Chapter 12: Problem 65
A balanced three-phase generator has an abc phase sequence with phase voltage \(\mathbf{V}_{a n}=255 / 0^{\circ} \mathrm{V}\). The generator feeds an induction motor which may be represented by a balanced Y-connected load with an impedance of \(12+j 5 \Omega\) per phase. Find the line currents and the load voltages. Assume a line impedance of \(2 \Omega\) per phase.
Short Answer
Step by step solution
Understand the Problem
Calculate Phase Currents
Calculate Line Currents
Calculate Load Voltages
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Balanced Three-Phase Generator
Impedance Calculation
- \(Z_{total} = Z_L + Z_{line} = (12 + j5) + (2 + j0) = 14 + j5 \Omega\)
- \(Z_{total} = \sqrt{14^2 + 5^2} \angle \tan^{-1}\left(\frac{5}{14}\right)\)
- \(Z_{total} = 14.87 \angle 19.29^\circ \Omega\)
Phase Sequence
Ohm's Law
- \(I = \frac{V}{Z}\)
- \(I_a = \frac{255 \angle 0^\circ}{14.87 \angle 19.29^\circ} = 17.15 \angle -19.29^\circ \text{A}\).