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Find the real values of \(x\) for which the following series are convergent: (a) \(\sum_{n=1}^{\infty} \frac{x^{n}}{n+1}\), (b) \(\sum_{n=1}^{\infty}(\sin x)^{n}\), (c) \(\sum_{n=1}^{\infty} n^{x}\), (d) \(\sum_{n=1}^{\infty} e^{n x} .\)

Short Answer

Expert verified
The series \(\sum_{n=1}^{\infty} \frac{x^{n}}{n+1}\) converges for \( -1<x<1 \). The series \(\sum_{n=1}^{\infty}(\sin x)^{n}\) converges for all \(x \in R\), except for \(x = k\pi\) where \(k\) is an integer. The series \(\sum_{n=1}^{\infty} n^{x}\) and \(\sum_{n=1}^{\infty} e^{n x}\) converge for \(x < 0\) .

Step by step solution

01

Convergence of the series (a)

To find the real values of \(x\) for which the series \(\sum_{n=1}^{\infty} \frac{x^{n}}{n+1}\) converges, apply the ratio test. The ratio test states that if the limit \(L = \lim_{n\rightarrow\infty} \frac{a_{n+1}}{a_n}\) is less than 1, then the series converges. For the given series, \(L = \lim_{n\rightarrow\infty} \frac{x^{n+1}/(n+2)}{x^n/(n+1)} = \lim_{n\rightarrow\infty} \frac{(n+1)x}{n+2} = |x|\). Therefore, the series converges when \(|x|<1\), or \( -1<x<1 \)
02

Convergence of the series (b)

For the series \(\sum_{n=1}^{\infty}(\sin x)^{n}\), note that \(-1 \leq \sin x \leq 1\). Therefore, this geometric series converges for all \(x \in R\) when \(|\sin x| < 1\), or when \(-1 < \sin x < 1\). This condition is fulfilled for all real numbers \(x\), except for \(x = k\pi\), where \(k\) is an integer.
03

Convergence of the series (c)

In the series \(\sum_{n=1}^{\infty} n^{x}\), \(n^{x}\) is always finite for real \(x\), but the series only converges when \(x < 0\) . This is because \(n^{x}\) increases with \(n\) for \(x > 0\), and \(n^{x} = 1\) for \(x = 0\). For \(x < 0\), the terms of the series decrease with \(n\) and approach zero.
04

Convergence of the series (d)

For the series \(\sum_{n=1}^{\infty} e^{n x}\), \(e^{n x}\) increases with \(n\) for \(x > 0\). Therefore, the series only converges when \(x < 0\). In this case, the terms of the series decrease with \(n\) and approach zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ratio Test
The Ratio Test is a powerful tool for determining the convergence of infinite series. It's particularly useful when dealing with series involving powers of a variable. The test states that a series \( \sum a_n \) converges if the limit \( L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1 \). If \( L > 1 \), the series diverges. If \( L = 1 \), the test is inconclusive.

In exercise (a), the series \( \sum_{n=1}^{\infty} \frac{x^n}{n+1} \) uses the ratio test to find that it converges for \( |x| < 1 \). By plugging \( a_n = \frac{x^n}{n+1} \) into the test, we simplify to \( L = |x| \). Thus, the series converges when \(-1 < x < 1\).

This test is handy for series with factorials, powers, or complicated products under certain conditions.
Geometric Series
A geometric series is a series where each term is a constant multiple of the previous term. It takes the form \( \sum_{n=0}^{\infty} ar^n \), where \( a \) is the first term and \( r \) is the common ratio. The series converges if \( |r| < 1 \), and its sum is \( \frac{a}{1-r} \).

For the series \( \sum_{n=1}^{\infty} (\sin x)^n \), a geometric series with a ratio \( \sin x \), it converges when \( |\sin x| < 1 \). This is satisfied for all real \( x \) except when \( x = k\pi \), where \( \sin x = \pm 1 \).

Understanding geometric series is crucial because they appear in many applications, from finance to physics.
Power Series
A power series is a series in the form \( \sum_{n=0}^{\infty} c_n(x-a)^n \), where \( c_n \) are coefficients and \( a \) is the center of the series. Power series can converge for all \( x \), no \( x \), or within a finite radius \( R \). The interval of convergence is determined using the ratio or root test.

The series \( \sum_{n=1}^{\infty} n^x \) is not a typical power series but introduces a key concept: convergence for particular values of \( x \). Here, the series converges when \( x < 0 \) because \( n^x \) approaches zero as \( n \) increases if \( x < 0 \).

Power series are used in calculus to represent functions and solve differential equations, making them a vital mathematical tool.
Exponential Series
The exponential series involves terms of the form \( e^{nx} \). The function \( e^x \) is unique for its property that its derivative and integral are the same function. The series \( \sum_{n=1}^{\infty} e^{nx} \) will converge if \( x \) is negative.

When \( x > 0 \), the terms \( e^{nx} \) grow with \( n \), leading to divergence. However, when \( x < 0 \), the terms shrink as \( n \) grows, ensuring convergence.

Exponential series are fundamental in exponential growth and decay models, which appear in everything from population growth to radioactive decay.

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Most popular questions from this chapter

If you invest \(£ 1000\) on the first day of each year and interest is paid at \(5 \%\) on your balance at the end of each year, how much money do you have after 25 years?

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