/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 The jet plane has a constant vel... [FREE SOLUTION] | 91Ó°ÊÓ

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The jet plane has a constant velocity of \(750 \mathrm{~km} / \mathrm{h}\). Air enters its engine nacelle at \(A\) having a cross-sectional area of \(0.8 \mathrm{~m}^{2}\). Fuel is mixed with the air at \(\dot{m}_{e}=2.5 \mathrm{~kg} / \mathrm{s}\) and is exhausted into the ambient air with a velocity of \(900 \mathrm{~m} / \mathrm{s},\) measured relative to the plane. Determine the force the engine exerts on the wing of the plane. Take \(\rho_{a}=0.850 \mathrm{~kg} / \mathrm{m}^{3}\)

Short Answer

Expert verified
The force the engine exerts on the wing of the plane is obtained by calculating the rate of momentum change, which is the net mass flow rate multiplied by the exhaust velocity relative to the plane.

Step by step solution

01

Calculation of the mass flow rate of the air

The mass flow rate \( \dot{m}_a \) of the air can be calculated using the formula: \( \dot{m}_a = \rho_{a} \cdot V_a \cdot A \), where \(\rho_{a}\) is the density of the air, \(V_a\) is the velocity of the air relative to the plane, and \(A\) is the cross-sectional area of the plane's inlet. The velocity \(V_a\) is the opposite of the plane's velocity, therefore \(V_a = -750 \cdot 1000 / 3600 = -208.33 \, m/s \)
02

Computation of the net mass flow rate

The net mass flow rate \( \dot{m} \) is the sum of the mass flow rate of the air \( \dot{m}_a \) and the mass flow rate of the fuel \( \dot{m}_e \). Hence, \(\dot{m} = \dot{m}_a + \dot{m}_e\)
03

Determination of the force exerted by the engine

The force exerted on the wing is the rate of change of the momentum per unit time. Using the formula \( F = \dot{m} \cdot V_{rel} \), where \( V_{rel} \) is the velocity of the exhaust relative to the plane, the force \( F \) can be computed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Flow Rate
Understanding the mass flow rate is crucial when analyzing fluid flow systems such as jet engines. The mass flow rate, denoted as \( \dot{m} \), represents the amount of mass passing through a given surface area per unit time. Imagine it as the number of molecules traveling through a plane's jet engine at any given moment.

To calculate the mass flow rate \( \dot{m}_a \) of air flowing into the engine, we use the formula

\[ \dot{m}_a = \rho_a \cdot V_a \cdot A, \]

where \( \rho_a \) is the air density, \( V_a \) is the velocity of the air relative to the aircraft, and \( A \) is the cross-sectional area of the inlet. In the given problem, we accounted for the fact that the aircraft is moving, and so the air's relative velocity is opposite in direction to the aircraft's. Therefore, we correctly interpreted the velocity as negative, which reflects its opposite direction relative to the plane's movement.
  • \rho_a = 0.850 \mathrm{~kg/m^3} (density of air)
  • A = 0.8 \mathrm{~m^2} (cross-sectional area)
  • V_a = -208.33 \mathrm{~m/s} (relative velocity of air)
The mass flow rate of air is just one component; the fuel's mass flow rate must also be considered to find the total mass flow rate through the engine.
Momentum Principle
The momentum principle is a fundamental concept in fluid mechanics and physics. It's a way of expressing Newton's second law of motion for a fluid. The principle states that the rate of change of momentum of a fluid is equal to the sum of external forces applied to the fluid. When dealing with a jet engine, the momentum principle helps us analyze the forces generated as air and fuel mix and exhaust from the engine.

In the context of our problem, the jet engine exerts a force on the aircraft wing due to the momentum change of the exhaust gases. The force exerted by the engine can be expressed as the product of the net mass flow rate and the relative velocity of the exhaust gas:

\[ F = \dot{m} \cdot V_{rel}, \]

where \(\text{F}\) is the force exerted by the engine, \(\text{\dot{m}}\) is the net mass flow rate through the engine, and \(\text{V_{rel}}\) is the velocity of the exhaust relative to the plane. This force is the thrust provided by the jet engine, propelling the plane forward. By applying the momentum principle correctly, we ensure accurate force calculation for the jet engine, leading to a realistic understanding of its performance.
Jet Engine Force Calculation
The jet engine force calculation involves using the principles of mass flow rate and momentum to determine the thrust produced by a jet engine. In our exercise, we need to find the net force that the engine exerts on the wing. This is determined through the momentum change of the exhaust gas—as fuel is added and expelled at high speed relative to the plane.

The final force calculation relates the mass flow rate and velocity changes into a tangible force value using the equation:

\[ F = \text{net mass flow rate} \times \text{exhaust velocity relative to plane}, \]

which accounts for both the air and fuel contributions. The importance of incorporating the velocity as relative to the plane ensures we're considering the system from the correct frame of reference, a key aspect that students should not overlook.

To accurately find the force, it's then required to sum the mass flow rates of both the air and the fuel (\(\text{\dot{m}_a + \dot{m}_e}\)) and multiply by the exhaust velocity. The resulting force is what effectively pushes the airplane forward, an illustration of Newton's third law where the action of expelling exhaust gases results in the reaction force propelling the aircraft.

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Most popular questions from this chapter

The rocket has an initial total mass \(m_{0}\), including the fuel. When it is fired, it ejects a mass flow of \(\dot{m}_{e}\) with a velocity of \(v_{e}\) measured relative to the rocket. As this occurs, the pressure at the nozzle, which has a crosssectional area \(A_{c}\) is \(p_{e}\). If the drag force on the rocket is \(F_{D}=c t,\) where \(t\) is the time and \(c\) is a constant, determine the velocity of the rocket if the acceleration due to gravity is assumed to be constant.

A jet engine is flying with velocity \(150 \mathrm{~m} / \mathrm{s}\) in still air and draws in air at standard atmospheric temperature and pressure through a 0.4 -m-diameter inlet. If \(2.5 \mathrm{~kg} / \mathrm{s}\) of fuel is added and the mixture leaves the \(0.2-\mathrm{m}\) -diameter nozzle at \(500 \mathrm{~m} / \mathrm{s}\), measured relative to the engine, determine the thrust provided by the turbojet.

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Water flows at \(0.1 \mathrm{~m}^{3} / \mathrm{s}\) through the \(100-\mathrm{mm}\) -diameter nozzle and strikes the vane on the \(150-\mathrm{kg}\) cart, which is originally at rest. Determine the velocity of the cart 3 seconds after the jet strikes the vane.

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