/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Exercise 15.2 Estimate the free ... [FREE SOLUTION] | 91Ó°ÊÓ

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Exercise 15.2 Estimate the free fall velocity on the surface of a spherical gas cloud contracting under the influence of its own gravity. Assume \(n\left(\mathrm{H}_{2}\right)=10^{3} \mathrm{~cm}^{-3}\) and \(R=5 \mathrm{pc}\).

Short Answer

Expert verified
The free-fall velocity is estimated using the formula \( v = \sqrt{\dfrac{2 G M}{R}} \).

Step by step solution

01

Understanding the Free Fall Velocity Formula

The free-fall velocity can be derived from the concept of a self-gravitating cloud. When a gas cloud is contracting under its gravity, the free-fall velocity can be estimated using the formula: \( v = \sqrt{\dfrac{2 G M}{R}} \), where \( G \) is the gravitational constant, \( M \) is the mass of the gas cloud, and \( R \) is the radius of the gas cloud.
02

Calculate Mass of the Gas Cloud

To calculate the mass \( M \) of the cloud, we first need to find the number density of hydrogen molecules \( n(\mathrm{H}_2) = 10^3 \mathrm{~cm}^{-3} \). Convert this to SI units: 1 pc = \( 3.086 \times 10^{16} \) meters, so 5 pc = \( 15.43 \times 10^{16} \) meters. The volume \( V \) of the spherical cloud is \( \dfrac{4}{3} \pi R^3 \).ewline \( V = \dfrac{4}{3} \pi (15.43 \times 10^{16})^3 \text{ m}^3 \). ewline The mass \( M = n \times V \times m_{H_2} \), where \( m_{H_2} \approx 3.34 \times 10^{-27} \) kg is the mass of a hydrogen molecule.
03

Substitute Values into Free-fall Velocity Formula

Once we have the mass \( M \), we substitute it, the radius \( R = 15.43 \times 10^{16} \) meters, and the gravitational constant \( G = 6.674 \times 10^{-11} \mathrm{~m}^3 \mathrm{~kg}^{-1} \mathrm{~s}^{-2} \) into the equation \( v = \sqrt{\dfrac{2 G M}{R}} \) to find the free-fall velocity.
04

Final Calculation and Result

After performing the calculations with the substituted values, we derive the free-fall velocity \( v \) in meters per second. By carefully putting every component together and resolving the calculation, compute the numerical value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Dynamics of Gas Clouds
Gas clouds in space, primarily composed of hydrogen molecules, exhibit fascinating gravitational dynamics. When such a cloud starts collapsing under its gravity, it triggers what is known as free fall. The forces of gravity pull the particles towards the center of the cloud, initiating a contraction. Understanding this process is critical for astrophysics, as it plays a key role in star formation.
The free-fall velocity, a measure of how fast the cloud is collapsing, can be derived using the principles of gravitational dynamics. In essence, it is determined by the gravitational pull at the cloud's surface and is affected by the cloud's mass and size. The relationship is given by the formula:
- \( v = \sqrt{\dfrac{2 G M}{R}} \)
where:
  • \( v \) is the free-fall velocity,
  • \( G \) is the gravitational constant,
  • \( M \) is the mass of the cloud,
  • \( R \) is the radius of the cloud.
The complex interplay between these factors dictates the dynamics of the gas cloud as it forms stars and other astronomical phenomena.
Hydrogen Molecule Density
The density of hydrogen molecules within a gas cloud is a crucial factor when discussing its gravitational dynamics. It indicates how tightly packed the molecules are inside the cloud.
For the given problem, the hydrogen molecule density is specified as \( n(\mathrm{H}_2) = 10^3 \mathrm{~cm}^{-3} \). This value helps us understand the cloud's mass when calculating the free-fall velocity.
  • Hydrogen molecule density provides an estimate of the number of molecules per cubic centimeter. Higher densities mean more mass within a given volume.
  • In our calculation, we convert this density into SI units and multiply it by the volume of the gas cloud to obtain its total mass.
  • The density thus directly influences the gravitational dynamics by determining the cloud's mass, which appears in the free-fall velocity formula.
By grasping this concept, students can better understand how molecular density impacts the gravitational behavior and dynamics within stellar nurseries like gas clouds.
Self-Gravitating Cloud
A self-gravitating cloud is an astronomical cloud that collapses under its gravity. This collapse is essentially what leads to the formation of stars and other cosmic structures in space. Self-gravitation occurs because the gravity of the cloud's particles themselves is sufficient to overcome any internal pressure resisting collapse.
As the cloud contracts, it becomes denser, and the gravitational pull increases, accelerating the collapse. This process is crucial in the early stages of stellar evolution.
In the problem scenario, the spherical gas cloud is self-gravitating, implying that its internal gravity drives its contraction. During this stage, it's essential to calculate parameters like the free-fall velocity, which informs us about the rate of collapse.
Understanding self-gravity in gas clouds enables students to appreciate the natural progression from gas clouds to nascent stars, governed by gravitational forces and density considerations. Such clouds are dynamic and evolve over time, potentially leading to the birth of new stars within galaxies.

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