Chapter 5: Problem 8
If an incandescent light bulb has a luminosity \(L=60 \mathrm{~W}\) and a filament temperature of \(T=2900 \mathrm{~K}\), what must be the surface area of its filament? If the filament consists of a cylindrical wire with diameter \(d=4.6 \times 10^{-5} \mathrm{~m}\) (as in a standard incandescent 60 watt, 120 volt bulb), what is the length of the wire?
Short Answer
Step by step solution
Understanding the Stefan-Boltzmann Law
Solving for Surface Area
Analyzing the Wire Geometry
Calculating the Wire Length
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Incandescent Light Bulb
Key characteristics of incandescent bulbs include:
- Simple design: An incandescent bulb is straightforward in its construction and does not require external electronics.
- Color rendering: They provide a warm light that closely matches that of natural sunlight, making colors appear more vibrant.
- Energy consumption: Although they are less energy-efficient compared to modern LEDs, incandescent bulbs convert over 90% of energy into heat rather than light. This inefficiency contributes to their being phased out in favor of more energy-efficient lighting solutions.
Luminosity
The Stefan-Boltzmann Law comes into play here, as it links luminosity (or power output) to the bulb's temperature and surface area. The equation \( L = \sigma A T^4 \) provides a detailed relationship:
- \( L \): Luminosity, which is the energy per second or wattage (e.g., 60 watts in our example).
- \( \sigma \): Stefan-Boltzmann constant, a fundamental constant that determines how much energy a black body radiates per unit area and temperature.
- \( A \): Surface area of the filament, determined by its geometry.
- \( T \): Absolute temperature of the filament in Kelvin.
Surface Area
The surface area of an object defines how much of it is exposed to the surroundings. For a wire, as in our incandescent bulb example, the surface area affects how efficiently it can release energy in the form of light and heat.
When calculating the filament's surface area required to emit a specified amount of luminosity, we use the rearranged Stefan-Boltzmann equation:
- \( A = \frac{L}{\sigma T^4} \)
Cylindrical Wire Geometry
For the filament found in the bulb, the cylindrical shape is analyzed with regard to its surface area using the formula:
- \( A = \pi d l \)
- Here, \( d \) is the diameter of the wire, and \( l \) is its length.
Utilizing the known surface area and diameter in our example, we rearrange to solve for the length:
\( l = \frac{A}{\pi d} \)
This calculation reveals how long the wire needs to be to meet specific emission characteristics, showcasing the importance of geometry in electrical and thermal design.