (P鈧 / P鈧). Given P鈧 = 150 bar and P鈧 = 100 bar: T鈧 = 280.15 K * (150 / 100) = 420.225 K Convert T鈧 to 掳C: T鈧 = 420.225 K - 273.15 = 147.075掳C.
04

Calculate Work Done (W)

Work done (W) is equal to the change in internal energy since the vessel is insulated. W = 螖U = cv * m * 螖T. Using cv (specific heat at constant volume) for oxygen, cv = 0.918 kJ/(kg路K), and the mass of oxygen from PV = nRT where n (number of moles) is found by n = m/M (m is mass and M is molar mass of O鈧 = 32 kg/kmol). First, determine m: m = (P鈧 * V) / (R鈧 * T鈧 ) where R鈧 = 8314 J/(kmol路K).
05

Compute Mass of Oxygen (m)

m = (100 bar * 0.142 m鲁) / (8314 J/(kmol路K) * 280.15 K/32). Bar to Pa conversion: 1 bar = 10^5 Pa. m = (100 * 10鈦 Pa * 0.142 m鲁) / (26310.75 Pa路K路kmol * 280.15 K/32) = 98.6 kg.
06

Compute Work Performed

W = 螖U = cv * m * 螖T. = 0.918 kJ/(kg路K) * 98.6 kg * (420.225 - 280.15) K = 12793.544 kJ = 12793.54 kJ.
07

Compute Exergy Destroyed ( 螖Ex)

The amount of exergy destroyed is determined using: 螖Ex = 螖U - T鈧螖S. Where 螖S = cv * ln(T鈧/T鈧), T鈧 = 280.15 K 螖S = cv * ln(T鈧/T鈧) 螖Ex = 12793.54 kJ - T鈧*cv*ln(T鈧/T鈧) 螖S = 918 J/kg路K * ln(420.225 K / 280.15) 螖Ex= W - T鈧 * 螖S = 12793.54 kJ - ( 280.15 K * 0.918 kJ/kg路K * ln(1.5) 鈮 12793.53kJ

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a crucial equation in thermodynamics and is formulated as: PV = nRT. In this equation, P represents the pressure of the gas, V is the volume, n is the number of moles, R is the gas constant, and T is the absolute temperature. This law helps us understand the relationship between these variables when analyzing gases.
The ideal gas law allows us to make predictions about how changes in one variable, like pressure, will affect others, like temperature, if the gas behaves ideally (no intermolecular forces and the gas molecules occupy no volume).
In our exercise, we used the ideal gas law to determine the final temperature of the oxygen gas in a rigid, insulated vessel, signifying no changes in volume or heat transfer. Specifically, we used the relationship: \[ P_1 / T_1 = P_2 / T_2 \].

This relationship directly arises from the ideal gas law and is essential for calculating the final temperature after the pressure change.
Internal Energy
Internal energy (U) in thermodynamics refers to the total energy contained within a system. This includes kinetic and potential energy at the molecular level. For an ideal gas, the internal energy depends only on temperature and the amount of substance, not on volume or pressure.
Internal energy change (螖U) is calculated as the product of mass (m), specific heat at constant volume (cv), and temperature change (螖T): \[ 螖U = c_v \times m \times 螖T \].

In the given exercise, the work done by the paddle wheel equals the change in internal energy since the system is insulated.We calculated the work as: \[ W = 螖U = c_v \times m \times (T_2 - T_1) \].
This shows that any energy added as work by the paddle wheel is manifested purely as an increase in the internal energy of the gas, resulting in a higher temperature.
Specific Heat at Constant Volume
Specific heat at constant volume (cv) is the amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius while keeping the volume constant. It's expressed in units such as kJ/(kg路K).
For an ideal gas, cv is vital because it relates the change in internal energy directly to the temperature change: \[ 螖U = c_v \times m \times 螖T \].
In our problem, the value of cv for oxygen (O鈧) was given as 0.918 kJ/(kg路K), and we used it to calculate the internal energy change due to the rise in temperature. Without this key value, we couldn't determine how much internal energy corresponds to the work done by the paddle wheel in increasing the gas's temperature.
Exergy Destruction
Exergy represents the useful work obtainable from a system as it comes into equilibrium with its surroundings. Exergy destruction, especially in an insulated system with work done, shows irreversible losses usually due to inefficiencies or entropy generation.
In our exercise, exergy destruction was determined using the formula: \[ 螖Ex = 螖U - T_0 螖S \].
Where 螖U is the change in internal energy, and 螖S is the change in entropy. The entropy change is given by \[ 螖S = c_v \times \text{ln} (T_2 / T_0) \].Here T鈧 is the reference temperature.
Calculating exergy destroyed helps in understanding the efficiency of a process and identifying how much work potential is lost, which is crucial for engineering applications.
Closed System Analysis
In thermodynamics, a closed system allows energy transfer but not mass transfer across its boundaries. Analyzing such systems requires careful accounting of energy forms鈥攈eat and work.
Since our vessel is closed and insulated, no mass enters or leaves the system, and heat transfer is zero. The only energy transfer is via work done by the paddle wheel, which affects internal energy and, consequently, temperature.
By using the principles of a closed system, including the conservation of energy, we derived the key results for temperature changes and exergy destruction based on initial and final states ensuring internal consistency and real-world applicability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Methane gas flows through a pipeline with a volumetric flow rate of \(11 \mathrm{ft}^{3} / \mathrm{s}\) at a pressure of 183 atm and a temperature of \(56^{\circ} \mathrm{F}\). Determine the mass flow rate, in lbis, using the (a) ideal gas equation of state. (b) van der Waals equation. (c) compressibility chart.

A rigid vessel initially contains carbon dioxide gas at \(32^{\circ} \mathrm{C}\) and pressure \(p\). Ethylene gas is allowed to flow into the tank until a mixture consisting of \(20 \%\) carbon dioxide and \(80 \%\) ethylene (molar basis) exists within the tank at a temperature of \(43^{\circ} \mathrm{C}\) and a pressure of 110 bar. Determine the pressure \(p\), in bar, using Kay's rule together with the generalized compressibility chart.

Nitrogen \(\left(\mathrm{N}_{2}\right)\) enters a compressor operating at steady state at \(1.5 \mathrm{MPa}, 300 \mathrm{~K}\) and exits at \(8 \mathrm{MPa}, 500 \mathrm{~K}\). If the work input is \(240 \mathrm{~kJ}\) per \(\mathrm{kg}\) of nitrogen flowing, determine the heat transfer, in kJ per \(\mathrm{kg}\) of nitrogen flowing. Ignore kinetic and potential energy effects.

Water vapor initially at \(240^{\circ} \mathrm{C}, 1\) MPa expands in a piston- cylinder assembly isothermally and without internal irreversibilities to a final pressure of 0.1 MPa. Evaluate the work done, in kJ/kg. Use a truncated virial equation of state with the form $$ Z=1+\frac{B}{v}+\frac{C}{v^{2}} $$ where \(B\) and \(C\) are evaluated from steam table data at \(240^{\circ} C\) and presstares ranging from 0 to \(1 \mathrm{MP}^{2}\).

Derive an equation for the Joule-Thomson coefficient as a function of \(T\) and \(y\) for a gas that obeys the van der Waals equation of state and whase specific heat \(c_{v}\) is given by \(c_{u}=A+B T+C T^{2}\), where \(A, B, C\) are constants. Evaluate the temperatures at the inversion states in terans of \(\boldsymbol{R}, v\), and the van der Waals constants \(a\) and \(b\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.